Effect of multiplying by regular matrix on number of solutions of linear equations











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I have following problem:



Let $A,B in F^{ntimes n}$, $B$ is regular. Which on of the following is true?



1.) If $(A|b)$ has at least one solution, then $(BA|b)$ has at least one solution.

2.) If $(A|b)$ has at least one solution, then $(AB|b)$ has at least one solution.

3.) If $(BA|b)$ has at least one solution, then $(A|b)$ has at least one solution.

4.) If $(AB|b)$ has at least one solution, then $(A|b)$ has at least one solution.

($(A|b)$ is a set of linear equations, not sure if that's clear)


If my logic is correct, 1 and 3 are true, and 2 and 4 are false.

Because regular matrix cannot change number of solutions, the multiplication should have no effect in this implication. However this is not true the other way around, if we multiply with not regular matrix, there is a possibility, that the number of solutions may change.


However the answer feels way too easy, so i am not sure if i am missing something obvious here.
Thanks for your time!










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    up vote
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    down vote

    favorite












    I have following problem:



    Let $A,B in F^{ntimes n}$, $B$ is regular. Which on of the following is true?



    1.) If $(A|b)$ has at least one solution, then $(BA|b)$ has at least one solution.

    2.) If $(A|b)$ has at least one solution, then $(AB|b)$ has at least one solution.

    3.) If $(BA|b)$ has at least one solution, then $(A|b)$ has at least one solution.

    4.) If $(AB|b)$ has at least one solution, then $(A|b)$ has at least one solution.

    ($(A|b)$ is a set of linear equations, not sure if that's clear)


    If my logic is correct, 1 and 3 are true, and 2 and 4 are false.

    Because regular matrix cannot change number of solutions, the multiplication should have no effect in this implication. However this is not true the other way around, if we multiply with not regular matrix, there is a possibility, that the number of solutions may change.


    However the answer feels way too easy, so i am not sure if i am missing something obvious here.
    Thanks for your time!










    share|cite|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I have following problem:



      Let $A,B in F^{ntimes n}$, $B$ is regular. Which on of the following is true?



      1.) If $(A|b)$ has at least one solution, then $(BA|b)$ has at least one solution.

      2.) If $(A|b)$ has at least one solution, then $(AB|b)$ has at least one solution.

      3.) If $(BA|b)$ has at least one solution, then $(A|b)$ has at least one solution.

      4.) If $(AB|b)$ has at least one solution, then $(A|b)$ has at least one solution.

      ($(A|b)$ is a set of linear equations, not sure if that's clear)


      If my logic is correct, 1 and 3 are true, and 2 and 4 are false.

      Because regular matrix cannot change number of solutions, the multiplication should have no effect in this implication. However this is not true the other way around, if we multiply with not regular matrix, there is a possibility, that the number of solutions may change.


      However the answer feels way too easy, so i am not sure if i am missing something obvious here.
      Thanks for your time!










      share|cite|improve this question













      I have following problem:



      Let $A,B in F^{ntimes n}$, $B$ is regular. Which on of the following is true?



      1.) If $(A|b)$ has at least one solution, then $(BA|b)$ has at least one solution.

      2.) If $(A|b)$ has at least one solution, then $(AB|b)$ has at least one solution.

      3.) If $(BA|b)$ has at least one solution, then $(A|b)$ has at least one solution.

      4.) If $(AB|b)$ has at least one solution, then $(A|b)$ has at least one solution.

      ($(A|b)$ is a set of linear equations, not sure if that's clear)


      If my logic is correct, 1 and 3 are true, and 2 and 4 are false.

      Because regular matrix cannot change number of solutions, the multiplication should have no effect in this implication. However this is not true the other way around, if we multiply with not regular matrix, there is a possibility, that the number of solutions may change.


      However the answer feels way too easy, so i am not sure if i am missing something obvious here.
      Thanks for your time!







      linear-algebra matrices matrix-equations






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      Tomáš Korený

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