Use first 4 terms of the series to approximate
$begingroup$
I need to use the first 4 non zero terms binomial Taylor series:
$(1+x)^r = sum^{infty}_{n=0} {(r n)x^n}$
centered at $0$
I need to use this series to approximate $(1.2)^{1/4}$.
What exactly is the question asking me to do? This topic is new to me so I am not sure how to start this problem.
taylor-expansion
asked Dec 18 '18 at 19:31
ElijahElijah
626
$endgroup$
add a comment |
$begingroup$
I need to use the first 4 non zero terms binomial Taylor series:
$(1+x)^r = sum^{infty}_{n=0} {(r n)x^n}$
centered at $0$
I need to use this series to approximate $(1.2)^{1/4}$.
What exactly is the question asking me to do? This topic is new to me so I am not sure how to start this problem.
taylor-expansion
asked Dec 18 '18 at 19:31
ElijahElijah
626
$endgroup$
$begingroup$
$x=0.2,r=0.25$. Need I say more?
$endgroup$
– Don Thousand
Dec 18 '18 at 19:33
$begingroup$
I can see how you got there, but how does that relate to the terms of the series?
$endgroup$
– Elijah
Dec 18 '18 at 19:36
$begingroup$
Notice that your summation uses $r,x$ as variables. I gave you their values...
$endgroup$
– Don Thousand
Dec 18 '18 at 19:38
add a comment |
$begingroup$
I need to use the first 4 non zero terms binomial Taylor series:
$(1+x)^r = sum^{infty}_{n=0} {(r n)x^n}$
centered at $0$
I need to use this series to approximate $(1.2)^{1/4}$.
What exactly is the question asking me to do? This topic is new to me so I am not sure how to start this problem.
taylor-expansion
asked Dec 18 '18 at 19:31
ElijahElijah
626
$endgroup$
I need to use the first 4 non zero terms binomial Taylor series:
$(1+x)^r = sum^{infty}_{n=0} {(r n)x^n}$
centered at $0$
I need to use this series to approximate $(1.2)^{1/4}$.
What exactly is the question asking me to do? This topic is new to me so I am not sure how to start this problem.
taylor-expansion
taylor-expansion
asked Dec 18 '18 at 19:31
ElijahElijah
626
asked Dec 18 '18 at 19:31
ElijahElijah
626
asked Dec 18 '18 at 19:31
ElijahElijah
626
asked Dec 18 '18 at 19:31
ElijahElijah
626
asked Dec 18 '18 at 19:31
ElijahElijah
626
626
$begingroup$
$x=0.2,r=0.25$. Need I say more?
$endgroup$
– Don Thousand
Dec 18 '18 at 19:33
$begingroup$
I can see how you got there, but how does that relate to the terms of the series?
$endgroup$
– Elijah
Dec 18 '18 at 19:36
$begingroup$
Notice that your summation uses $r,x$ as variables. I gave you their values...
$endgroup$
– Don Thousand
Dec 18 '18 at 19:38
add a comment |
$begingroup$
$x=0.2,r=0.25$. Need I say more?
$endgroup$
– Don Thousand
Dec 18 '18 at 19:33
$begingroup$
I can see how you got there, but how does that relate to the terms of the series?
$endgroup$
– Elijah
Dec 18 '18 at 19:36
$begingroup$
Notice that your summation uses $r,x$ as variables. I gave you their values...
$endgroup$
– Don Thousand
Dec 18 '18 at 19:38
$begingroup$
$x=0.2,r=0.25$. Need I say more?
$endgroup$
– Don Thousand
Dec 18 '18 at 19:33
$begingroup$
$x=0.2,r=0.25$. Need I say more?
$endgroup$
– Don Thousand
Dec 18 '18 at 19:33
$begingroup$
I can see how you got there, but how does that relate to the terms of the series?
$endgroup$
– Elijah
Dec 18 '18 at 19:36
$begingroup$
I can see how you got there, but how does that relate to the terms of the series?
$endgroup$
– Elijah
Dec 18 '18 at 19:36
$begingroup$
Notice that your summation uses $r,x$ as variables. I gave you their values...
$endgroup$
– Don Thousand
Dec 18 '18 at 19:38
$begingroup$
Notice that your summation uses $r,x$ as variables. I gave you their values...
$endgroup$
– Don Thousand
Dec 18 '18 at 19:38
add a comment |
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$begingroup$
$x=0.2,r=0.25$. Need I say more?
$endgroup$
– Don Thousand
Dec 18 '18 at 19:33
$begingroup$
I can see how you got there, but how does that relate to the terms of the series?
$endgroup$
– Elijah
Dec 18 '18 at 19:36
$begingroup$
Notice that your summation uses $r,x$ as variables. I gave you their values...
$endgroup$
– Don Thousand
Dec 18 '18 at 19:38