left and right not working on parentheses within the same line when internal fractions are changed
up vote
10
down vote
favorite
I'm trying to show the product of two Legendre symbols. When I compile the following
documentclass{article}
begin{document}
$$left(frac{x}{p}right) left(frac{x}{p}right)$$
end{document}
it yields
as expected. However, when I switch the variables, i.e.
documentclass{article}
begin{document}
$$left(frac{x}{p}right)left(frac{p}{x}right)$$
end{document}
it yields
How do I resolve this? Why do the values within the fractions matter?
math-mode
add a comment |
up vote
10
down vote
favorite
I'm trying to show the product of two Legendre symbols. When I compile the following
documentclass{article}
begin{document}
$$left(frac{x}{p}right) left(frac{x}{p}right)$$
end{document}
it yields
as expected. However, when I switch the variables, i.e.
documentclass{article}
begin{document}
$$left(frac{x}{p}right)left(frac{p}{x}right)$$
end{document}
it yields
How do I resolve this? Why do the values within the fractions matter?
math-mode
1
The double signs of$$
it is a old syntax. You should must[...]
.
– Sebastiano
Nov 24 at 19:30
add a comment |
up vote
10
down vote
favorite
up vote
10
down vote
favorite
I'm trying to show the product of two Legendre symbols. When I compile the following
documentclass{article}
begin{document}
$$left(frac{x}{p}right) left(frac{x}{p}right)$$
end{document}
it yields
as expected. However, when I switch the variables, i.e.
documentclass{article}
begin{document}
$$left(frac{x}{p}right)left(frac{p}{x}right)$$
end{document}
it yields
How do I resolve this? Why do the values within the fractions matter?
math-mode
I'm trying to show the product of two Legendre symbols. When I compile the following
documentclass{article}
begin{document}
$$left(frac{x}{p}right) left(frac{x}{p}right)$$
end{document}
it yields
as expected. However, when I switch the variables, i.e.
documentclass{article}
begin{document}
$$left(frac{x}{p}right)left(frac{p}{x}right)$$
end{document}
it yields
How do I resolve this? Why do the values within the fractions matter?
math-mode
math-mode
asked Nov 24 at 16:55
Antoine Ego
937
937
1
The double signs of$$
it is a old syntax. You should must[...]
.
– Sebastiano
Nov 24 at 19:30
add a comment |
1
The double signs of$$
it is a old syntax. You should must[...]
.
– Sebastiano
Nov 24 at 19:30
1
1
The double signs of
$$
it is a old syntax. You should must [...]
.– Sebastiano
Nov 24 at 19:30
The double signs of
$$
it is a old syntax. You should must [...]
.– Sebastiano
Nov 24 at 19:30
add a comment |
3 Answers
3
active
oldest
votes
up vote
13
down vote
accepted
This is somewhat similar to this question.
The values in the fractions matter because the boxes of the characters have different sizes. The p
has a descender below the baseline which the x
doesn't, thus when you swap them, the box of the denominator get a little bigger and TeX uses a larger delimiter to make that fit.
You have a few possibilities to work around that (basically the same ones I listed in the linked question):
You can use a fixed delimiter size (
bigg
orBig
, for instance):
$$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
$$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$
You can
raise
thep
so that TeX won't try to use a larger box:
$$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$
or you can add an invisible
p
next to thex
so that the delimiter used will be the larger one:
$$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$
Or you can change change TeX's
delimiterfactor
(anddelimitershortfall
, which I didn't show here) and let TeX adjust the delimiters accordingly:
$$delimiterfactor=790
left(frac{x}{p}right)left(frac{p}{x}right)$$
$$delimiterfactor=970
left(frac{x}{p}right)left(frac{p}{x}right)$$
Full code:
documentclass{article}
begin{document}
% delimitershortfall=5pt % Default
% delimiterfactor=901 % Default
$$left(frac{x}{p}right)left(frac{p}{x}right)$$
$$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
$$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$
$$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$
$$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$
$$delimiterfactor=790
left(frac{x}{p}right)left(frac{p}{x}right)$$
$$delimiterfactor=970
left(frac{x}{p}right)left(frac{p}{x}right)$$
end{document}
Output:
add a comment |
up vote
9
down vote
Use genfrac
for this:
documentclass{article}
usepackage{amsmath}
newcommand{genlegendre}[3]{genfrac{(}{)}{}{#1}{#2}{#3}}
newcommand{legendre}[2]{genlegendre{}{#1}{#2}}
newcommand{dlegendre}[2]{genlegendre{0}{#1}{#2}}
newcommand{tlegendre}[2]{genlegendre{1}{#1}{#2}}
begin{document}
[
legendre{x}{p}quadlegendre{p}{x}quad
legendre{x}{x}quadlegendre{d}{b}
]
end{document}
The variants dlegendre
and tlegendre
are analogous to dfrac
and tfrac
.
