C Primer Plus - Chapter 4 - Task 6 (string output)
Task
Write a Program that requests the user's first name and then the user's last name. Have it print the entered names on one line and the number of letters in each name on the following line. Align each letter count with the end of the corresponding name, as in the following:
Klaus Dieter
5 6
My Try
#include <stdio.h>
#include <string.h>
void printWhitespace(int times) {
for (int i = 0; i < times; i++) {
printf(" ");
}
}
int main(void) {
// get names
printf("first name: ");
char firstName[20];
scanf("%s", &firstName);
printf("last name: ");
char lastName[20];
scanf("%s", &lastName);
// display names
printf("%s %sn", firstName, lastName);
// display number of characters under last character of names
int numOfWhitespace = strlen(firstName) - 1;
printWhitespace(numOfWhitespace);
printf("%d ", strlen(firstName));
numOfWhitespace = strlen(lastName) - 1;
printWhitespace(numOfWhitespace);
printf("%dn", strlen(lastName));
}
Does the author expect that from me? Or is there a better way to write that?
c strings
New contributor
add a comment |
Task
Write a Program that requests the user's first name and then the user's last name. Have it print the entered names on one line and the number of letters in each name on the following line. Align each letter count with the end of the corresponding name, as in the following:
Klaus Dieter
5 6
My Try
#include <stdio.h>
#include <string.h>
void printWhitespace(int times) {
for (int i = 0; i < times; i++) {
printf(" ");
}
}
int main(void) {
// get names
printf("first name: ");
char firstName[20];
scanf("%s", &firstName);
printf("last name: ");
char lastName[20];
scanf("%s", &lastName);
// display names
printf("%s %sn", firstName, lastName);
// display number of characters under last character of names
int numOfWhitespace = strlen(firstName) - 1;
printWhitespace(numOfWhitespace);
printf("%d ", strlen(firstName));
numOfWhitespace = strlen(lastName) - 1;
printWhitespace(numOfWhitespace);
printf("%dn", strlen(lastName));
}
Does the author expect that from me? Or is there a better way to write that?
c strings
New contributor
add a comment |
Task
Write a Program that requests the user's first name and then the user's last name. Have it print the entered names on one line and the number of letters in each name on the following line. Align each letter count with the end of the corresponding name, as in the following:
Klaus Dieter
5 6
My Try
#include <stdio.h>
#include <string.h>
void printWhitespace(int times) {
for (int i = 0; i < times; i++) {
printf(" ");
}
}
int main(void) {
// get names
printf("first name: ");
char firstName[20];
scanf("%s", &firstName);
printf("last name: ");
char lastName[20];
scanf("%s", &lastName);
// display names
printf("%s %sn", firstName, lastName);
// display number of characters under last character of names
int numOfWhitespace = strlen(firstName) - 1;
printWhitespace(numOfWhitespace);
printf("%d ", strlen(firstName));
numOfWhitespace = strlen(lastName) - 1;
printWhitespace(numOfWhitespace);
printf("%dn", strlen(lastName));
}
Does the author expect that from me? Or is there a better way to write that?
c strings
New contributor
Task
Write a Program that requests the user's first name and then the user's last name. Have it print the entered names on one line and the number of letters in each name on the following line. Align each letter count with the end of the corresponding name, as in the following:
Klaus Dieter
5 6
My Try
#include <stdio.h>
#include <string.h>
void printWhitespace(int times) {
for (int i = 0; i < times; i++) {
printf(" ");
}
}
int main(void) {
// get names
printf("first name: ");
char firstName[20];
scanf("%s", &firstName);
printf("last name: ");
char lastName[20];
scanf("%s", &lastName);
// display names
printf("%s %sn", firstName, lastName);
// display number of characters under last character of names
int numOfWhitespace = strlen(firstName) - 1;
printWhitespace(numOfWhitespace);
printf("%d ", strlen(firstName));
numOfWhitespace = strlen(lastName) - 1;
printWhitespace(numOfWhitespace);
printf("%dn", strlen(lastName));
}
Does the author expect that from me? Or is there a better way to write that?
c strings
c strings
New contributor
New contributor
edited 30 mins ago
Reinderien
3,309720
3,309720
New contributor
asked 3 hours ago
Vengeancos
161
161
New contributor
New contributor
add a comment |
add a comment |
1 Answer
1
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oldest
votes
Small sugggestion for printWhitespace()
. You could do the following:
void printWhitespace(const unsigned int times) {
printf("%*s", times, " ");
}
I have made the function argument const as it probably isn't meant to be modified. it is generally a good idea to be as "const" as possible as this avoids the mistake of writing to a variable that should be read-only.
I would put the array declarations at the top of the function before any of the code with a blank line between the declarations and the first line of code.
The function scanf
can be used with caution... it can lead to buffer overflow attacks in the way it is used in your code. If the user enters a string longer than 19 characters (last character would be filled in as a null terminator in the buffer), scanf
will just write on past the end of the buffer.
