Matchstick puzzle with roman numerals












3














I got a puzzle from a book that asks to move one matchstick to get a valid equation. My "solutions"
feels like cheating... Does anyone have a good idea? The original equation, layed out with matches, is



VI = V + VII


the original picture. Sorry for the low quality






matches







share|improve this question









New contributor




Marc is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • Is the I made of 1 or 3 sticks?
    – Omega Krypton
    1 hour ago










  • It is only 1 stick
    – Marc
    1 hour ago










  • Please add the source of the puzzle
    – Dr Xorile
    1 hour ago










  • I don't have a source. It's a picture a friend showed me. And she made it a couple of days agoe in a mountain hut.
    – Marc
    1 hour ago
















3














I got a puzzle from a book that asks to move one matchstick to get a valid equation. My "solutions"
feels like cheating... Does anyone have a good idea? The original equation, layed out with matches, is



VI = V + VII


the original picture. Sorry for the low quality






matches







share|improve this question









New contributor




Marc is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • Is the I made of 1 or 3 sticks?
    – Omega Krypton
    1 hour ago










  • It is only 1 stick
    – Marc
    1 hour ago










  • Please add the source of the puzzle
    – Dr Xorile
    1 hour ago










  • I don't have a source. It's a picture a friend showed me. And she made it a couple of days agoe in a mountain hut.
    – Marc
    1 hour ago














3












3








3







I got a puzzle from a book that asks to move one matchstick to get a valid equation. My "solutions"
feels like cheating... Does anyone have a good idea? The original equation, layed out with matches, is



VI = V + VII


the original picture. Sorry for the low quality






matches







share|improve this question









New contributor




Marc is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I got a puzzle from a book that asks to move one matchstick to get a valid equation. My "solutions"
feels like cheating... Does anyone have a good idea? The original equation, layed out with matches, is



VI = V + VII


the original picture. Sorry for the low quality






matches




matches






share|improve this question









New contributor




Marc is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Marc is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 1 hour ago





















New contributor




Marc is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 1 hour ago









Marc

1184




1184




New contributor




Marc is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Marc is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Marc is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • Is the I made of 1 or 3 sticks?
    – Omega Krypton
    1 hour ago










  • It is only 1 stick
    – Marc
    1 hour ago










  • Please add the source of the puzzle
    – Dr Xorile
    1 hour ago










  • I don't have a source. It's a picture a friend showed me. And she made it a couple of days agoe in a mountain hut.
    – Marc
    1 hour ago


















  • Is the I made of 1 or 3 sticks?
    – Omega Krypton
    1 hour ago










  • It is only 1 stick
    – Marc
    1 hour ago










  • Please add the source of the puzzle
    – Dr Xorile
    1 hour ago










  • I don't have a source. It's a picture a friend showed me. And she made it a couple of days agoe in a mountain hut.
    – Marc
    1 hour ago
















Is the I made of 1 or 3 sticks?
– Omega Krypton
1 hour ago




Is the I made of 1 or 3 sticks?
– Omega Krypton
1 hour ago












It is only 1 stick
– Marc
1 hour ago




It is only 1 stick
– Marc
1 hour ago












Please add the source of the puzzle
– Dr Xorile
1 hour ago




Please add the source of the puzzle
– Dr Xorile
1 hour ago












I don't have a source. It's a picture a friend showed me. And she made it a couple of days agoe in a mountain hut.
– Marc
1 hour ago




I don't have a source. It's a picture a friend showed me. And she made it a couple of days agoe in a mountain hut.
– Marc
1 hour ago










4 Answers
4






active

oldest

votes


















3















Move the right most I so that it forms a square root sign with the right most V. So it looks something like this: $VI=V+sqrt{1}$







share|improve this answer





















  • That is a nifty idea.
    – Marc
    1 hour ago



















2














Something like this:




VII = V | VII (because 7=5|7, using bitwise |)




or:




VI ≠ V + VI







share|improve this answer








New contributor




chau giang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.














