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1 I was given the following problem: Assume propagation delay is less than transmission delay on a link connecting host A to B. If host A starts transmission at t=0, at time equal to transmission delay, where is the first bit of the packet? With the solution being that the first bit has reached Host B. However, I am having trouble understanding it. If the transmission delay has elapsed, then wouldn't the packed have just been transmitted and therefore would be on the wire still? Shouldn't the first bit reach Host B after the transmission delay + the propagation delay, regardless of how large they are in proportion to each other? In other words, how could the packet transmit AND propagate in just the time it takes to transmit? networking

0 $begingroup$ Operator Theoretic Aspects of Ergodic Theory. T. Eisner. B. Farkas. M. Haase and R. Nagel. Page 90 Exercise 3. How to prove that the following transformation $$T:mathbb{R}rightarrow mathbb{R}$$ $$T(x)=frac{1}{2}left(x-frac{1}{x}right) : xin mathbb{R-{0}}$$ $$T(0)=0$$ preserves the following measure $$lambdaleft([a,b]right)=int_{a}^{b}frac{dx}{pi(1+x^2)}$$ probability-theory measure-theory proof-verification proof-writing ergodic-theory share | cite | improve this question edited Dec 19 '18 at 8:40 Neil hawking