About $ f(w,L) = int_1^w int_0^{2 L pi} frac{ ln(frac{sin(x) + sin(vx)}{2} + frac{5}{4})}{L(w - 1)} dx dv $












0














Consider



$$ f(w,L) = int_1^w int_0^{2 L pi} frac{ ln(frac{sin(x) + sin(vx)}{2} + frac{5}{4})}{L(w - 1)} dx dv $$



For real $w > 1 $ and integer $ L > 1$



Conjecture :



$$ lim_{L to infty} f(w + 1, L) - f(w,L) = 0. $$



How to decide if this is true ?



Perhaps differentiation under the integral sign is the best method ?



——



To see where “ this is coming from “ ,



Notice



$$int_0^{2 pi} ln(sin(x) + frac{5}{4}) dx = 0 $$



And look at these :



Why is $sup f_- (n) inf f_+ (m) = frac{5}{4} $?



Why is $inf g sup g = frac{9}{16} $?



—-










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  • Although the Integral looks complicated it might be expressible in special functions ? I was thinking about hypergeometric. If that would be simpler or even helpful is another matter ...
    – mick
    Nov 25 '18 at 22:48










  • I think the conjecture is false actually but hard to show false ?
    – mick
    Nov 27 '18 at 20:21
















0














Consider



$$ f(w,L) = int_1^w int_0^{2 L pi} frac{ ln(frac{sin(x) + sin(vx)}{2} + frac{5}{4})}{L(w - 1)} dx dv $$



For real $w > 1 $ and integer $ L > 1$



Conjecture :



$$ lim_{L to infty} f(w + 1, L) - f(w,L) = 0. $$



How to decide if this is true ?



Perhaps differentiation under the integral sign is the best method ?



——



To see where “ this is coming from “ ,



Notice



$$int_0^{2 pi} ln(sin(x) + frac{5}{4}) dx = 0 $$



And look at these :



Why is $sup f_- (n) inf f_+ (m) = frac{5}{4} $?



Why is $inf g sup g = frac{9}{16} $?



—-










share|cite|improve this question
























  • Although the Integral looks complicated it might be expressible in special functions ? I was thinking about hypergeometric. If that would be simpler or even helpful is another matter ...
    – mick
    Nov 25 '18 at 22:48










  • I think the conjecture is false actually but hard to show false ?
    – mick
    Nov 27 '18 at 20:21














0












0








0


1





Consider



$$ f(w,L) = int_1^w int_0^{2 L pi} frac{ ln(frac{sin(x) + sin(vx)}{2} + frac{5}{4})}{L(w - 1)} dx dv $$



For real $w > 1 $ and integer $ L > 1$



Conjecture :



$$ lim_{L to infty} f(w + 1, L) - f(w,L) = 0. $$



How to decide if this is true ?



Perhaps differentiation under the integral sign is the best method ?



——



To see where “ this is coming from “ ,



Notice



$$int_0^{2 pi} ln(sin(x) + frac{5}{4}) dx = 0 $$



And look at these :



Why is $sup f_- (n) inf f_+ (m) = frac{5}{4} $?



Why is $inf g sup g = frac{9}{16} $?



—-










share|cite|improve this question















Consider



$$ f(w,L) = int_1^w int_0^{2 L pi} frac{ ln(frac{sin(x) + sin(vx)}{2} + frac{5}{4})}{L(w - 1)} dx dv $$



For real $w > 1 $ and integer $ L > 1$



Conjecture :



$$ lim_{L to infty} f(w + 1, L) - f(w,L) = 0. $$



How to decide if this is true ?



Perhaps differentiation under the integral sign is the best method ?



——



To see where “ this is coming from “ ,



Notice



$$int_0^{2 pi} ln(sin(x) + frac{5}{4}) dx = 0 $$



And look at these :



Why is $sup f_- (n) inf f_+ (m) = frac{5}{4} $?



Why is $inf g sup g = frac{9}{16} $?



—-







calculus limits proof-writing trigonometric-integrals






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 25 '18 at 22:33

























asked Nov 25 '18 at 22:27









mick

5,07922064




5,07922064












  • Although the Integral looks complicated it might be expressible in special functions ? I was thinking about hypergeometric. If that would be simpler or even helpful is another matter ...
    – mick
    Nov 25 '18 at 22:48










  • I think the conjecture is false actually but hard to show false ?
    – mick
    Nov 27 '18 at 20:21


















  • Although the Integral looks complicated it might be expressible in special functions ? I was thinking about hypergeometric. If that would be simpler or even helpful is another matter ...
    – mick
    Nov 25 '18 at 22:48










  • I think the conjecture is false actually but hard to show false ?
    – mick
    Nov 27 '18 at 20:21
















Although the Integral looks complicated it might be expressible in special functions ? I was thinking about hypergeometric. If that would be simpler or even helpful is another matter ...
– mick
Nov 25 '18 at 22:48




Although the Integral looks complicated it might be expressible in special functions ? I was thinking about hypergeometric. If that would be simpler or even helpful is another matter ...
– mick
Nov 25 '18 at 22:48












I think the conjecture is false actually but hard to show false ?
– mick
Nov 27 '18 at 20:21




I think the conjecture is false actually but hard to show false ?
– mick
Nov 27 '18 at 20:21










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