Let’s say a 1 ton (US) sphere of tungsten moving at 99.99% the speed of light hits earth, what happens? As...
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What kind of destruction would it cause? I’m assuming it’d be rather significant, could it shatter a tectonic plate? The crust? How would the oceans fare? Would the planet be able to catch the projectile? Could any life survive the event?
And if you’re able to stand another question, how immediately noticeable would this event be to other planets in the star system?
science-fiction physics explosions
asked Dec 4 '18 at 7:24
Claiming HeraldClaiming Herald
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What kind of destruction would it cause? I’m assuming it’d be rather significant, could it shatter a tectonic plate? The crust? How would the oceans fare? Would the planet be able to catch the projectile? Could any life survive the event?
And if you’re able to stand another question, how immediately noticeable would this event be to other planets in the star system?
science-fiction physics explosions
asked Dec 4 '18 at 7:24
Claiming HeraldClaiming Herald
250126
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Comments are not for extended discussion; this conversation has been moved to chat.
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– James♦
Dec 6 '18 at 5:50
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Duplicate of: worldbuilding.stackexchange.com/questions/112984/…
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– elemtilas
Dec 6 '18 at 13:59
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Possible duplicate of What would happen if the Earth struck a tiny but immovable object
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– elemtilas
Dec 6 '18 at 14:00
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Basically, it's just a matter of converting the kinetic energy (mass in kg times velocity in m/s gives kinetic energy in Joules) of the impact into megatons (4x10^15J). How that deforms the planet might be best asked and tagged as "astrophysics" on the physics stack exchange, though.
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– Dewi Morgan
Dec 6 '18 at 23:11
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Seems relevant: what-if.xkcd.com/1
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– Joshua Drake
Dec 7 '18 at 0:46
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show 1 more comment
$begingroup$
What kind of destruction would it cause? I’m assuming it’d be rather significant, could it shatter a tectonic plate? The crust? How would the oceans fare? Would the planet be able to catch the projectile? Could any life survive the event?
And if you’re able to stand another question, how immediately noticeable would this event be to other planets in the star system?
science-fiction physics explosions
asked Dec 4 '18 at 7:24
Claiming HeraldClaiming Herald
250126
$endgroup$
What kind of destruction would it cause? I’m assuming it’d be rather significant, could it shatter a tectonic plate? The crust? How would the oceans fare? Would the planet be able to catch the projectile? Could any life survive the event?
And if you’re able to stand another question, how immediately noticeable would this event be to other planets in the star system?
science-fiction physics explosions
science-fiction physics explosions
asked Dec 4 '18 at 7:24
Claiming HeraldClaiming Herald
250126
asked Dec 4 '18 at 7:24
Claiming HeraldClaiming Herald
250126
edited Dec 5 '18 at 8:32
Claiming Herald
asked Dec 4 '18 at 7:24
Claiming HeraldClaiming Herald
250126
asked Dec 4 '18 at 7:24
Claiming HeraldClaiming Herald
250126
asked Dec 4 '18 at 7:24
Claiming HeraldClaiming Herald
250126
250126
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Comments are not for extended discussion; this conversation has been moved to chat.
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– James♦
Dec 6 '18 at 5:50
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Duplicate of: worldbuilding.stackexchange.com/questions/112984/…
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– elemtilas
Dec 6 '18 at 13:59
$begingroup$
Possible duplicate of What would happen if the Earth struck a tiny but immovable object
$endgroup$
– elemtilas
Dec 6 '18 at 14:00
$begingroup$
Basically, it's just a matter of converting the kinetic energy (mass in kg times velocity in m/s gives kinetic energy in Joules) of the impact into megatons (4x10^15J). How that deforms the planet might be best asked and tagged as "astrophysics" on the physics stack exchange, though.
$endgroup$
– Dewi Morgan
Dec 6 '18 at 23:11
$begingroup$
Seems relevant: what-if.xkcd.com/1
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– Joshua Drake
Dec 7 '18 at 0:46
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show 1 more comment
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Comments are not for extended discussion; this conversation has been moved to chat.
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– James♦
Dec 6 '18 at 5:50
$begingroup$
Duplicate of: worldbuilding.stackexchange.com/questions/112984/…
$endgroup$
– elemtilas
Dec 6 '18 at 13:59
$begingroup$
Possible duplicate of What would happen if the Earth struck a tiny but immovable object
$endgroup$
– elemtilas
Dec 6 '18 at 14:00
$begingroup$
Basically, it's just a matter of converting the kinetic energy (mass in kg times velocity in m/s gives kinetic energy in Joules) of the impact into megatons (4x10^15J). How that deforms the planet might be best asked and tagged as "astrophysics" on the physics stack exchange, though.
$endgroup$
– Dewi Morgan
Dec 6 '18 at 23:11
$begingroup$
Seems relevant: what-if.xkcd.com/1
$endgroup$
– Joshua Drake
Dec 7 '18 at 0:46
$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– James♦
Dec 6 '18 at 5:50
$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– James♦
Dec 6 '18 at 5:50
$begingroup$
Duplicate of: worldbuilding.stackexchange.com/questions/112984/…
$endgroup$
– elemtilas
Dec 6 '18 at 13:59
$begingroup$
Duplicate of: worldbuilding.stackexchange.com/questions/112984/…
$endgroup$
– elemtilas
Dec 6 '18 at 13:59
$begingroup$
Possible duplicate of What would happen if the Earth struck a tiny but immovable object
$endgroup$
– elemtilas
Dec 6 '18 at 14:00
$begingroup$
Possible duplicate of What would happen if the Earth struck a tiny but immovable object
$endgroup$
– elemtilas
Dec 6 '18 at 14:00
$begingroup$
Basically, it's just a matter of converting the kinetic energy (mass in kg times velocity in m/s gives kinetic energy in Joules) of the impact into megatons (4x10^15J). How that deforms the planet might be best asked and tagged as "astrophysics" on the physics stack exchange, though.
$endgroup$
– Dewi Morgan
Dec 6 '18 at 23:11
$begingroup$
Basically, it's just a matter of converting the kinetic energy (mass in kg times velocity in m/s gives kinetic energy in Joules) of the impact into megatons (4x10^15J). How that deforms the planet might be best asked and tagged as "astrophysics" on the physics stack exchange, though.
$endgroup$
– Dewi Morgan
Dec 6 '18 at 23:11
$begingroup$
Seems relevant: what-if.xkcd.com/1
$endgroup$
– Joshua Drake
Dec 7 '18 at 0:46
$begingroup$
Seems relevant: what-if.xkcd.com/1
$endgroup$
– Joshua Drake
Dec 7 '18 at 0:46
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show 1 more comment
3 Answers
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This turned out unexpectedly fun... and for once the answer to a question involving 99.99% of the speed of light isn't "everybody dies"
Where is this sphere being fired from?
If it's from outside the solar system then hitting the earth as a sphere is.... a problem...
The volume of 1000 kg of tungsten = 51.9 L
Radius = 0.23 m
That's 5439.5 moles of tungsten.
As the sphere approaches from the orbit of Pluto we can estimate how much matter it would hit.
We can treat the space it passes through as a cylinder with radius 0.23 m and height of 7.5 billion kilometers.
It would take our projectile about 7 hours to travel that distance.
It would pass through 1246 km^3 (cubic kilometers) of space.
In the solar system with the solar wind the density of atoms is 2x10^7 per cubic meter, mostly hydrogen or helium.
Treating it all as hydrogen for simplicity that gives us 0.04171 mg of hydrogen.
This gives us 261.3 GJ (gigajoules) or 72.59 MW h (megawatt hours) as the approximate energy involved in the collisions between the fine mist of gas in the solar system and the bullet.
That's the energy of the atoms hitting the front of the bullet, and most of the energy would be effectively dumped into the metal.
Given this is over 7 hours that means there's something like 10.37 MW of energy being pumped into the sphere every hour.
Tungsten has a heat of vaporization of 800 kJ/mol, so it takes 4,351,600 kJ of energy to turn 1 ton of tungsten into gas.
Unfortunately your tungsten "bullet" sphere is getting hit with 37,332,000 kJ of energy per hour so within the first 7 minutes of its 7 hour journey it's become a cloud of atoms glowing hot at about 5555 degrees Celsius...
