Why a classical solution of the wave equation has to be $C^2$?












1












$begingroup$


A (classical) solution of the wave equation
$$
u_{tt}-c^2u_{xx}=0,qquad (x,t)inmathbb{R}timesmathbb{R}^*_+,
$$

is required to be of class $C^2$. Why?



I mean, why one imposes that all second partial derivatives, even $u_{xt}$ which does not appear in the PDE, to be continuous?!










share|cite|improve this question









$endgroup$

















    1












    $begingroup$


    A (classical) solution of the wave equation
    $$
    u_{tt}-c^2u_{xx}=0,qquad (x,t)inmathbb{R}timesmathbb{R}^*_+,
    $$

    is required to be of class $C^2$. Why?



    I mean, why one imposes that all second partial derivatives, even $u_{xt}$ which does not appear in the PDE, to be continuous?!










    share|cite|improve this question









    $endgroup$















      1












      1








      1





      $begingroup$


      A (classical) solution of the wave equation
      $$
      u_{tt}-c^2u_{xx}=0,qquad (x,t)inmathbb{R}timesmathbb{R}^*_+,
      $$

      is required to be of class $C^2$. Why?



      I mean, why one imposes that all second partial derivatives, even $u_{xt}$ which does not appear in the PDE, to be continuous?!










      share|cite|improve this question









      $endgroup$




      A (classical) solution of the wave equation
      $$
      u_{tt}-c^2u_{xx}=0,qquad (x,t)inmathbb{R}timesmathbb{R}^*_+,
      $$

      is required to be of class $C^2$. Why?



      I mean, why one imposes that all second partial derivatives, even $u_{xt}$ which does not appear in the PDE, to be continuous?!







      pde wave-equation hyperbolic-equations






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Nov 29 '18 at 10:08









      WangWang

      168210




      168210






















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