Which of the following probabilities CANNOT be found using the binomial distribution?
$begingroup$
- The probability that 3 out of 8 tosses of a coin will result in
heads
2.The probability of getting exactly five face cards when
drawing five cards from a standard deck of 52 cards without
replacement
(3) When randomly choosing a family with four children,
the probability that it will have exactly two boys and two girls as
children, if having a boy or a girl is equally likely
(4) The
probability that a student randomly guessing will get at least 8 out
of 10 multiple-choice questions correct (assuming every question has
five choices)
To me, all of these scenarios seem like I can apply the binomial distribution formula except for (2) . I believe I can use it on (1) and (3) and (4). For (2) though, the probabilities will change due to no replacement. I think this breaks the formula. Is this correct?
probability
$endgroup$
add a comment |
$begingroup$
- The probability that 3 out of 8 tosses of a coin will result in
heads
2.The probability of getting exactly five face cards when
drawing five cards from a standard deck of 52 cards without
replacement
(3) When randomly choosing a family with four children,
the probability that it will have exactly two boys and two girls as
children, if having a boy or a girl is equally likely
(4) The
probability that a student randomly guessing will get at least 8 out
of 10 multiple-choice questions correct (assuming every question has
five choices)
To me, all of these scenarios seem like I can apply the binomial distribution formula except for (2) . I believe I can use it on (1) and (3) and (4). For (2) though, the probabilities will change due to no replacement. I think this breaks the formula. Is this correct?
probability
$endgroup$
add a comment |
$begingroup$
- The probability that 3 out of 8 tosses of a coin will result in
heads
2.The probability of getting exactly five face cards when
drawing five cards from a standard deck of 52 cards without
replacement
(3) When randomly choosing a family with four children,
the probability that it will have exactly two boys and two girls as
children, if having a boy or a girl is equally likely
(4) The
probability that a student randomly guessing will get at least 8 out
of 10 multiple-choice questions correct (assuming every question has
five choices)
To me, all of these scenarios seem like I can apply the binomial distribution formula except for (2) . I believe I can use it on (1) and (3) and (4). For (2) though, the probabilities will change due to no replacement. I think this breaks the formula. Is this correct?
probability
$endgroup$
- The probability that 3 out of 8 tosses of a coin will result in
heads
2.The probability of getting exactly five face cards when
drawing five cards from a standard deck of 52 cards without
replacement
(3) When randomly choosing a family with four children,
the probability that it will have exactly two boys and two girls as
children, if having a boy or a girl is equally likely
(4) The
probability that a student randomly guessing will get at least 8 out
of 10 multiple-choice questions correct (assuming every question has
five choices)
To me, all of these scenarios seem like I can apply the binomial distribution formula except for (2) . I believe I can use it on (1) and (3) and (4). For (2) though, the probabilities will change due to no replacement. I think this breaks the formula. Is this correct?
probability
probability
asked Dec 17 '18 at 18:46
NaltNalt
776
776
add a comment |
add a comment |
1 Answer
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$begingroup$
Yep. All but 2 (because of no replacement). Use hypergeometric distribution for that!
$endgroup$
$begingroup$
Thank you Mr. Stork! Doubt is an annoying thing
$endgroup$
– Nalt
Dec 17 '18 at 18:51
1
$begingroup$
Doubt is essential for learning and understanding!
$endgroup$
– David G. Stork
Dec 17 '18 at 18:53
add a comment |
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1 Answer
1
active
oldest
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1 Answer
1
active
oldest
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active
oldest
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active
oldest
votes
$begingroup$
Yep. All but 2 (because of no replacement). Use hypergeometric distribution for that!
$endgroup$
$begingroup$
Thank you Mr. Stork! Doubt is an annoying thing
$endgroup$
– Nalt
Dec 17 '18 at 18:51
1
$begingroup$
Doubt is essential for learning and understanding!
$endgroup$
– David G. Stork
Dec 17 '18 at 18:53
add a comment |
$begingroup$
Yep. All but 2 (because of no replacement). Use hypergeometric distribution for that!
$endgroup$
$begingroup$
Thank you Mr. Stork! Doubt is an annoying thing
$endgroup$
– Nalt
Dec 17 '18 at 18:51
1
$begingroup$
Doubt is essential for learning and understanding!
$endgroup$
– David G. Stork
Dec 17 '18 at 18:53
add a comment |
$begingroup$
Yep. All but 2 (because of no replacement). Use hypergeometric distribution for that!
$endgroup$
Yep. All but 2 (because of no replacement). Use hypergeometric distribution for that!
answered Dec 17 '18 at 18:49
David G. StorkDavid G. Stork
11.1k41432
11.1k41432
$begingroup$
Thank you Mr. Stork! Doubt is an annoying thing
$endgroup$
– Nalt
Dec 17 '18 at 18:51
1
$begingroup$
Doubt is essential for learning and understanding!
$endgroup$
– David G. Stork
Dec 17 '18 at 18:53
add a comment |
$begingroup$
Thank you Mr. Stork! Doubt is an annoying thing
$endgroup$
– Nalt
Dec 17 '18 at 18:51
1
$begingroup$
Doubt is essential for learning and understanding!
$endgroup$
– David G. Stork
Dec 17 '18 at 18:53
$begingroup$
Thank you Mr. Stork! Doubt is an annoying thing
$endgroup$
– Nalt
Dec 17 '18 at 18:51
$begingroup$
Thank you Mr. Stork! Doubt is an annoying thing
$endgroup$
– Nalt
Dec 17 '18 at 18:51
1
1
$begingroup$
Doubt is essential for learning and understanding!
$endgroup$
– David G. Stork
Dec 17 '18 at 18:53
$begingroup$
Doubt is essential for learning and understanding!
$endgroup$
– David G. Stork
Dec 17 '18 at 18:53
add a comment |
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