API Access HTML/Javascript problem
I have an issue trying to use javascript to get the circulating supply by requesting data from Tzscan API:
HTML code to request the circulating supply:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JS Bin</title>
</head>
<body>
<h1>There Tezos Circulating : </h1>
<div id="getapi"></div>
</body>
</html>
Javascript Code to get the data from the API:
<script>
function createNode(element) {
return document.createElement(element);
}
function append(parent, el) {
return parent.appendChild(el);
}
const ul = document.getElementById('getapi');
const url = 'http://api6.tzscan.io/v3/supply';
fetch(url)
.then((resp) => resp.json())
.then(function(data) {
let span = createNode('span');
span.innerHTML = `${data.circulating_supply/1000000}`;
append(ul, span);
})
.catch(function(error) {
console.log(error);
});
</script>
The problem is that somehow it works when I create a HTML file locally but not online.
api javascript circulating-supply
New contributor
add a comment |
I have an issue trying to use javascript to get the circulating supply by requesting data from Tzscan API:
HTML code to request the circulating supply:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JS Bin</title>
</head>
<body>
<h1>There Tezos Circulating : </h1>
<div id="getapi"></div>
</body>
</html>
Javascript Code to get the data from the API:
<script>
function createNode(element) {
return document.createElement(element);
}
function append(parent, el) {
return parent.appendChild(el);
}
const ul = document.getElementById('getapi');
const url = 'http://api6.tzscan.io/v3/supply';
fetch(url)
.then((resp) => resp.json())
.then(function(data) {
let span = createNode('span');
span.innerHTML = `${data.circulating_supply/1000000}`;
append(ul, span);
})
.catch(function(error) {
console.log(error);
});
</script>
The problem is that somehow it works when I create a HTML file locally but not online.
api javascript circulating-supply
New contributor
it'll help to also include the errors you are getting. I know we could probably look at your codepen but for the sake of the question, it's best include the errors in the question.
– Frank
Mar 25 at 3:20
add a comment |
I have an issue trying to use javascript to get the circulating supply by requesting data from Tzscan API:
HTML code to request the circulating supply:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JS Bin</title>
</head>
<body>
<h1>There Tezos Circulating : </h1>
<div id="getapi"></div>
</body>
</html>
Javascript Code to get the data from the API:
<script>
function createNode(element) {
return document.createElement(element);
}
function append(parent, el) {
return parent.appendChild(el);
}
const ul = document.getElementById('getapi');
const url = 'http://api6.tzscan.io/v3/supply';
fetch(url)
.then((resp) => resp.json())
.then(function(data) {
let span = createNode('span');
span.innerHTML = `${data.circulating_supply/1000000}`;
append(ul, span);
})
.catch(function(error) {
console.log(error);
});
</script>
The problem is that somehow it works when I create a HTML file locally but not online.
api javascript circulating-supply
New contributor
I have an issue trying to use javascript to get the circulating supply by requesting data from Tzscan API:
HTML code to request the circulating supply:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JS Bin</title>
</head>
<body>
<h1>There Tezos Circulating : </h1>
<div id="getapi"></div>
</body>
</html>
Javascript Code to get the data from the API:
<script>
function createNode(element) {
return document.createElement(element);
}
function append(parent, el) {
return parent.appendChild(el);
}
const ul = document.getElementById('getapi');
const url = 'http://api6.tzscan.io/v3/supply';
fetch(url)
.then((resp) => resp.json())
.then(function(data) {
let span = createNode('span');
span.innerHTML = `${data.circulating_supply/1000000}`;
append(ul, span);
})
.catch(function(error) {
console.log(error);
});
</script>
The problem is that somehow it works when I create a HTML file locally but not online.
api javascript circulating-supply
api javascript circulating-supply
New contributor
New contributor
edited Mar 25 at 11:29
luchonacho
532216
532216
New contributor
asked Mar 24 at 21:49
LexxorLexxor
1006
1006
New contributor
New contributor
it'll help to also include the errors you are getting. I know we could probably look at your codepen but for the sake of the question, it's best include the errors in the question.
– Frank
Mar 25 at 3:20
add a comment |
it'll help to also include the errors you are getting. I know we could probably look at your codepen but for the sake of the question, it's best include the errors in the question.
– Frank
Mar 25 at 3:20
it'll help to also include the errors you are getting. I know we could probably look at your codepen but for the sake of the question, it's best include the errors in the question.
– Frank
Mar 25 at 3:20
it'll help to also include the errors you are getting. I know we could probably look at your codepen but for the sake of the question, it's best include the errors in the question.
– Frank
Mar 25 at 3:20
add a comment |
1 Answer
1
active
oldest
votes
You've encountered a mixed content error. Requests can't be a mixture of http and https, they need to be all of the same, preferably https. Just change the const url = 'http://api6.tzscan.io/v3/supply';
to be https
const url = 'https://api6.tzscan.io/v3/supply';
fetch(url)
.then(resp => resp.json())
.then(({dls}) => {
let span = createNode('span');
span.innerHTML = dls;
append(ul, span);
})
.catch(console.log);
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You've encountered a mixed content error. Requests can't be a mixture of http and https, they need to be all of the same, preferably https. Just change the const url = 'http://api6.tzscan.io/v3/supply';
to be https
const url = 'https://api6.tzscan.io/v3/supply';
fetch(url)
.then(resp => resp.json())
.then(({dls}) => {
let span = createNode('span');
span.innerHTML = dls;
append(ul, span);
})
.catch(console.log);
add a comment |
You've encountered a mixed content error. Requests can't be a mixture of http and https, they need to be all of the same, preferably https. Just change the const url = 'http://api6.tzscan.io/v3/supply';
to be https
const url = 'https://api6.tzscan.io/v3/supply';
fetch(url)
.then(resp => resp.json())
.then(({dls}) => {
let span = createNode('span');
span.innerHTML = dls;
append(ul, span);
})
.catch(console.log);
add a comment |
You've encountered a mixed content error. Requests can't be a mixture of http and https, they need to be all of the same, preferably https. Just change the const url = 'http://api6.tzscan.io/v3/supply';
to be https
const url = 'https://api6.tzscan.io/v3/supply';
fetch(url)
.then(resp => resp.json())
.then(({dls}) => {
let span = createNode('span');
span.innerHTML = dls;
append(ul, span);
})
.catch(console.log);
You've encountered a mixed content error. Requests can't be a mixture of http and https, they need to be all of the same, preferably https. Just change the const url = 'http://api6.tzscan.io/v3/supply';
to be https
const url = 'https://api6.tzscan.io/v3/supply';
fetch(url)
.then(resp => resp.json())
.then(({dls}) => {
let span = createNode('span');
span.innerHTML = dls;
append(ul, span);
})
.catch(console.log);
edited Mar 25 at 1:59
answered Mar 24 at 23:15
Richard AyotteRichard Ayotte
25917
25917
add a comment |
add a comment |
Lexxor is a new contributor. Be nice, and check out our Code of Conduct.
Lexxor is a new contributor. Be nice, and check out our Code of Conduct.
Lexxor is a new contributor. Be nice, and check out our Code of Conduct.
Lexxor is a new contributor. Be nice, and check out our Code of Conduct.
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it'll help to also include the errors you are getting. I know we could probably look at your codepen but for the sake of the question, it's best include the errors in the question.
– Frank
Mar 25 at 3:20