geometry measurements of rational and irrational numbers to calculate the area of shapes
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Is Pythagoras theorem (A SQUARED + B SQUARED = C SQUARED) Then SQUARE ROOT TO FIND HYPOTENUSE correct? If this is the proper equation why does the answer not agree with the geometric measurement? I am really trying to reduce my ignorance level and be very clear and concise so I can get an answer from compassionate mathematicians. I DREW A 6 INCH DIAGONAL LINE AT A 45 DEGREE ANGLE THEN CREATED A RIGHT TRIANGLE WITH TWO SIDES 4.25 AND 4.25. I am fairly sure the following calculation is right to find the hypotenuse? (4.25 SQUARED + 4.25 squared = 36.0125) (square root of 6.010408) to find the hypotenuse right? Two equal triangles like the aforementioned equals a square. Square area of a square using two triangles area.Base times height times half = triangle area (6 times 3 times .5 = 9 square inches times 2 = 18 square inches for the area of two triangles that create the hypothetical square) using the tangible drawn triangle the geometric measurement that is perfect the math is off by .0625. and is supported by a diagonal line 45 degrees 12 inches and 8.5 90 degree triangle creating sides that doubles in error. Side squared 4.25 = 18.0625. Would it be a good question to pose that asks if it is possible to arrive at the correct area of a tangible real shape a irrational number? My drawing and math would not up load for some reason sorry!! for this novel. may the force be with you!! I am adding this to help! Now cut the two triangles in half to create four! 4.25 base divided by 2 = 2.125. Using 6.01040764009 hypotenuse you can not make a right triangle.4.25 times 2.125 times .5 times four = 18.0625 can you imagine how far off that would be for a square a mile. @rustnorm twitter
geometry
asked Nov 12 at 21:40
apprentice DR NormanERustJR.
32
add a comment |
up vote
-1
down vote
favorite
Is Pythagoras theorem (A SQUARED + B SQUARED = C SQUARED) Then SQUARE ROOT TO FIND HYPOTENUSE correct? If this is the proper equation why does the answer not agree with the geometric measurement? I am really trying to reduce my ignorance level and be very clear and concise so I can get an answer from compassionate mathematicians. I DREW A 6 INCH DIAGONAL LINE AT A 45 DEGREE ANGLE THEN CREATED A RIGHT TRIANGLE WITH TWO SIDES 4.25 AND 4.25. I am fairly sure the following calculation is right to find the hypotenuse? (4.25 SQUARED + 4.25 squared = 36.0125) (square root of 6.010408) to find the hypotenuse right? Two equal triangles like the aforementioned equals a square. Square area of a square using two triangles area.Base times height times half = triangle area (6 times 3 times .5 = 9 square inches times 2 = 18 square inches for the area of two triangles that create the hypothetical square) using the tangible drawn triangle the geometric measurement that is perfect the math is off by .0625. and is supported by a diagonal line 45 degrees 12 inches and 8.5 90 degree triangle creating sides that doubles in error. Side squared 4.25 = 18.0625. Would it be a good question to pose that asks if it is possible to arrive at the correct area of a tangible real shape a irrational number? My drawing and math would not up load for some reason sorry!! for this novel. may the force be with you!! I am adding this to help! Now cut the two triangles in half to create four! 4.25 base divided by 2 = 2.125. Using 6.01040764009 hypotenuse you can not make a right triangle.4.25 times 2.125 times .5 times four = 18.0625 can you imagine how far off that would be for a square a mile. @rustnorm twitter
geometry
asked Nov 12 at 21:40
apprentice DR NormanERustJR.
32
1
I think you made a mistake in what you think you did. If you create a right-triangle where one of the angles has measure 45 degrees, then it must be an isosceles triangle. Therefore, it is impossible that you would have the two sides having the different lengths 4.25 and 4.5
– gd1035
Nov 12 at 21:43
1
It would help if you attach a picture. As mentioned before, with the angle between one of the sides and the hypotenuse in a right angle triangle being 45 degrees, the two sides must be equal, 4.5 in your case. If the sides are not equal, (say the angle is different than 45 degrees), then adding the two triangles would yield a rectangle, not a square
– Andrei
Nov 12 at 21:48
$6.010408$ inches minus $6$ inches is equal to $.010408$ inches, which is thinner than the thickness of any ordinary writing instrument used to draw the picture you describe, and is also at the limit of any difference that you could perceive with your own eyes. No human being can avoid an error of that magnitude when drawing a triangle.
