Find a matrix R α ∈ R 2 × 2 such that f ( x ) = f R α ( x ) for every x ∈ R 2












0














I'm trying to solve this task.



Let α∈R be given. Consider the linear map f:R^2→R^2,



   (x1   -->  ( x1·cos(α)−x2·sin(α)
x2) x1.sin(α)+x2·cos(α)).


a) Find a matrix Rα∈R2×2 such that f(x) =f Rα(x) for everyx∈R^2.



b) Interpret the map f, i.e. state what it does to a given vector x∈R^2.



First I thought, I should use this rule
|A| = ad − bc , but I think, It's already used . should i gave α a number like zero and then I will have a matrix and that's it?










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  • Your question is very difficult to read! You really have to learn MathJax. See this link for a good tutorial.
    – TonyK
    Nov 25 '18 at 22:08










  • You have a description there of the result of applying $f$ to an arbitrary column vector $(x_1,x_2)^T$. Can you write that result as a matrix times $(x_1,x_2)^T$ in any way?
    – Arthur
    Nov 25 '18 at 22:08










  • @TonyK thanks..
    – Amerov
    Nov 25 '18 at 22:25
















0














I'm trying to solve this task.



Let α∈R be given. Consider the linear map f:R^2→R^2,



   (x1   -->  ( x1·cos(α)−x2·sin(α)
x2) x1.sin(α)+x2·cos(α)).


a) Find a matrix Rα∈R2×2 such that f(x) =f Rα(x) for everyx∈R^2.



b) Interpret the map f, i.e. state what it does to a given vector x∈R^2.



First I thought, I should use this rule
|A| = ad − bc , but I think, It's already used . should i gave α a number like zero and then I will have a matrix and that's it?










share|cite|improve this question
























  • Your question is very difficult to read! You really have to learn MathJax. See this link for a good tutorial.
    – TonyK
    Nov 25 '18 at 22:08










  • You have a description there of the result of applying $f$ to an arbitrary column vector $(x_1,x_2)^T$. Can you write that result as a matrix times $(x_1,x_2)^T$ in any way?
    – Arthur
    Nov 25 '18 at 22:08










  • @TonyK thanks..
    – Amerov
    Nov 25 '18 at 22:25














0












0








0







I'm trying to solve this task.



Let α∈R be given. Consider the linear map f:R^2→R^2,



   (x1   -->  ( x1·cos(α)−x2·sin(α)
x2) x1.sin(α)+x2·cos(α)).


a) Find a matrix Rα∈R2×2 such that f(x) =f Rα(x) for everyx∈R^2.



b) Interpret the map f, i.e. state what it does to a given vector x∈R^2.



First I thought, I should use this rule
|A| = ad − bc , but I think, It's already used . should i gave α a number like zero and then I will have a matrix and that's it?










share|cite|improve this question















I'm trying to solve this task.



Let α∈R be given. Consider the linear map f:R^2→R^2,



   (x1   -->  ( x1·cos(α)−x2·sin(α)
x2) x1.sin(α)+x2·cos(α)).


a) Find a matrix Rα∈R2×2 such that f(x) =f Rα(x) for everyx∈R^2.



b) Interpret the map f, i.e. state what it does to a given vector x∈R^2.



First I thought, I should use this rule
|A| = ad − bc , but I think, It's already used . should i gave α a number like zero and then I will have a matrix and that's it?







linear-algebra matrices linear-transformations






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 25 '18 at 22:10

























asked Nov 25 '18 at 22:03









Amerov

35




35












  • Your question is very difficult to read! You really have to learn MathJax. See this link for a good tutorial.
    – TonyK
    Nov 25 '18 at 22:08










  • You have a description there of the result of applying $f$ to an arbitrary column vector $(x_1,x_2)^T$. Can you write that result as a matrix times $(x_1,x_2)^T$ in any way?
    – Arthur
    Nov 25 '18 at 22:08










  • @TonyK thanks..
    – Amerov
    Nov 25 '18 at 22:25


















  • Your question is very difficult to read! You really have to learn MathJax. See this link for a good tutorial.
    – TonyK
    Nov 25 '18 at 22:08










  • You have a description there of the result of applying $f$ to an arbitrary column vector $(x_1,x_2)^T$. Can you write that result as a matrix times $(x_1,x_2)^T$ in any way?
    – Arthur
    Nov 25 '18 at 22:08










  • @TonyK thanks..
    – Amerov
    Nov 25 '18 at 22:25
















Your question is very difficult to read! You really have to learn MathJax. See this link for a good tutorial.
– TonyK
Nov 25 '18 at 22:08




Your question is very difficult to read! You really have to learn MathJax. See this link for a good tutorial.
– TonyK
Nov 25 '18 at 22:08












You have a description there of the result of applying $f$ to an arbitrary column vector $(x_1,x_2)^T$. Can you write that result as a matrix times $(x_1,x_2)^T$ in any way?
– Arthur
Nov 25 '18 at 22:08




You have a description there of the result of applying $f$ to an arbitrary column vector $(x_1,x_2)^T$. Can you write that result as a matrix times $(x_1,x_2)^T$ in any way?
– Arthur
Nov 25 '18 at 22:08












@TonyK thanks..
– Amerov
Nov 25 '18 at 22:25




@TonyK thanks..
– Amerov
Nov 25 '18 at 22:25










1 Answer
1






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oldest

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0














Hint: The columns of the matrix are $f(1,0)$ and $f(0,1)$.



