Angular 6 @Viewchild is not working with lazy loading
up vote
6
down vote
favorite
Here is my code that gives error cannot read property title undefined.
Parent Component
import { Child } from './child.component';
@Component({
selector: 'parent',
})
export class ParentComponet implements OnInit, AfterViewInit {
constructor(){}
@ViewChild(Child) child: Child;
ngAfterViewInit(){
console.log("check data", this.child.title)
}
}
And Child Component is.
@Component({
selector: 'child',
})
export class ChildComponet {
public title = "hi"
constructor(){}
}
routing.module.ts is like
{
path: "",
component: ParentComponent,
children: [
{
path: '/child',
component: ChildComponent
}
]
}
And Gives error is
ERROR TypeError: Cannot read property 'title' of undefined(…)
javascript angular angular6 lazy-loading
add a comment |
up vote
6
down vote
favorite
Here is my code that gives error cannot read property title undefined.
Parent Component
import { Child } from './child.component';
@Component({
selector: 'parent',
})
export class ParentComponet implements OnInit, AfterViewInit {
constructor(){}
@ViewChild(Child) child: Child;
ngAfterViewInit(){
console.log("check data", this.child.title)
}
}
And Child Component is.
@Component({
selector: 'child',
})
export class ChildComponet {
public title = "hi"
constructor(){}
}
routing.module.ts is like
{
path: "",
component: ParentComponent,
children: [
{
path: '/child',
component: ChildComponent
}
]
}
And Gives error is
ERROR TypeError: Cannot read property 'title' of undefined(…)
javascript angular angular6 lazy-loading
2
can you share your parent.component.html file ?
– hana_wujira
Dec 5 at 7:48
1
Try with something like this... In your parent.component html:<child #myChildComponent></child>
and in your parent component typescript:@ViewChild('myChildComponent') child: Child;
– Deadpool
Dec 5 at 8:19
add a comment |
up vote
6
down vote
favorite
up vote
6
down vote
favorite
Here is my code that gives error cannot read property title undefined.
Parent Component
import { Child } from './child.component';
@Component({
selector: 'parent',
})
export class ParentComponet implements OnInit, AfterViewInit {
constructor(){}
@ViewChild(Child) child: Child;
ngAfterViewInit(){
console.log("check data", this.child.title)
}
}
And Child Component is.
@Component({
selector: 'child',
})
export class ChildComponet {
public title = "hi"
constructor(){}
}
routing.module.ts is like
{
path: "",
component: ParentComponent,
children: [
{
path: '/child',
component: ChildComponent
}
]
}
And Gives error is
ERROR TypeError: Cannot read property 'title' of undefined(…)
javascript angular angular6 lazy-loading
Here is my code that gives error cannot read property title undefined.
Parent Component
import { Child } from './child.component';
@Component({
selector: 'parent',
})
export class ParentComponet implements OnInit, AfterViewInit {
constructor(){}
@ViewChild(Child) child: Child;
ngAfterViewInit(){
console.log("check data", this.child.title)
}
}
And Child Component is.
@Component({
selector: 'child',
})
export class ChildComponet {
public title = "hi"
constructor(){}
}
routing.module.ts is like
{
path: "",
component: ParentComponent,
children: [
{
path: '/child',
component: ChildComponent
}
]
}
And Gives error is
ERROR TypeError: Cannot read property 'title' of undefined(…)
javascript angular angular6 lazy-loading
javascript angular angular6 lazy-loading
edited Dec 5 at 8:07
Deadpool
350119
350119
asked Dec 5 at 7:44
Ricky
1632211
1632211
2
can you share your parent.component.html file ?
– hana_wujira
Dec 5 at 7:48
1
Try with something like this... In your parent.component html:<child #myChildComponent></child>
and in your parent component typescript:@ViewChild('myChildComponent') child: Child;
– Deadpool
Dec 5 at 8:19
add a comment |
2
can you share your parent.component.html file ?
– hana_wujira
Dec 5 at 7:48
1
Try with something like this... In your parent.component html:<child #myChildComponent></child>
and in your parent component typescript:@ViewChild('myChildComponent') child: Child;
– Deadpool
Dec 5 at 8:19
2
2
can you share your parent.component.html file ?
– hana_wujira
Dec 5 at 7:48
can you share your parent.component.html file ?
