2D finite difference boundary conditions for radial direction
$begingroup$
I am trying to solve Poisson's equation in an axisymmetric cylindrical domain using finite difference. So I start with my differential equation and boundary conditions and discretize them. However, I'm having trouble thinking of how to discretize the radial portion
begin{array}{lll}
frac{1}{r} frac{partial}{partial r} left(r frac{partial u}{partial r} right) + frac{partial^2 u}{partial z^2} = -frac{rho}{varepsilon_0} & longrightarrow & frac{r_{i+1/2} u_{i+1, j} - 2 r_{i} u_{i,j} + r_{i-1/2} u_{i-1, j}}{r_i Delta r^2} + frac{u_{i, j+1} - 2 u_{i, j} + u_{i, j - 1}}{Delta z^2} = -frac{rho_{i,j}}{varepsilon_0} \
left. frac{partial u}{partial r} right|_{r = 0} = 0 & longrightarrow & u_{0,j} = frac{1}{3} left(4 u_{1,j} - u_{2,j} right) ~ \
lim_{rtoinfty} u(r, z) = 0 & longrightarrow & ? ~ \
u(r, l(r)) = f_3(r) & longrightarrow & u_{i, l(r_i)/Delta z} = f_3(r_i) \
u(r, h) = f_4(r) & longrightarrow & u_{i, N} = f_4(r_i) \
end{array}
where
$$
l(r) = left{begin{aligned}
&h - frac{H}{R} r &&: r le R\
&0 &&: r > R
end{aligned}
right.$$
Looking at my old class notes, the professor mentioned a method called irregular singular points as a method to better approximate boundary conditions in (semi-)infinite domains but, I don't understand how I would apply this to 2D systems or to radial systems.
I would appreciate any suggestions.
polar-coordinates boundary-value-problem finite-differences
$endgroup$
add a comment |
$begingroup$
I am trying to solve Poisson's equation in an axisymmetric cylindrical domain using finite difference. So I start with my differential equation and boundary conditions and discretize them. However, I'm having trouble thinking of how to discretize the radial portion
begin{array}{lll}
frac{1}{r} frac{partial}{partial r} left(r frac{partial u}{partial r} right) + frac{partial^2 u}{partial z^2} = -frac{rho}{varepsilon_0} & longrightarrow & frac{r_{i+1/2} u_{i+1, j} - 2 r_{i} u_{i,j} + r_{i-1/2} u_{i-1, j}}{r_i Delta r^2} + frac{u_{i, j+1} - 2 u_{i, j} + u_{i, j - 1}}{Delta z^2} = -frac{rho_{i,j}}{varepsilon_0} \
left. frac{partial u}{partial r} right|_{r = 0} = 0 & longrightarrow & u_{0,j} = frac{1}{3} left(4 u_{1,j} - u_{2,j} right) ~ \
lim_{rtoinfty} u(r, z) = 0 & longrightarrow & ? ~ \
u(r, l(r)) = f_3(r) & longrightarrow & u_{i, l(r_i)/Delta z} = f_3(r_i) \
u(r, h) = f_4(r) & longrightarrow & u_{i, N} = f_4(r_i) \
end{array}
where
$$
l(r) = left{begin{aligned}
&h - frac{H}{R} r &&: r le R\
&0 &&: r > R
end{aligned}
right.$$
Looking at my old class notes, the professor mentioned a method called irregular singular points as a method to better approximate boundary conditions in (semi-)infinite domains but, I don't understand how I would apply this to 2D systems or to radial systems.
I would appreciate any suggestions.
polar-coordinates boundary-value-problem finite-differences
$endgroup$
add a comment |
$begingroup$
I am trying to solve Poisson's equation in an axisymmetric cylindrical domain using finite difference. So I start with my differential equation and boundary conditions and discretize them. However, I'm having trouble thinking of how to discretize the radial portion
begin{array}{lll}
frac{1}{r} frac{partial}{partial r} left(r frac{partial u}{partial r} right) + frac{partial^2 u}{partial z^2} = -frac{rho}{varepsilon_0} & longrightarrow & frac{r_{i+1/2} u_{i+1, j} - 2 r_{i} u_{i,j} + r_{i-1/2} u_{i-1, j}}{r_i Delta r^2} + frac{u_{i, j+1} - 2 u_{i, j} + u_{i, j - 1}}{Delta z^2} = -frac{rho_{i,j}}{varepsilon_0} \
left. frac{partial u}{partial r} right|_{r = 0} = 0 & longrightarrow & u_{0,j} = frac{1}{3} left(4 u_{1,j} - u_{2,j} right) ~ \
lim_{rtoinfty} u(r, z) = 0 & longrightarrow & ? ~ \
u(r, l(r)) = f_3(r) & longrightarrow & u_{i, l(r_i)/Delta z} = f_3(r_i) \
u(r, h) = f_4(r) & longrightarrow & u_{i, N} = f_4(r_i) \
end{array}
where
$$
l(r) = left{begin{aligned}
&h - frac{H}{R} r &&: r le R\
&0 &&: r > R
end{aligned}
right.$$
Looking at my old class notes, the professor mentioned a method called irregular singular points as a method to better approximate boundary conditions in (semi-)infinite domains but, I don't understand how I would apply this to 2D systems or to radial systems.
