How to do division with bc (bench calculator) and obtain fractional results?
bc
1/2
0
5/3
1
10/3
3
When a fraction is entered into bc, the result is truncated to an integer. How can this behavior be avoided, such that the output of a division operation is a real number?
linux bc
edited Jun 14 '18 at 13:47
Ciro Santilli 新疆改造中心 六四事件 法轮功
4,04622735
asked Jan 12 '12 at 1:42
user001user001
92041427
add a comment |
bc
1/2
0
5/3
1
10/3
3
When a fraction is entered into bc, the result is truncated to an integer. How can this behavior be avoided, such that the output of a division operation is a real number?
linux bc
edited Jun 14 '18 at 13:47
Ciro Santilli 新疆改造中心 六四事件 法轮功
4,04622735
asked Jan 12 '12 at 1:42
user001user001
92041427
add a comment |
bc
1/2
0
5/3
1
10/3
3
When a fraction is entered into bc, the result is truncated to an integer. How can this behavior be avoided, such that the output of a division operation is a real number?
linux bc
edited Jun 14 '18 at 13:47
Ciro Santilli 新疆改造中心 六四事件 法轮功
4,04622735
asked Jan 12 '12 at 1:42
user001user001
92041427
bc
1/2
0
5/3
1
10/3
3
When a fraction is entered into bc, the result is truncated to an integer. How can this behavior be avoided, such that the output of a division operation is a real number?
linux bc
linux bc
edited Jun 14 '18 at 13:47
Ciro Santilli 新疆改造中心 六四事件 法轮功
4,04622735
asked Jan 12 '12 at 1:42
user001user001
92041427
edited Jun 14 '18 at 13:47
Ciro Santilli 新疆改造中心 六四事件 法轮功
4,04622735
asked Jan 12 '12 at 1:42
user001user001
92041427
edited Jun 14 '18 at 13:47
Ciro Santilli 新疆改造中心 六四事件 法轮功
4,04622735
edited Jun 14 '18 at 13:47
Ciro Santilli 新疆改造中心 六四事件 法轮功
4,04622735
edited Jun 14 '18 at 13:47
Ciro Santilli 新疆改造中心 六四事件 法轮功
4,04622735
4,04622735
asked Jan 12 '12 at 1:42
user001user001
92041427
asked Jan 12 '12 at 1:42
user001user001
92041427
asked Jan 12 '12 at 1:42
user001user001
92041427
92041427
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
Try something like scale=2
From the man page:
scale ( expression )
The value of the scale function is the number of digits after the
decimal point in the expression.
By default, the scale is 0, so no digits after the decimal are shown.
answered Jan 12 '12 at 2:27
daxleroddaxlerod
2,22611618
add a comment |
Use the scale special variable to define decimal places:
scale=4
1/2
.5000
answered Jan 12 '12 at 2:26
PaulPaul
48.1k13122147
Thanks, you both had the right answer, and at essentially the same time.
– user001
Jan 12 '12 at 3:30
add a comment |
The easiest way is to invoke bc with the -l argument:
bc -l
Example:
$ bc -l
1/2
.50000000000000000000
5/3
1.66666666666666666666
10/3
3.33333333333333333333
edited Jan 14 at 0:07
Daniel Beck♦
92.8k12233286
answered Jan 13 at 21:51
AilurusAilurus
211
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try something like scale=2
From the man page:
scale ( expression )
The value of the scale function is the number of digits after the
decimal point in the expression.
By default, the scale is 0, so no digits after the decimal are shown.
answered Jan 12 '12 at 2:27
daxleroddaxlerod
2,22611618
add a comment |
Try something like scale=2
From the man page:
scale ( expression )
The value of the scale function is the number of digits after the
decimal point in the expression.
By default, the scale is 0, so no digits after the decimal are shown.
answered Jan 12 '12 at 2:27
daxleroddaxlerod
2,22611618
add a comment |
Try something like scale=2
From the man page:
scale ( expression )
The value of the scale function is the number of digits after the
decimal point in the expression.