– hana_wujira
Dec 5 at 7:48
1
1
Try with something like this... In your parent.component html:
<child #myChildComponent></child>
and in your parent component typescript: @ViewChild('myChildComponent') child: Child;
– Deadpool
Dec 5 at 8:19
Try with something like this... In your parent.component html:
<child #myChildComponent></child>
and in your parent component typescript: @ViewChild('myChildComponent') child: Child;
– Deadpool
Dec 5 at 8:19
add a comment |
3 Answers
3
active
oldest
votes
up vote
9
down vote
accepted
I think you are missing 'template' or 'templateUrl' in relevance to creating a Component
ParentComponent
import { ChildComponent } from './child.component'; // {ChildComponent} not {Child} as we are referencing it to the exported class of ChildComponent
@Component({
selector: 'parent',
template: `<child></child>`
})
export class ParentComponet implements OnInit, AfterViewInit {...}
ChildComponent
@Component({
selector: 'child',
template: `<h1>{{ title }}</h1>`
})
export class ChildComponent {...} // Be sure to spell it right as yours were ChildComponet - missing 'n'
UPDATE as per the user's clarification on this thread
Had added a Stackblitz Demo for your reference (Check the console)
If you want to access the ChildComponent that is rendered under the Parent Component's <router-outlet>
you can do so by utilizing (activate) supported property of router-outlet:
A router outlet will emit an activate event any time a new component is being instantiated
Angular Docs
ParentComponent's Template
@Component({
selector: 'parent',
template: `<router-outlet (activate)="onActivate($event)"></router-outlet>`
})
export class ParentComponent {
onActivate(event): void {
console.log(event); // Sample Output when you visit ChildComponent url
// ChildComponent {title: "hi"}
console.log(event.title); // 'hi'
}
}
The result will differ based on the visited page under your parent's children
If you visit Child1Component you will get its instance
Child1Component {title: "hi"}
If you visit Child2Component you will get its instance
Child2Component {name: "Angular"}
These results will then be reflected on your ParentComponent's onActivate(event) console for you to access
Hiii @KShewengger...thanks for your time....Actually I have multiple child components so I am useing <router-outlet></router-outlet> to render child view..
– Ricky
Dec 5 at 9:07
1
Hi @Ricky had updated my answer :) Since you can't use @ViewChild() on your ParentComponent since your ChildComponent is not a direct descendant or physically included on your Parent Component's Template. So the workaround, since you are loading them on your router-outlet, why not try to use its (activate) supported property of router-outlet
– KShewengger
Dec 5 at 9:46
1
Thanks for your answer....its too helpful for me and others also...
– Ricky
Dec 5 at 10:46
add a comment |
up vote
3
down vote
That's not how it's supposed to work. You'll be only able to get the ChildComponent
in your ParentComponent
ONLY if you have the <app-child></app-child>
tag in your ParentComponent
Template.
Something like this:
...
<app-child></app-child>
...
But since you're using child routing, and the ChildComponent
will load on the router-outlet
of your ParentComponent
you won't have access to that using ViewChild
PS: You'll only have access to it inside ngAfterViewInit
as ViewChild
can only be considered safe to have instantiated after the View has loaded:
import { Component, OnInit, ViewChild } from '@angular/core';
import { ChildComponent } from '../child/child.component';
...
@Component({...})
export class ParentComponent implements OnInit {
@ViewChild(ChildComponent) childComponent: ChildComponent;
...
ngAfterViewInit() {
console.log(this.childComponent);
}
}
Here's a Working Sample StackBlitz for your ref that illustrates your scenario in both the cases.
PS: To get the ChildComponent
properties in your ParentComponent
, with Routing, you'll have to either use a SharedService
or you'll have to pass the ChildProperty in the route as a QueryParam and read it in your ParentComponent using the ActivatedRoute
UPDATE:
Sharing Data using Route Query Params:
Although this won't make much sense, but in your ChildComponent
, you can have a Link that would route the user to the ChildComponent with the title
property passed as a queryParam
. Something like this:
<a
[routerLink]="['/child']"
[queryParams]="{title: title}">
Go To Child Route With Query Params
</a>
And in your ParentComponent
have access to it using ActivatedRoute
like this:
...
import { ActivatedRoute } from '@angular/router';
...
@Component({...})
export class ParentComponent implements OnInit {
...
constructor(
private route: ActivatedRoute,
...
) { }
ngOnInit() {
this.route.queryParams.subscribe(queryParams => {
console.log('queryParams[`title`]', queryParams['title']);
});
...
}
...
}
Using a SharedService
Just create a SharedService
with a private
BehaviorSubject
that would be exposed as an Observable
by calling the asObservable
method on it. It's value can be set by exposing a method(setChildProperty
) that will essentially call the next
method with the updated childProperty
value :
import { Injectable } from '@angular/core';
import { BehaviorSubject, Observable } from 'rxjs';
@Injectable()
export class SharedService {
private childProperty: BehaviorSubject<string> = new BehaviorSubject<string>(null);
childProperty$: Observable<string> = this.childProperty.asObservable();
constructor() { }
setChildProperty(childProperty) {
this.childProperty.next(childProperty);
}
}
You can then inject it both in your ParentComponent
and in your ChildComponent
:
In ChildComponent
set the value:
import { Component, OnInit } from '@angular/core';
import { SharedService } from '../shared.service';
@Component({
selector: 'app-child',
templateUrl: './child.component.html',
styleUrls: ['./child.component.css']
})
export class ChildComponent implements OnInit {
public title = "hi"
constructor(private sharedService: SharedService) { }
ngOnInit() {
this.sharedService.setChildProperty(this.title);
}
}
And in your ParentComponent
get the value:
...