I've never heard oftfrac
, what's the package that defines it?
– AndréC
Nov 24 at 22:14
1
@AndréCamsmath
, along withdfrac
; alsobinom
,dbinom
andtbinom
. In some cases, in displaystfrac
is needed not to give prominence to fractional factors.
– egreg
Nov 24 at 22:24
add a comment |
up vote
0
down vote
I like the unified syntax for this kind of stuff in the mathtools
package.
documentclass{article}
usepackage{mathtools}
DeclarePairedDelimiter{paren}{lparen}{rparen}
begin{document}
begin{equation*}
paren*{frac{x}{p} }quad paren*{frac{p}{x}}
qquad
paren[bigg]{frac{x}{p}} quad paren[bigg]{frac{p}{x}}
end{equation*}
end{document}
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
13
down vote
accepted
This is somewhat similar to this question.
The values in the fractions matter because the boxes of the characters have different sizes. The p
has a descender below the baseline which the x
doesn't, thus when you swap them, the box of the denominator get a little bigger and TeX uses a larger delimiter to make that fit.
You have a few possibilities to work around that (basically the same ones I listed in the linked question):
You can use a fixed delimiter size (
bigg
orBig
, for instance):
$$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
$$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$
You can
raise
thep
so that TeX won't try to use a larger box:
$$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$
or you can add an invisible
p
next to thex
so that the delimiter used will be the larger one:
$$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$
Or you can change change TeX's
delimiterfactor
(anddelimitershortfall
, which I didn't show here) and let TeX adjust the delimiters accordingly:
$$delimiterfactor=790
left(frac{x}{p}right)left(frac{p}{x}right)$$
$$delimiterfactor=970
left(frac{x}{p}right)left(frac{p}{x}right)$$
Full code:
documentclass{article}
begin{document}
% delimitershortfall=5pt % Default
% delimiterfactor=901 % Default
$$left(frac{x}{p}right)left(frac{p}{x}right)$$
$$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
$$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$
$$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$
$$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$
$$delimiterfactor=790
left(frac{x}{p}right)left(frac{p}{x}right)$$
$$delimiterfactor=970
left(frac{x}{p}right)left(frac{p}{x}right)$$
end{document}
Output:
add a comment |
up vote
13
down vote
accepted
This is somewhat similar to this question.
The values in the fractions matter because the boxes of the characters have different sizes. The p
has a descender below the baseline which the x
doesn't, thus when you swap them, the box of the denominator get a little bigger and TeX uses a larger delimiter to make that fit.
You have a few possibilities to work around that (basically the same ones I listed in the linked question):
You can use a fixed delimiter size (
bigg
orBig
, for instance):
$$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
$$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$
You can
raise
thep
so that TeX won't try to use a larger box:
$$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$
or you can add an invisible
p
next to thex
so that the delimiter used will be the larger one:
$$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$
Or you can change change TeX's
delimiterfactor
(anddelimitershortfall
, which I didn't show here) and let TeX adjust the delimiters accordingly:
$$delimiterfactor=790
left(frac{x}{p}right)left(frac{p}{x}right)$$
$$delimiterfactor=970
left(frac{x}{p}right)left(frac{p}{x}right)$$
Full code:
documentclass{article}
begin{document}
% delimitershortfall=5pt % Default
% delimiterfactor=901 % Default
$$left(frac{x}{p}right)left(frac{p}{x}right)$$
$$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
$$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$
$$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$
$$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$
$$delimiterfactor=790
left(frac{x}{p}right)left(frac{p}{x}right)$$
$$delimiterfactor=970
left(frac{x}{p}right)left(frac{p}{x}right)$$
end{document}
Output:
add a comment |
up vote
13
down vote
accepted
up vote
13
down vote
accepted
This is somewhat similar to this question.
The values in the fractions matter because the boxes of the characters have different sizes. The p
has a descender below the baseline which the x
doesn't, thus when you swap them, the box of the denominator get a little bigger and TeX uses a larger delimiter to make that fit.