At this point the calculations get harder because it's no longer a nice neat sphere; it's a cloud of super-high temperature gas traveling so fast that it's glowing like the heart of a star and it's very hot gas so the cloud is expanding very fast. It's now hitting even more of the random atoms in space as it's approaching earth. Assuming the sphere was aimed to hit earth perfectly dead center I can't even tell you if all of the gas would actually hit the earth or if the hot cloud of gas would expand from itself fast enough to mostly miss the earth. I don't know how much extra energy the cloud would lose to hitting atoms along the way after the sphere melts and turns into gas since it now has a massive surface area...
But let's say that the cloud all still hits the earth's atmosphere, but over the 6 hours and 50 minutes since it passed Pluto it's spread out to hit the entire facing side of the earth fairly evenly and none misses and it's still carrying most of its energy.
As in L. Dutche's answer, according to Wolfram Alpha, the relativistic kinetic energy of such a bullet would be 6.265 x 10^21 J, or 1.5 million megatons.
... but... The total power output of the Sun hitting earth is about 4.3 × 10^20 J per hour hitting atmosphere on the side facing the sun.
The bullet is carrying far less energy than a single days worth of sunlight.
Cosmic rays can't pierce the earths atmosphere and the bullet is now more similar to a giant cloud of cosmic rays, but each with far less energy than the "Oh My God particle".
Everything in orbit on that side of the earth would be hit with a huge dose of cosmic rays.
The hard radiation would be caught by the atmosphere and some heat would make it to the surface... but the atmosphere is vast and that much isn't even enough to raise the temperature of the gas on that side of the planet by 1 degree Celsius average.
I suspect anyone outside might get flash burns. I don't know if the energy would be enough to start major fires. To an extent the more energy ends up as high energy particles and radiation the less hits the earth surface as heat.
But to answer your question: As it approached the gas cloud that used to be the bullet would burn brightly in the sky as it impacted gas and dust ... then for a brief moment the entire sky of half the earth would blaze with light thousands of times brighter than sun... it might burn things on the surface.... it might shower a significant amount of secondary radiation... but the tectonic plates would be safe.
Edit: re Yakk's comments below, as the cloud is passing through space there may also be bursts of something like space-lightning as the cloud interacts with subatomic particles that strip away electrons and depending on how far away from earth the bullet starts ..
Napkin math says this means a spread of E-5 (i.e., every E5 meters it spreads out 1 meter), which means over 100 AU that is 150,000 km. That is order-of-order-of-magnitude size of Earth.
~Yakk
So the cloud may partly miss earth since the diameter of earth is only 12,742 km, so it may be a little bit like getting caught in the middle of a 'shotgun blast' of space-lightning-filled hard radiation with much passing either side of the earth.
answered Dec 4 '18 at 13:02
MurphyMurphy
24.1k24787
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The solar wind density you quote is for earth orbit (hypertextbook.com/facts/2005/RandyAbbas.shtml). Presumably density falls off as 1/r^2 as you get farther from the sun.
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– Peter Cordes
Dec 5 '18 at 1:36
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So they would want to send a 1-ton dart to make sure it all gets there?
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– corsiKa
Dec 5 '18 at 3:07
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While this is an interesting reframing of the the question, I don't see how it answers the question and am surprised it was accepted. The question was not "what if a 1 ton sphere of tungsten entered our solar system on a trajectory towards Earth?" It was "what if a 1 ton sphere of tungsten hit Earth?"
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– Kevin
Dec 5 '18 at 13:54
1
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Heat of vaporization is typically defined as the enthalpy required to transition from a liquid state to a vapor state. If this is the case, you will need to account for the heat of fusion as well (not that it will likely change the answer much)
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– Aliden
Dec 5 '18 at 15:19
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Did you notice the pun hidden in your use of Wolfram Alpha to make computations about a tungsten bullet?
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– Hagen von Eitzen
Dec 5 '18 at 21:02
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show 26 more comments
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According to WolphramAlpha, the relativistic kinetic energy of such a bullet would be $6.265 cdot 10^{21} mathrm J$, or 1.5 million megatons.
The gravitational binding energy of Earth is $2 cdot 10^{32} mathrm J$, therefore we can stay assured that the planet won't be completely wiped out.
Quoting from this useful page, the impact energy would be comparable to the last eruption of Yellowstone super volcano. This event left a large deposit of tuffs, known as Lava Creek Tuffs. The following picture shows their extension:
The Lava Creek Tuff is distributed in a radial pattern around the caldera and is formed of 1,000 km3 (240 cu mi) of ignimbrites.
Lava Creek Tuff ranges in color from light gray to pale red in some locales. Rock texture of the tuff ranges from fine-grained to aphanitic and is densely welded. The maximum thickness of the tuff layer is approximately 180–200 m.
The relativistic impact would be for sure a global cataclysm: the spallation would probably temporarily deform the planet, and the following relaxation would result in increased volcanic activity.
The resulting emission of ashes and gases would severely impact life, with mass extinction effect.
An observer in a suitable position in the Solar system would notice a bright flash during the impact, probably followed by an increased IR emission due to the thermal effects of volcanic eruptions.
To give you a reference of how bright would the flash, the impact energy is about 1/10 of the total solar energy striking the Earth in one day, and it is released in a much shorter time. I assume that for few seconds the Sun and Earth would appear like twin stars in the sky.
answered Dec 4 '18 at 7:59
L.Dutch♦L.Dutch
82.4k27197407
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You might add that it corresponds to (gamma-1)mc². Where gamma=1/sqrt(1-(v/c)²). And furthermore, that would be the equivalent of about 30,000 Tsar bomba exploding at once.
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– bilbo_pingouin
Dec 4 '18 at 8:30
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"A bright flash" -- you can do better. How bright? "Can see in telescope", "visible to the naked eye from Mars", "like a camera flash", "beings on mars go blind if looking in the direction of the the Earth".
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– Yakk
Dec 4 '18 at 14:23
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Care to explain how to do this in WA so that every smash my planet question can just point here?
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– Mazura
Dec 5 '18 at 0:48
1
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"I assume that for few seconds the Sun and Earth would appear like twin stars in the sky." --- where would it look like that? On Mars?
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– BЈовић
Dec 5 '18 at 12:37
1
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'the median length of volcanic eruptions is 7 weeks' it seems intuitive that a more concentrated release of energy would have different characteristics, especially given the importance of direction of motion in kinetic events, resulting in an effect more akin to a nuclear pumped laser than a traditional kinetic event.
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– Giu Piete
Dec 5 '18 at 13:36
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I think that with the size and speed it would be quite powerful. First of all the impact would be virtually instantaneous. This would cause all the force to be extremely concentrated. If it's moving 99% the speed of light, well, imagine all that power compressed into a second--now imagine it being a million times faster than that. Now imagine it being WAY faster than that. The damage of the impact is going to be based on the force multiplied by the inverse of time--and as time approaches zero...
answered Dec 4 '18 at 17:32
Bill KBill K
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Cool image, but nothing like what would really happen.
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– zeta-band
Dec 4 '18 at 19:22
4
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In the baseball XKCD what-if.xkcd.com/1 mentioned above, the ball is much less dense and MUCH slower. It might not go straight through but it would definitely be life-ending. The diamond one would be closer: "The energy cracks a hole in the crust and blows open a crater so big you can see the molten mantle. This delivers the energy of 50 dinosaur-killing Chicxulub impacts—enough to cause a mass extinction, if not end life completely." (Although the diamond they are talking about is bigger I think it would be more or less on that scale)
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– Bill K
Dec 4 '18 at 20:03
1
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Even if ti hits the surface relatively intact, I doubt it penetrates deeper than a couple of miles, the vaporized tungsten is going to interact with the rock really strongly.
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– zeta-band
Dec 4 '18 at 20:08
2
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The question was if it hit the world, but as the XKCD does anything traveling at that speed would not be intact to start out with. It also wouldn't impact so much as phase. It would also be a strange shaped and be enveloped in a giant fireball with the power of multiple nuclear bombs behind it. With a speed like that it wouldn't have any time to break up and wouldn't actually interact much with the atoms it passes through. I'm thinking you are only considering normal physics and not relativistic.
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– Bill K
Dec 4 '18 at 21:36
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3 Answers
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3 Answers
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This turned out unexpectedly fun... and for once the answer to a question involving 99.99% of the speed of light isn't "everybody dies"
Where is this sphere being fired from?
If it's from outside the solar system then hitting the earth as a sphere is.... a problem...
The volume of 1000 kg of tungsten = 51.9 L
Radius = 0.23 m
That's 5439.5 moles of tungsten.
As the sphere approaches from the orbit of Pluto we can estimate how much matter it would hit.