import { SharedService } from '../shared.service';
@Component({...})
export class ParentComponent implements OnInit {
...
constructor(
...,
private sharedService: SharedService
) { }
ngOnInit() {
...
this.sharedService.childProperty$.subscribe(
childProperty => console.log('Got the Child Property from the Shared Service as: ', childProperty)
);
}
...
}
add a comment |
up vote
2
down vote
Make sure inside your parent.component.html
template you've added the <child></child>
tag.
Hiii @Morema...thanks for your time....Actually I have multiple child components so I am using <router-outlet></router-outlet> to render child view..
– Ricky
Dec 5 at 9:29
No worries, just trying to help and learn along the way. @KShewengger explained intelligently in his post and I also got to learn :)
– Morema
Dec 5 at 10:17
Thanks @Morema for helping me to out this..
– Ricky
Dec 5 at 10:48
Thank you @Morema :)
– KShewengger
Dec 5 at 14:28
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
9
down vote
accepted
I think you are missing 'template' or 'templateUrl' in relevance to creating a Component
ParentComponent
import { ChildComponent } from './child.component'; // {ChildComponent} not {Child} as we are referencing it to the exported class of ChildComponent
@Component({
selector: 'parent',
template: `<child></child>`
})
export class ParentComponet implements OnInit, AfterViewInit {...}
ChildComponent
@Component({
selector: 'child',
template: `<h1>{{ title }}</h1>`
})
export class ChildComponent {...} // Be sure to spell it right as yours were ChildComponet - missing 'n'
UPDATE as per the user's clarification on this thread
Had added a Stackblitz Demo for your reference (Check the console)
If you want to access the ChildComponent that is rendered under the Parent Component's <router-outlet>
you can do so by utilizing (activate) supported property of router-outlet:
A router outlet will emit an activate event any time a new component is being instantiated
Angular Docs
ParentComponent's Template
@Component({
selector: 'parent',
template: `<router-outlet (activate)="onActivate($event)"></router-outlet>`
})
export class ParentComponent {
onActivate(event): void {
console.log(event); // Sample Output when you visit ChildComponent url
// ChildComponent {title: "hi"}
console.log(event.title); // 'hi'
}
}
The result will differ based on the visited page under your parent's children
If you visit Child1Component you will get its instance
Child1Component {title: "hi"}
If you visit Child2Component you will get its instance
Child2Component {name: "Angular"}
These results will then be reflected on your ParentComponent's onActivate(event) console for you to access
Hiii @KShewengger...thanks for your time....Actually I have multiple child components so I am useing <router-outlet></router-outlet> to render child view..
– Ricky
Dec 5 at 9:07
1
Hi @Ricky had updated my answer :) Since you can't use @ViewChild() on your ParentComponent since your ChildComponent is not a direct descendant or physically included on your Parent Component's Template. So the workaround, since you are loading them on your router-outlet, why not try to use its (activate) supported property of router-outlet
– KShewengger
Dec 5 at 9:46
1
Thanks for your answer....its too helpful for me and others also...
– Ricky
Dec 5 at 10:46
add a comment |
up vote
9
down vote
accepted
I think you are missing 'template' or 'templateUrl' in relevance to creating a Component
ParentComponent
import { ChildComponent } from './child.component'; // {ChildComponent} not {Child} as we are referencing it to the exported class of ChildComponent
@Component({
selector: 'parent',
template: `<child></child>`
})
export class ParentComponet implements OnInit, AfterViewInit {...}
ChildComponent
@Component({
selector: 'child',
template: `<h1>{{ title }}</h1>`
})
export class ChildComponent {...} // Be sure to spell it right as yours were ChildComponet - missing 'n'
UPDATE as per the user's clarification on this thread
Had added a Stackblitz Demo for your reference (Check the console)
If you want to access the ChildComponent that is rendered under the Parent Component's <router-outlet>
you can do so by utilizing (activate) supported property of router-outlet:
A router outlet will emit an activate event any time a new component is being instantiated
Angular Docs
ParentComponent's Template
@Component({
selector: 'parent',
template: `<router-outlet (activate)="onActivate($event)"></router-outlet>`
})
export class ParentComponent {
onActivate(event): void {
console.log(event); // Sample Output when you visit ChildComponent url
// ChildComponent {title: "hi"}
console.log(event.title); // 'hi'
}
}
The result will differ based on the visited page under your parent's children
If you visit Child1Component you will get its instance
Child1Component {title: "hi"}
If you visit Child2Component you will get its instance
Child2Component {name: "Angular"}
These results will then be reflected on your ParentComponent's onActivate(event) console for you to access
Hiii @KShewengger...thanks for your time....Actually I have multiple child components so I am useing <router-outlet></router-outlet> to render child view..