You have a few possibilities to work around that (basically the same ones I listed in the linked question):
You can use a fixed delimiter size (
bigg
orBig
, for instance):
$$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
$$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$
You can
raise
thep
so that TeX won't try to use a larger box:
$$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$
or you can add an invisible
p
next to thex
so that the delimiter used will be the larger one:
$$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$
Or you can change change TeX's
delimiterfactor
(anddelimitershortfall
, which I didn't show here) and let TeX adjust the delimiters accordingly:
$$delimiterfactor=790
left(frac{x}{p}right)left(frac{p}{x}right)$$
$$delimiterfactor=970
left(frac{x}{p}right)left(frac{p}{x}right)$$
Full code:
documentclass{article}
begin{document}
% delimitershortfall=5pt % Default
% delimiterfactor=901 % Default
$$left(frac{x}{p}right)left(frac{p}{x}right)$$
$$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
$$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$
$$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$
$$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$
$$delimiterfactor=790
left(frac{x}{p}right)left(frac{p}{x}right)$$
$$delimiterfactor=970
left(frac{x}{p}right)left(frac{p}{x}right)$$
end{document}
Output:
This is somewhat similar to this question.
The values in the fractions matter because the boxes of the characters have different sizes. The p
has a descender below the baseline which the x
doesn't, thus when you swap them, the box of the denominator get a little bigger and TeX uses a larger delimiter to make that fit.
You have a few possibilities to work around that (basically the same ones I listed in the linked question):
You can use a fixed delimiter size (
bigg
orBig
, for instance):
$$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
$$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$
You can
raise
thep
so that TeX won't try to use a larger box:
$$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$
or you can add an invisible
p
next to thex
so that the delimiter used will be the larger one:
$$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$
Or you can change change TeX's
delimiterfactor
(anddelimitershortfall
, which I didn't show here) and let TeX adjust the delimiters accordingly:
$$delimiterfactor=790
left(frac{x}{p}right)left(frac{p}{x}right)$$
$$delimiterfactor=970
left(frac{x}{p}right)left(frac{p}{x}right)$$
Full code:
documentclass{article}
begin{document}
% delimitershortfall=5pt % Default
% delimiterfactor=901 % Default
$$left(frac{x}{p}right)left(frac{p}{x}right)$$
$$Bigl(frac{x}{p}Bigr)Bigl(frac{p}{x}Bigr)$$
$$biggl(frac{x}{p}biggr)biggl(frac{p}{x}biggr)$$
$$left(frac{x}{raise0.35exhbox{$p$}}right)left(frac{p}{x}right)$$
$$left(frac{x}{p}right)left(frac{p}{vphantom{p}x}right)$$
$$delimiterfactor=790
left(frac{x}{p}right)left(frac{p}{x}right)$$
$$delimiterfactor=970
left(frac{x}{p}right)left(frac{p}{x}right)$$
end{document}
Output:
answered Nov 24 at 17:16
Phelype Oleinik
20.9k54380
20.9k54380
add a comment |
add a comment |
up vote
9
down vote
Use genfrac
for this:
documentclass{article}
usepackage{amsmath}
newcommand{genlegendre}[3]{genfrac{(}{)}{}{#1}{#2}{#3}}
newcommand{legendre}[2]{genlegendre{}{#1}{#2}}
newcommand{dlegendre}[2]{genlegendre{0}{#1}{#2}}
newcommand{tlegendre}[2]{genlegendre{1}{#1}{#2}}
begin{document}
[
legendre{x}{p}quadlegendre{p}{x}quad
legendre{x}{x}quadlegendre{d}{b}
]
end{document}
The variants dlegendre
and tlegendre
are analogous to dfrac
and tfrac
.
I've never heard oftfrac
, what's the package that defines it?
– AndréC
Nov 24 at 22:14
1
@AndréCamsmath
, along withdfrac
; alsobinom
,dbinom
andtbinom
. In some cases, in displaystfrac
is needed not to give prominence to fractional factors.
– egreg
Nov 24 at 22:24
add a comment |
up vote
9
down vote
Use genfrac
for this:
documentclass{article}
usepackage{amsmath}
newcommand{genlegendre}[3]{genfrac{(}{)}{}{#1}{#2}{#3}}
newcommand{legendre}[2]{genlegendre{}{#1}{#2}}
newcommand{dlegendre}[2]{genlegendre{0}{#1}{#2}}
newcommand{tlegendre}[2]{genlegendre{1}{#1}{#2}}
begin{document}
[
legendre{x}{p}quadlegendre{p}{x}quad
legendre{x}{x}quadlegendre{d}{b}
]
end{document}
The variants dlegendre
and tlegendre
are analogous to dfrac
and tfrac
.
I've never heard oftfrac
, what's the package that defines it?
– AndréC
Nov 24 at 22:14
1
@AndréCamsmath
, along withdfrac
; alsobinom
,dbinom
andtbinom
. In some cases, in displaystfrac
is needed not to give prominence to fractional factors.