  • 1




    Bitwise or is very clever. The ≠ trick doesn't work because you don't have a valid equation
    – Dr Xorile
    1 hour ago



















1














How about this?




From: the right stroke of the right most V
To: intersect with the I on the right.
Outcome: VI=V+IxI (take x as multiplication sign)







share|improve this answer










New contributor




ladynoirminou2546 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.


















  • These puzzles allow for some lateral thinking, but usually a slanted line cannot be a 1
    – Dr Xorile
    1 hour ago










  • I also though about something like that. But then the 1 is not really a 1.
    – Marc
    1 hour ago



















0














How about:




moving the second I in VII so it turns the equal sign equal to a less than or equal sign (VI is less than or equal to V + VI)







share|improve this answer

















  • 2




    Then you wouldn't have "a valid equation"!
    – Dr Xorile
    53 mins ago











Your Answer





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4 Answers
4






active

oldest

votes








4 Answers
4






active

oldest

votes









active

oldest

votes






active

oldest

votes









3















Move the right most I so that it forms a square root sign with the right most V. So it looks something like this: $VI=V+sqrt{1}$







share|improve this answer





















  • That is a nifty idea.
    – Marc
    1 hour ago
















3















Move the right most I so that it forms a square root sign with the right most V. So it looks something like this: $VI=V+sqrt{1}$







share|improve this answer





















  • That is a nifty idea.
    – Marc
    1 hour ago














3












3








3







Move the right most I so that it forms a square root sign with the right most V. So it looks something like this: $VI=V+sqrt{1}$







share|improve this answer













Move the right most I so that it forms a square root sign with the right most V. So it looks something like this: $VI=V+sqrt{1}$








share|improve this answer












share|improve this answer



share|improve this answer










answered 1 hour ago









Dr Xorile

11.4k12363




11.4k12363












  • That is a nifty idea.
    – Marc
    1 hour ago


















  • That is a nifty idea.
    – Marc
    1 hour ago
















That is a nifty idea.
– Marc
1 hour ago




That is a nifty idea.
– Marc
1 hour ago











2














Something like this:




VII = V | VII (because 7=5|7, using bitwise |)




or:




VI ≠ V + VI







share|improve this answer








New contributor




chau giang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.














  • 1




    Bitwise or is very clever. The ≠ trick doesn't work because you don't have a valid equation
    – Dr Xorile
    1 hour ago
















2














Something like this:




VII = V | VII (because 7=5|7, using bitwise |)




or:




VI ≠ V + VI







share|improve this answer








New contributor




chau giang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.














  • 1




    Bitwise or is very clever. The ≠ trick doesn't work because you don't have a valid equation
    – Dr Xorile
    1 hour ago














2












2








2






Something like this:




VII = V | VII (because 7=5|7, using bitwise |)




or:




VI ≠ V + VI







share|improve this answer








New contributor




chau giang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









Something like this:




VII = V | VII (because 7=5|7, using bitwise |)




or:




VI ≠ V + VI








share|improve this answer








New contributor




chau giang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this answer



share|improve this answer






New contributor




chau giang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









answered 1 hour ago









chau giang

211




211




New contributor




chau giang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





chau giang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






chau giang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 1




    Bitwise or is very clever. The ≠ trick doesn't work because you don't have a valid equation
    – Dr Xorile
    1 hour ago














  • 1




    Bitwise or is very clever. The ≠ trick doesn't work because you don't have a valid equation
    – Dr Xorile
    1 hour ago








1




1




Bitwise or is very clever. The ≠ trick doesn't work because you don't have a valid equation
– Dr Xorile
1 hour ago




Bitwise or is very clever. The ≠ trick doesn't work because you don't have a valid equation
– Dr Xorile
1 hour ago











1














How about this?




From: the right stroke of the right most V
To: intersect with the I on the right.
Outcome: VI=V+IxI (take x as multiplication sign)







share|improve this answer










New contributor




ladynoirminou2546 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.


