– Ricky
Dec 5 at 9:07
1
Hi @Ricky had updated my answer :) Since you can't use @ViewChild() on your ParentComponent since your ChildComponent is not a direct descendant or physically included on your Parent Component's Template. So the workaround, since you are loading them on your router-outlet, why not try to use its (activate) supported property of router-outlet
– KShewengger
Dec 5 at 9:46
1
Thanks for your answer....its too helpful for me and others also...
– Ricky
Dec 5 at 10:46
add a comment |
up vote
9
down vote
accepted
up vote
9
down vote
accepted
I think you are missing 'template' or 'templateUrl' in relevance to creating a Component
ParentComponent
import { ChildComponent } from './child.component'; // {ChildComponent} not {Child} as we are referencing it to the exported class of ChildComponent
@Component({
selector: 'parent',
template: `<child></child>`
})
export class ParentComponet implements OnInit, AfterViewInit {...}
ChildComponent
@Component({
selector: 'child',
template: `<h1>{{ title }}</h1>`
})
export class ChildComponent {...} // Be sure to spell it right as yours were ChildComponet - missing 'n'
UPDATE as per the user's clarification on this thread
Had added a Stackblitz Demo for your reference (Check the console)
If you want to access the ChildComponent that is rendered under the Parent Component's <router-outlet>
you can do so by utilizing (activate) supported property of router-outlet:
A router outlet will emit an activate event any time a new component is being instantiated
Angular Docs
ParentComponent's Template
@Component({
selector: 'parent',
template: `<router-outlet (activate)="onActivate($event)"></router-outlet>`
})
export class ParentComponent {
onActivate(event): void {
console.log(event); // Sample Output when you visit ChildComponent url
// ChildComponent {title: "hi"}
console.log(event.title); // 'hi'
}
}
The result will differ based on the visited page under your parent's children
If you visit Child1Component you will get its instance
Child1Component {title: "hi"}
If you visit Child2Component you will get its instance
Child2Component {name: "Angular"}
These results will then be reflected on your ParentComponent's onActivate(event) console for you to access
I think you are missing 'template' or 'templateUrl' in relevance to creating a Component
ParentComponent
import { ChildComponent } from './child.component'; // {ChildComponent} not {Child} as we are referencing it to the exported class of ChildComponent
@Component({
selector: 'parent',
template: `<child></child>`
})
export class ParentComponet implements OnInit, AfterViewInit {...}
ChildComponent
@Component({
selector: 'child',
template: `<h1>{{ title }}</h1>`
})
export class ChildComponent {...} // Be sure to spell it right as yours were ChildComponet - missing 'n'
UPDATE as per the user's clarification on this thread
Had added a Stackblitz Demo for your reference (Check the console)
If you want to access the ChildComponent that is rendered under the Parent Component's <router-outlet>
you can do so by utilizing (activate) supported property of router-outlet:
A router outlet will emit an activate event any time a new component is being instantiated
Angular Docs
ParentComponent's Template
@Component({
selector: 'parent',
template: `<router-outlet (activate)="onActivate($event)"></router-outlet>`
})
export class ParentComponent {
onActivate(event): void {
console.log(event); // Sample Output when you visit ChildComponent url
// ChildComponent {title: "hi"}
console.log(event.title); // 'hi'
}
}
The result will differ based on the visited page under your parent's children
If you visit Child1Component you will get its instance
Child1Component {title: "hi"}
If you visit Child2Component you will get its instance
Child2Component {name: "Angular"}
These results will then be reflected on your ParentComponent's onActivate(event) console for you to access
edited Dec 5 at 11:47
answered Dec 5 at 8:14
KShewengger
1,07839
1,07839
Hiii @KShewengger...thanks for your time....Actually I have multiple child components so I am useing <router-outlet></router-outlet> to render child view..
– Ricky
Dec 5 at 9:07
1
Hi @Ricky had updated my answer :) Since you can't use @ViewChild() on your ParentComponent since your ChildComponent is not a direct descendant or physically included on your Parent Component's Template. So the workaround, since you are loading them on your router-outlet, why not try to use its (activate) supported property of router-outlet
– KShewengger
Dec 5 at 9:46
1
Thanks for your answer....its too helpful for me and others also...
– Ricky
Dec 5 at 10:46
add a comment |
Hiii @KShewengger...thanks for your time....Actually I have multiple child components so I am useing <router-outlet></router-outlet> to render child view..
– Ricky
Dec 5 at 9:07
1
Hi @Ricky had updated my answer :) Since you can't use @ViewChild() on your ParentComponent since your ChildComponent is not a direct descendant or physically included on your Parent Component's Template. So the workaround, since you are loading them on your router-outlet, why not try to use its (activate) supported property of router-outlet
– KShewengger
Dec 5 at 9:46
1
Thanks for your answer....its too helpful for me and others also...
– Ricky
Dec 5 at 10:46
Hiii @KShewengger...thanks for your time....Actually I have multiple child components so I am useing <router-outlet></router-outlet> to render child view..
– Ricky
Dec 5 at 9:07
Hiii @KShewengger...thanks for your time....Actually I have multiple child components so I am useing <router-outlet></router-outlet> to render child view..
– Ricky
Dec 5 at 9:07
1
1
Hi @Ricky had updated my answer :) Since you can't use @ViewChild() on your ParentComponent since your ChildComponent is not a direct descendant or physically included on your Parent Component's Template. So the workaround, since you are loading them on your router-outlet, why not try to use its (activate) supported property of router-outlet
– KShewengger
Dec 5 at 9:46
Hi @Ricky had updated my answer :) Since you can't use @ViewChild() on your ParentComponent since your ChildComponent is not a direct descendant or physically included on your Parent Component's Template. So the workaround, since you are loading them on your router-outlet, why not try to use its (activate) supported property of router-outlet
– KShewengger
Dec 5 at 9:46
1
1
Thanks for your answer....its too helpful for me and others also...
– Ricky
Dec 5 at 10:46
Thanks for your answer....its too helpful for me and others also...
– Ricky
Dec 5 at 10:46
add a comment |
up vote
3
down vote
That's not how it's supposed to work. You'll be only able to get the ChildComponent
in your ParentComponent
ONLY if you have the <app-child></app-child>
tag in your ParentComponent
Template.
Something like this:
...
<app-child></app-child>
...
But since you're using child routing, and the ChildComponent
will load on the router-outlet
of your ParentComponent
you won't have access to that using ViewChild
PS: You'll only have access to it inside ngAfterViewInit
as ViewChild
can only be considered safe to have instantiated after the View has loaded:
import { Component, OnInit, ViewChild } from '@angular/core';
import { ChildComponent } from '../child/child.component';
...
@Component({...})
export class ParentComponent implements OnInit {
@ViewChild(ChildComponent) childComponent: ChildComponent;
...
ngAfterViewInit() {
console.log(this.childComponent);
}
}
Here's a Working Sample StackBlitz for your ref that illustrates your scenario in both the cases.
PS: To get the ChildComponent
properties in your ParentComponent
, with Routing, you'll have to either use a SharedService
or you'll have to pass the ChildProperty in the route as a QueryParam and read it in your ParentComponent using the ActivatedRoute
UPDATE:
Sharing Data using Route Query Params:
Although this won't make much sense, but in your ChildComponent
, you can have a Link that would route the user to the ChildComponent with the title
property passed as a queryParam
. Something like this:
<a
[routerLink]="['/child']"
[queryParams]="{title: title}">
Go To Child Route With Query Params
</a>
And in your ParentComponent
have access to it using ActivatedRoute
like this:
...
import { ActivatedRoute } from '@angular/router';
...
@Component({...})
export class ParentComponent implements OnInit {
...
constructor(
private route: ActivatedRoute,
...
) { }
ngOnInit() {
this.route.queryParams.subscribe(queryParams => {
console.log('queryParams[`title`]', queryParams['title']);
});
...
}
...
}
Using a SharedService
Just create a SharedService
with a private
BehaviorSubject
that would be exposed as an Observable
by calling the asObservable
method on it. It's value can be set by exposing a method(setChildProperty
) that will essentially call the next
method with the updated childProperty
value :
import { Injectable } from '@angular/core';
import { BehaviorSubject, Observable } from 'rxjs';
@Injectable()
export class SharedService {
private childProperty: BehaviorSubject<string> = new BehaviorSubject<string>(null);
childProperty$: Observable<string> = this.childProperty.asObservable();
constructor() { }
setChildProperty(childProperty) {
this.childProperty.next(childProperty);
}
}
You can then inject it both in your ParentComponent
and in your ChildComponent
:
In ChildComponent
set the value:
import { Component, OnInit } from '@angular/core';
import { SharedService } from '../shared.service';
@Component({
selector: 'app-child',
templateUrl: './child.component.html',
styleUrls: ['./child.component.css']
})
export class ChildComponent implements OnInit {
public title = "hi"
constructor(private sharedService: SharedService) { }
ngOnInit() {
this.sharedService.setChildProperty(this.title);
}
}
And in your ParentComponent
get the value:
...
import { SharedService } from '../shared.service';
@Component({...})
export class ParentComponent implements OnInit {
...
constructor(
...,
private sharedService: SharedService
) { }
ngOnInit() {
...
this.sharedService.childProperty$.subscribe(
childProperty => console.log('Got the Child Property from the Shared Service as: ', childProperty)
);
}
...
