Compute likelihood from a uniform distribution with known $theta$
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I'm having a hard time trying to understand how to compute the likelihood from a uniform distribution with pair variables ($X_1$, $Y_1$) ...) i.i.d when $theta$ is known. Most examples I've found is with unknown $theta$.
Given a PDF
$$
X_theta(x,y)=
begin{cases}
frac{1}{8} quad -1 leq x leq 3 quad and quad 0 leq y leq 2 \
0 quad otherwise \
end{cases}
$$
And $theta = (-1, 2, 0, 3)$
How do I proceed from here?
uniform-distribution maximum-likelihood
asked Dec 8 '18 at 23:09
eagleeagle
33
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add a comment |
$begingroup$
I'm having a hard time trying to understand how to compute the likelihood from a uniform distribution with pair variables ($X_1$, $Y_1$) ...) i.i.d when $theta$ is known. Most examples I've found is with unknown $theta$.
Given a PDF
$$
X_theta(x,y)=
begin{cases}
frac{1}{8} quad -1 leq x leq 3 quad and quad 0 leq y leq 2 \
0 quad otherwise \
end{cases}
$$
And $theta = (-1, 2, 0, 3)$
How do I proceed from here?
uniform-distribution maximum-likelihood
asked Dec 8 '18 at 23:09
eagleeagle
33
$endgroup$
1
$begingroup$
You seem to have defined this distribution independently of $theta$. Surely the distribution should depend on $theta$ in some way...
$endgroup$
– Math1000
Dec 8 '18 at 23:55
add a comment |
$begingroup$
I'm having a hard time trying to understand how to compute the likelihood from a uniform distribution with pair variables ($X_1$, $Y_1$) ...) i.i.d when $theta$ is known. Most examples I've found is with unknown $theta$.
Given a PDF
$$
X_theta(x,y)=
begin{cases}
frac{1}{8} quad -1 leq x leq 3 quad and quad 0 leq y leq 2 \
0 quad otherwise \
end{cases}
$$
And $theta = (-1, 2, 0, 3)$
How do I proceed from here?
uniform-distribution maximum-likelihood
asked Dec 8 '18 at 23:09
eagleeagle
33
$endgroup$
I'm having a hard time trying to understand how to compute the likelihood from a uniform distribution with pair variables ($X_1$, $Y_1$) ...) i.i.d when $theta$ is known. Most examples I've found is with unknown $theta$.
Given a PDF
$$
X_theta(x,y)=
begin{cases}
frac{1}{8} quad -1 leq x leq 3 quad and quad 0 leq y leq 2 \
0 quad otherwise \
end{cases}
$$
And $theta = (-1, 2, 0, 3)$
How do I proceed from here?
uniform-distribution maximum-likelihood
uniform-distribution maximum-likelihood
asked Dec 8 '18 at 23:09
eagleeagle
33
asked Dec 8 '18 at 23:09
eagleeagle
33
asked Dec 8 '18 at 23:09
eagleeagle
33
asked Dec 8 '18 at 23:09
eagleeagle
33
asked Dec 8 '18 at 23:09
eagleeagle
33
33
1
$begingroup$
You seem to have defined this distribution independently of $theta$. Surely the distribution should depend on $theta$ in some way...
$endgroup$
– Math1000
Dec 8 '18 at 23:55
add a comment |
1
$begingroup$
You seem to have defined this distribution independently of $theta$. Surely the distribution should depend on $theta$ in some way...
$endgroup$
– Math1000
Dec 8 '18 at 23:55
1
1
$begingroup$
You seem to have defined this distribution independently of $theta$. Surely the distribution should depend on $theta$ in some way...
$endgroup$
– Math1000
Dec 8 '18 at 23:55
$begingroup$
You seem to have defined this distribution independently of $theta$. Surely the distribution should depend on $theta$ in some way...
$endgroup$
– Math1000
Dec 8 '18 at 23:55
add a comment |
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1
$begingroup$
You seem to have defined this distribution independently of $theta$. Surely the distribution should depend on $theta$ in some way...
$endgroup$
– Math1000
Dec 8 '18 at 23:55