– egreg
Nov 24 at 22:24
add a comment |
up vote
9
down vote
up vote
9
down vote
Use genfrac
for this:
documentclass{article}
usepackage{amsmath}
newcommand{genlegendre}[3]{genfrac{(}{)}{}{#1}{#2}{#3}}
newcommand{legendre}[2]{genlegendre{}{#1}{#2}}
newcommand{dlegendre}[2]{genlegendre{0}{#1}{#2}}
newcommand{tlegendre}[2]{genlegendre{1}{#1}{#2}}
begin{document}
[
legendre{x}{p}quadlegendre{p}{x}quad
legendre{x}{x}quadlegendre{d}{b}
]
end{document}
The variants dlegendre
and tlegendre
are analogous to dfrac
and tfrac
.
Use genfrac
for this:
documentclass{article}
usepackage{amsmath}
newcommand{genlegendre}[3]{genfrac{(}{)}{}{#1}{#2}{#3}}
newcommand{legendre}[2]{genlegendre{}{#1}{#2}}
newcommand{dlegendre}[2]{genlegendre{0}{#1}{#2}}
newcommand{tlegendre}[2]{genlegendre{1}{#1}{#2}}
begin{document}
[
legendre{x}{p}quadlegendre{p}{x}quad
legendre{x}{x}quadlegendre{d}{b}
]
end{document}
The variants dlegendre
and tlegendre
are analogous to dfrac
and tfrac
.
answered Nov 24 at 22:09
egreg
701k8618653140
701k8618653140
I've never heard oftfrac
, what's the package that defines it?
– AndréC
Nov 24 at 22:14
1
@AndréCamsmath
, along withdfrac
; alsobinom
,dbinom
andtbinom
. In some cases, in displaystfrac
is needed not to give prominence to fractional factors.
– egreg
Nov 24 at 22:24
add a comment |
I've never heard oftfrac
, what's the package that defines it?
– AndréC
Nov 24 at 22:14
1
@AndréCamsmath
, along withdfrac
; alsobinom
,dbinom
andtbinom
. In some cases, in displaystfrac
is needed not to give prominence to fractional factors.
– egreg
Nov 24 at 22:24
I've never heard of
tfrac
, what's the package that defines it?– AndréC
Nov 24 at 22:14
I've never heard of
tfrac
, what's the package that defines it?– AndréC
Nov 24 at 22:14
1
1
@AndréC
amsmath
, along with dfrac
; also binom
, dbinom
and tbinom
. In some cases, in displays tfrac
is needed not to give prominence to fractional factors.– egreg
Nov 24 at 22:24
@AndréC
amsmath
, along with dfrac
; also binom
, dbinom
and tbinom
. In some cases, in displays tfrac
is needed not to give prominence to fractional factors.– egreg
Nov 24 at 22:24
add a comment |
up vote
0
down vote
I like the unified syntax for this kind of stuff in the mathtools
package.
documentclass{article}
usepackage{mathtools}
DeclarePairedDelimiter{paren}{lparen}{rparen}
begin{document}
begin{equation*}
paren*{frac{x}{p} }quad paren*{frac{p}{x}}
qquad
paren[bigg]{frac{x}{p}} quad paren[bigg]{frac{p}{x}}
end{equation*}
end{document}
add a comment |
up vote
0
down vote
I like the unified syntax for this kind of stuff in the mathtools
package.
documentclass{article}
usepackage{mathtools}
DeclarePairedDelimiter{paren}{lparen}{rparen}
begin{document}
begin{equation*}
paren*{frac{x}{p} }quad paren*{frac{p}{x}}
qquad
paren[bigg]{frac{x}{p}} quad paren[bigg]{frac{p}{x}}
end{equation*}
end{document}
add a comment |
up vote
0
down vote
up vote
0
down vote
I like the unified syntax for this kind of stuff in the mathtools
package.
documentclass{article}
usepackage{mathtools}
DeclarePairedDelimiter{paren}{lparen}{rparen}
begin{document}
begin{equation*}
paren*{frac{x}{p} }quad paren*{frac{p}{x}}
qquad
paren[bigg]{frac{x}{p}} quad paren[bigg]{frac{p}{x}}
end{equation*}
end{document}
I like the unified syntax for this kind of stuff in the mathtools
package.
documentclass{article}
usepackage{mathtools}
DeclarePairedDelimiter{paren}{lparen}{rparen}
begin{document}
begin{equation*}
paren*{frac{x}{p} }quad paren*{frac{p}{x}}
qquad
paren[bigg]{frac{x}{p}} quad paren[bigg]{frac{p}{x}}
end{equation*}
end{document}
answered 2 days ago
Máté Wierdl
36918
36918
add a comment |
add a comment |
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1
The double signs of
$$
it is a old syntax. You should must[...]
.– Sebastiano
Nov 24 at 19:30