}
add a comment |
up vote
3
down vote
That's not how it's supposed to work. You'll be only able to get the ChildComponent
in your ParentComponent
ONLY if you have the <app-child></app-child>
tag in your ParentComponent
Template.
Something like this:
...
<app-child></app-child>
...
But since you're using child routing, and the ChildComponent
will load on the router-outlet
of your ParentComponent
you won't have access to that using ViewChild
PS: You'll only have access to it inside ngAfterViewInit
as ViewChild
can only be considered safe to have instantiated after the View has loaded:
import { Component, OnInit, ViewChild } from '@angular/core';
import { ChildComponent } from '../child/child.component';
...
@Component({...})
export class ParentComponent implements OnInit {
@ViewChild(ChildComponent) childComponent: ChildComponent;
...
ngAfterViewInit() {
console.log(this.childComponent);
}
}
Here's a Working Sample StackBlitz for your ref that illustrates your scenario in both the cases.
PS: To get the ChildComponent
properties in your ParentComponent
, with Routing, you'll have to either use a SharedService
or you'll have to pass the ChildProperty in the route as a QueryParam and read it in your ParentComponent using the ActivatedRoute
UPDATE:
Sharing Data using Route Query Params:
Although this won't make much sense, but in your ChildComponent
, you can have a Link that would route the user to the ChildComponent with the title
property passed as a queryParam
. Something like this:
<a
[routerLink]="['/child']"
[queryParams]="{title: title}">
Go To Child Route With Query Params
</a>
And in your ParentComponent
have access to it using ActivatedRoute
like this:
...
import { ActivatedRoute } from '@angular/router';
...
@Component({...})
export class ParentComponent implements OnInit {
...
constructor(
private route: ActivatedRoute,
...
) { }
ngOnInit() {
this.route.queryParams.subscribe(queryParams => {
console.log('queryParams[`title`]', queryParams['title']);
});
...
}
...
}
Using a SharedService
Just create a SharedService
with a private
BehaviorSubject
that would be exposed as an Observable
by calling the asObservable
method on it. It's value can be set by exposing a method(setChildProperty
) that will essentially call the next
method with the updated childProperty
value :
import { Injectable } from '@angular/core';
import { BehaviorSubject, Observable } from 'rxjs';
@Injectable()
export class SharedService {
private childProperty: BehaviorSubject<string> = new BehaviorSubject<string>(null);
childProperty$: Observable<string> = this.childProperty.asObservable();
constructor() { }
setChildProperty(childProperty) {
this.childProperty.next(childProperty);
}
}
You can then inject it both in your ParentComponent
and in your ChildComponent
:
In ChildComponent
set the value:
import { Component, OnInit } from '@angular/core';
import { SharedService } from '../shared.service';
@Component({
selector: 'app-child',
templateUrl: './child.component.html',
styleUrls: ['./child.component.css']
})
export class ChildComponent implements OnInit {
public title = "hi"
constructor(private sharedService: SharedService) { }
ngOnInit() {
this.sharedService.setChildProperty(this.title);
}
}
And in your ParentComponent
get the value:
...
import { SharedService } from '../shared.service';
@Component({...})
export class ParentComponent implements OnInit {
...
constructor(
...,
private sharedService: SharedService
) { }
ngOnInit() {
...
this.sharedService.childProperty$.subscribe(
childProperty => console.log('Got the Child Property from the Shared Service as: ', childProperty)
);
}
...
}
add a comment |
up vote
3
down vote
up vote
3
down vote
That's not how it's supposed to work. You'll be only able to get the ChildComponent
in your ParentComponent
ONLY if you have the <app-child></app-child>
tag in your ParentComponent
Template.
Something like this:
...
<app-child></app-child>
...
But since you're using child routing, and the ChildComponent
will load on the router-outlet
of your ParentComponent
you won't have access to that using ViewChild
PS: You'll only have access to it inside ngAfterViewInit
as ViewChild
can only be considered safe to have instantiated after the View has loaded:
import { Component, OnInit, ViewChild } from '@angular/core';
import { ChildComponent } from '../child/child.component';
...
@Component({...})
export class ParentComponent implements OnInit {
@ViewChild(ChildComponent) childComponent: ChildComponent;
...
ngAfterViewInit() {
console.log(this.childComponent);
}
}
Here's a Working Sample StackBlitz for your ref that illustrates your scenario in both the cases.
