divide a number in k parts such that GCD of the part is maximum
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You have been given a number $N$. You have to divide it in exactly $k$ parts such that the gcd of the $k$ parts is maximal.
elementary-number-theory
edited Nov 17 at 16:19
klirk
2,220428
asked Nov 17 at 15:22
Tanu kumar
11
add a comment |
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You have been given a number $N$. You have to divide it in exactly $k$ parts such that the gcd of the $k$ parts is maximal.
elementary-number-theory
edited Nov 17 at 16:19
klirk
2,220428
asked Nov 17 at 15:22
Tanu kumar
11
1
What do you want? An algorithm? Some bounds on the GCD? It is also useful to post what you have thought about so far : it helps others on the site.
– астон вілла олоф мэллбэрг
Nov 17 at 15:30
Also, you might want to consider writing the question in slightly more mathematical form, if possible.
– random123
Nov 17 at 15:34
@Tanukumar HINT: The GCD of a bunch of numbers can never be bigger than the smallest of the numbers.
– Frpzzd
Nov 17 at 15:36
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
You have been given a number $N$. You have to divide it in exactly $k$ parts such that the gcd of the $k$ parts is maximal.
elementary-number-theory
edited Nov 17 at 16:19
klirk
2,220428
asked Nov 17 at 15:22
Tanu kumar
11
You have been given a number $N$. You have to divide it in exactly $k$ parts such that the gcd of the $k$ parts is maximal.
elementary-number-theory
elementary-number-theory
edited Nov 17 at 16:19
klirk
2,220428
asked Nov 17 at 15:22
Tanu kumar
11
edited Nov 17 at 16:19
klirk
2,220428
asked Nov 17 at 15:22
Tanu kumar
11
edited Nov 17 at 16:19
klirk
2,220428
edited Nov 17 at 16:19
klirk
2,220428
edited Nov 17 at 16:19
klirk
2,220428
2,220428
asked Nov 17 at 15:22
Tanu kumar
11
asked Nov 17 at 15:22
Tanu kumar
11
asked Nov 17 at 15:22
Tanu kumar
11
11
1
What do you want? An algorithm? Some bounds on the GCD? It is also useful to post what you have thought about so far : it helps others on the site.
– астон вілла олоф мэллбэрг
Nov 17 at 15:30
Also, you might want to consider writing the question in slightly more mathematical form, if possible.
– random123
Nov 17 at 15:34
@Tanukumar HINT: The GCD of a bunch of numbers can never be bigger than the smallest of the numbers.
– Frpzzd
Nov 17 at 15:36
add a comment |
1
What do you want? An algorithm? Some bounds on the GCD? It is also useful to post what you have thought about so far : it helps others on the site.
– астон вілла олоф мэллбэрг
Nov 17 at 15:30
Also, you might want to consider writing the question in slightly more mathematical form, if possible.
– random123
Nov 17 at 15:34
@Tanukumar HINT: The GCD of a bunch of numbers can never be bigger than the smallest of the numbers.
– Frpzzd
Nov 17 at 15:36
1
1
What do you want? An algorithm? Some bounds on the GCD? It is also useful to post what you have thought about so far : it helps others on the site.
– астон вілла олоф мэллбэрг
Nov 17 at 15:30
What do you want? An algorithm? Some bounds on the GCD? It is also useful to post what you have thought about so far : it helps others on the site.
– астон вілла олоф мэллбэрг
Nov 17 at 15:30
Also, you might want to consider writing the question in slightly more mathematical form, if possible.
– random123
Nov 17 at 15:34
Also, you might want to consider writing the question in slightly more mathematical form, if possible.
– random123
Nov 17 at 15:34
@Tanukumar HINT: The GCD of a bunch of numbers can never be bigger than the smallest of the numbers.
– Frpzzd
Nov 17 at 15:36
@Tanukumar HINT: The GCD of a bunch of numbers can never be bigger than the smallest of the numbers.
– Frpzzd
Nov 17 at 15:36
add a comment |
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What do you want? An algorithm? Some bounds on the GCD? It is also useful to post what you have thought about so far : it helps others on the site.
– астон вілла олоф мэллбэрг
Nov 17 at 15:30
Also, you might want to consider writing the question in slightly more mathematical form, if possible.
– random123
Nov 17 at 15:34
@Tanukumar HINT: The GCD of a bunch of numbers can never be bigger than the smallest of the numbers.
– Frpzzd
Nov 17 at 15:36