Which of the following probabilities CANNOT be found using the binomial distribution?












0












$begingroup$




  1. The probability that 3 out of 8 tosses of a coin will result in
    heads


2.The probability of getting exactly five face cards when
drawing five cards from a standard deck of 52 cards without
replacement



(3) When randomly choosing a family with four children,
the probability that it will have exactly two boys and two girls as
children, if having a boy or a girl is equally likely



(4) The
probability that a student randomly guessing will get at least 8 out
of 10 multiple-choice questions correct (assuming every question has
five choices)




To me, all of these scenarios seem like I can apply the binomial distribution formula except for (2) . I believe I can use it on (1) and (3) and (4). For (2) though, the probabilities will change due to no replacement. I think this breaks the formula. Is this correct?










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    0












    $begingroup$




    1. The probability that 3 out of 8 tosses of a coin will result in
      heads


    2.The probability of getting exactly five face cards when
    drawing five cards from a standard deck of 52 cards without
    replacement



    (3) When randomly choosing a family with four children,
    the probability that it will have exactly two boys and two girls as
    children, if having a boy or a girl is equally likely



    (4) The
    probability that a student randomly guessing will get at least 8 out
    of 10 multiple-choice questions correct (assuming every question has
    five choices)




    To me, all of these scenarios seem like I can apply the binomial distribution formula except for (2) . I believe I can use it on (1) and (3) and (4). For (2) though, the probabilities will change due to no replacement. I think this breaks the formula. Is this correct?










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$




      1. The probability that 3 out of 8 tosses of a coin will result in
        heads


      2.The probability of getting exactly five face cards when
      drawing five cards from a standard deck of 52 cards without
      replacement



      (3) When randomly choosing a family with four children,
      the probability that it will have exactly two boys and two girls as
      children, if having a boy or a girl is equally likely



      (4) The
      probability that a student randomly guessing will get at least 8 out
      of 10 multiple-choice questions correct (assuming every question has
      five choices)




      To me, all of these scenarios seem like I can apply the binomial distribution formula except for (2) . I believe I can use it on (1) and (3) and (4). For (2) though, the probabilities will change due to no replacement. I think this breaks the formula. Is this correct?










      share|cite|improve this question









      $endgroup$






      1. The probability that 3 out of 8 tosses of a coin will result in
        heads


      2.The probability of getting exactly five face cards when
      drawing five cards from a standard deck of 52 cards without
      replacement



      (3) When randomly choosing a family with four children,
      the probability that it will have exactly two boys and two girls as
      children, if having a boy or a girl is equally likely



      (4) The
      probability that a student randomly guessing will get at least 8 out
      of 10 multiple-choice questions correct (assuming every question has
      five choices)




      To me, all of these scenarios seem like I can apply the binomial distribution formula except for (2) . I believe I can use it on (1) and (3) and (4). For (2) though, the probabilities will change due to no replacement. I think this breaks the formula. Is this correct?







      probability






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      asked Dec 17 '18 at 18:46









      NaltNalt

      776




      776






















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          $begingroup$

          Yep. All but 2 (because of no replacement). Use hypergeometric distribution for that!






          share|cite|improve this answer









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          • $begingroup$
            Thank you Mr. Stork! Doubt is an annoying thing
            $endgroup$
            – Nalt
            Dec 17 '18 at 18:51






          • 1




            $begingroup$
            Doubt is essential for learning and understanding!
            $endgroup$
            – David G. Stork
            Dec 17 '18 at 18:53











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          1 Answer
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          1 Answer
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          active

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          1












          $begingroup$

          Yep. All but 2 (because of no replacement). Use hypergeometric distribution for that!






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thank you Mr. Stork! Doubt is an annoying thing
            $endgroup$
            – Nalt
            Dec 17 '18 at 18:51






          • 1




            $begingroup$
            Doubt is essential for learning and understanding!
            $endgroup$
            – David G. Stork
            Dec 17 '18 at 18:53
















          1












          $begingroup$

          Yep. All but 2 (because of no replacement). Use hypergeometric distribution for that!






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thank you Mr. Stork! Doubt is an annoying thing
            $endgroup$
            – Nalt
            Dec 17 '18 at 18:51






          • 1




            $begingroup$
            Doubt is essential for learning and understanding!
            $endgroup$
            – David G. Stork
            Dec 17 '18 at 18:53














          1












          1








          1





          $begingroup$

          Yep. All but 2 (because of no replacement). Use hypergeometric distribution for that!






          share|cite|improve this answer









          $endgroup$



          Yep. All but 2 (because of no replacement). Use hypergeometric distribution for that!







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Dec 17 '18 at 18:49









          David G. StorkDavid G. Stork

          11.1k41432




          11.1k41432












          • $begingroup$
            Thank you Mr. Stork! Doubt is an annoying thing
            $endgroup$
            – Nalt
            Dec 17 '18 at 18:51






          • 1




            $begingroup$
            Doubt is essential for learning and understanding!
            $endgroup$
            – David G. Stork
            Dec 17 '18 at 18:53


















          • $begingroup$
            Thank you Mr. Stork! Doubt is an annoying thing
            $endgroup$
            – Nalt
            Dec 17 '18 at 18:51






          • 1




            $begingroup$
            Doubt is essential for learning and understanding!
            $endgroup$
            – David G. Stork
            Dec 17 '18 at 18:53
















          $begingroup$
          Thank you Mr. Stork! Doubt is an annoying thing
          $endgroup$
          – Nalt
          Dec 17 '18 at 18:51




          $begingroup$
          Thank you Mr. Stork! Doubt is an annoying thing
          $endgroup$
          – Nalt
          Dec 17 '18 at 18:51




          1




          1




          $begingroup$
          Doubt is essential for learning and understanding!
          $endgroup$
          – David G. Stork
          Dec 17 '18 at 18:53




          $begingroup$
          Doubt is essential for learning and understanding!
          $endgroup$
          – David G. Stork
          Dec 17 '18 at 18:53


















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