For the second part, look at what happens to $(1,0)$ and $(0,1)$ and apply a little trigonometry.






share|cite|improve this answer





















  • How did you know that the columns of the m. are f(1,0)and f(0,1)?
    – Amerov
    Nov 25 '18 at 22:24










  • This is always true.
    – Chris Custer
    Nov 25 '18 at 22:27










  • can you give me a simple example to know how the result should look like ?
    – Amerov
    Nov 25 '18 at 22:33










  • For the first column, $f(1,0)=(costheta,sintheta)$. So we have $begin{pmatrix}costheta &*\sintheta &*end{pmatrix}$, so far. You try the second column.
    – Chris Custer
    Nov 25 '18 at 22:39












  • it should be (x1,x2) if it's wrong please don't blame me XD XD XD
    – Amerov
    Nov 25 '18 at 22:46











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1 Answer
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active

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1 Answer
1






active

oldest

votes









active

oldest

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active

oldest

votes









0














Hint: The columns of the matrix are $f(1,0)$ and $f(0,1)$.



For the second part, look at what happens to $(1,0)$ and $(0,1)$ and apply a little trigonometry.






share|cite|improve this answer





















  • How did you know that the columns of the m. are f(1,0)and f(0,1)?
    – Amerov
    Nov 25 '18 at 22:24










  • This is always true.
    – Chris Custer
    Nov 25 '18 at 22:27










  • can you give me a simple example to know how the result should look like ?
    – Amerov
    Nov 25 '18 at 22:33










  • For the first column, $f(1,0)=(costheta,sintheta)$. So we have $begin{pmatrix}costheta &*\sintheta &*end{pmatrix}$, so far. You try the second column.
    – Chris Custer
    Nov 25 '18 at 22:39












  • it should be (x1,x2) if it's wrong please don't blame me XD XD XD
    – Amerov
    Nov 25 '18 at 22:46
















0














Hint: The columns of the matrix are $f(1,0)$ and $f(0,1)$.



For the second part, look at what happens to $(1,0)$ and $(0,1)$ and apply a little trigonometry.






share|cite|improve this answer





















  • How did you know that the columns of the m. are f(1,0)and f(0,1)?
    – Amerov
    Nov 25 '18 at 22:24










  • This is always true.
    – Chris Custer
    Nov 25 '18 at 22:27










  • can you give me a simple example to know how the result should look like ?
    – Amerov
    Nov 25 '18 at 22:33










  • For the first column, $f(1,0)=(costheta,sintheta)$. So we have $begin{pmatrix}costheta &*\sintheta &*end{pmatrix}$, so far. You try the second column.
    – Chris Custer
    Nov 25 '18 at 22:39












  • it should be (x1,x2) if it's wrong please don't blame me XD XD XD
    – Amerov
    Nov 25 '18 at 22:46














0












0








0






Hint: The columns of the matrix are $f(1,0)$ and $f(0,1)$.



For the second part, look at what happens to $(1,0)$ and $(0,1)$ and apply a little trigonometry.






share|cite|improve this answer












Hint: The columns of the matrix are $f(1,0)$ and $f(0,1)$.



For the second part, look at what happens to $(1,0)$ and $(0,1)$ and apply a little trigonometry.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Nov 25 '18 at 22:13









Chris Custer

10.8k3824




10.8k3824












  • How did you know that the columns of the m. are f(1,0)and f(0,1)?
    – Amerov
    Nov 25 '18 at 22:24










  • This is always true.
    – Chris Custer
    Nov 25 '18 at 22:27










  • can you give me a simple example to know how the result should look like ?
    – Amerov
    Nov 25 '18 at 22:33










  • For the first column, $f(1,0)=(costheta,sintheta)$. So we have $begin{pmatrix}costheta &*\sintheta &*end{pmatrix}$, so far. You try the second column.
    – Chris Custer
    Nov 25 '18 at 22:39












  • it should be (x1,x2) if it's wrong please don't blame me XD XD XD
    – Amerov
    Nov 25 '18 at 22:46


















  • How did you know that the columns of the m. are f(1,0)and f(0,1)?
    – Amerov
    Nov 25 '18 at 22:24










  • This is always true.
    – Chris Custer
    Nov 25 '18 at 22:27










  • can you give me a simple example to know how the result should look like ?
    – Amerov
    Nov 25 '18 at 22:33










  • For the first column, $f(1,0)=(costheta,sintheta)$. So we have $begin{pmatrix}costheta &*\sintheta &*end{pmatrix}$, so far. You try the second column.
    – Chris Custer
    Nov 25 '18 at 22:39












  • it should be (x1,x2) if it's wrong please don't blame me XD XD XD
    – Amerov
    Nov 25 '18 at 22:46
















How did you know that the columns of the m. are f(1,0)and f(0,1)?
– Amerov
Nov 25 '18 at 22:24




How did you know that the columns of the m. are f(1,0)and f(0,1)?
– Amerov
Nov 25 '18 at 22:24












This is always true.
– Chris Custer
Nov 25 '18 at 22:27




This is always true.
– Chris Custer
Nov 25 '18 at 22:27












can you give me a simple example to know how the result should look like ?
– Amerov
Nov 25 '18 at 22:33




can you give me a simple example to know how the result should look like ?
– Amerov
Nov 25 '18 at 22:33












For the first column, $f(1,0)=(costheta,sintheta)$. So we have $begin{pmatrix}costheta &*\sintheta &*end{pmatrix}$, so far. You try the second column.
– Chris Custer
Nov 25 '18 at 22:39






For the first column, $f(1,0)=(costheta,sintheta)$. So we have $begin{pmatrix}costheta &*\sintheta &*end{pmatrix}$, so far. You try the second column.
– Chris Custer
Nov 25 '18 at 22:39














it should be (x1,x2) if it's wrong please don't blame me XD XD XD
– Amerov
Nov 25 '18 at 22:46




it should be (x1,x2) if it's wrong please don't blame me XD XD XD
– Amerov
Nov 25 '18 at 22:46


















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