Getting the lowest value with key in array
11
I have an array like this: arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, …}
And I'm trying get the lowest value with key using Javascript.
What I've tried:
alert(Math.min.apply(Math, arr)); returns Infinity I don't know why
I got this on Google, just for try:
var keys = Object.keys(arr).map(Number).filter(function(a){
return arr[a];
}); alert(Math.min.apply(Math, keys));
returns Infinity too
I want something more complete, like this output: "The lowest value is 2 from lst9".
I really tried fix it myself before asking here, but without success!
Can you help me fix this "Infinity" issue? Thank you.
javascript arrays object
edited Mar 25 at 20:38
Jack Bashford
13.7k31848
asked Mar 25 at 6:44
MerntMernt
645
New contributor
Mernt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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|
show 4 more comments
11
I have an array like this: arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, …}
And I'm trying get the lowest value with key using Javascript.
What I've tried:
alert(Math.min.apply(Math, arr)); returns Infinity I don't know why
I got this on Google, just for try:
var keys = Object.keys(arr).map(Number).filter(function(a){
return arr[a];
}); alert(Math.min.apply(Math, keys));
returns Infinity too
I want something more complete, like this output: "The lowest value is 2 from lst9".
I really tried fix it myself before asking here, but without success!
Can you help me fix this "Infinity" issue? Thank you.
javascript arrays object
edited Mar 25 at 20:38
Jack Bashford
13.7k31848
asked Mar 25 at 6:44
MerntMernt
645
New contributor
Mernt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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What is expected output?
– Maheer Ali
Mar 25 at 6:45
2
Do you want to get, for example,lst3ifobj.lst3is the lowest value?
– Jack Bashford
Mar 25 at 6:47
2
Also, what islst9? Is itlst9: 2?
– Jack Bashford
Mar 25 at 6:48
may be a duplicte of stackoverflow.com/questions/38008307/…
– Syed Mehtab Hassan
Mar 25 at 6:49
9
arris not an array but anobject
– Isaac
Mar 25 at 6:53
|
show 4 more comments
11
11
11
1
I have an array like this: arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, …}
And I'm trying get the lowest value with key using Javascript.
What I've tried:
alert(Math.min.apply(Math, arr)); returns Infinity I don't know why
I got this on Google, just for try:
var keys = Object.keys(arr).map(Number).filter(function(a){
return arr[a];
}); alert(Math.min.apply(Math, keys));
returns Infinity too
I want something more complete, like this output: "The lowest value is 2 from lst9".
I really tried fix it myself before asking here, but without success!
Can you help me fix this "Infinity" issue? Thank you.
javascript arrays object
edited Mar 25 at 20:38
Jack Bashford
13.7k31848
asked Mar 25 at 6:44
MerntMernt
645
New contributor
Mernt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I have an array like this: arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, …}
And I'm trying get the lowest value with key using Javascript.
What I've tried:
alert(Math.min.apply(Math, arr)); returns Infinity I don't know why
I got this on Google, just for try:
var keys = Object.keys(arr).map(Number).filter(function(a){
return arr[a];
}); alert(Math.min.apply(Math, keys));
returns Infinity too
I want something more complete, like this output: "The lowest value is 2 from lst9".
I really tried fix it myself before asking here, but without success!
Can you help me fix this "Infinity" issue? Thank you.
javascript arrays object
javascript arrays object
edited Mar 25 at 20:38
Jack Bashford
13.7k31848
asked Mar 25 at 6:44
MerntMernt
645
New contributor
Mernt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Mar 25 at 20:38
Jack Bashford
13.7k31848
asked Mar 25 at 6:44
MerntMernt
645
New contributor
Mernt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Mar 25 at 20:38
Jack Bashford
13.7k31848
edited Mar 25 at 20:38
Jack Bashford
13.7k31848
edited Mar 25 at 20:38
Jack Bashford
13.7k31848
13.7k31848
asked Mar 25 at 6:44
MerntMernt
645
New contributor
Mernt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Mar 25 at 6:44
MerntMernt
645
asked Mar 25 at 6:44
MerntMernt
645
645
New contributor
Mernt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Mernt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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Check out our Code of Conduct.
What is expected output?
– Maheer Ali
Mar 25 at 6:45
2
Do you want to get, for example,lst3ifobj.lst3is the lowest value?
– Jack Bashford
Mar 25 at 6:47
2
Also, what islst9? Is itlst9: 2?
– Jack Bashford
Mar 25 at 6:48
may be a duplicte of stackoverflow.com/questions/38008307/…
– Syed Mehtab Hassan
Mar 25 at 6:49
9
arris not an array but anobject
– Isaac
Mar 25 at 6:53
|
show 4 more comments
What is expected output?
– Maheer Ali
Mar 25 at 6:45
2
Do you want to get, for example,lst3ifobj.lst3is the lowest value?
– Jack Bashford
Mar 25 at 6:47
2
Also, what islst9? Is itlst9: 2?
– Jack Bashford
Mar 25 at 6:48
may be a duplicte of stackoverflow.com/questions/38008307/…
– Syed Mehtab Hassan
Mar 25 at 6:49
9
arris not an array but anobject
– Isaac
Mar 25 at 6:53
What is expected output?
– Maheer Ali
Mar 25 at 6:45
What is expected output?
– Maheer Ali
Mar 25 at 6:45
2
2
Do you want to get, for example,
lst3 if obj.lst3 is the lowest value?– Jack Bashford
Mar 25 at 6:47
Do you want to get, for example,
lst3 if obj.lst3 is the lowest value?– Jack Bashford
Mar 25 at 6:47
2
2
Also, what is
lst9? Is it lst9: 2?– Jack Bashford
Mar 25 at 6:48
Also, what is
lst9? Is it lst9: 2?– Jack Bashford
Mar 25 at 6:48
may be a duplicte of stackoverflow.com/questions/38008307/…
– Syed Mehtab Hassan
Mar 25 at 6:49
may be a duplicte of stackoverflow.com/questions/38008307/…
– Syed Mehtab Hassan
Mar 25 at 6:49
9
9
arr is not an array but an object– Isaac
Mar 25 at 6:53
arr is not an array but an object– Isaac
Mar 25 at 6:53
|
show 4 more comments
9 Answers
9
active
oldest
votes
11
You can get the key and value using Object.entries:
var arr = {
lst1: 300,
lst2: 381,
lst3: 4,
lst4: 4,
lst5: 49
};
function lowestValueAndKey(obj) {
var lowestItems = Object.entries(obj).sort(([ ,v1], [ ,v2]) => v1 - v2)[0];
return `Lowest value is ${lowestItems[1]}, with a key of ${lowestItems[0]}`;
}
var lowest = lowestValueAndKey(arr);
console.log(lowest);answered Mar 25 at 6:54
Jack BashfordJack Bashford
13.7k31848
Hello, Are there an way to make this script compatible with Internet Explorer too?