PS: To get the ChildComponent
properties in your ParentComponent
, with Routing, you'll have to either use a SharedService
or you'll have to pass the ChildProperty in the route as a QueryParam and read it in your ParentComponent using the ActivatedRoute
UPDATE:
Sharing Data using Route Query Params:
Although this won't make much sense, but in your ChildComponent
, you can have a Link that would route the user to the ChildComponent with the title
property passed as a queryParam
. Something like this:
<a
[routerLink]="['/child']"
[queryParams]="{title: title}">
Go To Child Route With Query Params
</a>
And in your ParentComponent
have access to it using ActivatedRoute
like this:
...
import { ActivatedRoute } from '@angular/router';
...
@Component({...})
export class ParentComponent implements OnInit {
...
constructor(
private route: ActivatedRoute,
...
) { }
ngOnInit() {
this.route.queryParams.subscribe(queryParams => {
console.log('queryParams[`title`]', queryParams['title']);
});
...
}
...
}
Using a SharedService
Just create a SharedService
with a private
BehaviorSubject
that would be exposed as an Observable
by calling the asObservable
method on it. It's value can be set by exposing a method(setChildProperty
) that will essentially call the next
method with the updated childProperty
value :
import { Injectable } from '@angular/core';
import { BehaviorSubject, Observable } from 'rxjs';
@Injectable()
export class SharedService {
private childProperty: BehaviorSubject<string> = new BehaviorSubject<string>(null);
childProperty$: Observable<string> = this.childProperty.asObservable();
constructor() { }
setChildProperty(childProperty) {
this.childProperty.next(childProperty);
}
}
You can then inject it both in your ParentComponent
and in your ChildComponent
:
In ChildComponent
set the value:
import { Component, OnInit } from '@angular/core';
import { SharedService } from '../shared.service';
@Component({
selector: 'app-child',
templateUrl: './child.component.html',
styleUrls: ['./child.component.css']
})
export class ChildComponent implements OnInit {
public title = "hi"
constructor(private sharedService: SharedService) { }
ngOnInit() {
this.sharedService.setChildProperty(this.title);
}
}
And in your ParentComponent
get the value:
...
import { SharedService } from '../shared.service';
@Component({...})
export class ParentComponent implements OnInit {
...
constructor(
...,
private sharedService: SharedService
) { }
ngOnInit() {
...
this.sharedService.childProperty$.subscribe(
childProperty => console.log('Got the Child Property from the Shared Service as: ', childProperty)
);
}
...
}
That's not how it's supposed to work. You'll be only able to get the ChildComponent
in your ParentComponent
ONLY if you have the <app-child></app-child>
tag in your ParentComponent
Template.
Something like this:
...
<app-child></app-child>
...
But since you're using child routing, and the ChildComponent
will load on the router-outlet
of your ParentComponent
you won't have access to that using ViewChild
PS: You'll only have access to it inside ngAfterViewInit
as ViewChild
can only be considered safe to have instantiated after the View has loaded:
import { Component, OnInit, ViewChild } from '@angular/core';
import { ChildComponent } from '../child/child.component';
...
@Component({...})
export class ParentComponent implements OnInit {
@ViewChild(ChildComponent) childComponent: ChildComponent;
...
ngAfterViewInit() {
console.log(this.childComponent);
}
}
Here's a Working Sample StackBlitz for your ref that illustrates your scenario in both the cases.
PS: To get the ChildComponent
properties in your ParentComponent
, with Routing, you'll have to either use a SharedService
or you'll have to pass the ChildProperty in the route as a QueryParam and read it in your ParentComponent using the ActivatedRoute
UPDATE:
Sharing Data using Route Query Params:
Although this won't make much sense, but in your ChildComponent
, you can have a Link that would route the user to the ChildComponent with the title
property passed as a queryParam
. Something like this:
<a
[routerLink]="['/child']"
[queryParams]="{title: title}">
Go To Child Route With Query Params
</a>
And in your ParentComponent
have access to it using ActivatedRoute
like this:
...
import { ActivatedRoute } from '@angular/router';
...
@Component({...})
export class ParentComponent implements OnInit {
...
constructor(
private route: ActivatedRoute,
...
) { }
ngOnInit() {
this.route.queryParams.subscribe(queryParams => {
console.log('queryParams[`title`]', queryParams['title']);
});
...
}
...
