Why a classical solution of the wave equation has to be $C^2$?
$begingroup$
A (classical) solution of the wave equation
$$
u_{tt}-c^2u_{xx}=0,qquad (x,t)inmathbb{R}timesmathbb{R}^*_+,
$$
is required to be of class $C^2$. Why?
I mean, why one imposes that all second partial derivatives, even $u_{xt}$ which does not appear in the PDE, to be continuous?!
pde wave-equation hyperbolic-equations
$endgroup$
add a comment |
$begingroup$
A (classical) solution of the wave equation
$$
u_{tt}-c^2u_{xx}=0,qquad (x,t)inmathbb{R}timesmathbb{R}^*_+,
$$
is required to be of class $C^2$. Why?
I mean, why one imposes that all second partial derivatives, even $u_{xt}$ which does not appear in the PDE, to be continuous?!
pde wave-equation hyperbolic-equations
$endgroup$
add a comment |
$begingroup$
A (classical) solution of the wave equation
$$
u_{tt}-c^2u_{xx}=0,qquad (x,t)inmathbb{R}timesmathbb{R}^*_+,
$$
is required to be of class $C^2$. Why?
I mean, why one imposes that all second partial derivatives, even $u_{xt}$ which does not appear in the PDE, to be continuous?!
pde wave-equation hyperbolic-equations
$endgroup$
A (classical) solution of the wave equation
$$
u_{tt}-c^2u_{xx}=0,qquad (x,t)inmathbb{R}timesmathbb{R}^*_+,
$$
is required to be of class $C^2$. Why?
I mean, why one imposes that all second partial derivatives, even $u_{xt}$ which does not appear in the PDE, to be continuous?!
pde wave-equation hyperbolic-equations
pde wave-equation hyperbolic-equations
asked Nov 29 '18 at 10:08
WangWang
168210
168210
add a comment |
add a comment |
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