You could help guard against this by using scanf("%20s", &firstName);
and scanf("%20s", &lastName);
Looked into this a little more and this SO answer, the author says:
Note that the POSIX 2008 (2013) version of the scanf() family of
functions supports a format modifier m (an assignment-allocation
character) for string inputs (%s, %c, %[). Instead of taking a char *
argument, it takes a char ** argument, and it allocates the necessary
space for the value it reads
That would be a useful way of avoiding buffer overflow, but you must remember to free()
the buffer returned.
The variable numOfWhitespace
can also be const
. Might put that to top of function too.
Your last bit of code that tries to align the numbers to the end of the words will only align properly if the string length is 9 or less. If the string length is greater then the number will be double digits so you could account for this.
Add return 0;
to the end of the function. You reach the end of a non-void function without returning anything...
Hope that helps :)
New contributor
I disagree with yourconst
suggestion. Have a read through this answer - softwareengineering.stackexchange.com/a/204720 - with which I agree on most points.const
is not useful on arguments unless the arguments are referential.
– Reinderien
23 mins ago
As of C99,return 0;
in main is optional, compare stackoverflow.com/q/4138649/1187415.
– Martin R
7 mins ago
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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active
oldest
votes
active
oldest
votes
Small sugggestion for printWhitespace()
. You could do the following:
void printWhitespace(const unsigned int times) {
printf("%*s", times, " ");
}
I have made the function argument const as it probably isn't meant to be modified. it is generally a good idea to be as "const" as possible as this avoids the mistake of writing to a variable that should be read-only.
I would put the array declarations at the top of the function before any of the code with a blank line between the declarations and the first line of code.
The function scanf
can be used with caution... it can lead to buffer overflow attacks in the way it is used in your code. If the user enters a string longer than 19 characters (last character would be filled in as a null terminator in the buffer), scanf
will just write on past the end of the buffer.
You could help guard against this by using scanf("%20s", &firstName);
and scanf("%20s", &lastName);
Looked into this a little more and this SO answer, the author says:
Note that the POSIX 2008 (2013) version of the scanf() family of
functions supports a format modifier m (an assignment-allocation
character) for string inputs (%s, %c, %[). Instead of taking a char *
argument, it takes a char ** argument, and it allocates the necessary
space for the value it reads
That would be a useful way of avoiding buffer overflow, but you must remember to free()
the buffer returned.
The variable numOfWhitespace
can also be const
. Might put that to top of function too.
Your last bit of code that tries to align the numbers to the end of the words will only align properly if the string length is 9 or less. If the string length is greater then the number will be double digits so you could account for this.
Add return 0;
to the end of the function. You reach the end of a non-void function without returning anything...
Hope that helps :)
New contributor
I disagree with yourconst
suggestion. Have a read through this answer - softwareengineering.stackexchange.com/a/204720 - with which I agree on most points.const
is not useful on arguments unless the arguments are referential.
– Reinderien
23 mins ago
As of C99,return 0;
in main is optional, compare stackoverflow.com/q/4138649/1187415.
– Martin R
7 mins ago
add a comment |
Small sugggestion for printWhitespace()
. You could do the following:
void printWhitespace(const unsigned int times) {
printf("%*s", times, " ");
}
I have made the function argument const as it probably isn't meant to be modified. it is generally a good idea to be as "const" as possible as this avoids the mistake of writing to a variable that should be read-only.
I would put the array declarations at the top of the function before any of the code with a blank line between the declarations and the first line of code.
The function scanf
can be used with caution... it can lead to buffer overflow attacks in the way it is used in your code. If the user enters a string longer than 19 characters (last character would be filled in as a null terminator in the buffer), scanf
will just write on past the end of the buffer.
You could help guard against this by using scanf("%20s", &firstName);
and scanf("%20s", &lastName);
Looked into this a little more and this SO answer, the author says:
Note that the POSIX 2008 (2013) version of the scanf() family of
functions supports a format modifier m (an assignment-allocation
character) for string inputs (%s, %c, %[). Instead of taking a char *
argument, it takes a char ** argument, and it allocates the necessary
space for the value it reads
That would be a useful way of avoiding buffer overflow, but you must remember to free()
the buffer returned.
The variable numOfWhitespace
can also be const
. Might put that to top of function too.
Your last bit of code that tries to align the numbers to the end of the words will only align properly if the string length is 9 or less. If the string length is greater then the number will be double digits so you could account for this.
Add return 0;
to the end of the function. You reach the end of a non-void function without returning anything...
Hope that helps :)
New contributor
I disagree with yourconst
suggestion. Have a read through this answer - softwareengineering.stackexchange.com/a/204720 - with which I agree on most points.const
is not useful on arguments unless the arguments are referential.
– Reinderien
23 mins ago
As of C99,return 0;
in main is optional, compare stackoverflow.com/q/4138649/1187415.