We can treat the space it passes through as a cylinder with radius 0.23 m and height of 7.5 billion kilometers.
It would take our projectile about 7 hours to travel that distance.
It would pass through 1246 km^3 (cubic kilometers) of space.
In the solar system with the solar wind the density of atoms is 2x10^7 per cubic meter, mostly hydrogen or helium.
Treating it all as hydrogen for simplicity that gives us 0.04171 mg of hydrogen.
This gives us 261.3 GJ (gigajoules) or 72.59 MW h (megawatt hours) as the approximate energy involved in the collisions between the fine mist of gas in the solar system and the bullet.
That's the energy of the atoms hitting the front of the bullet, and most of the energy would be effectively dumped into the metal.
Given this is over 7 hours that means there's something like 10.37 MW of energy being pumped into the sphere every hour.
Tungsten has a heat of vaporization of 800 kJ/mol, so it takes 4,351,600 kJ of energy to turn 1 ton of tungsten into gas.
Unfortunately your tungsten "bullet" sphere is getting hit with 37,332,000 kJ of energy per hour so within the first 7 minutes of its 7 hour journey it's become a cloud of atoms glowing hot at about 5555 degrees Celsius...
At this point the calculations get harder because it's no longer a nice neat sphere; it's a cloud of super-high temperature gas traveling so fast that it's glowing like the heart of a star and it's very hot gas so the cloud is expanding very fast. It's now hitting even more of the random atoms in space as it's approaching earth. Assuming the sphere was aimed to hit earth perfectly dead center I can't even tell you if all of the gas would actually hit the earth or if the hot cloud of gas would expand from itself fast enough to mostly miss the earth. I don't know how much extra energy the cloud would lose to hitting atoms along the way after the sphere melts and turns into gas since it now has a massive surface area...
But let's say that the cloud all still hits the earth's atmosphere, but over the 6 hours and 50 minutes since it passed Pluto it's spread out to hit the entire facing side of the earth fairly evenly and none misses and it's still carrying most of its energy.
As in L. Dutche's answer, according to Wolfram Alpha, the relativistic kinetic energy of such a bullet would be 6.265 x 10^21 J, or 1.5 million megatons.
... but... The total power output of the Sun hitting earth is about 4.3 × 10^20 J per hour hitting atmosphere on the side facing the sun.
The bullet is carrying far less energy than a single days worth of sunlight.
Cosmic rays can't pierce the earths atmosphere and the bullet is now more similar to a giant cloud of cosmic rays, but each with far less energy than the "Oh My God particle".
Everything in orbit on that side of the earth would be hit with a huge dose of cosmic rays.
The hard radiation would be caught by the atmosphere and some heat would make it to the surface... but the atmosphere is vast and that much isn't even enough to raise the temperature of the gas on that side of the planet by 1 degree Celsius average.
I suspect anyone outside might get flash burns. I don't know if the energy would be enough to start major fires. To an extent the more energy ends up as high energy particles and radiation the less hits the earth surface as heat.
But to answer your question: As it approached the gas cloud that used to be the bullet would burn brightly in the sky as it impacted gas and dust ... then for a brief moment the entire sky of half the earth would blaze with light thousands of times brighter than sun... it might burn things on the surface.... it might shower a significant amount of secondary radiation... but the tectonic plates would be safe.
Edit: re Yakk's comments below, as the cloud is passing through space there may also be bursts of something like space-lightning as the cloud interacts with subatomic particles that strip away electrons and depending on how far away from earth the bullet starts ..
Napkin math says this means a spread of E-5 (i.e., every E5 meters it spreads out 1 meter), which means over 100 AU that is 150,000 km. That is order-of-order-of-magnitude size of Earth.
~Yakk
So the cloud may partly miss earth since the diameter of earth is only 12,742 km, so it may be a little bit like getting caught in the middle of a 'shotgun blast' of space-lightning-filled hard radiation with much passing either side of the earth.
answered Dec 4 '18 at 13:02
MurphyMurphy
24.1k24787
$endgroup$
4
$begingroup$
The solar wind density you quote is for earth orbit (hypertextbook.com/facts/2005/RandyAbbas.shtml). Presumably density falls off as 1/r^2 as you get farther from the sun.
$endgroup$
– Peter Cordes
Dec 5 '18 at 1:36
1
$begingroup$
So they would want to send a 1-ton dart to make sure it all gets there?
$endgroup$
– corsiKa
Dec 5 '18 at 3:07
29
$begingroup$
While this is an interesting reframing of the the question, I don't see how it answers the question and am surprised it was accepted. The question was not "what if a 1 ton sphere of tungsten entered our solar system on a trajectory towards Earth?" It was "what if a 1 ton sphere of tungsten hit Earth?"
$endgroup$
– Kevin
Dec 5 '18 at 13:54
1
$begingroup$
Heat of vaporization is typically defined as the enthalpy required to transition from a liquid state to a vapor state. If this is the case, you will need to account for the heat of fusion as well (not that it will likely change the answer much)
$endgroup$
– Aliden
Dec 5 '18 at 15:19
2
$begingroup$
Did you notice the pun hidden in your use of Wolfram Alpha to make computations about a tungsten bullet?
$endgroup$
– Hagen von Eitzen
Dec 5 '18 at 21:02
|
show 26 more comments
$begingroup$
This turned out unexpectedly fun... and for once the answer to a question involving 99.99% of the speed of light isn't "everybody dies"
Where is this sphere being fired from?
If it's from outside the solar system then hitting the earth as a sphere is.... a problem...
The volume of 1000 kg of tungsten = 51.9 L
Radius = 0.23 m
That's 5439.5 moles of tungsten.
As the sphere approaches from the orbit of Pluto we can estimate how much matter it would hit.
We can treat the space it passes through as a cylinder with radius 0.23 m and height of 7.5 billion kilometers.
It would take our projectile about 7 hours to travel that distance.
It would pass through 1246 km^3 (cubic kilometers) of space.
In the solar system with the solar wind the density of atoms is 2x10^7 per cubic meter, mostly hydrogen or helium.
Treating it all as hydrogen for simplicity that gives us 0.04171 mg of hydrogen.
This gives us 261.3 GJ (gigajoules) or 72.59 MW h (megawatt hours) as the approximate energy involved in the collisions between the fine mist of gas in the solar system and the bullet.
That's the energy of the atoms hitting the front of the bullet, and most of the energy would be effectively dumped into the metal.
Given this is over 7 hours that means there's something like 10.37 MW of energy being pumped into the sphere every hour.
Tungsten has a heat of vaporization of 800 kJ/mol, so it takes 4,351,600 kJ of energy to turn 1 ton of tungsten into gas.
Unfortunately your tungsten "bullet" sphere is getting hit with 37,332,000 kJ of energy per hour so within the first 7 minutes of its 7 hour journey it's become a cloud of atoms glowing hot at about 5555 degrees Celsius...
At this point the calculations get harder because it's no longer a nice neat sphere; it's a cloud of super-high temperature gas traveling so fast that it's glowing like the heart of a star and it's very hot gas so the cloud is expanding very fast. It's now hitting even more of the random atoms in space as it's approaching earth. Assuming the sphere was aimed to hit earth perfectly dead center I can't even tell you if all of the gas would actually hit the earth or if the hot cloud of gas would expand from itself fast enough to mostly miss the earth. I don't know how much extra energy the cloud would lose to hitting atoms along the way after the sphere melts and turns into gas since it now has a massive surface area...
But let's say that the cloud all still hits the earth's atmosphere, but over the 6 hours and 50 minutes since it passed Pluto it's spread out to hit the entire facing side of the earth fairly evenly and none misses and it's still carrying most of its energy.
As in L. Dutche's answer, according to Wolfram Alpha, the relativistic kinetic energy of such a bullet would be 6.265 x 10^21 J, or 1.5 million megatons.
... but... The total power output of the Sun hitting earth is about 4.3 × 10^20 J per hour hitting atmosphere on the side facing the sun.
The bullet is carrying far less energy than a single days worth of sunlight.
Cosmic rays can't pierce the earths atmosphere and the bullet is now more similar to a giant cloud of cosmic rays, but each with far less energy than the "Oh My God particle".
Everything in orbit on that side of the earth would be hit with a huge dose of cosmic rays.
The hard radiation would be caught by the atmosphere and some heat would make it to the surface... but the atmosphere is vast and that much isn't even enough to raise the temperature of the gas on that side of the planet by 1 degree Celsius average.
I suspect anyone outside might get flash burns. I don't know if the energy would be enough to start major fires. To an extent the more energy ends up as high energy particles and radiation the less hits the earth surface as heat.
But to answer your question: As it approached the gas cloud that used to be the bullet would burn brightly in the sky as it impacted gas and dust ... then for a brief moment the entire sky of half the earth would blaze with light thousands of times brighter than sun... it might burn things on the surface.... it might shower a significant amount of secondary radiation... but the tectonic plates would be safe.
Edit: re Yakk's comments below, as the cloud is passing through space there may also be bursts of something like space-lightning as the cloud interacts with subatomic particles that strip away electrons and depending on how far away from earth the bullet starts ..
Napkin math says this means a spread of E-5 (i.e., every E5 meters it spreads out 1 meter), which means over 100 AU that is 150,000 km. That is order-of-order-of-magnitude size of Earth.
~Yakk
So the cloud may partly miss earth since the diameter of earth is only 12,742 km, so it may be a little bit like getting caught in the middle of a 'shotgun blast' of space-lightning-filled hard radiation with much passing either side of the earth.
answered Dec 4 '18 at 13:02
MurphyMurphy
24.1k24787
$endgroup$
4
$begingroup$
The solar wind density you quote is for earth orbit (hypertextbook.com/facts/2005/RandyAbbas.shtml). Presumably density falls off as 1/r^2 as you get farther from the sun.
$endgroup$
– Peter Cordes
Dec 5 '18 at 1:36
1
$begingroup$
So they would want to send a 1-ton dart to make sure it all gets there?
$endgroup$
– corsiKa
Dec 5 '18 at 3:07
29
$begingroup$
While this is an interesting reframing of the the question, I don't see how it answers the question and am surprised it was accepted. The question was not "what if a 1 ton sphere of tungsten entered our solar system on a trajectory towards Earth?" It was "what if a 1 ton sphere of tungsten hit Earth?"
$endgroup$
– Kevin
Dec 5 '18 at 13:54
1
$begingroup$
Heat of vaporization is typically defined as the enthalpy required to transition from a liquid state to a vapor state. If this is the case, you will need to account for the heat of fusion as well (not that it will likely change the answer much)
$endgroup$
– Aliden
Dec 5 '18 at 15:19
2
$begingroup$
Did you notice the pun hidden in your use of Wolfram Alpha to make computations about a tungsten bullet?
$endgroup$
– Hagen von Eitzen
Dec 5 '18 at 21:02
|
show 26 more comments
$begingroup$
This turned out unexpectedly fun... and for once the answer to a question involving 99.99% of the speed of light isn't "everybody dies"
Where is this sphere being fired from?
If it's from outside the solar system then hitting the earth as a sphere is.... a problem...
The volume of 1000 kg of tungsten = 51.9 L
Radius = 0.23 m
That's 5439.5 moles of tungsten.
As the sphere approaches from the orbit of Pluto we can estimate how much matter it would hit.
We can treat the space it passes through as a cylinder with radius 0.23 m and height of 7.5 billion kilometers.
It would take our projectile about 7 hours to travel that distance.
It would pass through 1246 km^3 (cubic kilometers) of space.
In the solar system with the solar wind the density of atoms is 2x10^7 per cubic meter, mostly hydrogen or helium.
Treating it all as hydrogen for simplicity that gives us 0.04171 mg of hydrogen.
This gives us 261.3 GJ (gigajoules) or 72.59 MW h (megawatt hours) as the approximate energy involved in the collisions between the fine mist of gas in the solar system and the bullet.
That's the energy of the atoms hitting the front of the bullet, and most of the energy would be effectively dumped into the metal.
Given this is over 7 hours that means there's something like 10.37 MW of energy being pumped into the sphere every hour.
Tungsten has a heat of vaporization of 800 kJ/mol, so it takes 4,351,600 kJ of energy to turn 1 ton of tungsten into gas.
Unfortunately your tungsten "bullet" sphere is getting hit with 37,332,000 kJ of energy per hour so within the first 7 minutes of its 7 hour journey it's become a cloud of atoms glowing hot at about 5555 degrees Celsius...
At this point the calculations get harder because it's no longer a nice neat sphere; it's a cloud of super-high temperature gas traveling so fast that it's glowing like the heart of a star and it's very hot gas so the cloud is expanding very fast. It's now hitting even more of the random atoms in space as it's approaching earth. Assuming the sphere was aimed to hit earth perfectly dead center I can't even tell you if all of the gas would actually hit the earth or if the hot cloud of gas would expand from itself fast enough to mostly miss the earth. I don't know how much extra energy the cloud would lose to hitting atoms along the way after the sphere melts and turns into gas since it now has a massive surface area...
But let's say that the cloud all still hits the earth's atmosphere, but over the 6 hours and 50 minutes since it passed Pluto it's spread out to hit the entire facing side of the earth fairly evenly and none misses and it's still carrying most of its energy.
As in L. Dutche's answer, according to Wolfram Alpha, the relativistic kinetic energy of such a bullet would be 6.265 x 10^21 J, or 1.5 million megatons.
... but... The total power output of the Sun hitting earth is about 4.3 × 10^20 J per hour hitting atmosphere on the side facing the sun.
The bullet is carrying far less energy than a single days worth of sunlight.
Cosmic rays can't pierce the earths atmosphere and the bullet is now more similar to a giant cloud of cosmic rays, but each with far less energy than the "Oh My God particle".
Everything in orbit on that side of the earth would be hit with a huge dose of cosmic rays.
The hard radiation would be caught by the atmosphere and some heat would make it to the surface... but the atmosphere is vast and that much isn't even enough to raise the temperature of the gas on that side of the planet by 1 degree Celsius average.
I suspect anyone outside might get flash burns. I don't know if the energy would be enough to start major fires. To an extent the more energy ends up as high energy particles and radiation the less hits the earth surface as heat.
But to answer your question: As it approached the gas cloud that used to be the bullet would burn brightly in the sky as it impacted gas and dust ... then for a brief moment the entire sky of half the earth would blaze with light thousands of times brighter than sun... it might burn things on the surface.... it might shower a significant amount of secondary radiation... but the tectonic plates would be safe.
Edit: re Yakk's comments below, as the cloud is passing through space there may also be bursts of something like space-lightning as the cloud interacts with subatomic particles that strip away electrons and depending on how far away from earth the bullet starts ..
Napkin math says this means a spread of E-5 (i.e., every E5 meters it spreads out 1 meter), which means over 100 AU that is 150,000 km. That is order-of-order-of-magnitude size of Earth.
~Yakk
So the cloud may partly miss earth since the diameter of earth is only 12,742 km, so it may be a little bit like getting caught in the middle of a 'shotgun blast' of space-lightning-filled hard radiation with much passing either side of the earth.
answered Dec 4 '18 at 13:02
MurphyMurphy
24.1k24787
$endgroup$
This turned out unexpectedly fun... and for once the answer to a question involving 99.99% of the speed of light isn't "everybody dies"
Where is this sphere being fired from?
If it's from outside the solar system then hitting the earth as a sphere is.... a problem...
The volume of 1000 kg of tungsten = 51.9 L
Radius = 0.23 m
That's 5439.5 moles of tungsten.
As the sphere approaches from the orbit of Pluto we can estimate how much matter it would hit.
We can treat the space it passes through as a cylinder with radius 0.23 m and height of 7.5 billion kilometers.
It would take our projectile about 7 hours to travel that distance.
It would pass through 1246 km^3 (cubic kilometers) of space.
In the solar system with the solar wind the density of atoms is 2x10^7 per cubic meter, mostly hydrogen or helium.
Treating it all as hydrogen for simplicity that gives us 0.04171 mg of hydrogen.
This gives us 261.3 GJ (gigajoules) or 72.59 MW h (megawatt hours) as the approximate energy involved in the collisions between the fine mist of gas in the solar system and the bullet.
That's the energy of the atoms hitting the front of the bullet, and most of the energy would be effectively dumped into the metal.
Given this is over 7 hours that means there's something like 10.37 MW of energy being pumped into the sphere every hour.
Tungsten has a heat of vaporization of 800 kJ/mol, so it takes 4,351,600 kJ of energy to turn 1 ton of tungsten into gas.
Unfortunately your tungsten "bullet" sphere is getting hit with 37,332,000 kJ of energy per hour so within the first 7 minutes of its 7 hour journey it's become a cloud of atoms glowing hot at about 5555 degrees Celsius...
At this point the calculations get harder because it's no longer a nice neat sphere; it's a cloud of super-high temperature gas traveling so fast that it's glowing like the heart of a star and it's very hot gas so the cloud is expanding very fast. It's now hitting even more of the random atoms in space as it's approaching earth. Assuming the sphere was aimed to hit earth perfectly dead center I can't even tell you if all of the gas would actually hit the earth or if the hot cloud of gas would expand from itself fast enough to mostly miss the earth. I don't know how much extra energy the cloud would lose to hitting atoms along the way after the sphere melts and turns into gas since it now has a massive surface area...
But let's say that the cloud all still hits the earth's atmosphere, but over the 6 hours and 50 minutes since it passed Pluto it's spread out to hit the entire facing side of the earth fairly evenly and none misses and it's still carrying most of its energy.
As in L. Dutche's answer, according to Wolfram Alpha, the relativistic kinetic energy of such a bullet would be 6.265 x 10^21 J, or 1.5 million megatons.
... but... The total power output of the Sun hitting earth is about 4.3 × 10^20 J per hour hitting atmosphere on the side facing the sun.
The bullet is carrying far less energy than a single days worth of sunlight.
Cosmic rays can't pierce the earths atmosphere and the bullet is now more similar to a giant cloud of cosmic rays, but each with far less energy than the "Oh My God particle".
Everything in orbit on that side of the earth would be hit with a huge dose of cosmic rays.
The hard radiation would be caught by the atmosphere and some heat would make it to the surface... but the atmosphere is vast and that much isn't even enough to raise the temperature of the gas on that side of the planet by 1 degree Celsius average.
I suspect anyone outside might get flash burns. I don't know if the energy would be enough to start major fires. To an extent the more energy ends up as high energy particles and radiation the less hits the earth surface as heat.
But to answer your question: As it approached the gas cloud that used to be the bullet would burn brightly in the sky as it impacted gas and dust ... then for a brief moment the entire sky of half the earth would blaze with light thousands of times brighter than sun... it might burn things on the surface.... it might shower a significant amount of secondary radiation... but the tectonic plates would be safe.
Edit: re Yakk's comments below, as the cloud is passing through space there may also be bursts of something like space-lightning as the cloud interacts with subatomic particles that strip away electrons and depending on how far away from earth the bullet starts ..
Napkin math says this means a spread of E-5 (i.e., every E5 meters it spreads out 1 meter), which means over 100 AU that is 150,000 km. That is order-of-order-of-magnitude size of Earth.
~Yakk
So the cloud may partly miss earth since the diameter of earth is only 12,742 km, so it may be a little bit like getting caught in the middle of a 'shotgun blast' of space-lightning-filled hard radiation with much passing either side of the earth.
answered Dec 4 '18 at 13:02
MurphyMurphy
24.1k24787
edited Dec 7 '18 at 16:29
answered Dec 4 '18 at 13:02
MurphyMurphy
24.1k24787
answered Dec 4 '18 at 13:02
MurphyMurphy
24.1k24787
answered Dec 4 '18 at 13:02
MurphyMurphy
24.1k24787
24.1k24787
4
$begingroup$
The solar wind density you quote is for earth orbit (hypertextbook.com/facts/2005/RandyAbbas.shtml). Presumably density falls off as 1/r^2 as you get farther from the sun.
$endgroup$
– Peter Cordes
Dec 5 '18 at 1:36
1
$begingroup$
So they would want to send a 1-ton dart to make sure it all gets there?
$endgroup$
– corsiKa
Dec 5 '18 at 3:07
29
$begingroup$
While this is an interesting reframing of the the question, I don't see how it answers the question and am surprised it was accepted. The question was not "what if a 1 ton sphere of tungsten entered our solar system on a trajectory towards Earth?" It was "what if a 1 ton sphere of tungsten hit Earth?"
$endgroup$
– Kevin
Dec 5 '18 at 13:54
1
$begingroup$
Heat of vaporization is typically defined as the enthalpy required to transition from a liquid state to a vapor state. If this is the case, you will need to account for the heat of fusion as well (not that it will likely change the answer much)
$endgroup$
– Aliden
Dec 5 '18 at 15:19
2
$begingroup$
Did you notice the pun hidden in your use of Wolfram Alpha to make computations about a tungsten bullet?
$endgroup$
– Hagen von Eitzen
Dec 5 '18 at 21:02
|
show 26 more comments
4
$begingroup$
The solar wind density you quote is for earth orbit (hypertextbook.com/facts/2005/RandyAbbas.shtml). Presumably density falls off as 1/r^2 as you get farther from the sun.
$endgroup$
– Peter Cordes
Dec 5 '18 at 1:36
1
$begingroup$
So they would want to send a 1-ton dart to make sure it all gets there?
$endgroup$
– corsiKa
Dec 5 '18 at 3:07
29
$begingroup$
While this is an interesting reframing of the the question, I don't see how it answers the question and am surprised it was accepted. The question was not "what if a 1 ton sphere of tungsten entered our solar system on a trajectory towards Earth?" It was "what if a 1 ton sphere of tungsten hit Earth?"
$endgroup$
– Kevin
Dec 5 '18 at 13:54
1
$begingroup$
Heat of vaporization is typically defined as the enthalpy required to transition from a liquid state to a vapor state. If this is the case, you will need to account for the heat of fusion as well (not that it will likely change the answer much)
$endgroup$
– Aliden
Dec 5 '18 at 15:19
2
$begingroup$
Did you notice the pun hidden in your use of Wolfram Alpha to make computations about a tungsten bullet?
$endgroup$
– Hagen von Eitzen
Dec 5 '18 at 21:02
4
4
$begingroup$
The solar wind density you quote is for earth orbit (hypertextbook.com/facts/2005/RandyAbbas.shtml). Presumably density falls off as 1/r^2 as you get farther from the sun.
$endgroup$
– Peter Cordes
Dec 5 '18 at 1:36
$begingroup$
The solar wind density you quote is for earth orbit (hypertextbook.com/facts/2005/RandyAbbas.shtml). Presumably density falls off as 1/r^2 as you get farther from the sun.
$endgroup$
– Peter Cordes
Dec 5 '18 at 1:36
1
1
$begingroup$
So they would want to send a 1-ton dart to make sure it all gets there?
$endgroup$
– corsiKa
Dec 5 '18 at 3:07
$begingroup$
So they would want to send a 1-ton dart to make sure it all gets there?
$endgroup$
– corsiKa
Dec 5 '18 at 3:07
29
29
$begingroup$
While this is an interesting reframing of the the question, I don't see how it answers the question and am surprised it was accepted. The question was not "what if a 1 ton sphere of tungsten entered our solar system on a trajectory towards Earth?" It was "what if a 1 ton sphere of tungsten hit Earth?"
$endgroup$
– Kevin
Dec 5 '18 at 13:54
$begingroup$
While this is an interesting reframing of the the question, I don't see how it answers the question and am surprised it was accepted. The question was not "what if a 1 ton sphere of tungsten entered our solar system on a trajectory towards Earth?" It was "what if a 1 ton sphere of tungsten hit Earth?"
$endgroup$
– Kevin
Dec 5 '18 at 13:54
1
1
$begingroup$
Heat of vaporization is typically defined as the enthalpy required to transition from a liquid state to a vapor state. If this is the case, you will need to account for the heat of fusion as well (not that it will likely change the answer much)
$endgroup$
– Aliden
Dec 5 '18 at 15:19
$begingroup$
Heat of vaporization is typically defined as the enthalpy required to transition from a liquid state to a vapor state. If this is the case, you will need to account for the heat of fusion as well (not that it will likely change the answer much)
$endgroup$
– Aliden
Dec 5 '18 at 15:19
2
2
$begingroup$
Did you notice the pun hidden in your use of Wolfram Alpha to make computations about a tungsten bullet?
$endgroup$
– Hagen von Eitzen
Dec 5 '18 at 21:02
$begingroup$
Did you notice the pun hidden in your use of Wolfram Alpha to make computations about a tungsten bullet?
$endgroup$
– Hagen von Eitzen
Dec 5 '18 at 21:02
|
show 26 more comments
$begingroup$
According to WolphramAlpha, the relativistic kinetic energy of such a bullet would be $6.265 cdot 10^{21} mathrm J$, or 1.5 million megatons.
The gravitational binding energy of Earth is $2 cdot 10^{32} mathrm J$, therefore we can stay assured that the planet won't be completely wiped out.
Quoting from this useful page, the impact energy would be comparable to the last eruption of Yellowstone super volcano. This event left a large deposit of tuffs, known as Lava Creek Tuffs. The following picture shows their extension:
The Lava Creek Tuff is distributed in a radial pattern around the caldera and is formed of 1,000 km3 (240 cu mi) of ignimbrites.
Lava Creek Tuff ranges in color from light gray to pale red in some locales. Rock texture of the tuff ranges from fine-grained to aphanitic and is densely welded. The maximum thickness of the tuff layer is approximately 180–200 m.
The relativistic impact would be for sure a global cataclysm: the spallation would probably temporarily deform the planet, and the following relaxation would result in increased volcanic activity.
The resulting emission of ashes and gases would severely impact life, with mass extinction effect.
An observer in a suitable position in the Solar system would notice a bright flash during the impact, probably followed by an increased IR emission due to the thermal effects of volcanic eruptions.
To give you a reference of how bright would the flash, the impact energy is about 1/10 of the total solar energy striking the Earth in one day, and it is released in a much shorter time. I assume that for few seconds the Sun and Earth would appear like twin stars in the sky.
answered Dec 4 '18 at 7:59
L.Dutch♦L.Dutch
82.4k27197407
$endgroup$
$begingroup$
You might add that it corresponds to (gamma-1)mc². Where gamma=1/sqrt(1-(v/c)²). And furthermore, that would be the equivalent of about 30,000 Tsar bomba exploding at once.
$endgroup$
– bilbo_pingouin
Dec 4 '18 at 8:30
8
$begingroup$
"A bright flash" -- you can do better. How bright? "Can see in telescope", "visible to the naked eye from Mars", "like a camera flash", "beings on mars go blind if looking in the direction of the the Earth".
$endgroup$
– Yakk
Dec 4 '18 at 14:23
$begingroup$
Care to explain how to do this in WA so that every smash my planet question can just point here?
$endgroup$
– Mazura
Dec 5 '18 at 0:48
1
$begingroup$
"I assume that for few seconds the Sun and Earth would appear like twin stars in the sky." --- where would it look like that? On Mars?
$endgroup$
– BЈовић
Dec 5 '18 at 12:37
1
$begingroup$
'the median length of volcanic eruptions is 7 weeks' it seems intuitive that a more concentrated release of energy would have different characteristics, especially given the importance of direction of motion in kinetic events, resulting in an effect more akin to a nuclear pumped laser than a traditional kinetic event.
$endgroup$
– Giu Piete
Dec 5 '18 at 13:36
|
show 2 more comments
$begingroup$
According to WolphramAlpha, the relativistic kinetic energy of such a bullet would be $6.265 cdot 10^{21} mathrm J$, or 1.5 million megatons.
The gravitational binding energy of Earth is $2 cdot 10^{32} mathrm J$, therefore we can stay assured that the planet won't be completely wiped out.
Quoting from this useful page, the impact energy would be comparable to the last eruption of Yellowstone super volcano. This event left a large deposit of tuffs, known as Lava Creek Tuffs. The following picture shows their extension:
The Lava Creek Tuff is distributed in a radial pattern around the caldera and is formed of 1,000 km3 (240 cu mi) of ignimbrites.
Lava Creek Tuff ranges in color from light gray to pale red in some locales. Rock texture of the tuff ranges from fine-grained to aphanitic and is densely welded. The maximum thickness of the tuff layer is approximately 180–200 m.
The relativistic impact would be for sure a global cataclysm: the spallation would probably temporarily deform the planet, and the following relaxation would result in increased volcanic activity.
The resulting emission of ashes and gases would severely impact life, with mass extinction effect.
An observer in a suitable position in the Solar system would notice a bright flash during the impact, probably followed by an increased IR emission due to the thermal effects of volcanic eruptions.
To give you a reference of how bright would the flash, the impact energy is about 1/10 of the total solar energy striking the Earth in one day, and it is released in a much shorter time. I assume that for few seconds the Sun and Earth would appear like twin stars in the sky.
answered Dec 4 '18 at 7:59
L.Dutch♦L.Dutch
82.4k27197407
$endgroup$
$begingroup$
You might add that it corresponds to (gamma-1)mc². Where gamma=1/sqrt(1-(v/c)²). And furthermore, that would be the equivalent of about 30,000 Tsar bomba exploding at once.
$endgroup$
– bilbo_pingouin
Dec 4 '18 at 8:30
8
$begingroup$
"A bright flash" -- you can do better. How bright? "Can see in telescope", "visible to the naked eye from Mars", "like a camera flash", "beings on mars go blind if looking in the direction of the the Earth".
$endgroup$
– Yakk
Dec 4 '18 at 14:23
$begingroup$
Care to explain how to do this in WA so that every smash my planet question can just point here?
$endgroup$
– Mazura
Dec 5 '18 at 0:48
1
$begingroup$
"I assume that for few seconds the Sun and Earth would appear like twin stars in the sky." --- where would it look like that? On Mars?
$endgroup$
– BЈовић
Dec 5 '18 at 12:37
1
$begingroup$
'the median length of volcanic eruptions is 7 weeks' it seems intuitive that a more concentrated release of energy would have different characteristics, especially given the importance of direction of motion in kinetic events, resulting in an effect more akin to a nuclear pumped laser than a traditional kinetic event.
$endgroup$
– Giu Piete
Dec 5 '18 at 13:36
|
show 2 more comments
$begingroup$
According to WolphramAlpha, the relativistic kinetic energy of such a bullet would be $6.265 cdot 10^{21} mathrm J$, or 1.5 million megatons.
The gravitational binding energy of Earth is $2 cdot 10^{32} mathrm J$, therefore we can stay assured that the planet won't be completely wiped out.
Quoting from this useful page, the impact energy would be comparable to the last eruption of Yellowstone super volcano. This event left a large deposit of tuffs, known as Lava Creek Tuffs. The following picture shows their extension:
The Lava Creek Tuff is distributed in a radial pattern around the caldera and is formed of 1,000 km3 (240 cu mi) of ignimbrites.
Lava Creek Tuff ranges in color from light gray to pale red in some locales. Rock texture of the tuff ranges from fine-grained to aphanitic and is densely welded. The maximum thickness of the tuff layer is approximately 180–200 m.
The relativistic impact would be for sure a global cataclysm: the spallation would probably temporarily deform the planet, and the following relaxation would result in increased volcanic activity.
The resulting emission of ashes and gases would severely impact life, with mass extinction effect.
An observer in a suitable position in the Solar system would notice a bright flash during the impact, probably followed by an increased IR emission due to the thermal effects of volcanic eruptions.
To give you a reference of how bright would the flash, the impact energy is about 1/10 of the total solar energy striking the Earth in one day, and it is released in a much shorter time. I assume that for few seconds the Sun and Earth would appear like twin stars in the sky.
answered Dec 4 '18 at 7:59
L.Dutch♦L.Dutch
82.4k27197407
$endgroup$
According to WolphramAlpha, the relativistic kinetic energy of such a bullet would be $6.265 cdot 10^{21} mathrm J$, or 1.5 million megatons.
The gravitational binding energy of Earth is $2 cdot 10^{32} mathrm J$, therefore we can stay assured that the planet won't be completely wiped out.
Quoting from this useful page, the impact energy would be comparable to the last eruption of Yellowstone super volcano. This event left a large deposit of tuffs, known as Lava Creek Tuffs. The following picture shows their extension:
The Lava Creek Tuff is distributed in a radial pattern around the caldera and is formed of 1,000 km3 (240 cu mi) of ignimbrites.
Lava Creek Tuff ranges in color from light gray to pale red in some locales. Rock texture of the tuff ranges from fine-grained to aphanitic and is densely welded. The maximum thickness of the tuff layer is approximately 180–200 m.
The relativistic impact would be for sure a global cataclysm: the spallation would probably temporarily deform the planet, and the following relaxation would result in increased volcanic activity.
The resulting emission of ashes and gases would severely impact life, with mass extinction effect.
An observer in a suitable position in the Solar system would notice a bright flash during the impact, probably followed by an increased IR emission due to the thermal effects of volcanic eruptions.