– Mernt
Mar 25 at 7:41
@Mernt developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
– JollyJoker
Mar 25 at 7:59
I tried but I'm getting a syntax error on linevar lowestItems = Object.entries(arr).sort(([ ,v1], [ ,v2]) => v1 - v2)[0]
– Mernt
Mar 25 at 8:06
If you look here developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… you'll see that Internet Explorer does not supportObject.entries
– ChatterOne
Mar 25 at 8:08
1
@Mernt IE doesn't support the fat arrow notation. You need to rewrite([ ,v1], [ ,v2]) => v1 - v2in old style Javascript
– JollyJoker
Mar 25 at 8:12
|
show 5 more comments
8
There are several ways to arrive at what you want. Please see the following methods:
const obj = { lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49 }
const values = Object.values(obj)
const lowest = Math.min.apply(null, values)
// Using Object.keys(), Object.values() and findIndex()
const keys = Object.keys(obj)
const indexOfLowest = values.findIndex(function (x) { return x === lowest })
console.log(`The lowest value is ${lowest} from ${keys[indexOfLowest]}`)
// OR Using Object.keys() and filter()
const key = Object.keys(obj).filter(function (x) { return obj[x] === lowest })[0]
console.log(`The lowest value is ${lowest} from ${key}`)
// OR Using Object.entries() and sort()
const [[lowestKey, lowestVal]] = Object.entries(obj).sort(function ([,valA], [,valB]) { return valA - valB });
console.log(`The lowest value is ${lowestVal} from ${lowestKey}`)answered Mar 25 at 6:53
John KennedyJohn Kennedy
2,91521227
It should work as is in IE > = 11
– John Kennedy
Mar 25 at 8:02
Syntax error on linevar key = Object.keys(arr).filter(x => arr[x] === lowest)[0]
– Mernt
Mar 25 at 8:08
1
I'll suggest using a polyfill if it doesn't work in IE. See here: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… I should also inform you that on my IE on Windows 10 it works without needing a polyfill.
– John Kennedy
Mar 25 at 8:10
1
@JohnKennedy I'd be surprised by that, IE doesn't support arrow functions
– Nick A
Mar 25 at 14:47
add a comment |
7
There are many ways to approach your problem, but here is one simple alternative way to do it. Basically, it is a brute force way of doing things, whereby you iterate through every property to check for the value.
const obj = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const getSmallest = function (object) {
let smallestValue = Number.MAX_VALUE;
let selectedKey = '';
for (let key in object) {
if (object[key] < smallestValue) {
smallestValue = object[key];
selectedKey = key;
}
};
console.log(selectedKey, smallestValue)
return `The lowest value is ${smallestValue} from ${selectedKey}`;
};
getSmallest(obj);
add a comment |
3
To get only the minimum number you can use Math.min(...Object.entries(arr).map(o => o[1])):
const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const lowestValue = Math.min(...Object.entries(arr).map(o => o[1]));
console.log(lowestValue);And to get the object with the minimum value you can use Object.entries(arr).reduce((a, [k, v]) => a[Object.keys(a)[0]] < v ? a : {[k]: v}, {}):
const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const lowestObj = Object.entries(arr).reduce((a, [k, v]) => a[Object.keys(a)[0]] < v ? a : {[k]: v}, {});
console.log(lowestObj);answered Mar 25 at 7:03
Yosvel QuinteroYosvel Quintero
12k42531
add a comment |
2
You can try this:
obj = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}; // This is an object, That;s ehy you getting infinite
var arr = Object.keys( obj ).map(function ( key ) { return obj[key]; });
alert(Math.min.apply( null, arr ));
Fiddle: https://jsfiddle.net/ozvubmdr/
answered Mar 25 at 6:51
Ajay MakwanaAjay Makwana
1,537926
add a comment |
2
Easy, though not optimal, as it traverses the array twice: find the smallest value, then find the key belonging to it.
arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}
min = Math.min(...Object.values(arr));
minkey = Object.keys(arr).find(key => arr[key] = min);
console.log(`Lowest is ${min} at ${minkey}`);answered Mar 25 at 6:54
AmadanAmadan
133k13148198
add a comment |
2
You may try this:
const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}
const minVal = Math.min(...Object.values(arr))
const fromKey = Object.keys(arr).find(key => arr[key] === minVal)
console.log(`The lowest value is ${minVal} from ${fromKey}`)answered Mar 25 at 6:59
Pak Wah WongPak Wah Wong
38317
add a comment |
2
Here we first assume that the min, key and value as first property and the value respectively. Then we iterate through all the elements and compare with minValue to find any value less than that in the object. If it is, then we update both minValue and minKey. Anyway, the arr type is an Object. it is not an array in javascript.
var arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
var minkey = Object.keys(arr)[0];
var minValue = arr[Object.keys(arr)[0]];
for (var key in arr) {
if (arr.hasOwnProperty(key)) {
if(arr[key] < minValue){
minValue = arr[key];
minKey = key;
}
}
}
answered Mar 25 at 7:02
HarshanaHarshana
338211
add a comment |
2
You can use Object.entries and use Array.reduce to reduce the resulting [key-value] pair to an object which will have lowest entry:
const data = {lst1: 300, lst2: -381, lst3: 4, lst4: 4, lst5: 49, lst6: -49, lst7: 0, lst7: 78, lst7: -90};
const obj = Object.entries(data).reduce((acc, [key, value]) =>{
acc["lowest"] = acc["lowest"] ? Object.values(acc["lowest"])[0] < value ? acc["lowest"] : {[key] : value} : {[key] : value };
return acc;
}, {});
console.log(`Lowest value is found in ${JSON.stringify(obj.lowest)}`);answered Mar 25 at 7:02
Amardeep BhowmickAmardeep Bhowmick
5,03321128
add a comment |
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9 Answers
9
active
oldest
votes
9 Answers
9
active
oldest
votes
active
oldest
votes
active
oldest
votes
11
You can get the key and value using Object.entries:
var arr = {
lst1: 300,
lst2: 381,
lst3: 4,
lst4: 4,
lst5: 49
};
function lowestValueAndKey(obj) {
var lowestItems = Object.entries(obj).sort(([ ,v1], [ ,v2]) => v1 - v2)[0];
return `Lowest value is ${lowestItems[1]}, with a key of ${lowestItems[0]}`;
}
var lowest = lowestValueAndKey(arr);
console.log(lowest);answered Mar 25 at 6:54
Jack BashfordJack Bashford
13.7k31848
Hello, Are there an way to make this script compatible with Internet Explorer too?
– Mernt
Mar 25 at 7:41
@Mernt developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
– JollyJoker
Mar 25 at 7:59
I tried but I'm getting a syntax error on linevar lowestItems = Object.entries(arr).sort(([ ,v1], [ ,v2]) => v1 - v2)[0]
– Mernt
Mar 25 at 8:06
If you look here developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… you'll see that Internet Explorer does not supportObject.entries
– ChatterOne
Mar 25 at 8:08
1
@Mernt IE doesn't support the fat arrow notation. You need to rewrite([ ,v1], [ ,v2]) => v1 - v2in old style Javascript
– JollyJoker
Mar 25 at 8:12
|
show 5 more comments
11
You can get the key and value using Object.entries:
var arr = {
lst1: 300,
lst2: 381,
lst3: 4,
lst4: 4,
lst5: 49
};
function lowestValueAndKey(obj) {
var lowestItems = Object.entries(obj).sort(([ ,v1], [ ,v2]) => v1 - v2)[0];
return `Lowest value is ${lowestItems[1]}, with a key of ${lowestItems[0]}`;
}
var lowest = lowestValueAndKey(arr);
console.log(lowest);answered Mar 25 at 6:54
Jack BashfordJack Bashford
13.7k31848
Hello, Are there an way to make this script compatible with Internet Explorer too?
– Mernt
Mar 25 at 7:41
@Mernt developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
– JollyJoker
Mar 25 at 7:59
I tried but I'm getting a syntax error on linevar lowestItems = Object.entries(arr).sort(([ ,v1], [ ,v2]) => v1 - v2)[0]
– Mernt
Mar 25 at 8:06
If you look here developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… you'll see that Internet Explorer does not supportObject.entries
– ChatterOne
Mar 25 at 8:08
1
@Mernt IE doesn't support the fat arrow notation. You need to rewrite([ ,v1], [ ,v2]) => v1 - v2in old style Javascript
– JollyJoker
Mar 25 at 8:12
|
show 5 more comments
11
11
11
You can get the key and value using Object.entries:
var arr = {
lst1: 300,
lst2: 381,
lst3: 4,
lst4: 4,
lst5: 49
};
function lowestValueAndKey(obj) {
var lowestItems = Object.entries(obj).sort(([ ,v1], [ ,v2]) => v1 - v2)[0];
return `Lowest value is ${lowestItems[1]}, with a key of ${lowestItems[0]}`;
}
var lowest = lowestValueAndKey(arr);
console.log(lowest);answered Mar 25 at 6:54
Jack BashfordJack Bashford
13.7k31848
You can get the key and value using Object.entries:
var arr = {
lst1: 300,
lst2: 381,
lst3: 4,
lst4: 4,
lst5: 49
};
function lowestValueAndKey(obj) {
var lowestItems = Object.entries(obj).sort(([ ,v1], [ ,v2]) => v1 - v2)[0];
return `Lowest value is ${lowestItems[1]}, with a key of ${lowestItems[0]}`;
}
var lowest = lowestValueAndKey(arr);
console.log(lowest);var arr = {
lst1: 300,
lst2: 381,
lst3: 4,
lst4: 4,
lst5: 49
};
function lowestValueAndKey(obj) {
var lowestItems = Object.entries(obj).sort(([ ,v1], [ ,v2]) => v1 - v2)[0];
return `Lowest value is ${lowestItems[1]}, with a key of ${lowestItems[0]}`;
}
var lowest = lowestValueAndKey(arr);
console.log(lowest);var arr = {
lst1: 300,
lst2: 381,
lst3: 4,
lst4: 4,
lst5: 49
};
function lowestValueAndKey(obj) {
var lowestItems = Object.entries(obj).sort(([ ,v1], [ ,v2]) => v1 - v2)[0];
return `Lowest value is ${lowestItems[1]}, with a key of ${lowestItems[0]}`;
}
var lowest = lowestValueAndKey(arr);
console.log(lowest);answered Mar 25 at 6:54
Jack BashfordJack Bashford
13.7k31848
answered Mar 25 at 6:54
Jack BashfordJack Bashford
13.7k31848
answered Mar 25 at 6:54
Jack BashfordJack Bashford
13.7k31848
answered Mar 25 at 6:54
Jack BashfordJack Bashford
13.7k31848
13.7k31848
Hello, Are there an way to make this script compatible with Internet Explorer too?
– Mernt
Mar 25 at 7:41
@Mernt developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
– JollyJoker
Mar 25 at 7:59
I tried but I'm getting a syntax error on linevar lowestItems = Object.entries(arr).sort(([ ,v1], [ ,v2]) => v1 - v2)[0]
– Mernt
Mar 25 at 8:06
If you look here developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… you'll see that Internet Explorer does not supportObject.entries
– ChatterOne
Mar 25 at 8:08
1
@Mernt IE doesn't support the fat arrow notation. You need to rewrite([ ,v1], [ ,v2]) => v1 - v2in old style Javascript
– JollyJoker
Mar 25 at 8:12
|
show 5 more comments
Hello, Are there an way to make this script compatible with Internet Explorer too?
