Proabability in Scrabble expected number does it take to draw a blank,(yes replacement)












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In the game of Scrabble, players begin by drawing 7 tiles from a bag containing 100 tiles, 2 of which are blank. A player cheats by looking at the first tile he draws, and if it is not blank, he replaces the tile and draws again, repeating this process until he draws a blank tile. What is the expected number of draws this player must make until he draws a blank tile?










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    In the game of Scrabble, players begin by drawing 7 tiles from a bag containing 100 tiles, 2 of which are blank. A player cheats by looking at the first tile he draws, and if it is not blank, he replaces the tile and draws again, repeating this process until he draws a blank tile. What is the expected number of draws this player must make until he draws a blank tile?










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      In the game of Scrabble, players begin by drawing 7 tiles from a bag containing 100 tiles, 2 of which are blank. A player cheats by looking at the first tile he draws, and if it is not blank, he replaces the tile and draws again, repeating this process until he draws a blank tile. What is the expected number of draws this player must make until he draws a blank tile?










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      In the game of Scrabble, players begin by drawing 7 tiles from a bag containing 100 tiles, 2 of which are blank. A player cheats by looking at the first tile he draws, and if it is not blank, he replaces the tile and draws again, repeating this process until he draws a blank tile. What is the expected number of draws this player must make until he draws a blank tile?







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      asked Dec 22 '18 at 20:00









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          Let $X$ be the number of draws the player has to make to draw a blank. The probability that any given draw is a success is $frac{1}{50}$ and we continue until we succeed so $X$ is geometrically distributed with parameter $frac{1}{50}$.



          The expected value of a geometrically distributed random variable with probability $p$ is $frac{1}{p}$, so in your case, the expected number of draws the player must make is $50$.






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            $begingroup$

            Let $X$ be the number of draws the player has to make to draw a blank. The probability that any given draw is a success is $frac{1}{50}$ and we continue until we succeed so $X$ is geometrically distributed with parameter $frac{1}{50}$.



            The expected value of a geometrically distributed random variable with probability $p$ is $frac{1}{p}$, so in your case, the expected number of draws the player must make is $50$.






            share|cite|improve this answer









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              $begingroup$

              Let $X$ be the number of draws the player has to make to draw a blank. The probability that any given draw is a success is $frac{1}{50}$ and we continue until we succeed so $X$ is geometrically distributed with parameter $frac{1}{50}$.



              The expected value of a geometrically distributed random variable with probability $p$ is $frac{1}{p}$, so in your case, the expected number of draws the player must make is $50$.






              share|cite|improve this answer









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                $begingroup$

                Let $X$ be the number of draws the player has to make to draw a blank. The probability that any given draw is a success is $frac{1}{50}$ and we continue until we succeed so $X$ is geometrically distributed with parameter $frac{1}{50}$.



                The expected value of a geometrically distributed random variable with probability $p$ is $frac{1}{p}$, so in your case, the expected number of draws the player must make is $50$.






                share|cite|improve this answer









                $endgroup$



                Let $X$ be the number of draws the player has to make to draw a blank. The probability that any given draw is a success is $frac{1}{50}$ and we continue until we succeed so $X$ is geometrically distributed with parameter $frac{1}{50}$.



                The expected value of a geometrically distributed random variable with probability $p$ is $frac{1}{p}$, so in your case, the expected number of draws the player must make is $50$.







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                answered Dec 22 '18 at 20:05









                ODFODF

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