To give you a reference of how bright would the flash, the impact energy is about 1/10 of the total solar energy striking the Earth in one day, and it is released in a much shorter time. I assume that for few seconds the Sun and Earth would appear like twin stars in the sky.
answered Dec 4 '18 at 7:59
L.Dutch♦L.Dutch
82.4k27197407
edited Dec 5 '18 at 0:30
answered Dec 4 '18 at 7:59
L.Dutch♦L.Dutch
82.4k27197407
answered Dec 4 '18 at 7:59
L.Dutch♦L.Dutch
82.4k27197407
answered Dec 4 '18 at 7:59
L.Dutch♦L.Dutch
82.4k27197407
82.4k27197407
$begingroup$
You might add that it corresponds to (gamma-1)mc². Where gamma=1/sqrt(1-(v/c)²). And furthermore, that would be the equivalent of about 30,000 Tsar bomba exploding at once.
$endgroup$
– bilbo_pingouin
Dec 4 '18 at 8:30
8
$begingroup$
"A bright flash" -- you can do better. How bright? "Can see in telescope", "visible to the naked eye from Mars", "like a camera flash", "beings on mars go blind if looking in the direction of the the Earth".
$endgroup$
– Yakk
Dec 4 '18 at 14:23
$begingroup$
Care to explain how to do this in WA so that every smash my planet question can just point here?
$endgroup$
– Mazura
Dec 5 '18 at 0:48
1
$begingroup$
"I assume that for few seconds the Sun and Earth would appear like twin stars in the sky." --- where would it look like that? On Mars?
$endgroup$
– BЈовић
Dec 5 '18 at 12:37
1
$begingroup$
'the median length of volcanic eruptions is 7 weeks' it seems intuitive that a more concentrated release of energy would have different characteristics, especially given the importance of direction of motion in kinetic events, resulting in an effect more akin to a nuclear pumped laser than a traditional kinetic event.
$endgroup$
– Giu Piete
Dec 5 '18 at 13:36
|
show 2 more comments
$begingroup$
You might add that it corresponds to (gamma-1)mc². Where gamma=1/sqrt(1-(v/c)²). And furthermore, that would be the equivalent of about 30,000 Tsar bomba exploding at once.
$endgroup$
– bilbo_pingouin
Dec 4 '18 at 8:30
8
$begingroup$
"A bright flash" -- you can do better. How bright? "Can see in telescope", "visible to the naked eye from Mars", "like a camera flash", "beings on mars go blind if looking in the direction of the the Earth".
$endgroup$
– Yakk
Dec 4 '18 at 14:23
$begingroup$
Care to explain how to do this in WA so that every smash my planet question can just point here?
$endgroup$
– Mazura
Dec 5 '18 at 0:48
1
$begingroup$
"I assume that for few seconds the Sun and Earth would appear like twin stars in the sky." --- where would it look like that? On Mars?
$endgroup$
– BЈовић
Dec 5 '18 at 12:37
1
$begingroup$
'the median length of volcanic eruptions is 7 weeks' it seems intuitive that a more concentrated release of energy would have different characteristics, especially given the importance of direction of motion in kinetic events, resulting in an effect more akin to a nuclear pumped laser than a traditional kinetic event.
$endgroup$
– Giu Piete
Dec 5 '18 at 13:36
$begingroup$
You might add that it corresponds to (gamma-1)mc². Where gamma=1/sqrt(1-(v/c)²). And furthermore, that would be the equivalent of about 30,000 Tsar bomba exploding at once.
$endgroup$
– bilbo_pingouin
Dec 4 '18 at 8:30
$begingroup$
You might add that it corresponds to (gamma-1)mc². Where gamma=1/sqrt(1-(v/c)²). And furthermore, that would be the equivalent of about 30,000 Tsar bomba exploding at once.
$endgroup$
– bilbo_pingouin
Dec 4 '18 at 8:30
8
8
$begingroup$
"A bright flash" -- you can do better. How bright? "Can see in telescope", "visible to the naked eye from Mars", "like a camera flash", "beings on mars go blind if looking in the direction of the the Earth".
$endgroup$
– Yakk
Dec 4 '18 at 14:23
$begingroup$
"A bright flash" -- you can do better. How bright? "Can see in telescope", "visible to the naked eye from Mars", "like a camera flash", "beings on mars go blind if looking in the direction of the the Earth".
$endgroup$
– Yakk
Dec 4 '18 at 14:23
$begingroup$
Care to explain how to do this in WA so that every smash my planet question can just point here?
$endgroup$
– Mazura
Dec 5 '18 at 0:48
$begingroup$
Care to explain how to do this in WA so that every smash my planet question can just point here?
$endgroup$
– Mazura
Dec 5 '18 at 0:48
1
1
$begingroup$
"I assume that for few seconds the Sun and Earth would appear like twin stars in the sky." --- where would it look like that? On Mars?
$endgroup$
– BЈовић
Dec 5 '18 at 12:37
$begingroup$
"I assume that for few seconds the Sun and Earth would appear like twin stars in the sky." --- where would it look like that? On Mars?
$endgroup$
– BЈовић
Dec 5 '18 at 12:37
1
1
$begingroup$
'the median length of volcanic eruptions is 7 weeks' it seems intuitive that a more concentrated release of energy would have different characteristics, especially given the importance of direction of motion in kinetic events, resulting in an effect more akin to a nuclear pumped laser than a traditional kinetic event.
$endgroup$
– Giu Piete
Dec 5 '18 at 13:36
$begingroup$
'the median length of volcanic eruptions is 7 weeks' it seems intuitive that a more concentrated release of energy would have different characteristics, especially given the importance of direction of motion in kinetic events, resulting in an effect more akin to a nuclear pumped laser than a traditional kinetic event.
$endgroup$
– Giu Piete
Dec 5 '18 at 13:36
|
show 2 more comments
$begingroup$
I think that with the size and speed it would be quite powerful. First of all the impact would be virtually instantaneous. This would cause all the force to be extremely concentrated. If it's moving 99% the speed of light, well, imagine all that power compressed into a second--now imagine it being a million times faster than that. Now imagine it being WAY faster than that. The damage of the impact is going to be based on the force multiplied by the inverse of time--and as time approaches zero...
answered Dec 4 '18 at 17:32
Bill KBill K
99157
$endgroup$
20
$begingroup$
Cool image, but nothing like what would really happen.
$endgroup$
– zeta-band
Dec 4 '18 at 19:22
4
$begingroup$
In the baseball XKCD what-if.xkcd.com/1 mentioned above, the ball is much less dense and MUCH slower. It might not go straight through but it would definitely be life-ending. The diamond one would be closer: "The energy cracks a hole in the crust and blows open a crater so big you can see the molten mantle. This delivers the energy of 50 dinosaur-killing Chicxulub impacts—enough to cause a mass extinction, if not end life completely." (Although the diamond they are talking about is bigger I think it would be more or less on that scale)
$endgroup$
– Bill K
Dec 4 '18 at 20:03
1
$begingroup$
Even if ti hits the surface relatively intact, I doubt it penetrates deeper than a couple of miles, the vaporized tungsten is going to interact with the rock really strongly.
$endgroup$
– zeta-band
Dec 4 '18 at 20:08
2
$begingroup$
The question was if it hit the world, but as the XKCD does anything traveling at that speed would not be intact to start out with. It also wouldn't impact so much as phase. It would also be a strange shaped and be enveloped in a giant fireball with the power of multiple nuclear bombs behind it. With a speed like that it wouldn't have any time to break up and wouldn't actually interact much with the atoms it passes through. I'm thinking you are only considering normal physics and not relativistic.
$endgroup$
– Bill K
Dec 4 '18 at 21:36
add a comment |
$begingroup$
I think that with the size and speed it would be quite powerful. First of all the impact would be virtually instantaneous. This would cause all the force to be extremely concentrated. If it's moving 99% the speed of light, well, imagine all that power compressed into a second--now imagine it being a million times faster than that. Now imagine it being WAY faster than that. The damage of the impact is going to be based on the force multiplied by the inverse of time--and as time approaches zero...
answered Dec 4 '18 at 17:32
Bill KBill K
99157
$endgroup$
20
$begingroup$
Cool image, but nothing like what would really happen.
$endgroup$
– zeta-band
Dec 4 '18 at 19:22
4
$begingroup$
In the baseball XKCD what-if.xkcd.com/1 mentioned above, the ball is much less dense and MUCH slower. It might not go straight through but it would definitely be life-ending. The diamond one would be closer: "The energy cracks a hole in the crust and blows open a crater so big you can see the molten mantle. This delivers the energy of 50 dinosaur-killing Chicxulub impacts—enough to cause a mass extinction, if not end life completely." (Although the diamond they are talking about is bigger I think it would be more or less on that scale)
$endgroup$
– Bill K
Dec 4 '18 at 20:03
1
$begingroup$
Even if ti hits the surface relatively intact, I doubt it penetrates deeper than a couple of miles, the vaporized tungsten is going to interact with the rock really strongly.
