What is the conditional probability if we condition with the empty set?












0














It's an interesting question I think (or what is most likely I'm missing some subtle details). On one hand, we know that the empty set is independent of any other event so for any $A in mathcal{F}:$ $P( A , | , emptyset) = P(A)$, on the other hand, if we write this conditional probability using the definition, we might get that something is divided by zero. So what is $P( A , | , emptyset) :
\
P(A),, , 0 , ,text{or something undefined ?}$



p.s.: I added zero because intuitively if we know that everything is wrong (our condition) then A must be wrong (like never to happen).










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  • 2




    The probability is not defined in such case.
    – DavidPM
    Nov 25 '18 at 23:02










  • How can you elaborate that?
    – NickM
    Nov 25 '18 at 23:02






  • 1




    Well, by definition, the conditional probability of A given B would be the probability of their intersection / conjunction divided by the probability of B. If B is the empty set you get null probability (the empty set has no measure) and thus would yield division by 0. Thus, undefined.
    – DavidPM
    Nov 25 '18 at 23:12


















0














It's an interesting question I think (or what is most likely I'm missing some subtle details). On one hand, we know that the empty set is independent of any other event so for any $A in mathcal{F}:$ $P( A , | , emptyset) = P(A)$, on the other hand, if we write this conditional probability using the definition, we might get that something is divided by zero. So what is $P( A , | , emptyset) :
\
P(A),, , 0 , ,text{or something undefined ?}$



p.s.: I added zero because intuitively if we know that everything is wrong (our condition) then A must be wrong (like never to happen).










share|cite|improve this question




















  • 2




    The probability is not defined in such case.
    – DavidPM
    Nov 25 '18 at 23:02










  • How can you elaborate that?
    – NickM
    Nov 25 '18 at 23:02






  • 1




    Well, by definition, the conditional probability of A given B would be the probability of their intersection / conjunction divided by the probability of B. If B is the empty set you get null probability (the empty set has no measure) and thus would yield division by 0. Thus, undefined.
    – DavidPM
    Nov 25 '18 at 23:12
















0












0








0







It's an interesting question I think (or what is most likely I'm missing some subtle details). On one hand, we know that the empty set is independent of any other event so for any $A in mathcal{F}:$ $P( A , | , emptyset) = P(A)$, on the other hand, if we write this conditional probability using the definition, we might get that something is divided by zero. So what is $P( A , | , emptyset) :
\
P(A),, , 0 , ,text{or something undefined ?}$



p.s.: I added zero because intuitively if we know that everything is wrong (our condition) then A must be wrong (like never to happen).










share|cite|improve this question















It's an interesting question I think (or what is most likely I'm missing some subtle details). On one hand, we know that the empty set is independent of any other event so for any $A in mathcal{F}:$ $P( A , | , emptyset) = P(A)$, on the other hand, if we write this conditional probability using the definition, we might get that something is divided by zero. So what is $P( A , | , emptyset) :
\
P(A),, , 0 , ,text{or something undefined ?}$



p.s.: I added zero because intuitively if we know that everything is wrong (our condition) then A must be wrong (like never to happen).







probability probability-theory






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 25 '18 at 23:09

























asked Nov 25 '18 at 23:01









NickM

163




163








  • 2




    The probability is not defined in such case.
    – DavidPM
    Nov 25 '18 at 23:02










  • How can you elaborate that?
    – NickM
    Nov 25 '18 at 23:02






  • 1




    Well, by definition, the conditional probability of A given B would be the probability of their intersection / conjunction divided by the probability of B. If B is the empty set you get null probability (the empty set has no measure) and thus would yield division by 0. Thus, undefined.
    – DavidPM
    Nov 25 '18 at 23:12
















  • 2




    The probability is not defined in such case.
    – DavidPM
    Nov 25 '18 at 23:02










  • How can you elaborate that?
    – NickM
    Nov 25 '18 at 23:02






  • 1




    Well, by definition, the conditional probability of A given B would be the probability of their intersection / conjunction divided by the probability of B. If B is the empty set you get null probability (the empty set has no measure) and thus would yield division by 0. Thus, undefined.
    – DavidPM
    Nov 25 '18 at 23:12










2




2




The probability is not defined in such case.
– DavidPM
Nov 25 '18 at 23:02




The probability is not defined in such case.
– DavidPM
Nov 25 '18 at 23:02












How can you elaborate that?
– NickM
Nov 25 '18 at 23:02




How can you elaborate that?
– NickM
Nov 25 '18 at 23:02




1




1




Well, by definition, the conditional probability of A given B would be the probability of their intersection / conjunction divided by the probability of B. If B is the empty set you get null probability (the empty set has no measure) and thus would yield division by 0. Thus, undefined.
– DavidPM
Nov 25 '18 at 23:12






Well, by definition, the conditional probability of A given B would be the probability of their intersection / conjunction divided by the probability of B. If B is the empty set you get null probability (the empty set has no measure) and thus would yield division by 0. Thus, undefined.
– DavidPM
Nov 25 '18 at 23:12












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