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Integration of $int_0^frac{pi}{6} cos^{-3}2x sin2x , dx $?

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0 $begingroup$ I tried substituting $x=frac{cos t}{2}$ but I didn't got anywhere. Thanks! calculus integration definite-integrals share | cite | improve this question asked Dec 11 '18 at 16:38 Raghav Raghav 55 7 $endgroup$ add a comment  |  0 $begingroup