– Mernt
Mar 25 at 7:41
@Mernt developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
– JollyJoker
Mar 25 at 7:59
I tried but I'm getting a syntax error on linevar lowestItems = Object.entries(arr).sort(([ ,v1], [ ,v2]) => v1 - v2)[0]
– Mernt
Mar 25 at 8:06
If you look here developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… you'll see that Internet Explorer does not supportObject.entries
– ChatterOne
Mar 25 at 8:08
1
@Mernt IE doesn't support the fat arrow notation. You need to rewrite([ ,v1], [ ,v2]) => v1 - v2in old style Javascript
– JollyJoker
Mar 25 at 8:12
Hello, Are there an way to make this script compatible with Internet Explorer too?
– Mernt
Mar 25 at 7:41
Hello, Are there an way to make this script compatible with Internet Explorer too?
– Mernt
Mar 25 at 7:41
@Mernt developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
– JollyJoker
Mar 25 at 7:59
@Mernt developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
– JollyJoker
Mar 25 at 7:59
I tried but I'm getting a syntax error on line
var lowestItems = Object.entries(arr).sort(([ ,v1], [ ,v2]) => v1 - v2)[0]– Mernt
Mar 25 at 8:06
I tried but I'm getting a syntax error on line
var lowestItems = Object.entries(arr).sort(([ ,v1], [ ,v2]) => v1 - v2)[0]– Mernt
Mar 25 at 8:06
If you look here developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… you'll see that Internet Explorer does not support
Object.entries– ChatterOne
Mar 25 at 8:08
If you look here developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… you'll see that Internet Explorer does not support
Object.entries– ChatterOne
Mar 25 at 8:08
1
1
@Mernt IE doesn't support the fat arrow notation. You need to rewrite
([ ,v1], [ ,v2]) => v1 - v2 in old style Javascript– JollyJoker
Mar 25 at 8:12
@Mernt IE doesn't support the fat arrow notation. You need to rewrite
([ ,v1], [ ,v2]) => v1 - v2 in old style Javascript– JollyJoker
Mar 25 at 8:12
|
show 5 more comments
8
There are several ways to arrive at what you want. Please see the following methods:
const obj = { lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49 }
const values = Object.values(obj)
const lowest = Math.min.apply(null, values)
// Using Object.keys(), Object.values() and findIndex()
const keys = Object.keys(obj)
const indexOfLowest = values.findIndex(function (x) { return x === lowest })
console.log(`The lowest value is ${lowest} from ${keys[indexOfLowest]}`)
// OR Using Object.keys() and filter()
const key = Object.keys(obj).filter(function (x) { return obj[x] === lowest })[0]
console.log(`The lowest value is ${lowest} from ${key}`)
// OR Using Object.entries() and sort()
const [[lowestKey, lowestVal]] = Object.entries(obj).sort(function ([,valA], [,valB]) { return valA - valB });
console.log(`The lowest value is ${lowestVal} from ${lowestKey}`)answered Mar 25 at 6:53
John KennedyJohn Kennedy
2,91521227
It should work as is in IE > = 11
– John Kennedy
Mar 25 at 8:02
Syntax error on linevar key = Object.keys(arr).filter(x => arr[x] === lowest)[0]
– Mernt
Mar 25 at 8:08
1
I'll suggest using a polyfill if it doesn't work in IE. See here: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… I should also inform you that on my IE on Windows 10 it works without needing a polyfill.
– John Kennedy
Mar 25 at 8:10
1
@JohnKennedy I'd be surprised by that, IE doesn't support arrow functions
– Nick A
Mar 25 at 14:47
add a comment |
8
There are several ways to arrive at what you want. Please see the following methods:
const obj = { lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49 }
const values = Object.values(obj)
const lowest = Math.min.apply(null, values)
// Using Object.keys(), Object.values() and findIndex()
const keys = Object.keys(obj)
const indexOfLowest = values.findIndex(function (x) { return x === lowest })
console.log(`The lowest value is ${lowest} from ${keys[indexOfLowest]}`)
// OR Using Object.keys() and filter()
const key = Object.keys(obj).filter(function (x) { return obj[x] === lowest })[0]
console.log(`The lowest value is ${lowest} from ${key}`)
// OR Using Object.entries() and sort()
const [[lowestKey, lowestVal]] = Object.entries(obj).sort(function ([,valA], [,valB]) { return valA - valB });
console.log(`The lowest value is ${lowestVal} from ${lowestKey}`)answered Mar 25 at 6:53
John KennedyJohn Kennedy
2,91521227
It should work as is in IE > = 11
– John Kennedy
Mar 25 at 8:02
Syntax error on linevar key = Object.keys(arr).filter(x => arr[x] === lowest)[0]
– Mernt
Mar 25 at 8:08
1
I'll suggest using a polyfill if it doesn't work in IE. See here: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… I should also inform you that on my IE on Windows 10 it works without needing a polyfill.