– Lee Mosher
Nov 17 at 17:06
Sorry as stated the the drawing would not up load there is a typo 4.5 is 4.25 and I apologize. I draw cabinet blue print accurate. Well within 256 of an inch. One side of the square is a geometric drawing of the right triangle.The other side is mathematical hypothetical triangle.( stage set ) Math does not lie. When you use half of the two triangles the base is 4.25 inchs find the center (divide by two) 2.125 center That is also the height. If you use 6.01040764009 hypotenuse you can not have a right triangle. Can you reason why the math has a fundamental error. Let's collaborate.
– apprentice DR NormanERustJR.
Nov 17 at 19:06
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
Is Pythagoras theorem (A SQUARED + B SQUARED = C SQUARED) Then SQUARE ROOT TO FIND HYPOTENUSE correct? If this is the proper equation why does the answer not agree with the geometric measurement? I am really trying to reduce my ignorance level and be very clear and concise so I can get an answer from compassionate mathematicians. I DREW A 6 INCH DIAGONAL LINE AT A 45 DEGREE ANGLE THEN CREATED A RIGHT TRIANGLE WITH TWO SIDES 4.25 AND 4.25. I am fairly sure the following calculation is right to find the hypotenuse? (4.25 SQUARED + 4.25 squared = 36.0125) (square root of 6.010408) to find the hypotenuse right? Two equal triangles like the aforementioned equals a square. Square area of a square using two triangles area.Base times height times half = triangle area (6 times 3 times .5 = 9 square inches times 2 = 18 square inches for the area of two triangles that create the hypothetical square) using the tangible drawn triangle the geometric measurement that is perfect the math is off by .0625. and is supported by a diagonal line 45 degrees 12 inches and 8.5 90 degree triangle creating sides that doubles in error. Side squared 4.25 = 18.0625. Would it be a good question to pose that asks if it is possible to arrive at the correct area of a tangible real shape a irrational number? My drawing and math would not up load for some reason sorry!! for this novel. may the force be with you!! I am adding this to help! Now cut the two triangles in half to create four! 4.25 base divided by 2 = 2.125. Using 6.01040764009 hypotenuse you can not make a right triangle.4.25 times 2.125 times .5 times four = 18.0625 can you imagine how far off that would be for a square a mile. @rustnorm twitter
geometry
asked Nov 12 at 21:40
apprentice DR NormanERustJR.
32
Is Pythagoras theorem (A SQUARED + B SQUARED = C SQUARED) Then SQUARE ROOT TO FIND HYPOTENUSE correct? If this is the proper equation why does the answer not agree with the geometric measurement? I am really trying to reduce my ignorance level and be very clear and concise so I can get an answer from compassionate mathematicians. I DREW A 6 INCH DIAGONAL LINE AT A 45 DEGREE ANGLE THEN CREATED A RIGHT TRIANGLE WITH TWO SIDES 4.25 AND 4.25. I am fairly sure the following calculation is right to find the hypotenuse? (4.25 SQUARED + 4.25 squared = 36.0125) (square root of 6.010408) to find the hypotenuse right? Two equal triangles like the aforementioned equals a square. Square area of a square using two triangles area.Base times height times half = triangle area (6 times 3 times .5 = 9 square inches times 2 = 18 square inches for the area of two triangles that create the hypothetical square) using the tangible drawn triangle the geometric measurement that is perfect the math is off by .0625. and is supported by a diagonal line 45 degrees 12 inches and 8.5 90 degree triangle creating sides that doubles in error. Side squared 4.25 = 18.0625. Would it be a good question to pose that asks if it is possible to arrive at the correct area of a tangible real shape a irrational number? My drawing and math would not up load for some reason sorry!! for this novel. may the force be with you!! I am adding this to help! Now cut the two triangles in half to create four! 4.25 base divided by 2 = 2.125. Using 6.01040764009 hypotenuse you can not make a right triangle.4.25 times 2.125 times .5 times four = 18.0625 can you imagine how far off that would be for a square a mile. @rustnorm twitter
geometry
geometry
asked Nov 12 at 21:40
apprentice DR NormanERustJR.
