how to make parametric equation of cube












-1












$begingroup$


this is my hyperbolic equation



$y = x^2$



then convert to paramteric equation, like this:



$x = u$



$y = u^2$



so i insert the equation into x and y Axis Generator



x: u
y: u
z: 0


the output is: 2D hyperbolic object



when i insert v parameter into z Axis



the output is: 3D hyperbolic object



my question is how to make 3D cube using parametric equation and how to insert it into the Generator.



any help thank youu :-) I LOVE YOU



another exemple:



x: cos(u)
y: sin(u)
z: v


the output is: pipe



where:



u minimal: 0
u maximal: 6.28

v minimal: 0
v maximal: 1









share|cite|improve this question











$endgroup$












  • $begingroup$
    Well, you could start by considering the walls of the cube. How would you make the floor? Something like $z=0$ ?
    $endgroup$
    – Matti P.
    Dec 14 '18 at 7:52










  • $begingroup$
    i make floor using simple parametric u and v. but hard to find how make the walls. is it possible make the walls as same as when i make circle. i don't know, is my problem about parametric or not.
    $endgroup$
    – vaiana
    Dec 14 '18 at 8:00












  • $begingroup$
    thank you for your respon. what should i do with those equations? because hard to read the equation without u and v parameter. @MohammadZuhairKhan
    $endgroup$
    – vaiana
    Dec 14 '18 at 8:16


















-1












$begingroup$


this is my hyperbolic equation



$y = x^2$



then convert to paramteric equation, like this:



$x = u$



$y = u^2$



so i insert the equation into x and y Axis Generator



x: u
y: u
z: 0


the output is: 2D hyperbolic object



when i insert v parameter into z Axis



the output is: 3D hyperbolic object



my question is how to make 3D cube using parametric equation and how to insert it into the Generator.



any help thank youu :-) I LOVE YOU



another exemple:



x: cos(u)
y: sin(u)
z: v


the output is: pipe



where:



u minimal: 0
u maximal: 6.28

v minimal: 0
v maximal: 1









share|cite|improve this question











$endgroup$












  • $begingroup$
    Well, you could start by considering the walls of the cube. How would you make the floor? Something like $z=0$ ?
    $endgroup$
    – Matti P.
    Dec 14 '18 at 7:52










  • $begingroup$
    i make floor using simple parametric u and v. but hard to find how make the walls. is it possible make the walls as same as when i make circle. i don't know, is my problem about parametric or not.
    $endgroup$
    – vaiana
    Dec 14 '18 at 8:00












  • $begingroup$
    thank you for your respon. what should i do with those equations? because hard to read the equation without u and v parameter. @MohammadZuhairKhan
    $endgroup$
    – vaiana
    Dec 14 '18 at 8:16
















-1












-1








-1





$begingroup$


this is my hyperbolic equation



$y = x^2$



then convert to paramteric equation, like this:



$x = u$



$y = u^2$



so i insert the equation into x and y Axis Generator



x: u
y: u
z: 0


the output is: 2D hyperbolic object



when i insert v parameter into z Axis



the output is: 3D hyperbolic object



my question is how to make 3D cube using parametric equation and how to insert it into the Generator.



any help thank youu :-) I LOVE YOU



another exemple:



x: cos(u)
y: sin(u)
z: v


the output is: pipe



where:



u minimal: 0
u maximal: 6.28

v minimal: 0
v maximal: 1









share|cite|improve this question











$endgroup$




this is my hyperbolic equation



$y = x^2$



then convert to paramteric equation, like this:



$x = u$



$y = u^2$



so i insert the equation into x and y Axis Generator



x: u
y: u
z: 0


the output is: 2D hyperbolic object



when i insert v parameter into z Axis



the output is: 3D hyperbolic object



my question is how to make 3D cube using parametric equation and how to insert it into the Generator.



any help thank youu :-) I LOVE YOU



another exemple:



x: cos(u)
y: sin(u)
z: v


the output is: pipe



where:



u minimal: 0
u maximal: 6.28

v minimal: 0
v maximal: 1






parametric






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 14 '18 at 7:47







vaiana

















asked Dec 14 '18 at 7:35









vaianavaiana

32




32












  • $begingroup$
    Well, you could start by considering the walls of the cube. How would you make the floor? Something like $z=0$ ?
    $endgroup$
    – Matti P.
    Dec 14 '18 at 7:52










  • $begingroup$
    i make floor using simple parametric u and v. but hard to find how make the walls. is it possible make the walls as same as when i make circle. i don't know, is my problem about parametric or not.
    $endgroup$
    – vaiana
    Dec 14 '18 at 8:00












