What is the geometrical significance of a complex-valued singular value decomposition?
up vote
0
down vote
favorite
Suppose you have a 2x2 real-valued matrix, $mathbf{A}$. If you perform a singular value decomposition (SVD), then this can be understood geometrically as a decomposition of $mathbf{A}$ into a 2-D rotation, scaling and second 2-D rotation of the form:
$$mathbf{A} = mathbf{R_1 S R_2}$$
However, if the entries of $mathbf{A}$ are complex, then what is the geometric meaning of this? Now $mathbf{R_1}$ and $mathbf{R_2}$ will also be complex. Are these still rotation matrices? Is there an additional underlying rotation happening in the complex plane? What does it mean if you have a "complex rotation matrix"?
Any help, clarification or references is appreciated.
linear-algebra complex-numbers linear-transformations svd
add a comment |
up vote
0
down vote
favorite
Suppose you have a 2x2 real-valued matrix, $mathbf{A}$. If you perform a singular value decomposition (SVD), then this can be understood geometrically as a decomposition of $mathbf{A}$ into a 2-D rotation, scaling and second 2-D rotation of the form:
$$mathbf{A} = mathbf{R_1 S R_2}$$
However, if the entries of $mathbf{A}$ are complex, then what is the geometric meaning of this? Now $mathbf{R_1}$ and $mathbf{R_2}$ will also be complex. Are these still rotation matrices? Is there an additional underlying rotation happening in the complex plane? What does it mean if you have a "complex rotation matrix"?
Any help, clarification or references is appreciated.
linear-algebra complex-numbers linear-transformations svd
They'll be unitary matrices, which can still be thought of as rotations in a suitable sense.
– Qiaochu Yuan
Nov 15 at 21:27
Rotation through what angle though? What does it mean to have a "complex rotation matrix"? The matrix multiplication does not preserve real and imaginary components as separate. For example, if $mathbf{R_1}$ is a complex rotation matrix and you take some real valued vector, $mathbf{v}$, then $mathbf{R_1v}$ will be complex valued as well. I'm just struggling to understand what this actually means geometrically.
– Darcy
Nov 15 at 21:59
The eigenvalues of a unitary matrix, like an orthogonal matrix, are unit complex numbers $e^{i theta}$, so can be thought of in terms of rotations by $theta$.
– Qiaochu Yuan
Nov 15 at 22:02
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Suppose you have a 2x2 real-valued matrix, $mathbf{A}$. If you perform a singular value decomposition (SVD), then this can be understood geometrically as a decomposition of $mathbf{A}$ into a 2-D rotation, scaling and second 2-D rotation of the form:
$$mathbf{A} = mathbf{R_1 S R_2}$$
However, if the entries of $mathbf{A}$ are complex, then what is the geometric meaning of this? Now $mathbf{R_1}$ and $mathbf{R_2}$ will also be complex. Are these still rotation matrices? Is there an additional underlying rotation happening in the complex plane? What does it mean if you have a "complex rotation matrix"?
Any help, clarification or references is appreciated.
linear-algebra complex-numbers linear-transformations svd
Suppose you have a 2x2 real-valued matrix, $mathbf{A}$. If you perform a singular value decomposition (SVD), then this can be understood geometrically as a decomposition of $mathbf{A}$ into a 2-D rotation, scaling and second 2-D rotation of the form:
$$mathbf{A} = mathbf{R_1 S R_2}$$
However, if the entries of $mathbf{A}$ are complex, then what is the geometric meaning of this? Now $mathbf{R_1}$ and $mathbf{R_2}$ will also be complex. Are these still rotation matrices? Is there an additional underlying rotation happening in the complex plane? What does it mean if you have a "complex rotation matrix"?
Any help, clarification or references is appreciated.
linear-algebra complex-numbers linear-transformations svd
linear-algebra complex-numbers linear-transformations svd
asked Nov 15 at 20:42
Darcy
14411
14411
They'll be unitary matrices, which can still be thought of as rotations in a suitable sense.