32
asked Nov 12 at 21:40
apprentice DR NormanERustJR.
32
edited Nov 17 at 22:47
asked Nov 12 at 21:40
apprentice DR NormanERustJR.
32
asked Nov 12 at 21:40
apprentice DR NormanERustJR.
32
asked Nov 12 at 21:40
apprentice DR NormanERustJR.
32
32
1
I think you made a mistake in what you think you did. If you create a right-triangle where one of the angles has measure 45 degrees, then it must be an isosceles triangle. Therefore, it is impossible that you would have the two sides having the different lengths 4.25 and 4.5
– gd1035
Nov 12 at 21:43
1
It would help if you attach a picture. As mentioned before, with the angle between one of the sides and the hypotenuse in a right angle triangle being 45 degrees, the two sides must be equal, 4.5 in your case. If the sides are not equal, (say the angle is different than 45 degrees), then adding the two triangles would yield a rectangle, not a square
– Andrei
Nov 12 at 21:48
$6.010408$ inches minus $6$ inches is equal to $.010408$ inches, which is thinner than the thickness of any ordinary writing instrument used to draw the picture you describe, and is also at the limit of any difference that you could perceive with your own eyes. No human being can avoid an error of that magnitude when drawing a triangle.
– Lee Mosher
Nov 17 at 17:06
Sorry as stated the the drawing would not up load there is a typo 4.5 is 4.25 and I apologize. I draw cabinet blue print accurate. Well within 256 of an inch. One side of the square is a geometric drawing of the right triangle.The other side is mathematical hypothetical triangle.( stage set ) Math does not lie. When you use half of the two triangles the base is 4.25 inchs find the center (divide by two) 2.125 center That is also the height. If you use 6.01040764009 hypotenuse you can not have a right triangle. Can you reason why the math has a fundamental error. Let's collaborate.
– apprentice DR NormanERustJR.
Nov 17 at 19:06
add a comment |
1
I think you made a mistake in what you think you did. If you create a right-triangle where one of the angles has measure 45 degrees, then it must be an isosceles triangle. Therefore, it is impossible that you would have the two sides having the different lengths 4.25 and 4.5
– gd1035
Nov 12 at 21:43
1
It would help if you attach a picture. As mentioned before, with the angle between one of the sides and the hypotenuse in a right angle triangle being 45 degrees, the two sides must be equal, 4.5 in your case. If the sides are not equal, (say the angle is different than 45 degrees), then adding the two triangles would yield a rectangle, not a square
– Andrei
Nov 12 at 21:48
$6.010408$ inches minus $6$ inches is equal to $.010408$ inches, which is thinner than the thickness of any ordinary writing instrument used to draw the picture you describe, and is also at the limit of any difference that you could perceive with your own eyes. No human being can avoid an error of that magnitude when drawing a triangle.
– Lee Mosher
Nov 17 at 17:06
Sorry as stated the the drawing would not up load there is a typo 4.5 is 4.25 and I apologize. I draw cabinet blue print accurate. Well within 256 of an inch. One side of the square is a geometric drawing of the right triangle.The other side is mathematical hypothetical triangle.( stage set ) Math does not lie. When you use half of the two triangles the base is 4.25 inchs find the center (divide by two) 2.125 center That is also the height. If you use 6.01040764009 hypotenuse you can not have a right triangle. Can you reason why the math has a fundamental error. Let's collaborate.
– apprentice DR NormanERustJR.
