How many ways to fill in a square grid with certain restrictions












3














Suppose I have a 5x5 grid of squares. I would like to fill in 15 checkmarks in the squares such that (1) each of the 25 square cells contains at most one checkmark, (2) each row has exactly 3 checkmarks, and (3) each column has exactly 3 checkmarks. How many ways are there to fill in these 15 checkmarks?



More generally, suppose I have an $n times n $ square grid, and I would like to fill in $mn$ checkmarks such that (1) each of the $n^2$ square cells contains at most one checkmark, (2) each row has exactly m checkmarks, and (3) each column has exactly m checkmarks. How many ways are there to do so? If $m=1,$ I think the answer is $n!$. But I am not sure about the general case.



Also, if I have an additional restriction that no checkmarks on the diagonal, i.e., no checkmark in the (1,1), (2,2),... (n,n) cells. How many ways are there?



Thanks very much! Wish all very happy new year!










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  • If you remove the only one checkmark per box requirement then you are looking at the Ehrhart polynomial of the Birkhoff polytope, and get into the Anand-Dumir-Gupta conjecture and related areas.
    – Sam Hopkins
    48 mins ago
















3














Suppose I have a 5x5 grid of squares. I would like to fill in 15 checkmarks in the squares such that (1) each of the 25 square cells contains at most one checkmark, (2) each row has exactly 3 checkmarks, and (3) each column has exactly 3 checkmarks. How many ways are there to fill in these 15 checkmarks?



More generally, suppose I have an $n times n $ square grid, and I would like to fill in $mn$ checkmarks such that (1) each of the $n^2$ square cells contains at most one checkmark, (2) each row has exactly m checkmarks, and (3) each column has exactly m checkmarks. How many ways are there to do so? If $m=1,$ I think the answer is $n!$. But I am not sure about the general case.



Also, if I have an additional restriction that no checkmarks on the diagonal, i.e., no checkmark in the (1,1), (2,2),... (n,n) cells. How many ways are there?



Thanks very much! Wish all very happy new year!










share|cite|improve this question






















  • If you remove the only one checkmark per box requirement then you are looking at the Ehrhart polynomial of the Birkhoff polytope, and get into the Anand-Dumir-Gupta conjecture and related areas.
    – Sam Hopkins
    48 mins ago














3












3








3







Suppose I have a 5x5 grid of squares. I would like to fill in 15 checkmarks in the squares such that (1) each of the 25 square cells contains at most one checkmark, (2) each row has exactly 3 checkmarks, and (3) each column has exactly 3 checkmarks. How many ways are there to fill in these 15 checkmarks?



More generally, suppose I have an $n times n $ square grid, and I would like to fill in $mn$ checkmarks such that (1) each of the $n^2$ square cells contains at most one checkmark, (2) each row has exactly m checkmarks, and (3) each column has exactly m checkmarks. How many ways are there to do so? If $m=1,$ I think the answer is $n!$. But I am not sure about the general case.



Also, if I have an additional restriction that no checkmarks on the diagonal, i.e., no checkmark in the (1,1), (2,2),... (n,n) cells. How many ways are there?



Thanks very much! Wish all very happy new year!










share|cite|improve this question













Suppose I have a 5x5 grid of squares. I would like to fill in 15 checkmarks in the squares such that (1) each of the 25 square cells contains at most one checkmark, (2) each row has exactly 3 checkmarks, and (3) each column has exactly 3 checkmarks. How many ways are there to fill in these 15 checkmarks?



More generally, suppose I have an $n times n $ square grid, and I would like to fill in $mn$ checkmarks such that (1) each of the $n^2$ square cells contains at most one checkmark, (2) each row has exactly m checkmarks, and (3) each column has exactly m checkmarks. How many ways are there to do so? If $m=1,$ I think the answer is $n!$. But I am not sure about the general case.



Also, if I have an additional restriction that no checkmarks on the diagonal, i.e., no checkmark in the (1,1), (2,2),... (n,n) cells. How many ways are there?



Thanks very much! Wish all very happy new year!







co.combinatorics






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asked 3 hours ago









KPU

513




513












  • If you remove the only one checkmark per box requirement then you are looking at the Ehrhart polynomial of the Birkhoff polytope, and get into the Anand-Dumir-Gupta conjecture and related areas.
    – Sam Hopkins
    48 mins ago


















  • If you remove the only one checkmark per box requirement then you are looking at the Ehrhart polynomial of the Birkhoff polytope, and get into the Anand-Dumir-Gupta conjecture and related areas.
    – Sam Hopkins
    48 mins ago
















If you remove the only one checkmark per box requirement then you are looking at the Ehrhart polynomial of the Birkhoff polytope, and get into the Anand-Dumir-Gupta conjecture and related areas.
– Sam Hopkins
48 mins ago




If you remove the only one checkmark per box requirement then you are looking at the Ehrhart polynomial of the Birkhoff polytope, and get into the Anand-Dumir-Gupta conjecture and related areas.
– Sam Hopkins
48 mins ago










2 Answers
2






active

oldest

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4














What you are looking for is the number of matrices in the class $mathcal A(n,m)$ of $(0,1)$-matrices that are $ntimes n$ and have each row and column containing exactly $m$ entries equal to $1$. This is a pretty well-studied question, but an exact answer isn't known except in some small cases.