}
Using a SharedService
Just create a SharedService
with a private
BehaviorSubject
that would be exposed as an Observable
by calling the asObservable
method on it. It's value can be set by exposing a method(setChildProperty
) that will essentially call the next
method with the updated childProperty
value :
import { Injectable } from '@angular/core';
import { BehaviorSubject, Observable } from 'rxjs';
@Injectable()
export class SharedService {
private childProperty: BehaviorSubject<string> = new BehaviorSubject<string>(null);
childProperty$: Observable<string> = this.childProperty.asObservable();
constructor() { }
setChildProperty(childProperty) {
this.childProperty.next(childProperty);
}
}
You can then inject it both in your ParentComponent
and in your ChildComponent
:
In ChildComponent
set the value:
import { Component, OnInit } from '@angular/core';
import { SharedService } from '../shared.service';
@Component({
selector: 'app-child',
templateUrl: './child.component.html',
styleUrls: ['./child.component.css']
})
export class ChildComponent implements OnInit {
public title = "hi"
constructor(private sharedService: SharedService) { }
ngOnInit() {
this.sharedService.setChildProperty(this.title);
}
}
And in your ParentComponent
get the value:
...
import { SharedService } from '../shared.service';
@Component({...})
export class ParentComponent implements OnInit {
...
constructor(
...,
private sharedService: SharedService
) { }
ngOnInit() {
...
this.sharedService.childProperty$.subscribe(
childProperty => console.log('Got the Child Property from the Shared Service as: ', childProperty)
);
}
...
}
edited Dec 5 at 8:44
answered Dec 5 at 8:14
SiddAjmera
11.7k21137
11.7k21137
add a comment |
add a comment |
up vote
2
down vote
Make sure inside your parent.component.html
template you've added the <child></child>
tag.
Hiii @Morema...thanks for your time....Actually I have multiple child components so I am using <router-outlet></router-outlet> to render child view..
– Ricky
Dec 5 at 9:29
No worries, just trying to help and learn along the way. @KShewengger explained intelligently in his post and I also got to learn :)
– Morema
Dec 5 at 10:17
Thanks @Morema for helping me to out this..
– Ricky
Dec 5 at 10:48
Thank you @Morema :)
– KShewengger
Dec 5 at 14:28
add a comment |
up vote
2
down vote
Make sure inside your parent.component.html
template you've added the <child></child>
tag.
Hiii @Morema...thanks for your time....Actually I have multiple child components so I am using <router-outlet></router-outlet> to render child view..
– Ricky
Dec 5 at 9:29
No worries, just trying to help and learn along the way. @KShewengger explained intelligently in his post and I also got to learn :)
– Morema
Dec 5 at 10:17
Thanks @Morema for helping me to out this..
– Ricky
Dec 5 at 10:48
Thank you @Morema :)
– KShewengger
Dec 5 at 14:28
add a comment |
up vote
2
down vote
up vote
2
down vote
Make sure inside your parent.component.html
template you've added the <child></child>
tag.
Make sure inside your parent.component.html
template you've added the <child></child>
tag.
edited Dec 5 at 8:25
answered Dec 5 at 8:01
Morema
589
589
Hiii @Morema...thanks for your time....Actually I have multiple child components so I am using <router-outlet></router-outlet> to render child view..
– Ricky
Dec 5 at 9:29
No worries, just trying to help and learn along the way. @KShewengger explained intelligently in his post and I also got to learn :)
– Morema
Dec 5 at 10:17
Thanks @Morema for helping me to out this..
– Ricky
Dec 5 at 10:48
Thank you @Morema :)
– KShewengger
Dec 5 at 14:28
add a comment |
Hiii @Morema...thanks for your time....Actually I have multiple child components so I am using <router-outlet></router-outlet> to render child view..
– Ricky
Dec 5 at 9:29
No worries, just trying to help and learn along the way. @KShewengger explained intelligently in his post and I also got to learn :)
– Morema
Dec 5 at 10:17
Thanks @Morema for helping me to out this..
– Ricky
Dec 5 at 10:48
Thank you @Morema :)
– KShewengger
Dec 5 at 14:28
Hiii @Morema...thanks for your time....Actually I have multiple child components so I am using <router-outlet></router-outlet> to render child view..
– Ricky
Dec 5 at 9:29
Hiii @Morema...thanks for your time....Actually I have multiple child components so I am using <router-outlet></router-outlet> to render child view..
– Ricky
Dec 5 at 9:29
No worries, just trying to help and learn along the way. @KShewengger explained intelligently in his post and I also got to learn :)
– Morema
Dec 5 at 10:17
No worries, just trying to help and learn along the way. @KShewengger explained intelligently in his post and I also got to learn :)
– Morema
Dec 5 at 10:17
Thanks @Morema for helping me to out this..
– Ricky
Dec 5 at 10:48
Thanks @Morema for helping me to out this..
– Ricky
Dec 5 at 10:48
Thank you @Morema :)
– KShewengger
Dec 5 at 14:28
Thank you @Morema :)
– KShewengger
Dec 5 at 14:28
add a comment |
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2
can you share your parent.component.html file ?
– hana_wujira
Dec 5 at 7:48
1
Try with something like this... In your parent.component html:
<child #myChildComponent></child>
and in your parent component typescript:@ViewChild('myChildComponent') child: Child;
– Deadpool
Dec 5 at 8:19