Nov 17 at 19:06
1
1
I think you made a mistake in what you think you did. If you create a right-triangle where one of the angles has measure 45 degrees, then it must be an isosceles triangle. Therefore, it is impossible that you would have the two sides having the different lengths 4.25 and 4.5
– gd1035
Nov 12 at 21:43
I think you made a mistake in what you think you did. If you create a right-triangle where one of the angles has measure 45 degrees, then it must be an isosceles triangle. Therefore, it is impossible that you would have the two sides having the different lengths 4.25 and 4.5
– gd1035
Nov 12 at 21:43
1
1
It would help if you attach a picture. As mentioned before, with the angle between one of the sides and the hypotenuse in a right angle triangle being 45 degrees, the two sides must be equal, 4.5 in your case. If the sides are not equal, (say the angle is different than 45 degrees), then adding the two triangles would yield a rectangle, not a square
– Andrei
Nov 12 at 21:48
It would help if you attach a picture. As mentioned before, with the angle between one of the sides and the hypotenuse in a right angle triangle being 45 degrees, the two sides must be equal, 4.5 in your case. If the sides are not equal, (say the angle is different than 45 degrees), then adding the two triangles would yield a rectangle, not a square
– Andrei
Nov 12 at 21:48
$6.010408$ inches minus $6$ inches is equal to $.010408$ inches, which is thinner than the thickness of any ordinary writing instrument used to draw the picture you describe, and is also at the limit of any difference that you could perceive with your own eyes. No human being can avoid an error of that magnitude when drawing a triangle.
– Lee Mosher
Nov 17 at 17:06
$6.010408$ inches minus $6$ inches is equal to $.010408$ inches, which is thinner than the thickness of any ordinary writing instrument used to draw the picture you describe, and is also at the limit of any difference that you could perceive with your own eyes. No human being can avoid an error of that magnitude when drawing a triangle.
– Lee Mosher
Nov 17 at 17:06
Sorry as stated the the drawing would not up load there is a typo 4.5 is 4.25 and I apologize. I draw cabinet blue print accurate. Well within 256 of an inch. One side of the square is a geometric drawing of the right triangle.The other side is mathematical hypothetical triangle.( stage set ) Math does not lie. When you use half of the two triangles the base is 4.25 inchs find the center (divide by two) 2.125 center That is also the height. If you use 6.01040764009 hypotenuse you can not have a right triangle. Can you reason why the math has a fundamental error. Let's collaborate.
– apprentice DR NormanERustJR.
Nov 17 at 19:06
Sorry as stated the the drawing would not up load there is a typo 4.5 is 4.25 and I apologize. I draw cabinet blue print accurate. Well within 256 of an inch. One side of the square is a geometric drawing of the right triangle.The other side is mathematical hypothetical triangle.( stage set ) Math does not lie. When you use half of the two triangles the base is 4.25 inchs find the center (divide by two) 2.125 center That is also the height. If you use 6.01040764009 hypotenuse you can not have a right triangle. Can you reason why the math has a fundamental error. Let's collaborate.
– apprentice DR NormanERustJR.
Nov 17 at 19:06
add a comment |
1 Answer
1
active
oldest
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up vote
-1
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accepted
Looks like you lack drawing expertise : a paper, a pen, a ruler and a compass would help you a lot to make a good drawing of a square. Quickest way is to draw a circle and mark the two points on a diameter segment (a segment through circle center). Mark any other point (one corner of your future square) on the circle and you have rectangular triangle. Then extend the two segments from that point to 4.5 inches using ruler. Mark the end points as two other corners. Measure distance (diagonal length of your half square between these two points with ruler and check it is sqrt(2) times 4.5. For area : height of your triangle (half a square) is 1/2 sqrt(2) times 4.5 so the area of half of that triangle is 1/2 (sqrt(2) times 4.5 ) (1/2 sqrt(2) times 4.5) = 1/2 (4.5)^2 ...a rational area
answered Nov 12 at 22:19
Dominique Laurain
472
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
-1
down vote
accepted
Looks like you lack drawing expertise : a paper, a pen, a ruler and a compass would help you a lot to make a good drawing of a square. Quickest way is to draw a circle and mark the two points on a diameter segment (a segment through circle center). Mark any other point (one corner of your future square) on the circle and you have rectangular triangle. Then extend the two segments from that point to 4.5 inches using ruler. Mark the end points as two other corners. Measure distance (diagonal length of your half square between these two points with ruler and check it is sqrt(2) times 4.5. For area : height of your triangle (half a square) is 1/2 sqrt(2) times 4.5 so the area of half of that triangle is 1/2 (sqrt(2) times 4.5 ) (1/2 sqrt(2) times 4.5) = 1/2 (4.5)^2 ...a rational area