– John Kennedy
Mar 25 at 8:10
1
@JohnKennedy I'd be surprised by that, IE doesn't support arrow functions
– Nick A
Mar 25 at 14:47
add a comment |
8
8
8
There are several ways to arrive at what you want. Please see the following methods:
const obj = { lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49 }
const values = Object.values(obj)
const lowest = Math.min.apply(null, values)
// Using Object.keys(), Object.values() and findIndex()
const keys = Object.keys(obj)
const indexOfLowest = values.findIndex(function (x) { return x === lowest })
console.log(`The lowest value is ${lowest} from ${keys[indexOfLowest]}`)
// OR Using Object.keys() and filter()
const key = Object.keys(obj).filter(function (x) { return obj[x] === lowest })[0]
console.log(`The lowest value is ${lowest} from ${key}`)
// OR Using Object.entries() and sort()
const [[lowestKey, lowestVal]] = Object.entries(obj).sort(function ([,valA], [,valB]) { return valA - valB });
console.log(`The lowest value is ${lowestVal} from ${lowestKey}`)answered Mar 25 at 6:53
John KennedyJohn Kennedy
2,91521227
There are several ways to arrive at what you want. Please see the following methods:
const obj = { lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49 }
const values = Object.values(obj)
const lowest = Math.min.apply(null, values)
// Using Object.keys(), Object.values() and findIndex()
const keys = Object.keys(obj)
const indexOfLowest = values.findIndex(function (x) { return x === lowest })
console.log(`The lowest value is ${lowest} from ${keys[indexOfLowest]}`)
// OR Using Object.keys() and filter()
const key = Object.keys(obj).filter(function (x) { return obj[x] === lowest })[0]
console.log(`The lowest value is ${lowest} from ${key}`)
// OR Using Object.entries() and sort()
const [[lowestKey, lowestVal]] = Object.entries(obj).sort(function ([,valA], [,valB]) { return valA - valB });
console.log(`The lowest value is ${lowestVal} from ${lowestKey}`)const obj = { lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49 }
const values = Object.values(obj)
const lowest = Math.min.apply(null, values)
// Using Object.keys(), Object.values() and findIndex()
const keys = Object.keys(obj)
const indexOfLowest = values.findIndex(function (x) { return x === lowest })
console.log(`The lowest value is ${lowest} from ${keys[indexOfLowest]}`)
// OR Using Object.keys() and filter()
const key = Object.keys(obj).filter(function (x) { return obj[x] === lowest })[0]
console.log(`The lowest value is ${lowest} from ${key}`)
// OR Using Object.entries() and sort()
const [[lowestKey, lowestVal]] = Object.entries(obj).sort(function ([,valA], [,valB]) { return valA - valB });
console.log(`The lowest value is ${lowestVal} from ${lowestKey}`)const obj = { lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49 }
const values = Object.values(obj)
const lowest = Math.min.apply(null, values)
// Using Object.keys(), Object.values() and findIndex()
const keys = Object.keys(obj)
const indexOfLowest = values.findIndex(function (x) { return x === lowest })
console.log(`The lowest value is ${lowest} from ${keys[indexOfLowest]}`)
// OR Using Object.keys() and filter()
const key = Object.keys(obj).filter(function (x) { return obj[x] === lowest })[0]
console.log(`The lowest value is ${lowest} from ${key}`)
// OR Using Object.entries() and sort()
const [[lowestKey, lowestVal]] = Object.entries(obj).sort(function ([,valA], [,valB]) { return valA - valB });
console.log(`The lowest value is ${lowestVal} from ${lowestKey}`)answered Mar 25 at 6:53
John KennedyJohn Kennedy
2,91521227
edited Mar 25 at 21:42
answered Mar 25 at 6:53
John KennedyJohn Kennedy
2,91521227
answered Mar 25 at 6:53
John KennedyJohn Kennedy
2,91521227
answered Mar 25 at 6:53
John KennedyJohn Kennedy
2,91521227
2,91521227
It should work as is in IE > = 11
– John Kennedy
Mar 25 at 8:02
Syntax error on linevar key = Object.keys(arr).filter(x => arr[x] === lowest)[0]
– Mernt
Mar 25 at 8:08
1
I'll suggest using a polyfill if it doesn't work in IE. See here: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… I should also inform you that on my IE on Windows 10 it works without needing a polyfill.
– John Kennedy
Mar 25 at 8:10
1
@JohnKennedy I'd be surprised by that, IE doesn't support arrow functions
– Nick A
Mar 25 at 14:47
add a comment |
It should work as is in IE > = 11
– John Kennedy
Mar 25 at 8:02
Syntax error on linevar key = Object.keys(arr).filter(x => arr[x] === lowest)[0]
– Mernt
Mar 25 at 8:08
1
I'll suggest using a polyfill if it doesn't work in IE. See here: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… I should also inform you that on my IE on Windows 10 it works without needing a polyfill.
– John Kennedy
Mar 25 at 8:10
1
@JohnKennedy I'd be surprised by that, IE doesn't support arrow functions
– Nick A
Mar 25 at 14:47
It should work as is in IE > = 11
– John Kennedy
Mar 25 at 8:02
It should work as is in IE > = 11
– John Kennedy
Mar 25 at 8:02
Syntax error on line
var key = Object.keys(arr).filter(x => arr[x] === lowest)[0]– Mernt
Mar 25 at 8:08
Syntax error on line
var key = Object.keys(arr).filter(x => arr[x] === lowest)[0]– Mernt
Mar 25 at 8:08
1
1
I'll suggest using a polyfill if it doesn't work in IE. See here: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… I should also inform you that on my IE on Windows 10 it works without needing a polyfill.
– John Kennedy
Mar 25 at 8:10
I'll suggest using a polyfill if it doesn't work in IE. See here: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… I should also inform you that on my IE on Windows 10 it works without needing a polyfill.
– John Kennedy
Mar 25 at 8:10
1
1
@JohnKennedy I'd be surprised by that, IE doesn't support arrow functions
– Nick A
Mar 25 at 14:47
@JohnKennedy I'd be surprised by that, IE doesn't support arrow functions
– Nick A
Mar 25 at 14:47
add a comment |
7
There are many ways to approach your problem, but here is one simple alternative way to do it. Basically, it is a brute force way of doing things, whereby you iterate through every property to check for the value.
const obj = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const getSmallest = function (object) {
let smallestValue = Number.MAX_VALUE;
let selectedKey = '';
for (let key in object) {
if (object[key] < smallestValue) {
smallestValue = object[key];
selectedKey = key;
}
};
console.log(selectedKey, smallestValue)
return `The lowest value is ${smallestValue} from ${selectedKey}`;
};
getSmallest(obj);
add a comment |
7
There are many ways to approach your problem, but here is one simple alternative way to do it. Basically, it is a brute force way of doing things, whereby you iterate through every property to check for the value.