  • These puzzles allow for some lateral thinking, but usually a slanted line cannot be a 1
    – Dr Xorile
    1 hour ago










  • I also though about something like that. But then the 1 is not really a 1.
    – Marc
    1 hour ago
















1














How about this?




From: the right stroke of the right most V
To: intersect with the I on the right.
Outcome: VI=V+IxI (take x as multiplication sign)







share|improve this answer










New contributor




ladynoirminou2546 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.


















  • These puzzles allow for some lateral thinking, but usually a slanted line cannot be a 1
    – Dr Xorile
    1 hour ago










  • I also though about something like that. But then the 1 is not really a 1.
    – Marc
    1 hour ago














1












1








1






How about this?




From: the right stroke of the right most V
To: intersect with the I on the right.
Outcome: VI=V+IxI (take x as multiplication sign)







share|improve this answer










New contributor




ladynoirminou2546 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









How about this?




From: the right stroke of the right most V
To: intersect with the I on the right.
Outcome: VI=V+IxI (take x as multiplication sign)








share|improve this answer










New contributor




ladynoirminou2546 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this answer



share|improve this answer








edited 1 hour ago









Dr Xorile

11.4k12363




11.4k12363






New contributor




ladynoirminou2546 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









answered 1 hour ago









ladynoirminou2546

191




191




New contributor




ladynoirminou2546 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





ladynoirminou2546 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






ladynoirminou2546 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • These puzzles allow for some lateral thinking, but usually a slanted line cannot be a 1
    – Dr Xorile
    1 hour ago










  • I also though about something like that. But then the 1 is not really a 1.
    – Marc
    1 hour ago


















  • These puzzles allow for some lateral thinking, but usually a slanted line cannot be a 1
    – Dr Xorile
    1 hour ago










  • I also though about something like that. But then the 1 is not really a 1.
    – Marc
    1 hour ago
















These puzzles allow for some lateral thinking, but usually a slanted line cannot be a 1
– Dr Xorile
1 hour ago




These puzzles allow for some lateral thinking, but usually a slanted line cannot be a 1
– Dr Xorile
1 hour ago












I also though about something like that. But then the 1 is not really a 1.
– Marc
1 hour ago




I also though about something like that. But then the 1 is not really a 1.
– Marc
1 hour ago











0














How about:




moving the second I in VII so it turns the equal sign equal to a less than or equal sign (VI is less than or equal to V + VI)







share|improve this answer

















  • 2




    Then you wouldn't have "a valid equation"!
    – Dr Xorile
    53 mins ago
















0














How about:




moving the second I in VII so it turns the equal sign equal to a less than or equal sign (VI is less than or equal to V + VI)







share|improve this answer

















  • 2




    Then you wouldn't have "a valid equation"!
    – Dr Xorile
    53 mins ago














0












0








0






How about:




moving the second I in VII so it turns the equal sign equal to a less than or equal sign (VI is less than or equal to V + VI)







share|improve this answer












How about:




moving the second I in VII so it turns the equal sign equal to a less than or equal sign (VI is less than or equal to V + VI)








share|improve this answer












share|improve this answer



share|improve this answer










answered 1 hour ago









Excited Raichu

5,5782860




5,5782860








  • 2




    Then you wouldn't have "a valid equation"!
    – Dr Xorile
    53 mins ago














  • 2




    Then you wouldn't have "a valid equation"!
    – Dr Xorile
    53 mins ago








2




2




Then you wouldn't have "a valid equation"!
– Dr Xorile
53 mins ago




Then you wouldn't have "a valid equation"!
– Dr Xorile
53 mins ago










Marc is a new contributor. Be nice, and check out our Code of Conduct.










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Marc is a new contributor. Be nice, and check out our Code of Conduct.













Marc is a new contributor. Be nice, and check out our Code of Conduct.












Marc is a new contributor. Be nice, and check out our Code of Conduct.
















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