You are right that for $m=1$, the number is $n!$, as then you are counting the $ntimes n$ permutation matrices. A sort of generalization of this was obtained in




Wei, Wan-Di. "The class $mathfrak A(R,S)$ of $(0,1)$-matrices." Discrete Mathematics 39, no. 3 (1982): 301–305. Journal link




where it is given that the number of such matrices is at least



$$frac{(n!)^m}{(m!)^n}.$$



I say it is “sort of” a generalization because it is only a lower bound. Again, there is no closed form known for the exact number. I think the most frequently-cited asymptotic results are those of McKay and others, for example see




McKay, Brendan D., Wang, Xiaoji. "Asymptotic enumeration of 0-1 matrices with equal row sums and equal column sums." Linear Algebra and its Applications. 373 (2003): 273–287. Journal link




and anything that cites it.



There are other results – and other asymptotic results – out there. A good starting point for more details is the book Combinatorial Matrix Classes by Brualdi.



Finally, note that this is the same as counting balanced regular bipartite graphs. For example, your question is the same as this one where the $d_v$ and $d_c$ of that question are taken to be equal. So you may wish to see the answer – provided by McKay! – appearing there.






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    0














    The problem amounts to counting binary or $0/1$-matrices with restrictions on row/column sums.



    In general, let the row sums be $r(n)=(r_1,dots,r_n)$ and column sums $c(n)=(c_1,dots,c_n)$. Obviously, $0leq r_i, c_jleq n$ for all $i, j$. Further, let $mathbf{x}=(x_1,dots,x_n)$ and $mathbf{y}=(y_1,dots,y_n)$ with the multi-exponent notation $mathbf{x}^{u}=x_1^{u_1}cdots x_n^{u_n}$. Then, there is this generating function
    $$prod_{i,j=1}^n(1+x_iy_j)=sum_{r(n),c(n)} N(r(n),c(n))mathbf{x}^{r(n)}mathbf{y}^{c(n)} tag1$$
    for the enumeration $N(r(n),c(n))$ of the number of binary matrices with row sums $r(n)$ and $c(n)$.



    To get back to your question, extract the coefficient $N((k,dots,k),(k,dots,k))$ of
    $$mathbf{x}^{(k,dots,k)}mathbf{y}^{(k,dots,k)}$$
    from the above product in (1).






    share|cite|improve this answer























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      2 Answers
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      2 Answers
      2






      active

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      active

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      active

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      4














      What you are looking for is the number of matrices in the class $mathcal A(n,m)$ of $(0,1)$-matrices that are $ntimes n$ and have each row and column containing exactly $m$ entries equal to $1$. This is a pretty well-studied question, but an exact answer isn't known except in some small cases.



      You are right that for $m=1$, the number is $n!$, as then you are counting the $ntimes n$ permutation matrices. A sort of generalization of this was obtained in




      Wei, Wan-Di. "The class $mathfrak A(R,S)$ of $(0,1)$-matrices." Discrete Mathematics 39, no. 3 (1982): 301–305. Journal link




      where it is given that the number of such matrices is at least



      $$frac{(n!)^m}{(m!)^n}.$$



      I say it is “sort of” a generalization because it is only a lower bound. Again, there is no closed form known for the exact number. I think the most frequently-cited asymptotic results are those of McKay and others, for example see




      McKay, Brendan D., Wang, Xiaoji. "Asymptotic enumeration of 0-1 matrices with equal row sums and equal column sums." Linear Algebra and its Applications. 373 (2003): 273–287. Journal link




      and anything that cites it.



      There are other results – and other asymptotic results – out there. A good starting point for more details is the book Combinatorial Matrix Classes by Brualdi.



      Finally, note that this is the same as counting balanced regular bipartite graphs. For example, your question is the same as this one where the $d_v$ and $d_c$ of that question are taken to be equal. So you may wish to see the answer – provided by McKay! – appearing there.






      share|cite|improve this answer


























        4














        What you are looking for is the number of matrices in the class $mathcal A(n,m)$ of $(0,1)$-matrices that are $ntimes n$ and have each row and column containing exactly $m$ entries equal to $1$. This is a pretty well-studied question, but an exact answer isn't known except in some small cases.



        You are right that for $m=1$, the number is $n!$, as then you are counting the $ntimes n$ permutation matrices. A sort of generalization of this was obtained in




        Wei, Wan-Di. "The class $mathfrak A(R,S)$ of $(0,1)$-matrices." Discrete Mathematics 39, no. 3 (1982): 301–305. Journal link




        where it is given that the number of such matrices is at least



        $$frac{(n!)^m}{(m!)^n}.$$



        I say it is “sort of” a generalization because it is only a lower bound. Again, there is no closed form known for the exact number. I think the most frequently-cited asymptotic results are those of McKay and others, for example see




        McKay, Brendan D., Wang, Xiaoji. "Asymptotic enumeration of 0-1 matrices with equal row sums and equal column sums." Linear Algebra and its Applications. 373 (2003): 273–287. Journal link




        and anything that cites it.



        There are other results – and other asymptotic results – out there. A good starting point for more details is the book Combinatorial Matrix Classes by Brualdi.



        Finally, note that this is the same as counting balanced regular bipartite graphs. For example, your question is the same as this one where the $d_v$ and $d_c$ of that question are taken to be equal. So you may wish to see the answer – provided by McKay! – appearing there.






        share|cite|improve this answer
























          4












          4








          4






          What you are looking for is the number of matrices in the class $mathcal A(n,m)$ of $(0,1)$-matrices that are $ntimes n$ and have each row and column containing exactly $m$ entries equal to $1$. This is a pretty well-studied question, but an exact answer isn't known except in some small cases.



          You are right that for $m=1$, the number is $n!$, as then you are counting the $ntimes n$ permutation matrices. A sort of generalization of this was obtained in




          Wei, Wan-Di. "The class $mathfrak A(R,S)$ of $(0,1)$-matrices." Discrete Mathematics 39, no. 3 (1982): 301–305. Journal link




          where it is given that the number of such matrices is at least



          $$frac{(n!)^m}{(m!)^n}.$$



          I say it is “sort of” a generalization because it is only a lower bound. Again, there is no closed form known for the exact number. I think the most frequently-cited asymptotic results are those of McKay and others, for example see




          McKay, Brendan D., Wang, Xiaoji. "Asymptotic enumeration of 0-1 matrices with equal row sums and equal column sums." Linear Algebra and its Applications. 373 (2003): 273–287. Journal link




          and anything that cites it.



          There are other results – and other asymptotic results – out there. A good starting point for more details is the book Combinatorial Matrix Classes by Brualdi.



          Finally, note that this is the same as counting balanced regular bipartite graphs. For example, your question is the same as this one where the $d_v$ and $d_c$ of that question are taken to be equal. So you may wish to see the answer – provided by McKay! – appearing there.






          share|cite|improve this answer












          What you are looking for is the number of matrices in the class $mathcal A(n,m)$ of $(0,1)$-matrices that are $ntimes n$ and have each row and column containing exactly $m$ entries equal to $1$. This is a pretty well-studied question, but an exact answer isn't known except in some small cases.



          You are right that for $m=1$, the number is $n!$, as then you are counting the $ntimes n$ permutation matrices. A sort of generalization of this was obtained in




          Wei, Wan-Di. "The class $mathfrak A(R,S)$ of $(0,1)$-matrices." Discrete Mathematics 39, no. 3 (1982): 301–305. Journal link




          where it is given that the number of such matrices is at least



          $$frac{(n!)^m}{(m!)^n}.$$



          I say it is “sort of” a generalization because it is only a lower bound. Again, there is no closed form known for the exact number. I think the most frequently-cited asymptotic results are those of McKay and others, for example see




          McKay, Brendan D., Wang, Xiaoji. "Asymptotic enumeration of 0-1 matrices with equal row sums and equal column sums." Linear Algebra and its Applications. 373 (2003): 273–287. Journal link




          and anything that cites it.



          There are other results – and other asymptotic results – out there. A good starting point for more details is the book Combinatorial Matrix Classes by Brualdi.



          Finally, note that this is the same as counting balanced regular bipartite graphs. For example, your question is the same as this one where the $d_v$ and $d_c$ of that question are taken to be equal. So you may wish to see the answer – provided by McKay! – appearing there.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered 1 hour ago









          Louis Deaett

          7451618




          7451618























              0














              The problem amounts to counting binary or $0/1$-matrices with restrictions on row/column sums.