  • $begingroup$
    thank you for your respon. what should i do with those equations? because hard to read the equation without u and v parameter. @MohammadZuhairKhan
    $endgroup$
    – vaiana
    Dec 14 '18 at 8:16




















  • $begingroup$
    Well, you could start by considering the walls of the cube. How would you make the floor? Something like $z=0$ ?
    $endgroup$
    – Matti P.
    Dec 14 '18 at 7:52










  • $begingroup$
    i make floor using simple parametric u and v. but hard to find how make the walls. is it possible make the walls as same as when i make circle. i don't know, is my problem about parametric or not.
    $endgroup$
    – vaiana
    Dec 14 '18 at 8:00












  • $begingroup$
    thank you for your respon. what should i do with those equations? because hard to read the equation without u and v parameter. @MohammadZuhairKhan
    $endgroup$
    – vaiana
    Dec 14 '18 at 8:16


















$begingroup$
Well, you could start by considering the walls of the cube. How would you make the floor? Something like $z=0$ ?
$endgroup$
– Matti P.
Dec 14 '18 at 7:52




$begingroup$
Well, you could start by considering the walls of the cube. How would you make the floor? Something like $z=0$ ?
$endgroup$
– Matti P.
Dec 14 '18 at 7:52












$begingroup$
i make floor using simple parametric u and v. but hard to find how make the walls. is it possible make the walls as same as when i make circle. i don't know, is my problem about parametric or not.
$endgroup$
– vaiana
Dec 14 '18 at 8:00






$begingroup$
i make floor using simple parametric u and v. but hard to find how make the walls. is it possible make the walls as same as when i make circle. i don't know, is my problem about parametric or not.
$endgroup$
– vaiana
Dec 14 '18 at 8:00














$begingroup$
thank you for your respon. what should i do with those equations? because hard to read the equation without u and v parameter. @MohammadZuhairKhan
$endgroup$
– vaiana
Dec 14 '18 at 8:16






$begingroup$
thank you for your respon. what should i do with those equations? because hard to read the equation without u and v parameter. @MohammadZuhairKhan
$endgroup$
– vaiana
Dec 14 '18 at 8:16












1 Answer
1






active

oldest

votes


















1












$begingroup$

The equation of a solid cube of side-length $ainBbb R^+$ centred at the origin would be:



$|x|le a/2\|y|le a/2\|z|le a/2$



Parameterize it as:



$x=u, |u|le a/2\y=v, |v|le a/2\z=w, |w|le a/2$






share|cite|improve this answer











$endgroup$













  • $begingroup$
    i cannot read your equation. i input x = v ≤ a/2 and y = v ≤a/2 and then z = a/2 and still doesn't work @ShubhamJohri
    $endgroup$
    – vaiana
    Dec 20 '18 at 3:56










  • $begingroup$
    Carefully not the modulus sign around $v. y=v, |v|le a/2implies -a/2le vle a/2$, in other words $y=v,v_{min}=-a/2,v_{max}=a/2$
    $endgroup$
    – Shubham Johri
    Dec 20 '18 at 4:53












  • $begingroup$
    still not work well sir, .. i use free Blender software to make the object.. still confuse for weeks @ShubhamJohri
    $endgroup$
    – vaiana
    Dec 24 '18 at 6:13











Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3039072%2fhow-to-make-parametric-equation-of-cube%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1












$begingroup$

The equation of a solid cube of side-length $ainBbb R^+$ centred at the origin would be:



$|x|le a/2\|y|le a/2\|z|le a/2$



Parameterize it as:



$x=u, |u|le a/2\y=v, |v|le a/2\z=w, |w|le a/2$






share|cite|improve this answer











$endgroup$













  • $begingroup$
    i cannot read your equation. i input x = v ≤ a/2 and y = v ≤a/2 and then z = a/2 and still doesn't work @ShubhamJohri
    $endgroup$
    – vaiana
    Dec 20 '18 at 3:56










  • $begingroup$
    Carefully not the modulus sign around $v. y=v, |v|le a/2implies -a/2le vle a/2$, in other words $y=v,v_{min}=-a/2,v_{max}=a/2$
    $endgroup$
    – Shubham Johri
    Dec 20 '18 at 4:53












  • $begingroup$
    still not work well sir, .. i use free Blender software to make the object.. still confuse for weeks @ShubhamJohri
    $endgroup$
    – vaiana
    Dec 24 '18 at 6:13
















1












$begingroup$

The equation of a solid cube of side-length $ainBbb R^+$ centred at the origin would be:



$|x|le a/2\|y|le a/2\|z|le a/2$



Parameterize it as:



$x=u, |u|le a/2\y=v, |v|le a/2\z=w, |w|le a/2$






share|cite|improve this answer











$endgroup$













  • $begingroup$
    i cannot read your equation. i input x = v ≤ a/2 and y = v ≤a/2 and then z = a/2 and still doesn't work @ShubhamJohri
    $endgroup$
    – vaiana
    Dec 20 '18 at 3:56










  • $begingroup$
    Carefully not the modulus sign around $v. y=v, |v|le a/2implies -a/2le vle a/2$, in other words $y=v,v_{min}=-a/2,v_{max}=a/2$
    $endgroup$
    – Shubham Johri
    Dec 20 '18 at 4:53












  • $begingroup$
    still not work well sir, .. i use free Blender software to make the object.. still confuse for weeks @ShubhamJohri
    $endgroup$
    – vaiana
    Dec 24 '18 at 6:13














1












1








1





$begingroup$

The equation of a solid cube of side-length $ainBbb R^+$ centred at the origin would be:



$|x|le a/2\|y|le a/2\|z|le a/2$



Parameterize it as:



$x=u, |u|le a/2\y=v, |v|le a/2\z=w, |w|le a/2$






share|cite|improve this answer











$endgroup$



The equation of a solid cube of side-length $ainBbb R^+$ centred at the origin would be:



$|x|le a/2\|y|le a/2\|z|le a/2$



Parameterize it as:



$x=u, |u|le a/2\y=v, |v|le a/2\z=w, |w|le a/2$







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Dec 24 '18 at 10:33

























answered Dec 14 '18 at 8:07









Shubham JohriShubham Johri

5,204718




5,204718












  • $begingroup$
    i cannot read your equation. i input x = v ≤ a/2 and y = v ≤a/2 and then z = a/2 and still doesn't work @ShubhamJohri
    $endgroup$
    – vaiana
    Dec 20 '18 at 3:56










  • $begingroup$
    Carefully not the modulus sign around $v. y=v, |v|le a/2implies -a/2le vle a/2$, in other words $y=v,v_{min}=-a/2,v_{max}=a/2$
    $endgroup$
    – Shubham Johri
    Dec 20 '18 at 4:53












  • $begingroup$
    still not work well sir, .. i use free Blender software to make the object.. still confuse for weeks @ShubhamJohri
    $endgroup$
    – vaiana
    Dec 24 '18 at 6:13


















  • $begingroup$
    i cannot read your equation. i input x = v ≤ a/2 and y = v ≤a/2 and then z = a/2 and still doesn't work @ShubhamJohri
    $endgroup$
    – vaiana
    Dec 20 '18 at 3:56










  • $begingroup$
    Carefully not the modulus sign around $v. y=v, |v|le a/2implies -a/2le vle a/2$, in other words $y=v,v_{min}=-a/2,v_{max}=a/2$
    $endgroup$
    – Shubham Johri
    Dec 20 '18 at 4:53












  • $begingroup$
    still not work well sir, .. i use free Blender software to make the object.. still confuse for weeks @ShubhamJohri
    $endgroup$
    – vaiana
    Dec 24 '18 at 6:13
















$begingroup$
i cannot read your equation. i input x = v ≤ a/2 and y = v ≤a/2 and then z = a/2 and still doesn't work @ShubhamJohri
$endgroup$
– vaiana
Dec 20 '18 at 3:56




$begingroup$
i cannot read your equation. i input x = v ≤ a/2 and y = v ≤a/2 and then z = a/2 and still doesn't work @ShubhamJohri
$endgroup$
– vaiana
Dec 20 '18 at 3:56












$begingroup$
Carefully not the modulus sign around $v. y=v, |v|le a/2implies -a/2le vle a/2$, in other words $y=v,v_{min}=-a/2,v_{max}=a/2$
$endgroup$
– Shubham Johri
Dec 20 '18 at 4:53






$begingroup$
Carefully not the modulus sign around $v. y=v, |v|le a/2implies -a/2le vle a/2$, in other words $y=v,v_{min}=-a/2,v_{max}=a/2$
$endgroup$
– Shubham Johri
Dec 20 '18 at 4:53














$begingroup$
still not work well sir, .. i use free Blender software to make the object.. still confuse for weeks @ShubhamJohri
$endgroup$
– vaiana
Dec 24 '18 at 6:13




$begingroup$
still not work well sir, .. i use free Blender software to make the object.. still confuse for weeks @ShubhamJohri
$endgroup$
– vaiana
Dec 24 '18 at 6:13


















draft saved

draft discarded




















































Thanks for contributing an answer to Mathematics Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3039072%2fhow-to-make-parametric-equation-of-cube%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Plaza Victoria

Puebla de Zaragoza

Musa