How to create table with 2D function values?
$begingroup$
Consider some function f[x,y]. I want to create a table in the form
table = {{x1,y1,f[x1,y1]},{x1,y2,f[x1,y2]},...,{x2,y1,f[x2,y1]},{x2,y2,f[x2,y2]},...},
where $x_{i},x_{i+1}$ and $y_{i},y_{i+1}$ are separated by some distances $Delta x$, $Delta y$, and i ranges from 1 to some N.
The only way I know is to manually create a table
table=Join[Table[{x1,y,f[x1,y]},{y,y1,yN,Deltay}],Table[{x2,y,f[x2,y]},{y,y1,yN,Deltay}],...]
However, this is not a smart way, especially for large N. Could you please provide some smarter way to build the table?
table
asked Mar 22 at 14:23
John TaylorJohn Taylor
766211
$endgroup$
add a comment |
$begingroup$
Consider some function f[x,y]. I want to create a table in the form
table = {{x1,y1,f[x1,y1]},{x1,y2,f[x1,y2]},...,{x2,y1,f[x2,y1]},{x2,y2,f[x2,y2]},...},
where $x_{i},x_{i+1}$ and $y_{i},y_{i+1}$ are separated by some distances $Delta x$, $Delta y$, and i ranges from 1 to some N.
The only way I know is to manually create a table
table=Join[Table[{x1,y,f[x1,y]},{y,y1,yN,Deltay}],Table[{x2,y,f[x2,y]},{y,y1,yN,Deltay}],...]
However, this is not a smart way, especially for large N. Could you please provide some smarter way to build the table?
table
asked Mar 22 at 14:23
John TaylorJohn Taylor
766211
$endgroup$
1
$begingroup$
Have a look at Menu/Help/WolframDocumentation/Table. That's what will help you.
$endgroup$
– Alexei Boulbitch
Mar 22 at 14:32
add a comment |
$begingroup$
Consider some function f[x,y]. I want to create a table in the form
table = {{x1,y1,f[x1,y1]},{x1,y2,f[x1,y2]},...,{x2,y1,f[x2,y1]},{x2,y2,f[x2,y2]},...},
where $x_{i},x_{i+1}$ and $y_{i},y_{i+1}$ are separated by some distances $Delta x$, $Delta y$, and i ranges from 1 to some N.
The only way I know is to manually create a table
table=Join[Table[{x1,y,f[x1,y]},{y,y1,yN,Deltay}],Table[{x2,y,f[x2,y]},{y,y1,yN,Deltay}],...]
However, this is not a smart way, especially for large N. Could you please provide some smarter way to build the table?
table
asked Mar 22 at 14:23
John TaylorJohn Taylor
766211
$endgroup$
Consider some function f[x,y]. I want to create a table in the form
table = {{x1,y1,f[x1,y1]},{x1,y2,f[x1,y2]},...,{x2,y1,f[x2,y1]},{x2,y2,f[x2,y2]},...},
where $x_{i},x_{i+1}$ and $y_{i},y_{i+1}$ are separated by some distances $Delta x$, $Delta y$, and i ranges from 1 to some N.
The only way I know is to manually create a table
table=Join[Table[{x1,y,f[x1,y]},{y,y1,yN,Deltay}],Table[{x2,y,f[x2,y]},{y,y1,yN,Deltay}],...]
However, this is not a smart way, especially for large N. Could you please provide some smarter way to build the table?
table
table
asked Mar 22 at 14:23
John TaylorJohn Taylor
766211
asked Mar 22 at 14:23
John TaylorJohn Taylor
766211
asked Mar 22 at 14:23
John TaylorJohn Taylor
766211
asked Mar 22 at 14:23
John TaylorJohn Taylor
766211
asked Mar 22 at 14:23
John TaylorJohn Taylor
766211
766211
1
$begingroup$
Have a look at Menu/Help/WolframDocumentation/Table. That's what will help you.
$endgroup$
– Alexei Boulbitch
Mar 22 at 14:32
add a comment |
1
$begingroup$
Have a look at Menu/Help/WolframDocumentation/Table. That's what will help you.
$endgroup$
– Alexei Boulbitch
Mar 22 at 14:32
1
1
$begingroup$
Have a look at Menu/Help/WolframDocumentation/Table. That's what will help you.
$endgroup$
– Alexei Boulbitch
Mar 22 at 14:32
$begingroup$
Have a look at Menu/Help/WolframDocumentation/Table. That's what will help you.
$endgroup$
– Alexei Boulbitch
Mar 22 at 14:32
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
x1 = 1; xN = 9; Δx = 3;
y1 = 0; yN = 5; Δy = 1;
table = Join @@ Table[{i, j, f[i, j]}, {i, x1, xN, Δx}, {j, y1, yN, Δy}]
{{1, 0, f[1, 0]}, {1, 1, f[1, 1]}, {1, 2, f[1, 2]}, {1, 3,
f[1, 3]}, {1, 4, f[1, 4]}, {1, 5, f[1, 5]},
{4, 0, f[4, 0]}, {4, 1,
f[4, 1]}, {4, 2, f[4, 2]}, {4, 3, f[4, 3]}, {4, 4, f[4, 4]}, {4, 5,
f[4, 5]},
{7, 0, f[7, 0]}, {7, 1, f[7, 1]}, {7, 2, f[7, 2]}, {7, 3,
f[7, 3]}, {7, 4, f[7, 4]}, {7, 5, f[7, 5]}}
Also
table2 = {##, f @ ##} & @@@ Tuples[{Range[x1, xN, Δx], Range[y1, yN, Δy]}]
table2 == table
True
answered Mar 22 at 14:30
kglrkglr
189k10206424
$endgroup$
add a comment |
$begingroup$
This would be a nice answer (using the Outer product to create the 2D array):
x1 = 1; xN = 9; dx = 3;
y1 = 0; yN = 5; dy = 1;
Partition[Flatten[
Outer[Through[{List, f}[#1, #2]] &, Range[x1, xN, dx], Range[y1, yN, dy]]], 3]
except that Outer returns too many levels -- hence the Flatten and Partition are needed to remove the extra brackets. Answer is the same as kglr's.
answered Mar 22 at 16:06
bill sbill s
54.7k377157
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
x1 = 1; xN = 9; Δx = 3;
y1 = 0; yN = 5; Δy = 1;
table = Join @@ Table[{i, j, f[i, j]}, {i, x1, xN, Δx}, {j, y1, yN, Δy}]
{{1, 0, f[1, 0]}, {1, 1, f[1, 1]}, {1, 2, f[1, 2]}, {1, 3,
f[1, 3]}, {1, 4, f[1, 4]}, {1, 5, f[1, 5]},
{4, 0, f[4, 0]}, {4, 1,
f[4, 1]}, {4, 2, f[4, 2]}, {4, 3, f[4, 3]}, {4, 4, f[4, 4]}, {4, 5,
f[4, 5]},
{7, 0, f[7, 0]}, {7, 1, f[7, 1]}, {7, 2, f[7, 2]}, {7, 3,
f[7, 3]}, {7, 4, f[7, 4]}, {7, 5, f[7, 5]}}
Also
table2 = {##, f @ ##} & @@@ Tuples[{Range[x1, xN, Δx], Range[y1, yN, Δy]}]
table2 == table
True
answered Mar 22 at 14:30
kglrkglr
189k10206424
$endgroup$
add a comment |
$begingroup$
x1 = 1; xN = 9; Δx = 3;
y1 = 0; yN = 5; Δy = 1;
table = Join @@ Table[{i, j, f[i, j]}, {i, x1, xN, Δx}, {j, y1, yN, Δy}]
{{1, 0, f[1, 0]}, {1, 1, f[1, 1]}, {1, 2, f[1, 2]}, {1, 3,
f[1, 3]}, {1, 4, f[1, 4]}, {1, 5, f[1, 5]},
{4, 0, f[4, 0]}, {4, 1,
f[4, 1]}, {4, 2, f[4, 2]}, {4, 3, f[4, 3]}, {4, 4, f[4, 4]}, {4, 5,
f[4, 5]},
{7, 0, f[7, 0]}, {7, 1, f[7, 1]}, {7, 2, f[7, 2]}, {7, 3,
f[7, 3]}, {7, 4, f[7, 4]}, {7, 5, f[7, 5]}}
Also
table2 = {##, f @ ##} & @@@ Tuples[{Range[x1, xN, Δx], Range[y1, yN, Δy]}]
table2 == table
True
answered Mar 22 at 14:30
kglrkglr
189k10206424
$endgroup$
add a comment |
$begingroup$
x1 = 1; xN = 9; Δx = 3;
y1 = 0; yN = 5; Δy = 1;
table = Join @@ Table[{i, j, f[i, j]}, {i, x1, xN, Δx}, {j, y1, yN, Δy}]
{{1, 0, f[1, 0]}, {1, 1, f[1, 1]}, {1, 2, f[1, 2]}, {1, 3,
f[1, 3]}, {1, 4, f[1, 4]}, {1, 5, f[1, 5]},
{4, 0, f[4, 0]}, {4, 1,
f[4, 1]}, {4, 2, f[4, 2]}, {4, 3, f[4, 3]}, {4, 4, f[4, 4]}, {4, 5,
f[4, 5]},
{7, 0, f[7, 0]}, {7, 1, f[7, 1]}, {7, 2, f[7, 2]}, {7, 3,
f[7, 3]}, {7, 4, f[7, 4]}, {7, 5, f[7, 5]}}
Also
table2 = {##, f @ ##} & @@@ Tuples[{Range[x1, xN, Δx], Range[y1, yN, Δy]}]
table2 == table
True
answered Mar 22 at 14:30
kglrkglr