$endgroup$
– zeta-band
Dec 4 '18 at 20:08
2
$begingroup$
The question was if it hit the world, but as the XKCD does anything traveling at that speed would not be intact to start out with. It also wouldn't impact so much as phase. It would also be a strange shaped and be enveloped in a giant fireball with the power of multiple nuclear bombs behind it. With a speed like that it wouldn't have any time to break up and wouldn't actually interact much with the atoms it passes through. I'm thinking you are only considering normal physics and not relativistic.
$endgroup$
– Bill K
Dec 4 '18 at 21:36
add a comment |
$begingroup$
I think that with the size and speed it would be quite powerful. First of all the impact would be virtually instantaneous. This would cause all the force to be extremely concentrated. If it's moving 99% the speed of light, well, imagine all that power compressed into a second--now imagine it being a million times faster than that. Now imagine it being WAY faster than that. The damage of the impact is going to be based on the force multiplied by the inverse of time--and as time approaches zero...
answered Dec 4 '18 at 17:32
Bill KBill K
99157
$endgroup$
I think that with the size and speed it would be quite powerful. First of all the impact would be virtually instantaneous. This would cause all the force to be extremely concentrated. If it's moving 99% the speed of light, well, imagine all that power compressed into a second--now imagine it being a million times faster than that. Now imagine it being WAY faster than that. The damage of the impact is going to be based on the force multiplied by the inverse of time--and as time approaches zero...
answered Dec 4 '18 at 17:32
Bill KBill K
99157
edited Dec 4 '18 at 17:38
answered Dec 4 '18 at 17:32
Bill KBill K
99157
answered Dec 4 '18 at 17:32
Bill KBill K
99157
answered Dec 4 '18 at 17:32
Bill KBill K
99157
99157
20
$begingroup$
Cool image, but nothing like what would really happen.
$endgroup$
– zeta-band
Dec 4 '18 at 19:22
4
$begingroup$
In the baseball XKCD what-if.xkcd.com/1 mentioned above, the ball is much less dense and MUCH slower. It might not go straight through but it would definitely be life-ending. The diamond one would be closer: "The energy cracks a hole in the crust and blows open a crater so big you can see the molten mantle. This delivers the energy of 50 dinosaur-killing Chicxulub impacts—enough to cause a mass extinction, if not end life completely." (Although the diamond they are talking about is bigger I think it would be more or less on that scale)
$endgroup$
– Bill K
Dec 4 '18 at 20:03
1
$begingroup$
Even if ti hits the surface relatively intact, I doubt it penetrates deeper than a couple of miles, the vaporized tungsten is going to interact with the rock really strongly.
$endgroup$
– zeta-band
Dec 4 '18 at 20:08
2
$begingroup$
The question was if it hit the world, but as the XKCD does anything traveling at that speed would not be intact to start out with. It also wouldn't impact so much as phase. It would also be a strange shaped and be enveloped in a giant fireball with the power of multiple nuclear bombs behind it. With a speed like that it wouldn't have any time to break up and wouldn't actually interact much with the atoms it passes through. I'm thinking you are only considering normal physics and not relativistic.
$endgroup$
– Bill K
Dec 4 '18 at 21:36
add a comment |
20
$begingroup$
Cool image, but nothing like what would really happen.
$endgroup$
– zeta-band
Dec 4 '18 at 19:22
4
$begingroup$
In the baseball XKCD what-if.xkcd.com/1 mentioned above, the ball is much less dense and MUCH slower. It might not go straight through but it would definitely be life-ending. The diamond one would be closer: "The energy cracks a hole in the crust and blows open a crater so big you can see the molten mantle. This delivers the energy of 50 dinosaur-killing Chicxulub impacts—enough to cause a mass extinction, if not end life completely." (Although the diamond they are talking about is bigger I think it would be more or less on that scale)
$endgroup$
– Bill K
Dec 4 '18 at 20:03
1
$begingroup$
Even if ti hits the surface relatively intact, I doubt it penetrates deeper than a couple of miles, the vaporized tungsten is going to interact with the rock really strongly.
$endgroup$
– zeta-band
Dec 4 '18 at 20:08
2
$begingroup$
The question was if it hit the world, but as the XKCD does anything traveling at that speed would not be intact to start out with. It also wouldn't impact so much as phase. It would also be a strange shaped and be enveloped in a giant fireball with the power of multiple nuclear bombs behind it. With a speed like that it wouldn't have any time to break up and wouldn't actually interact much with the atoms it passes through. I'm thinking you are only considering normal physics and not relativistic.
$endgroup$
– Bill K
Dec 4 '18 at 21:36
20
20
$begingroup$
Cool image, but nothing like what would really happen.
$endgroup$
– zeta-band
Dec 4 '18 at 19:22
$begingroup$
Cool image, but nothing like what would really happen.
$endgroup$
– zeta-band
Dec 4 '18 at 19:22
4
4
$begingroup$
In the baseball XKCD what-if.xkcd.com/1 mentioned above, the ball is much less dense and MUCH slower. It might not go straight through but it would definitely be life-ending. The diamond one would be closer: "The energy cracks a hole in the crust and blows open a crater so big you can see the molten mantle. This delivers the energy of 50 dinosaur-killing Chicxulub impacts—enough to cause a mass extinction, if not end life completely." (Although the diamond they are talking about is bigger I think it would be more or less on that scale)
$endgroup$
– Bill K
Dec 4 '18 at 20:03
$begingroup$
In the baseball XKCD what-if.xkcd.com/1 mentioned above, the ball is much less dense and MUCH slower. It might not go straight through but it would definitely be life-ending. The diamond one would be closer: "The energy cracks a hole in the crust and blows open a crater so big you can see the molten mantle. This delivers the energy of 50 dinosaur-killing Chicxulub impacts—enough to cause a mass extinction, if not end life completely." (Although the diamond they are talking about is bigger I think it would be more or less on that scale)
$endgroup$
– Bill K
Dec 4 '18 at 20:03
1
1
$begingroup$
Even if ti hits the surface relatively intact, I doubt it penetrates deeper than a couple of miles, the vaporized tungsten is going to interact with the rock really strongly.
$endgroup$
– zeta-band
Dec 4 '18 at 20:08
$begingroup$
Even if ti hits the surface relatively intact, I doubt it penetrates deeper than a couple of miles, the vaporized tungsten is going to interact with the rock really strongly.
$endgroup$
– zeta-band
Dec 4 '18 at 20:08
2
2
$begingroup$
The question was if it hit the world, but as the XKCD does anything traveling at that speed would not be intact to start out with. It also wouldn't impact so much as phase. It would also be a strange shaped and be enveloped in a giant fireball with the power of multiple nuclear bombs behind it. With a speed like that it wouldn't have any time to break up and wouldn't actually interact much with the atoms it passes through. I'm thinking you are only considering normal physics and not relativistic.
$endgroup$
– Bill K
Dec 4 '18 at 21:36
$begingroup$
The question was if it hit the world, but as the XKCD does anything traveling at that speed would not be intact to start out with. It also wouldn't impact so much as phase. It would also be a strange shaped and be enveloped in a giant fireball with the power of multiple nuclear bombs behind it. With a speed like that it wouldn't have any time to break up and wouldn't actually interact much with the atoms it passes through. I'm thinking you are only considering normal physics and not relativistic.
$endgroup$
– Bill K
Dec 4 '18 at 21:36
add a comment |
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$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– James♦
Dec 6 '18 at 5:50
$begingroup$
Duplicate of: worldbuilding.stackexchange.com/questions/112984/…
$endgroup$
– elemtilas
Dec 6 '18 at 13:59
$begingroup$
Possible duplicate of What would happen if the Earth struck a tiny but immovable object
$endgroup$
– elemtilas
Dec 6 '18 at 14:00
$begingroup$
Basically, it's just a matter of converting the kinetic energy (mass in kg times velocity in m/s gives kinetic energy in Joules) of the impact into megatons (4x10^15J). How that deforms the planet might be best asked and tagged as "astrophysics" on the physics stack exchange, though.
$endgroup$
– Dewi Morgan
Dec 6 '18 at 23:11
$begingroup$
Seems relevant: what-if.xkcd.com/1
$endgroup$
– Joshua Drake
Dec 7 '18 at 0:46