– Qiaochu Yuan
Nov 15 at 21:27
Rotation through what angle though? What does it mean to have a "complex rotation matrix"? The matrix multiplication does not preserve real and imaginary components as separate. For example, if $mathbf{R_1}$ is a complex rotation matrix and you take some real valued vector, $mathbf{v}$, then $mathbf{R_1v}$ will be complex valued as well. I'm just struggling to understand what this actually means geometrically.
– Darcy
Nov 15 at 21:59
The eigenvalues of a unitary matrix, like an orthogonal matrix, are unit complex numbers $e^{i theta}$, so can be thought of in terms of rotations by $theta$.
– Qiaochu Yuan
Nov 15 at 22:02
add a comment |
They'll be unitary matrices, which can still be thought of as rotations in a suitable sense.
– Qiaochu Yuan
Nov 15 at 21:27
Rotation through what angle though? What does it mean to have a "complex rotation matrix"? The matrix multiplication does not preserve real and imaginary components as separate. For example, if $mathbf{R_1}$ is a complex rotation matrix and you take some real valued vector, $mathbf{v}$, then $mathbf{R_1v}$ will be complex valued as well. I'm just struggling to understand what this actually means geometrically.
– Darcy
Nov 15 at 21:59
The eigenvalues of a unitary matrix, like an orthogonal matrix, are unit complex numbers $e^{i theta}$, so can be thought of in terms of rotations by $theta$.
– Qiaochu Yuan
Nov 15 at 22:02
They'll be unitary matrices, which can still be thought of as rotations in a suitable sense.
– Qiaochu Yuan
Nov 15 at 21:27
They'll be unitary matrices, which can still be thought of as rotations in a suitable sense.
– Qiaochu Yuan
Nov 15 at 21:27
Rotation through what angle though? What does it mean to have a "complex rotation matrix"? The matrix multiplication does not preserve real and imaginary components as separate. For example, if $mathbf{R_1}$ is a complex rotation matrix and you take some real valued vector, $mathbf{v}$, then $mathbf{R_1v}$ will be complex valued as well. I'm just struggling to understand what this actually means geometrically.
– Darcy
Nov 15 at 21:59
Rotation through what angle though? What does it mean to have a "complex rotation matrix"? The matrix multiplication does not preserve real and imaginary components as separate. For example, if $mathbf{R_1}$ is a complex rotation matrix and you take some real valued vector, $mathbf{v}$, then $mathbf{R_1v}$ will be complex valued as well. I'm just struggling to understand what this actually means geometrically.
– Darcy
Nov 15 at 21:59
The eigenvalues of a unitary matrix, like an orthogonal matrix, are unit complex numbers $e^{i theta}$, so can be thought of in terms of rotations by $theta$.
– Qiaochu Yuan
Nov 15 at 22:02
The eigenvalues of a unitary matrix, like an orthogonal matrix, are unit complex numbers $e^{i theta}$, so can be thought of in terms of rotations by $theta$.
– Qiaochu Yuan
Nov 15 at 22:02
add a comment |
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3000298%2fwhat-is-the-geometrical-significance-of-a-complex-valued-singular-value-decompos%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
They'll be unitary matrices, which can still be thought of as rotations in a suitable sense.
– Qiaochu Yuan
Nov 15 at 21:27
Rotation through what angle though? What does it mean to have a "complex rotation matrix"? The matrix multiplication does not preserve real and imaginary components as separate. For example, if $mathbf{R_1}$ is a complex rotation matrix and you take some real valued vector, $mathbf{v}$, then $mathbf{R_1v}$ will be complex valued as well. I'm just struggling to understand what this actually means geometrically.
– Darcy
Nov 15 at 21:59
The eigenvalues of a unitary matrix, like an orthogonal matrix, are unit complex numbers $e^{i theta}$, so can be thought of in terms of rotations by $theta$.
– Qiaochu Yuan
Nov 15 at 22:02