189k10206424
$endgroup$
x1 = 1; xN = 9; Δx = 3;
y1 = 0; yN = 5; Δy = 1;
table = Join @@ Table[{i, j, f[i, j]}, {i, x1, xN, Δx}, {j, y1, yN, Δy}]
{{1, 0, f[1, 0]}, {1, 1, f[1, 1]}, {1, 2, f[1, 2]}, {1, 3,
f[1, 3]}, {1, 4, f[1, 4]}, {1, 5, f[1, 5]},
{4, 0, f[4, 0]}, {4, 1,
f[4, 1]}, {4, 2, f[4, 2]}, {4, 3, f[4, 3]}, {4, 4, f[4, 4]}, {4, 5,
f[4, 5]},
{7, 0, f[7, 0]}, {7, 1, f[7, 1]}, {7, 2, f[7, 2]}, {7, 3,
f[7, 3]}, {7, 4, f[7, 4]}, {7, 5, f[7, 5]}}
Also
table2 = {##, f @ ##} & @@@ Tuples[{Range[x1, xN, Δx], Range[y1, yN, Δy]}]
table2 == table
True
answered Mar 22 at 14:30
kglrkglr
189k10206424
edited Mar 22 at 14:36
answered Mar 22 at 14:30
kglrkglr
189k10206424
answered Mar 22 at 14:30
kglrkglr
189k10206424
answered Mar 22 at 14:30
kglrkglr
189k10206424
189k10206424
add a comment |
add a comment |
$begingroup$
This would be a nice answer (using the Outer product to create the 2D array):
x1 = 1; xN = 9; dx = 3;
y1 = 0; yN = 5; dy = 1;
Partition[Flatten[
Outer[Through[{List, f}[#1, #2]] &, Range[x1, xN, dx], Range[y1, yN, dy]]], 3]
except that Outer returns too many levels -- hence the Flatten and Partition are needed to remove the extra brackets. Answer is the same as kglr's.
answered Mar 22 at 16:06
bill sbill s
54.7k377157
$endgroup$
add a comment |
$begingroup$
This would be a nice answer (using the Outer product to create the 2D array):
x1 = 1; xN = 9; dx = 3;
y1 = 0; yN = 5; dy = 1;
Partition[Flatten[
Outer[Through[{List, f}[#1, #2]] &, Range[x1, xN, dx], Range[y1, yN, dy]]], 3]
except that Outer returns too many levels -- hence the Flatten and Partition are needed to remove the extra brackets. Answer is the same as kglr's.
answered Mar 22 at 16:06
bill sbill s
54.7k377157
$endgroup$
add a comment |
$begingroup$
This would be a nice answer (using the Outer product to create the 2D array):
x1 = 1; xN = 9; dx = 3;
y1 = 0; yN = 5; dy = 1;
Partition[Flatten[
Outer[Through[{List, f}[#1, #2]] &, Range[x1, xN, dx], Range[y1, yN, dy]]], 3]
except that Outer returns too many levels -- hence the Flatten and Partition are needed to remove the extra brackets. Answer is the same as kglr's.
answered Mar 22 at 16:06
bill sbill s
54.7k377157
$endgroup$
This would be a nice answer (using the Outer product to create the 2D array):
x1 = 1; xN = 9; dx = 3;
y1 = 0; yN = 5; dy = 1;
Partition[Flatten[
Outer[Through[{List, f}[#1, #2]] &, Range[x1, xN, dx], Range[y1, yN, dy]]], 3]
except that Outer returns too many levels -- hence the Flatten and Partition are needed to remove the extra brackets. Answer is the same as kglr's.
answered Mar 22 at 16:06
bill sbill s
54.7k377157
answered Mar 22 at 16:06
bill sbill s
54.7k377157
answered Mar 22 at 16:06
bill sbill s
54.7k377157
answered Mar 22 at 16:06
bill sbill s
54.7k377157
54.7k377157
add a comment |
add a comment |
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$begingroup$
Have a look at Menu/Help/WolframDocumentation/Table. That's what will help you.
$endgroup$
– Alexei Boulbitch
Mar 22 at 14:32