By default, the scale is 0, so no digits after the decimal are shown.
answered Jan 12 '12 at 2:27
daxleroddaxlerod
2,22611618
Try something like scale=2
From the man page:
scale ( expression )
The value of the scale function is the number of digits after the
decimal point in the expression.
By default, the scale is 0, so no digits after the decimal are shown.
answered Jan 12 '12 at 2:27
daxleroddaxlerod
2,22611618
answered Jan 12 '12 at 2:27
daxleroddaxlerod
2,22611618
answered Jan 12 '12 at 2:27
daxleroddaxlerod
2,22611618
answered Jan 12 '12 at 2:27
daxleroddaxlerod
2,22611618
2,22611618
add a comment |
add a comment |
Use the scale special variable to define decimal places:
scale=4
1/2
.5000
answered Jan 12 '12 at 2:26
PaulPaul
48.1k13122147
Thanks, you both had the right answer, and at essentially the same time.
– user001
Jan 12 '12 at 3:30
add a comment |
Use the scale special variable to define decimal places:
scale=4
1/2
.5000
answered Jan 12 '12 at 2:26
PaulPaul
48.1k13122147
Thanks, you both had the right answer, and at essentially the same time.
– user001
Jan 12 '12 at 3:30
add a comment |
Use the scale special variable to define decimal places:
scale=4
1/2
.5000
answered Jan 12 '12 at 2:26
PaulPaul
48.1k13122147
Use the scale special variable to define decimal places:
scale=4
1/2
.5000
answered Jan 12 '12 at 2:26
PaulPaul
48.1k13122147
answered Jan 12 '12 at 2:26
PaulPaul
48.1k13122147
answered Jan 12 '12 at 2:26
PaulPaul
48.1k13122147
answered Jan 12 '12 at 2:26
PaulPaul
48.1k13122147
48.1k13122147
Thanks, you both had the right answer, and at essentially the same time.
– user001
Jan 12 '12 at 3:30
add a comment |
Thanks, you both had the right answer, and at essentially the same time.
– user001
Jan 12 '12 at 3:30
Thanks, you both had the right answer, and at essentially the same time.
– user001
Jan 12 '12 at 3:30
Thanks, you both had the right answer, and at essentially the same time.
– user001
Jan 12 '12 at 3:30
add a comment |
The easiest way is to invoke bc with the -l argument:
bc -l
Example:
$ bc -l
1/2
.50000000000000000000
5/3
1.66666666666666666666
10/3
3.33333333333333333333
edited Jan 14 at 0:07
Daniel Beck♦
92.8k12233286
answered Jan 13 at 21:51
AilurusAilurus
211
add a comment |
The easiest way is to invoke bc with the -l argument:
bc -l
Example:
$ bc -l
1/2
.50000000000000000000
5/3
1.66666666666666666666
10/3
3.33333333333333333333
edited Jan 14 at 0:07
Daniel Beck♦
92.8k12233286
answered Jan 13 at 21:51
AilurusAilurus
211
add a comment |
The easiest way is to invoke bc with the -l argument:
bc -l
Example:
$ bc -l
1/2
.50000000000000000000
5/3
1.66666666666666666666
10/3
3.33333333333333333333
edited Jan 14 at 0:07
Daniel Beck♦
92.8k12233286
answered Jan 13 at 21:51
AilurusAilurus
211
The easiest way is to invoke bc with the -l argument:
bc -l
Example:
$ bc -l
1/2
.50000000000000000000
5/3
1.66666666666666666666
10/3
3.33333333333333333333
edited Jan 14 at 0:07
Daniel Beck♦
92.8k12233286
answered Jan 13 at 21:51
AilurusAilurus
211
edited Jan 14 at 0:07
Daniel Beck♦
92.8k12233286
edited Jan 14 at 0:07
Daniel Beck♦
92.8k12233286
edited Jan 14 at 0:07
Daniel Beck♦
92.8k12233286
92.8k12233286
answered Jan 13 at 21:51
AilurusAilurus
211
answered Jan 13 at 21:51
AilurusAilurus
211
answered Jan 13 at 21:51
AilurusAilurus
211
211
add a comment |
add a comment |
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