I would appreciate any suggestions.
polar-coordinates boundary-value-problem finite-differences
$endgroup$
I am trying to solve Poisson's equation in an axisymmetric cylindrical domain using finite difference. So I start with my differential equation and boundary conditions and discretize them. However, I'm having trouble thinking of how to discretize the radial portion
begin{array}{lll}
frac{1}{r} frac{partial}{partial r} left(r frac{partial u}{partial r} right) + frac{partial^2 u}{partial z^2} = -frac{rho}{varepsilon_0} & longrightarrow & frac{r_{i+1/2} u_{i+1, j} - 2 r_{i} u_{i,j} + r_{i-1/2} u_{i-1, j}}{r_i Delta r^2} + frac{u_{i, j+1} - 2 u_{i, j} + u_{i, j - 1}}{Delta z^2} = -frac{rho_{i,j}}{varepsilon_0} \
left. frac{partial u}{partial r} right|_{r = 0} = 0 & longrightarrow & u_{0,j} = frac{1}{3} left(4 u_{1,j} - u_{2,j} right) ~ \
lim_{rtoinfty} u(r, z) = 0 & longrightarrow & ? ~ \
u(r, l(r)) = f_3(r) & longrightarrow & u_{i, l(r_i)/Delta z} = f_3(r_i) \
u(r, h) = f_4(r) & longrightarrow & u_{i, N} = f_4(r_i) \
end{array}
where
$$
l(r) = left{begin{aligned}
&h - frac{H}{R} r &&: r le R\
&0 &&: r > R
end{aligned}
right.$$
Looking at my old class notes, the professor mentioned a method called irregular singular points as a method to better approximate boundary conditions in (semi-)infinite domains but, I don't understand how I would apply this to 2D systems or to radial systems.
I would appreciate any suggestions.
polar-coordinates boundary-value-problem finite-differences
polar-coordinates boundary-value-problem finite-differences
edited Aug 14 '15 at 17:49
user1543042
asked Aug 14 '15 at 14:28
user1543042user1543042
330111
330111
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
The actual boundary condition should be
$$lim_{r rightarrow infty} frac{partial u}{partial r} = 0$$
which I approximated at some finite point using the backward second order finite difference.
The actual boundary condition can be seen to be correct by a simple thought experiment by setting $H = 0$ (a rectangular grid) with $rho = 0$ and we must recover the solution 1D cartesian solution to Laplace's equation.
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f1397153%2f2d-finite-difference-boundary-conditions-for-radial-direction%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The actual boundary condition should be
$$lim_{r rightarrow infty} frac{partial u}{partial r} = 0$$
which I approximated at some finite point using the backward second order finite difference.
The actual boundary condition can be seen to be correct by a simple thought experiment by setting $H = 0$ (a rectangular grid) with $rho = 0$ and we must recover the solution 1D cartesian solution to Laplace's equation.
$endgroup$
add a comment |
$begingroup$
The actual boundary condition should be
$$lim_{r rightarrow infty} frac{partial u}{partial r} = 0$$
which I approximated at some finite point using the backward second order finite difference.
The actual boundary condition can be seen to be correct by a simple thought experiment by setting $H = 0$ (a rectangular grid) with $rho = 0$ and we must recover the solution 1D cartesian solution to Laplace's equation.
$endgroup$
add a comment |
$begingroup$
The actual boundary condition should be
$$lim_{r rightarrow infty} frac{partial u}{partial r} = 0$$
which I approximated at some finite point using the backward second order finite difference.
The actual boundary condition can be seen to be correct by a simple thought experiment by setting $H = 0$ (a rectangular grid) with $rho = 0$ and we must recover the solution 1D cartesian solution to Laplace's equation.
$endgroup$
The actual boundary condition should be
$$lim_{r rightarrow infty} frac{partial u}{partial r} = 0$$
which I approximated at some finite point using the backward second order finite difference.
The actual boundary condition can be seen to be correct by a simple thought experiment by setting $H = 0$ (a rectangular grid) with $rho = 0$ and we must recover the solution 1D cartesian solution to Laplace's equation.
answered Aug 28 '15 at 1:50
user1543042user1543042
330111
330111
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f1397153%2f2d-finite-difference-boundary-conditions-for-radial-direction%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown