API Access HTML/Javascript problem












4















I have an issue trying to use javascript to get the circulating supply by requesting data from Tzscan API:



HTML code to request the circulating supply:



<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JS Bin</title>
</head>
<body>
<h1>There Tezos Circulating : </h1>
<div id="getapi"></div>
</body>
</html>


Javascript Code to get the data from the API:



<script>
function createNode(element) {
return document.createElement(element);
}

function append(parent, el) {
return parent.appendChild(el);
}

const ul = document.getElementById('getapi');
const url = 'http://api6.tzscan.io/v3/supply';
fetch(url)
.then((resp) => resp.json())
.then(function(data) {
let span = createNode('span');
span.innerHTML = `${data.circulating_supply/1000000}`;
append(ul, span);
})
.catch(function(error) {
console.log(error);
});
</script>


The problem is that somehow it works when I create a HTML file locally but not online.










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New contributor




Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





















  • it'll help to also include the errors you are getting. I know we could probably look at your codepen but for the sake of the question, it's best include the errors in the question.

    – Frank
    Mar 25 at 3:20
















4















I have an issue trying to use javascript to get the circulating supply by requesting data from Tzscan API:



HTML code to request the circulating supply:



<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JS Bin</title>
</head>
<body>
<h1>There Tezos Circulating : </h1>
<div id="getapi"></div>
</body>
</html>


Javascript Code to get the data from the API:



<script>
function createNode(element) {
return document.createElement(element);
}

function append(parent, el) {
return parent.appendChild(el);
}

const ul = document.getElementById('getapi');
const url = 'http://api6.tzscan.io/v3/supply';
fetch(url)
.then((resp) => resp.json())
.then(function(data) {
let span = createNode('span');
span.innerHTML = `${data.circulating_supply/1000000}`;
append(ul, span);
})
.catch(function(error) {
console.log(error);
});
</script>


The problem is that somehow it works when I create a HTML file locally but not online.










share|improve this question









New contributor




Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





















  • it'll help to also include the errors you are getting. I know we could probably look at your codepen but for the sake of the question, it's best include the errors in the question.

    – Frank
    Mar 25 at 3:20














4












4








4








I have an issue trying to use javascript to get the circulating supply by requesting data from Tzscan API:



HTML code to request the circulating supply:



<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JS Bin</title>
</head>
<body>
<h1>There Tezos Circulating : </h1>
<div id="getapi"></div>
</body>
</html>


Javascript Code to get the data from the API:



<script>
function createNode(element) {
return document.createElement(element);
}

function append(parent, el) {
return parent.appendChild(el);
}

const ul = document.getElementById('getapi');
const url = 'http://api6.tzscan.io/v3/supply';
fetch(url)
.then((resp) => resp.json())
.then(function(data) {
let span = createNode('span');
span.innerHTML = `${data.circulating_supply/1000000}`;
append(ul, span);
})
.catch(function(error) {
console.log(error);
});
</script>


The problem is that somehow it works when I create a HTML file locally but not online.










share|improve this question









New contributor




Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












I have an issue trying to use javascript to get the circulating supply by requesting data from Tzscan API:



HTML code to request the circulating supply:



<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JS Bin</title>
</head>
<body>
<h1>There Tezos Circulating : </h1>
<div id="getapi"></div>
</body>
</html>


Javascript Code to get the data from the API:



<script>
function createNode(element) {
return document.createElement(element);
}

function append(parent, el) {
return parent.appendChild(el);
}

const ul = document.getElementById('getapi');
const url = 'http://api6.tzscan.io/v3/supply';
fetch(url)
.then((resp) => resp.json())
.then(function(data) {
let span = createNode('span');
span.innerHTML = `${data.circulating_supply/1000000}`;
append(ul, span);
})
.catch(function(error) {
console.log(error);
});
</script>


The problem is that somehow it works when I create a HTML file locally but not online.







api javascript circulating-supply






share|improve this question









New contributor




Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited Mar 25 at 11:29









luchonacho

532216




532216






New contributor




Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked Mar 24 at 21:49









LexxorLexxor

1006




1006




New contributor




Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.













  • it'll help to also include the errors you are getting. I know we could probably look at your codepen but for the sake of the question, it's best include the errors in the question.

    – Frank
    Mar 25 at 3:20



















  • it'll help to also include the errors you are getting. I know we could probably look at your codepen but for the sake of the question, it's best include the errors in the question.

    – Frank
    Mar 25 at 3:20

















it'll help to also include the errors you are getting. I know we could probably look at your codepen but for the sake of the question, it's best include the errors in the question.

– Frank
Mar 25 at 3:20





it'll help to also include the errors you are getting. I know we could probably look at your codepen but for the sake of the question, it's best include the errors in the question.

– Frank
Mar 25 at 3:20










1 Answer
1






active

oldest

votes


















7














You've encountered a mixed content error. Requests can't be a mixture of http and https, they need to be all of the same, preferably https. Just change the const url = 'http://api6.tzscan.io/v3/supply'; to be https





const url = 'https://api6.tzscan.io/v3/supply';

fetch(url)
.then(resp => resp.json())
.then(({dls}) => {
let span = createNode('span');
span.innerHTML = dls;
append(ul, span);
})
.catch(console.log);





share|improve this answer


























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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    7














    You've encountered a mixed content error. Requests can't be a mixture of http and https, they need to be all of the same, preferably https. Just change the const url = 'http://api6.tzscan.io/v3/supply'; to be https





    const url = 'https://api6.tzscan.io/v3/supply';

    fetch(url)
    .then(resp => resp.json())
    .then(({dls}) => {
    let span = createNode('span');
    span.innerHTML = dls;
    append(ul, span);
    })
    .catch(console.log);





    share|improve this answer






























      7














      You've encountered a mixed content error. Requests can't be a mixture of http and https, they need to be all of the same, preferably https. Just change the const url = 'http://api6.tzscan.io/v3/supply'; to be https





      const url = 'https://api6.tzscan.io/v3/supply';

      fetch(url)
      .then(resp => resp.json())
      .then(({dls}) => {
      let span = createNode('span');
      span.innerHTML = dls;
      append(ul, span);
      })
      .catch(console.log);





      share|improve this answer




























        7












        7








        7







        You've encountered a mixed content error. Requests can't be a mixture of http and https, they need to be all of the same, preferably https. Just change the const url = 'http://api6.tzscan.io/v3/supply'; to be https





        const url = 'https://api6.tzscan.io/v3/supply';

        fetch(url)
        .then(resp => resp.json())
        .then(({dls}) => {
        let span = createNode('span');
        span.innerHTML = dls;
        append(ul, span);
        })
        .catch(console.log);





        share|improve this answer















        You've encountered a mixed content error. Requests can't be a mixture of http and https, they need to be all of the same, preferably https. Just change the const url = 'http://api6.tzscan.io/v3/supply'; to be https





        const url = 'https://api6.tzscan.io/v3/supply';

        fetch(url)
        .then(resp => resp.json())
        .then(({dls}) => {
        let span = createNode('span');
        span.innerHTML = dls;
        append(ul, span);
        })
        .catch(console.log);






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Mar 25 at 1:59

























        answered Mar 24 at 23:15









        Richard AyotteRichard Ayotte

        25917




        25917






















            Lexxor is a new contributor. Be nice, and check out our Code of Conduct.










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