grep: Not a recognized flag: o
3
I am trying to extract the date and timestamps from my log file string ($Data in the below code) on AIX using a regex and loading it into a text file as below:
Data="Logs/2018-12-03/log.txt:3:2018-12-03 00:00:04,333 452621453 [blah blah blah"
echo "$data" | grep -o -n '[0-9]{4}-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[0-1]) (2[0-3]|[01][0-9]):[0-5][0-9]' > timestamps.txt
I get the below error most probably due to the unix version in my host being too old and it doesn't recognize the -o option. Is there any alternative method in which I can get the functionality of -o done?
grep: Not a recognized flag: o
Usage: grep [-r] [-R] [-H] [-L] [-E|-F] [-c|-l|-q] [-insvxbhwyu] [-p[parasep]] -e pattern_list...
[-f pattern_file...] [file...]
Usage: grep [-r] [-R] [-H] [-L] [-E|-F] [-c|-l|-q] [-insvxbhwyu] [-p[parasep]] [-e pattern_list...]
-f pattern_file... [file...]
Usage: grep [-r] [-R] [-H] [-L] [-E|-F] [-c|-l|-q] [-insvxbhwyu] [-p[parasep]] pattern_list [file...]
grep variable aix
edited Dec 9 '18 at 14:29
Jeff Schaller
40.7k1056129
asked Dec 4 '18 at 9:03
BlueNinjaBlueNinja
213
add a comment |
3
I am trying to extract the date and timestamps from my log file string ($Data in the below code) on AIX using a regex and loading it into a text file as below:
Data="Logs/2018-12-03/log.txt:3:2018-12-03 00:00:04,333 452621453 [blah blah blah"
echo "$data" | grep -o -n '[0-9]{4}-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[0-1]) (2[0-3]|[01][0-9]):[0-5][0-9]' > timestamps.txt
I get the below error most probably due to the unix version in my host being too old and it doesn't recognize the -o option. Is there any alternative method in which I can get the functionality of -o done?
grep: Not a recognized flag: o
Usage: grep [-r] [-R] [-H] [-L] [-E|-F] [-c|-l|-q] [-insvxbhwyu] [-p[parasep]] -e pattern_list...
[-f pattern_file...] [file...]
Usage: grep [-r] [-R] [-H] [-L] [-E|-F] [-c|-l|-q] [-insvxbhwyu] [-p[parasep]] [-e pattern_list...]
-f pattern_file... [file...]
Usage: grep [-r] [-R] [-H] [-L] [-E|-F] [-c|-l|-q] [-insvxbhwyu] [-p[parasep]] pattern_list [file...]
grep variable aix
edited Dec 9 '18 at 14:29
Jeff Schaller
40.7k1056129
asked Dec 4 '18 at 9:03
BlueNinjaBlueNinja
213
What operating system are you using?
– terdon♦
Dec 4 '18 at 9:16
The commanduname -sgives me 'AIX'
– BlueNinja
Dec 4 '18 at 9:21
1
It's not that your Unix is "too old", it's that you are relying on non-standard functionality.
– Kusalananda
Dec 4 '18 at 9:24
Is yourDatavariable a line from the output ofgrep? If it is, you can probably do whatever you are doing a fair bit more efficiently by runningperlorawkover the original log files. Parsing the output ofgrepis not an ideal solution.
– Kusalananda
Dec 4 '18 at 10:41
add a comment |
3
3
3
I am trying to extract the date and timestamps from my log file string ($Data in the below code) on AIX using a regex and loading it into a text file as below:
Data="Logs/2018-12-03/log.txt:3:2018-12-03 00:00:04,333 452621453 [blah blah blah"
echo "$data" | grep -o -n '[0-9]{4}-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[0-1]) (2[0-3]|[01][0-9]):[0-5][0-9]' > timestamps.txt
I get the below error most probably due to the unix version in my host being too old and it doesn't recognize the -o option. Is there any alternative method in which I can get the functionality of -o done?
grep: Not a recognized flag: o
Usage: grep [-r] [-R] [-H] [-L] [-E|-F] [-c|-l|-q] [-insvxbhwyu] [-p[parasep]] -e pattern_list...
[-f pattern_file...] [file...]
Usage: grep [-r] [-R] [-H] [-L] [-E|-F] [-c|-l|-q] [-insvxbhwyu] [-p[parasep]] [-e pattern_list...]
-f pattern_file... [file...]
Usage: grep [-r] [-R] [-H] [-L] [-E|-F] [-c|-l|-q] [-insvxbhwyu] [-p[parasep]] pattern_list [file...]
grep variable aix
edited Dec 9 '18 at 14:29
Jeff Schaller
40.7k1056129
asked Dec 4 '18 at 9:03
BlueNinjaBlueNinja
213
I am trying to extract the date and timestamps from my log file string ($Data in the below code) on AIX using a regex and loading it into a text file as below:
Data="Logs/2018-12-03/log.txt:3:2018-12-03 00:00:04,333 452621453 [blah blah blah"
echo "$data" | grep -o -n '[0-9]{4}-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[0-1]) (2[0-3]|[01][0-9]):[0-5][0-9]' > timestamps.txt
I get the below error most probably due to the unix version in my host being too old and it doesn't recognize the -o option. Is there any alternative method in which I can get the functionality of -o done?
grep: Not a recognized flag: o
Usage: grep [-r] [-R] [-H] [-L] [-E|-F] [-c|-l|-q] [-insvxbhwyu] [-p[parasep]] -e pattern_list...
[-f pattern_file...] [file...]
Usage: grep [-r] [-R] [-H] [-L] [-E|-F] [-c|-l|-q] [-insvxbhwyu] [-p[parasep]] [-e pattern_list...]
-f pattern_file... [file...]
Usage: grep [-r] [-R] [-H] [-L] [-E|-F] [-c|-l|-q] [-insvxbhwyu] [-p[parasep]] pattern_list [file...]
grep variable aix
grep variable aix
edited Dec 9 '18 at 14:29
Jeff Schaller
40.7k1056129
asked Dec 4 '18 at 9:03
BlueNinjaBlueNinja
213
edited Dec 9 '18 at 14:29
Jeff Schaller
40.7k1056129
asked Dec 4 '18 at 9:03
BlueNinjaBlueNinja
213
edited Dec 9 '18 at 14:29
Jeff Schaller
40.7k1056129
edited Dec 9 '18 at 14:29
Jeff Schaller
40.7k1056129
edited Dec 9 '18 at 14:29
Jeff Schaller
40.7k1056129
40.7k1056129
asked Dec 4 '18 at 9:03
BlueNinjaBlueNinja
213
asked Dec 4 '18 at 9:03
BlueNinjaBlueNinja
213
asked Dec 4 '18 at 9:03
BlueNinjaBlueNinja
213
213
What operating system are you using?
– terdon♦
Dec 4 '18 at 9:16
The commanduname -sgives me 'AIX'
– BlueNinja
Dec 4 '18 at 9:21
1
It's not that your Unix is "too old", it's that you are relying on non-standard functionality.
– Kusalananda
Dec 4 '18 at 9:24
Is yourDatavariable a line from the output ofgrep? If it is, you can probably do whatever you are doing a fair bit more efficiently by runningperlorawkover the original log files. Parsing the output ofgrepis not an ideal solution.
– Kusalananda
Dec 4 '18 at 10:41
add a comment |
What operating system are you using?
– terdon♦
Dec 4 '18 at 9:16
The commanduname -sgives me 'AIX'
– BlueNinja
Dec 4 '18 at 9:21
1
It's not that your Unix is "too old", it's that you are relying on non-standard functionality.
– Kusalananda
Dec 4 '18 at 9:24
Is yourDatavariable a line from the output ofgrep? If it is, you can probably do whatever you are doing a fair bit more efficiently by runningperlorawkover the original log files. Parsing the output ofgrepis not an ideal solution.
– Kusalananda
Dec 4 '18 at 10:41
What operating system are you using?
– terdon♦
Dec 4 '18 at 9:16
What operating system are you using?
– terdon♦
Dec 4 '18 at 9:16
The command
uname -s gives me 'AIX'– BlueNinja
Dec 4 '18 at 9:21
The command
uname -s gives me 'AIX'– BlueNinja
Dec 4 '18 at 9:21
1
1
It's not that your Unix is "too old", it's that you are relying on non-standard functionality.
– Kusalananda
Dec 4 '18 at 9:24
It's not that your Unix is "too old", it's that you are relying on non-standard functionality.
– Kusalananda
Dec 4 '18 at 9:24
Is your
Data variable a line from the output of grep? If it is, you can probably do whatever you are doing a fair bit more efficiently by running perl or awk over the original log files. Parsing the output of grep is not an ideal solution.– Kusalananda
Dec 4 '18 at 10:41
Is your
Data variable a line from the output of grep? If it is, you can probably do whatever you are doing a fair bit more efficiently by running perl or awk over the original log files. Parsing the output of grep is not an ideal solution.– Kusalananda
Dec 4 '18 at 10:41
add a comment |
1 Answer
1
active
oldest
votes
5
Note that your regex wouldn't work even if -o was recognized by your grep implementation. You also need -E to enable extended regular expressions. Assuming you have perl, which you probably do, you can try:
$ Data="Logs/2018-12-03/log.txt:3:2018-12-03 00:00:04,333 452621453 [blah blah blah"
$ echo "$Data" | perl -lne '/[0-9]{4}-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[0-1]) (2[0-3]|[01][0-9]):[0-5][0-9]/ && print "$.:$&"'
1:2018-12-03 00:00
But do you really need to make your regex that complicated? Isn't this enough?
$ echo "$Data" | perl -lne '/d{4}-d{2}-d{2} d{2}:d{2}/ && print "$.:$&"'
1:2018-12-03 00:00
answered Dec 4 '18 at 9:20
terdon♦terdon
130k32254432
1
Note also that the data in theDatavariable is a line produced bygrep. This makes me think that the user is first running a grep of some kind to get the lines they want, and then iterating in a shell loop over these lines. This is quite an suboptimal approach to log file parsing.
– Kusalananda
Dec 4 '18 at 10:43
add a comment |
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5
Note that your regex wouldn't work even if -o was recognized by your grep implementation. You also need -E to enable extended regular expressions. Assuming you have perl, which you probably do, you can try:
$ Data="Logs/2018-12-03/log.txt:3:2018-12-03 00:00:04,333 452621453 [blah blah blah"
$ echo "$Data" | perl -lne '/[0-9]{4}-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[0-1]) (2[0-3]|[01][0-9]):[0-5][0-9]/ && print "$.:$&"'
1:2018-12-03 00:00
But do you really need to make your regex that complicated? Isn't this enough?
$ echo "$Data" | perl -lne '/d{4}-d{2}-d{2} d{2}:d{2}/ && print "$.:$&"'
1:2018-12-03 00:00
answered Dec 4 '18 at 9:20
terdon♦terdon
130k32254432
1
Note also that the data in theDatavariable is a line produced bygrep. This makes me think that the user is first running a grep of some kind to get the lines they want, and then iterating in a shell loop over these lines. This is quite an suboptimal approach to log file parsing.
– Kusalananda
Dec 4 '18 at 10:43
add a comment |
5
Note that your regex wouldn't work even if -o was recognized by your grep implementation. You also need -E to enable extended regular expressions. Assuming you have perl, which you probably do, you can try:
$ Data="Logs/2018-12-03/log.txt:3:2018-12-03 00:00:04,333 452621453 [blah blah blah"
$ echo "$Data" | perl -lne '/[0-9]{4}-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[0-1]) (2[0-3]|[01][0-9]):[0-5][0-9]/ && print "$.:$&"'
1:2018-12-03 00:00
But do you really need to make your regex that complicated? Isn't this enough?
$ echo "$Data" | perl -lne '/d{4}-d{2}-d{2} d{2}:d{2}/ && print "$.:$&"'
1:2018-12-03 00:00
answered Dec 4 '18 at 9:20
terdon♦terdon
130k32254432
1
Note also that the data in theDatavariable is a line produced bygrep. This makes me think that the user is first running a grep of some kind to get the lines they want, and then iterating in a shell loop over these lines. This is quite an suboptimal approach to log file parsing.
– Kusalananda
Dec 4 '18 at 10:43
add a comment |
5
5
5
Note that your regex wouldn't work even if -o was recognized by your grep implementation. You also need -E to enable extended regular expressions. Assuming you have perl, which you probably do, you can try:
$ Data="Logs/2018-12-03/log.txt:3:2018-12-03 00:00:04,333 452621453 [blah blah blah"
$ echo "$Data" | perl -lne '/[0-9]{4}-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[0-1]) (2[0-3]|[01][0-9]):[0-5][0-9]/ && print "$.:$&"'
1:2018-12-03 00:00
But do you really need to make your regex that complicated? Isn't this enough?
$ echo "$Data" | perl -lne '/d{4}-d{2}-d{2} d{2}:d{2}/ && print "$.:$&"'
1:2018-12-03 00:00
answered Dec 4 '18 at 9:20
terdon♦terdon
130k32254432
Note that your regex wouldn't work even if -o was recognized by your grep implementation. You also need -E to enable extended regular expressions. Assuming you have perl, which you probably do, you can try:
$ Data="Logs/2018-12-03/log.txt:3:2018-12-03 00:00:04,333 452621453 [blah blah blah"
$ echo "$Data" | perl -lne '/[0-9]{4}-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[0-1]) (2[0-3]|[01][0-9]):[0-5][0-9]/ && print "$.:$&"'
1:2018-12-03 00:00
But do you really need to make your regex that complicated? Isn't this enough?
$ echo "$Data" | perl -lne '/d{4}-d{2}-d{2} d{2}:d{2}/ && print "$.:$&"'
1:2018-12-03 00:00
answered Dec 4 '18 at 9:20
terdon♦terdon
130k32254432
edited Dec 4 '18 at 9:28
answered Dec 4 '18 at 9:20
terdon♦terdon
130k32254432
answered Dec 4 '18 at 9:20
terdon♦terdon
130k32254432
answered Dec 4 '18 at 9:20
terdon♦terdon
130k32254432
130k32254432
1
Note also that the data in theDatavariable is a line produced bygrep. This makes me think that the user is first running a grep of some kind to get the lines they want, and then iterating in a shell loop over these lines. This is quite an suboptimal approach to log file parsing.
– Kusalananda
Dec 4 '18 at 10:43
add a comment |
1
Note also that the data in theDatavariable is a line produced bygrep. This makes me think that the user is first running a grep of some kind to get the lines they want, and then iterating in a shell loop over these lines. This is quite an suboptimal approach to log file parsing.
– Kusalananda
Dec 4 '18 at 10:43
1
1
Note also that the data in the
Data variable is a line produced by grep. This makes me think that the user is first running a grep of some kind to get the lines they want, and then iterating in a shell loop over these lines. This is quite an suboptimal approach to log file parsing.– Kusalananda
Dec 4 '18 at 10:43
Note also that the data in the
Data variable is a line produced by grep. This makes me think that the user is first running a grep of some kind to get the lines they want, and then iterating in a shell loop over these lines. This is quite an suboptimal approach to log file parsing.– Kusalananda
Dec 4 '18 at 10:43
add a comment |
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What operating system are you using?
– terdon♦
Dec 4 '18 at 9:16
The command
uname -sgives me 'AIX'– BlueNinja
Dec 4 '18 at 9:21
1
It's not that your Unix is "too old", it's that you are relying on non-standard functionality.
– Kusalananda
Dec 4 '18 at 9:24
Is your
Datavariable a line from the output ofgrep? If it is, you can probably do whatever you are doing a fair bit more efficiently by runningperlorawkover the original log files. Parsing the output ofgrepis not an ideal solution.– Kusalananda
Dec 4 '18 at 10:41