const obj = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const getSmallest = function (object) {
let smallestValue = Number.MAX_VALUE;
let selectedKey = '';
for (let key in object) {
if (object[key] < smallestValue) {
smallestValue = object[key];
selectedKey = key;
}
};
console.log(selectedKey, smallestValue)
return `The lowest value is ${smallestValue} from ${selectedKey}`;
};
getSmallest(obj);
add a comment |
7
7
7
There are many ways to approach your problem, but here is one simple alternative way to do it. Basically, it is a brute force way of doing things, whereby you iterate through every property to check for the value.
const obj = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const getSmallest = function (object) {
let smallestValue = Number.MAX_VALUE;
let selectedKey = '';
for (let key in object) {
if (object[key] < smallestValue) {
smallestValue = object[key];
selectedKey = key;
}
};
console.log(selectedKey, smallestValue)
return `The lowest value is ${smallestValue} from ${selectedKey}`;
};
getSmallest(obj);
There are many ways to approach your problem, but here is one simple alternative way to do it. Basically, it is a brute force way of doing things, whereby you iterate through every property to check for the value.
const obj = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const getSmallest = function (object) {
let smallestValue = Number.MAX_VALUE;
let selectedKey = '';
for (let key in object) {
if (object[key] < smallestValue) {
smallestValue = object[key];
selectedKey = key;
}
};
console.log(selectedKey, smallestValue)
return `The lowest value is ${smallestValue} from ${selectedKey}`;
};
getSmallest(obj);
edited Mar 25 at 8:12
answered Mar 25 at 6:55
user10997785
add a comment |
add a comment |
3
To get only the minimum number you can use Math.min(...Object.entries(arr).map(o => o[1])):
const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const lowestValue = Math.min(...Object.entries(arr).map(o => o[1]));
console.log(lowestValue);And to get the object with the minimum value you can use Object.entries(arr).reduce((a, [k, v]) => a[Object.keys(a)[0]] < v ? a : {[k]: v}, {}):
const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const lowestObj = Object.entries(arr).reduce((a, [k, v]) => a[Object.keys(a)[0]] < v ? a : {[k]: v}, {});
console.log(lowestObj);answered Mar 25 at 7:03
Yosvel QuinteroYosvel Quintero
12k42531
add a comment |
3
To get only the minimum number you can use Math.min(...Object.entries(arr).map(o => o[1])):
const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const lowestValue = Math.min(...Object.entries(arr).map(o => o[1]));
console.log(lowestValue);And to get the object with the minimum value you can use Object.entries(arr).reduce((a, [k, v]) => a[Object.keys(a)[0]] < v ? a : {[k]: v}, {}):
const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const lowestObj = Object.entries(arr).reduce((a, [k, v]) => a[Object.keys(a)[0]] < v ? a : {[k]: v}, {});
console.log(lowestObj);answered Mar 25 at 7:03
Yosvel QuinteroYosvel Quintero
12k42531
add a comment |
3
3
3
To get only the minimum number you can use Math.min(...Object.entries(arr).map(o => o[1])):
const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const lowestValue = Math.min(...Object.entries(arr).map(o => o[1]));
console.log(lowestValue);And to get the object with the minimum value you can use Object.entries(arr).reduce((a, [k, v]) => a[Object.keys(a)[0]] < v ? a : {[k]: v}, {}):
const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const lowestObj = Object.entries(arr).reduce((a, [k, v]) => a[Object.keys(a)[0]] < v ? a : {[k]: v}, {});
console.log(lowestObj);answered Mar 25 at 7:03
Yosvel QuinteroYosvel Quintero
12k42531
To get only the minimum number you can use Math.min(...Object.entries(arr).map(o => o[1])):
const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const lowestValue = Math.min(...Object.entries(arr).map(o => o[1]));
console.log(lowestValue);And to get the object with the minimum value you can use Object.entries(arr).reduce((a, [k, v]) => a[Object.keys(a)[0]] < v ? a : {[k]: v}, {}):
const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const lowestObj = Object.entries(arr).reduce((a, [k, v]) => a[Object.keys(a)[0]] < v ? a : {[k]: v}, {});
console.log(lowestObj);const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const lowestValue = Math.min(...Object.entries(arr).map(o => o[1]));
console.log(lowestValue);const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const lowestValue = Math.min(...Object.entries(arr).map(o => o[1]));
console.log(lowestValue);const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const lowestObj = Object.entries(arr).reduce((a, [k, v]) => a[Object.keys(a)[0]] < v ? a : {[k]: v}, {});
console.log(lowestObj);const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
const lowestObj = Object.entries(arr).reduce((a, [k, v]) => a[Object.keys(a)[0]] < v ? a : {[k]: v}, {});
console.log(lowestObj);answered Mar 25 at 7:03
Yosvel QuinteroYosvel Quintero
12k42531
edited Mar 25 at 8:01
answered Mar 25 at 7:03
Yosvel QuinteroYosvel Quintero
12k42531
answered Mar 25 at 7:03
Yosvel QuinteroYosvel Quintero
12k42531
answered Mar 25 at 7:03
Yosvel QuinteroYosvel Quintero
12k42531
12k42531
add a comment |
add a comment |
2
You can try this:
obj = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}; // This is an object, That;s ehy you getting infinite
var arr = Object.keys( obj ).map(function ( key ) { return obj[key]; });
alert(Math.min.apply( null, arr ));
Fiddle: https://jsfiddle.net/ozvubmdr/
answered Mar 25 at 6:51
Ajay MakwanaAjay Makwana
1,537926
add a comment |
2
You can try this:
obj = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}; // This is an object, That;s ehy you getting infinite
var arr = Object.keys( obj ).map(function ( key ) { return obj[key]; });
alert(Math.min.apply( null, arr ));
Fiddle: https://jsfiddle.net/ozvubmdr/
answered Mar 25 at 6:51
Ajay MakwanaAjay Makwana
1,537926
add a comment |
2
2
2
You can try this:
obj = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}; // This is an object, That;s ehy you getting infinite
var arr = Object.keys( obj ).map(function ( key ) { return obj[key]; });
alert(Math.min.apply( null, arr ));
Fiddle: https://jsfiddle.net/ozvubmdr/
answered Mar 25 at 6:51
Ajay MakwanaAjay Makwana
1,537926
You can try this:
obj = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}; // This is an object, That;s ehy you getting infinite
var arr = Object.keys( obj ).map(function ( key ) { return obj[key]; });
alert(Math.min.apply( null, arr ));
Fiddle: https://jsfiddle.net/ozvubmdr/
answered Mar 25 at 6:51
Ajay MakwanaAjay Makwana
1,537926
answered Mar 25 at 6:51
Ajay MakwanaAjay Makwana
1,537926
answered Mar 25 at 6:51
Ajay MakwanaAjay Makwana
1,537926
answered Mar 25 at 6:51
Ajay MakwanaAjay Makwana
1,537926
1,537926
add a comment |
add a comment |
2
Easy, though not optimal, as it traverses the array twice: find the smallest value, then find the key belonging to it.
arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}
min = Math.min(...Object.values(arr));
minkey = Object.keys(arr).find(key => arr[key] = min);
console.log(`Lowest is ${min} at ${minkey}`);answered Mar 25 at 6:54
AmadanAmadan
133k13148198
add a comment |
2
Easy, though not optimal, as it traverses the array twice: find the smallest value, then find the key belonging to it.
arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}
min = Math.min(...Object.values(arr));
minkey = Object.keys(arr).find(key => arr[key] = min);
console.log(`Lowest is ${min} at ${minkey}`);answered Mar 25 at 6:54
AmadanAmadan
133k13148198
add a comment |
2
2
2
Easy, though not optimal, as it traverses the array twice: find the smallest value, then find the key belonging to it.
arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}
min = Math.min(...Object.values(arr));
minkey = Object.keys(arr).find(key => arr[key] = min);
console.log(`Lowest is ${min} at ${minkey}`);answered Mar 25 at 6:54
AmadanAmadan
133k13148198
Easy, though not optimal, as it traverses the array twice: find the smallest value, then find the key belonging to it.
arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}
min = Math.min(...Object.values(arr));
minkey = Object.keys(arr).find(key => arr[key] = min);
console.log(`Lowest is ${min} at ${minkey}`);arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}
min = Math.min(...Object.values(arr));
minkey = Object.keys(arr).find(key => arr[key] = min);
console.log(`Lowest is ${min} at ${minkey}`);arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}
min = Math.min(...Object.values(arr));
minkey = Object.keys(arr).find(key => arr[key] = min);
console.log(`Lowest is ${min} at ${minkey}`);answered Mar 25 at 6:54
AmadanAmadan
133k13148198
answered Mar 25 at 6:54
AmadanAmadan
133k13148198
answered Mar 25 at 6:54
AmadanAmadan
133k13148198
answered Mar 25 at 6:54
AmadanAmadan
133k13148198
133k13148198
add a comment |
add a comment |
2
You may try this:
const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}
const minVal = Math.min(...Object.values(arr))
const fromKey = Object.keys(arr).find(key => arr[key] === minVal)
console.log(`The lowest value is ${minVal} from ${fromKey}`)answered Mar 25 at 6:59
Pak Wah WongPak Wah Wong
38317
add a comment |
2
You may try this:
const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}
const minVal = Math.min(...Object.values(arr))
const fromKey = Object.keys(arr).find(key => arr[key] === minVal)
console.log(`The lowest value is ${minVal} from ${fromKey}`)answered Mar 25 at 6:59
Pak Wah WongPak Wah Wong
38317
add a comment |
2
2
2
You may try this:
const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}
const minVal = Math.min(...Object.values(arr))
const fromKey = Object.keys(arr).find(key => arr[key] === minVal)
console.log(`The lowest value is ${minVal} from ${fromKey}`)answered Mar 25 at 6:59
Pak Wah WongPak Wah Wong
38317
You may try this:
const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}
const minVal = Math.min(...Object.values(arr))
const fromKey = Object.keys(arr).find(key => arr[key] === minVal)
console.log(`The lowest value is ${minVal} from ${fromKey}`)const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}
const minVal = Math.min(...Object.values(arr))
const fromKey = Object.keys(arr).find(key => arr[key] === minVal)
console.log(`The lowest value is ${minVal} from ${fromKey}`)const arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49, lst9: 2}
const minVal = Math.min(...Object.values(arr))
const fromKey = Object.keys(arr).find(key => arr[key] === minVal)
console.log(`The lowest value is ${minVal} from ${fromKey}`)answered Mar 25 at 6:59
Pak Wah WongPak Wah Wong
38317
answered Mar 25 at 6:59
Pak Wah WongPak Wah Wong
38317
answered Mar 25 at 6:59
Pak Wah WongPak Wah Wong
38317
answered Mar 25 at 6:59
Pak Wah WongPak Wah Wong
38317
38317
add a comment |
add a comment |
2
Here we first assume that the min, key and value as first property and the value respectively. Then we iterate through all the elements and compare with minValue to find any value less than that in the object. If it is, then we update both minValue and minKey. Anyway, the arr type is an Object. it is not an array in javascript.
var arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
var minkey = Object.keys(arr)[0];
var minValue = arr[Object.keys(arr)[0]];
for (var key in arr) {
if (arr.hasOwnProperty(key)) {
if(arr[key] < minValue){
minValue = arr[key];
minKey = key;
}
}
}
answered Mar 25 at 7:02
HarshanaHarshana
338211
add a comment |
2
Here we first assume that the min, key and value as first property and the value respectively. Then we iterate through all the elements and compare with minValue to find any value less than that in the object. If it is, then we update both minValue and minKey. Anyway, the arr type is an Object. it is not an array in javascript.
var arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
var minkey = Object.keys(arr)[0];
var minValue = arr[Object.keys(arr)[0]];
for (var key in arr) {
if (arr.hasOwnProperty(key)) {
if(arr[key] < minValue){
minValue = arr[key];
minKey = key;
}
}
}
answered Mar 25 at 7:02
HarshanaHarshana
338211
add a comment |
2
2
2
Here we first assume that the min, key and value as first property and the value respectively. Then we iterate through all the elements and compare with minValue to find any value less than that in the object. If it is, then we update both minValue and minKey. Anyway, the arr type is an Object. it is not an array in javascript.
var arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
var minkey = Object.keys(arr)[0];
var minValue = arr[Object.keys(arr)[0]];
for (var key in arr) {
if (arr.hasOwnProperty(key)) {
if(arr[key] < minValue){
minValue = arr[key];
minKey = key;
}
}
}
answered Mar 25 at 7:02
HarshanaHarshana
338211
Here we first assume that the min, key and value as first property and the value respectively. Then we iterate through all the elements and compare with minValue to find any value less than that in the object. If it is, then we update both minValue and minKey. Anyway, the arr type is an Object. it is not an array in javascript.
var arr = {lst1: 300, lst2: 381, lst3: 4, lst4: 4, lst5: 49};
var minkey = Object.keys(arr)[0];
var minValue = arr[Object.keys(arr)[0]];
for (var key in arr) {
if (arr.hasOwnProperty(key)) {
if(arr[key] < minValue){
minValue = arr[key];
minKey = key;
}
}
}
answered Mar 25 at 7:02
HarshanaHarshana
338211
answered Mar 25 at 7:02
HarshanaHarshana
338211
answered Mar 25 at 7:02
HarshanaHarshana
338211
answered Mar 25 at 7:02
HarshanaHarshana
338211
338211
add a comment |
add a comment |
2
You can use Object.entries and use Array.reduce to reduce the resulting [key-value] pair to an object which will have lowest entry:
const data = {lst1: 300, lst2: -381, lst3: 4, lst4: 4, lst5: 49, lst6: -49, lst7: 0, lst7: 78, lst7: -90};
const obj = Object.entries(data).reduce((acc, [key, value]) =>{
acc["lowest"] = acc["lowest"] ? Object.values(acc["lowest"])[0] < value ? acc["lowest"] : {[key] : value} : {[key] : value };
return acc;
}, {});
console.log(`Lowest value is found in ${JSON.stringify(obj.lowest)}`);answered Mar 25 at 7:02
Amardeep BhowmickAmardeep Bhowmick
5,03321128
add a comment |
2
You can use Object.entries and use Array.reduce to reduce the resulting [key-value] pair to an object which will have lowest entry:
const data = {lst1: 300, lst2: -381, lst3: 4, lst4: 4, lst5: 49, lst6: -49, lst7: 0, lst7: 78, lst7: -90};
const obj = Object.entries(data).reduce((acc, [key, value]) =>{
acc["lowest"] = acc["lowest"] ? Object.values(acc["lowest"])[0] < value ? acc["lowest"] : {[key] : value} : {[key] : value };
return acc;
}, {});
console.log(`Lowest value is found in ${JSON.stringify(obj.lowest)}`);answered Mar 25 at 7:02
Amardeep BhowmickAmardeep Bhowmick
5,03321128
add a comment |
2
2
2
You can use Object.entries and use Array.reduce to reduce the resulting [key-value] pair to an object which will have lowest entry:
const data = {lst1: 300, lst2: -381, lst3: 4, lst4: 4, lst5: 49, lst6: -49, lst7: 0, lst7: 78, lst7: -90};
const obj = Object.entries(data).reduce((acc, [key, value]) =>{
acc["lowest"] = acc["lowest"] ? Object.values(acc["lowest"])[0] < value ? acc["lowest"] : {[key] : value} : {[key] : value };
return acc;
}, {});
console.log(`Lowest value is found in ${JSON.stringify(obj.lowest)}`);answered Mar 25 at 7:02
Amardeep BhowmickAmardeep Bhowmick
5,03321128
You can use Object.entries and use Array.reduce to reduce the resulting [key-value] pair to an object which will have lowest entry:
const data = {lst1: 300, lst2: -381, lst3: 4, lst4: 4, lst5: 49, lst6: -49, lst7: 0, lst7: 78, lst7: -90};
const obj = Object.entries(data).reduce((acc, [key, value]) =>{
acc["lowest"] = acc["lowest"] ? Object.values(acc["lowest"])[0] < value ? acc["lowest"] : {[key] : value} : {[key] : value };
return acc;
}, {});
console.log(`Lowest value is found in ${JSON.stringify(obj.lowest)}`);const data = {lst1: 300, lst2: -381, lst3: 4, lst4: 4, lst5: 49, lst6: -49, lst7: 0, lst7: 78, lst7: -90};
const obj = Object.entries(data).reduce((acc, [key, value]) =>{
acc["lowest"] = acc["lowest"] ? Object.values(acc["lowest"])[0] < value ? acc["lowest"] : {[key] : value} : {[key] : value };
return acc;
}, {});
console.log(`Lowest value is found in ${JSON.stringify(obj.lowest)}`);const data = {lst1: 300, lst2: -381, lst3: 4, lst4: 4, lst5: 49, lst6: -49, lst7: 0, lst7: 78, lst7: -90};
const obj = Object.entries(data).reduce((acc, [key, value]) =>{
acc["lowest"] = acc["lowest"] ? Object.values(acc["lowest"])[0] < value ? acc["lowest"] : {[key] : value} : {[key] : value };
return acc;
}, {});
console.log(`Lowest value is found in ${JSON.stringify(obj.lowest)}`);answered Mar 25 at 7:02
Amardeep BhowmickAmardeep Bhowmick
5,03321128
edited Mar 25 at 7:30
answered Mar 25 at 7:02
Amardeep BhowmickAmardeep Bhowmick
5,03321128
answered Mar 25 at 7:02
Amardeep BhowmickAmardeep Bhowmick
5,03321128
answered Mar 25 at 7:02
Amardeep BhowmickAmardeep Bhowmick
5,03321128
5,03321128
add a comment |
add a comment |
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What is expected output?
– Maheer Ali
Mar 25 at 6:45
2
Do you want to get, for example,
lst3ifobj.lst3is the lowest value?– Jack Bashford
Mar 25 at 6:47
2
Also, what is
lst9? Is itlst9: 2?– Jack Bashford
Mar 25 at 6:48
may be a duplicte of stackoverflow.com/questions/38008307/…
– Syed Mehtab Hassan
Mar 25 at 6:49
9
arris not an array but anobject– Isaac
Mar 25 at 6:53