answered Nov 12 at 22:19
Dominique Laurain
472
add a comment |
up vote
-1
down vote
accepted
Looks like you lack drawing expertise : a paper, a pen, a ruler and a compass would help you a lot to make a good drawing of a square. Quickest way is to draw a circle and mark the two points on a diameter segment (a segment through circle center). Mark any other point (one corner of your future square) on the circle and you have rectangular triangle. Then extend the two segments from that point to 4.5 inches using ruler. Mark the end points as two other corners. Measure distance (diagonal length of your half square between these two points with ruler and check it is sqrt(2) times 4.5. For area : height of your triangle (half a square) is 1/2 sqrt(2) times 4.5 so the area of half of that triangle is 1/2 (sqrt(2) times 4.5 ) (1/2 sqrt(2) times 4.5) = 1/2 (4.5)^2 ...a rational area
answered Nov 12 at 22:19
Dominique Laurain
472
add a comment |
up vote
-1
down vote
accepted
up vote
-1
down vote
accepted
Looks like you lack drawing expertise : a paper, a pen, a ruler and a compass would help you a lot to make a good drawing of a square. Quickest way is to draw a circle and mark the two points on a diameter segment (a segment through circle center). Mark any other point (one corner of your future square) on the circle and you have rectangular triangle. Then extend the two segments from that point to 4.5 inches using ruler. Mark the end points as two other corners. Measure distance (diagonal length of your half square between these two points with ruler and check it is sqrt(2) times 4.5. For area : height of your triangle (half a square) is 1/2 sqrt(2) times 4.5 so the area of half of that triangle is 1/2 (sqrt(2) times 4.5 ) (1/2 sqrt(2) times 4.5) = 1/2 (4.5)^2 ...a rational area
answered Nov 12 at 22:19
Dominique Laurain
472
Looks like you lack drawing expertise : a paper, a pen, a ruler and a compass would help you a lot to make a good drawing of a square. Quickest way is to draw a circle and mark the two points on a diameter segment (a segment through circle center). Mark any other point (one corner of your future square) on the circle and you have rectangular triangle. Then extend the two segments from that point to 4.5 inches using ruler. Mark the end points as two other corners. Measure distance (diagonal length of your half square between these two points with ruler and check it is sqrt(2) times 4.5. For area : height of your triangle (half a square) is 1/2 sqrt(2) times 4.5 so the area of half of that triangle is 1/2 (sqrt(2) times 4.5 ) (1/2 sqrt(2) times 4.5) = 1/2 (4.5)^2 ...a rational area
answered Nov 12 at 22:19
Dominique Laurain
472
answered Nov 12 at 22:19
Dominique Laurain
472
answered Nov 12 at 22:19
Dominique Laurain
472
answered Nov 12 at 22:19
Dominique Laurain
472
472
add a comment |
add a comment |
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I think you made a mistake in what you think you did. If you create a right-triangle where one of the angles has measure 45 degrees, then it must be an isosceles triangle. Therefore, it is impossible that you would have the two sides having the different lengths 4.25 and 4.5
– gd1035
Nov 12 at 21:43
1
It would help if you attach a picture. As mentioned before, with the angle between one of the sides and the hypotenuse in a right angle triangle being 45 degrees, the two sides must be equal, 4.5 in your case. If the sides are not equal, (say the angle is different than 45 degrees), then adding the two triangles would yield a rectangle, not a square
– Andrei
Nov 12 at 21:48
$6.010408$ inches minus $6$ inches is equal to $.010408$ inches, which is thinner than the thickness of any ordinary writing instrument used to draw the picture you describe, and is also at the limit of any difference that you could perceive with your own eyes. No human being can avoid an error of that magnitude when drawing a triangle.
– Lee Mosher
Nov 17 at 17:06
Sorry as stated the the drawing would not up load there is a typo 4.5 is 4.25 and I apologize. I draw cabinet blue print accurate. Well within 256 of an inch. One side of the square is a geometric drawing of the right triangle.The other side is mathematical hypothetical triangle.( stage set ) Math does not lie. When you use half of the two triangles the base is 4.25 inchs find the center (divide by two) 2.125 center That is also the height. If you use 6.01040764009 hypotenuse you can not have a right triangle. Can you reason why the math has a fundamental error. Let's collaborate.
– apprentice DR NormanERustJR.
Nov 17 at 19:06