– Martin R
7 mins ago
add a comment |
Small sugggestion for printWhitespace()
. You could do the following:
void printWhitespace(const unsigned int times) {
printf("%*s", times, " ");
}
I have made the function argument const as it probably isn't meant to be modified. it is generally a good idea to be as "const" as possible as this avoids the mistake of writing to a variable that should be read-only.
I would put the array declarations at the top of the function before any of the code with a blank line between the declarations and the first line of code.
The function scanf
can be used with caution... it can lead to buffer overflow attacks in the way it is used in your code. If the user enters a string longer than 19 characters (last character would be filled in as a null terminator in the buffer), scanf
will just write on past the end of the buffer.
You could help guard against this by using scanf("%20s", &firstName);
and scanf("%20s", &lastName);
Looked into this a little more and this SO answer, the author says:
Note that the POSIX 2008 (2013) version of the scanf() family of
functions supports a format modifier m (an assignment-allocation
character) for string inputs (%s, %c, %[). Instead of taking a char *
argument, it takes a char ** argument, and it allocates the necessary
space for the value it reads
That would be a useful way of avoiding buffer overflow, but you must remember to free()
the buffer returned.
The variable numOfWhitespace
can also be const
. Might put that to top of function too.
Your last bit of code that tries to align the numbers to the end of the words will only align properly if the string length is 9 or less. If the string length is greater then the number will be double digits so you could account for this.
Add return 0;
to the end of the function. You reach the end of a non-void function without returning anything...
Hope that helps :)
New contributor
Small sugggestion for printWhitespace()
. You could do the following:
void printWhitespace(const unsigned int times) {
printf("%*s", times, " ");
}
I have made the function argument const as it probably isn't meant to be modified. it is generally a good idea to be as "const" as possible as this avoids the mistake of writing to a variable that should be read-only.
I would put the array declarations at the top of the function before any of the code with a blank line between the declarations and the first line of code.
The function scanf
can be used with caution... it can lead to buffer overflow attacks in the way it is used in your code. If the user enters a string longer than 19 characters (last character would be filled in as a null terminator in the buffer), scanf
will just write on past the end of the buffer.
You could help guard against this by using scanf("%20s", &firstName);
and scanf("%20s", &lastName);
Looked into this a little more and this SO answer, the author says:
Note that the POSIX 2008 (2013) version of the scanf() family of
functions supports a format modifier m (an assignment-allocation
character) for string inputs (%s, %c, %[). Instead of taking a char *
argument, it takes a char ** argument, and it allocates the necessary
space for the value it reads
That would be a useful way of avoiding buffer overflow, but you must remember to free()
the buffer returned.
The variable numOfWhitespace
can also be const
. Might put that to top of function too.
Your last bit of code that tries to align the numbers to the end of the words will only align properly if the string length is 9 or less. If the string length is greater then the number will be double digits so you could account for this.
Add return 0;
to the end of the function. You reach the end of a non-void function without returning anything...
Hope that helps :)
New contributor
edited 2 hours ago
New contributor
answered 2 hours ago
Jimbo
1213
1213
New contributor
New contributor
I disagree with yourconst
suggestion. Have a read through this answer - softwareengineering.stackexchange.com/a/204720 - with which I agree on most points.const
is not useful on arguments unless the arguments are referential.
– Reinderien
23 mins ago
As of C99,return 0;
in main is optional, compare stackoverflow.com/q/4138649/1187415.
– Martin R
7 mins ago
add a comment |
I disagree with yourconst
suggestion. Have a read through this answer - softwareengineering.stackexchange.com/a/204720 - with which I agree on most points.const
is not useful on arguments unless the arguments are referential.
– Reinderien
23 mins ago
As of C99,return 0;
in main is optional, compare stackoverflow.com/q/4138649/1187415.
– Martin R
7 mins ago
I disagree with your
const
suggestion. Have a read through this answer - softwareengineering.stackexchange.com/a/204720 - with which I agree on most points. const
is not useful on arguments unless the arguments are referential.– Reinderien
23 mins ago
I disagree with your
const
suggestion. Have a read through this answer - softwareengineering.stackexchange.com/a/204720 - with which I agree on most points. const
is not useful on arguments unless the arguments are referential.– Reinderien
23 mins ago
As of C99,
return 0;
in main is optional, compare stackoverflow.com/q/4138649/1187415.– Martin R
7 mins ago
As of C99,
return 0;
in main is optional, compare stackoverflow.com/q/4138649/1187415.– Martin R
7 mins ago
add a comment |
Vengeancos is a new contributor. Be nice, and check out our Code of Conduct.
Vengeancos is a new contributor. Be nice, and check out our Code of Conduct.
Vengeancos is a new contributor. Be nice, and check out our Code of Conduct.
Vengeancos is a new contributor. Be nice, and check out our Code of Conduct.
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