              In general, let the row sums be $r(n)=(r_1,dots,r_n)$ and column sums $c(n)=(c_1,dots,c_n)$. Obviously, $0leq r_i, c_jleq n$ for all $i, j$. Further, let $mathbf{x}=(x_1,dots,x_n)$ and $mathbf{y}=(y_1,dots,y_n)$ with the multi-exponent notation $mathbf{x}^{u}=x_1^{u_1}cdots x_n^{u_n}$. Then, there is this generating function
              $$prod_{i,j=1}^n(1+x_iy_j)=sum_{r(n),c(n)} N(r(n),c(n))mathbf{x}^{r(n)}mathbf{y}^{c(n)} tag1$$
              for the enumeration $N(r(n),c(n))$ of the number of binary matrices with row sums $r(n)$ and $c(n)$.



              To get back to your question, extract the coefficient $N((k,dots,k),(k,dots,k))$ of
              $$mathbf{x}^{(k,dots,k)}mathbf{y}^{(k,dots,k)}$$
              from the above product in (1).






              share|cite|improve this answer




























                0














                The problem amounts to counting binary or $0/1$-matrices with restrictions on row/column sums.



                In general, let the row sums be $r(n)=(r_1,dots,r_n)$ and column sums $c(n)=(c_1,dots,c_n)$. Obviously, $0leq r_i, c_jleq n$ for all $i, j$. Further, let $mathbf{x}=(x_1,dots,x_n)$ and $mathbf{y}=(y_1,dots,y_n)$ with the multi-exponent notation $mathbf{x}^{u}=x_1^{u_1}cdots x_n^{u_n}$. Then, there is this generating function
                $$prod_{i,j=1}^n(1+x_iy_j)=sum_{r(n),c(n)} N(r(n),c(n))mathbf{x}^{r(n)}mathbf{y}^{c(n)} tag1$$
                for the enumeration $N(r(n),c(n))$ of the number of binary matrices with row sums $r(n)$ and $c(n)$.



                To get back to your question, extract the coefficient $N((k,dots,k),(k,dots,k))$ of
                $$mathbf{x}^{(k,dots,k)}mathbf{y}^{(k,dots,k)}$$
                from the above product in (1).






                share|cite|improve this answer


























                  0












                  0








                  0






                  The problem amounts to counting binary or $0/1$-matrices with restrictions on row/column sums.



                  In general, let the row sums be $r(n)=(r_1,dots,r_n)$ and column sums $c(n)=(c_1,dots,c_n)$. Obviously, $0leq r_i, c_jleq n$ for all $i, j$. Further, let $mathbf{x}=(x_1,dots,x_n)$ and $mathbf{y}=(y_1,dots,y_n)$ with the multi-exponent notation $mathbf{x}^{u}=x_1^{u_1}cdots x_n^{u_n}$. Then, there is this generating function
                  $$prod_{i,j=1}^n(1+x_iy_j)=sum_{r(n),c(n)} N(r(n),c(n))mathbf{x}^{r(n)}mathbf{y}^{c(n)} tag1$$
                  for the enumeration $N(r(n),c(n))$ of the number of binary matrices with row sums $r(n)$ and $c(n)$.



                  To get back to your question, extract the coefficient $N((k,dots,k),(k,dots,k))$ of
                  $$mathbf{x}^{(k,dots,k)}mathbf{y}^{(k,dots,k)}$$
                  from the above product in (1).






                  share|cite|improve this answer














                  The problem amounts to counting binary or $0/1$-matrices with restrictions on row/column sums.



                  In general, let the row sums be $r(n)=(r_1,dots,r_n)$ and column sums $c(n)=(c_1,dots,c_n)$. Obviously, $0leq r_i, c_jleq n$ for all $i, j$. Further, let $mathbf{x}=(x_1,dots,x_n)$ and $mathbf{y}=(y_1,dots,y_n)$ with the multi-exponent notation $mathbf{x}^{u}=x_1^{u_1}cdots x_n^{u_n}$. Then, there is this generating function
                  $$prod_{i,j=1}^n(1+x_iy_j)=sum_{r(n),c(n)} N(r(n),c(n))mathbf{x}^{r(n)}mathbf{y}^{c(n)} tag1$$
                  for the enumeration $N(r(n),c(n))$ of the number of binary matrices with row sums $r(n)$ and $c(n)$.



                  To get back to your question, extract the coefficient $N((k,dots,k),(k,dots,k))$ of
                  $$mathbf{x}^{(k,dots,k)}mathbf{y}^{(k,dots,k)}$$
                  from the above product in (1).







                  share|cite|improve this answer














                  share|cite|improve this answer



                  share|cite|improve this answer








                  edited 1 hour ago

























                  answered 2 hours ago









                  T. Amdeberhan

                  17.1k228126




                  17.1k228126






























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