Principles of math analysis by Rudin, Chapter 6 Problem 7
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Suppose $f$ is a real function on $(0, 1]$ and $f in mathscr{R}$ on $[c,1]$ for every $c>0$. Define $int_0^1 f(x)dx=lim_{cto 0} int_c^1 f(x)dx$ if this limit exists (and is finite).
(a) If $f in mathscr{R}$ on $[0,1]$, show that this definition of the integral agrees with the old one.
(b) Construct a function $f$ such that the above limit exists, although it fails to exist with $|f|$ in place of $f$.
This is Problem 7 of Chapter 6 in Principles of Mathematical Analysis by Rudin. For (a), I can prove the equation is correct but I am not sure what does 'definition agrees' mean? For (b), I have no idea.
Thank you in advance.
calculus real-analysis integration
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Suppose $f$ is a real function on $(0, 1]$ and $f in mathscr{R}$ on $[c,1]$ for every $c>0$. Define $int_0^1 f(x)dx=lim_{cto 0} int_c^1 f(x)dx$ if this limit exists (and is finite).
(a) If $f in mathscr{R}$ on $[0,1]$, show that this definition of the integral agrees with the old one.
(b) Construct a function $f$ such that the above limit exists, although it fails to exist with $|f|$ in place of $f$.
This is Problem 7 of Chapter 6 in Principles of Mathematical Analysis by Rudin. For (a), I can prove the equation is correct but I am not sure what does 'definition agrees' mean? For (b), I have no idea.
Thank you in advance.
calculus real-analysis integration
1
For (b) suppose, for $nin Bbb N,$ that $int_{1/(n+1)}^{1/n}f(x)dx=(-1)^n/n .$ Suppose that when $xin [1/(n+1),1/n]$ then $f(x)leq 0$ if $n$ is odd, while $f(x)geq 0$ if $n$ is even.
– DanielWainfleet
Nov 17 at 10:26
The above answer is more intuitive.
– Tengerye
Nov 20 at 9:02
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Suppose $f$ is a real function on $(0, 1]$ and $f in mathscr{R}$ on $[c,1]$ for every $c>0$. Define $int_0^1 f(x)dx=lim_{cto 0} int_c^1 f(x)dx$ if this limit exists (and is finite).
(a) If $f in mathscr{R}$ on $[0,1]$, show that this definition of the integral agrees with the old one.
(b) Construct a function $f$ such that the above limit exists, although it fails to exist with $|f|$ in place of $f$.
This is Problem 7 of Chapter 6 in Principles of Mathematical Analysis by Rudin. For (a), I can prove the equation is correct but I am not sure what does 'definition agrees' mean? For (b), I have no idea.
Thank you in advance.
calculus real-analysis integration
Suppose $f$ is a real function on $(0, 1]$ and $f in mathscr{R}$ on $[c,1]$ for every $c>0$. Define $int_0^1 f(x)dx=lim_{cto 0} int_c^1 f(x)dx$ if this limit exists (and is finite).
(a) If $f in mathscr{R}$ on $[0,1]$, show that this definition of the integral agrees with the old one.
(b) Construct a function $f$ such that the above limit exists, although it fails to exist with $|f|$ in place of $f$.
This is Problem 7 of Chapter 6 in Principles of Mathematical Analysis by Rudin. For (a), I can prove the equation is correct but I am not sure what does 'definition agrees' mean? For (b), I have no idea.
Thank you in advance.
calculus real-analysis integration
calculus real-analysis integration
edited Nov 17 at 3:52
qbert
21.7k32459
21.7k32459
asked Nov 17 at 3:12
Tengerye
477
477
1
For (b) suppose, for $nin Bbb N,$ that $int_{1/(n+1)}^{1/n}f(x)dx=(-1)^n/n .$ Suppose that when $xin [1/(n+1),1/n]$ then $f(x)leq 0$ if $n$ is odd, while $f(x)geq 0$ if $n$ is even.
– DanielWainfleet
Nov 17 at 10:26
The above answer is more intuitive.
– Tengerye
Nov 20 at 9:02
add a comment |
1
For (b) suppose, for $nin Bbb N,$ that $int_{1/(n+1)}^{1/n}f(x)dx=(-1)^n/n .$ Suppose that when $xin [1/(n+1),1/n]$ then $f(x)leq 0$ if $n$ is odd, while $f(x)geq 0$ if $n$ is even.
– DanielWainfleet
Nov 17 at 10:26
The above answer is more intuitive.
– Tengerye
Nov 20 at 9:02
1
1
For (b) suppose, for $nin Bbb N,$ that $int_{1/(n+1)}^{1/n}f(x)dx=(-1)^n/n .$ Suppose that when $xin [1/(n+1),1/n]$ then $f(x)leq 0$ if $n$ is odd, while $f(x)geq 0$ if $n$ is even.
– DanielWainfleet
Nov 17 at 10:26
For (b) suppose, for $nin Bbb N,$ that $int_{1/(n+1)}^{1/n}f(x)dx=(-1)^n/n .$ Suppose that when $xin [1/(n+1),1/n]$ then $f(x)leq 0$ if $n$ is odd, while $f(x)geq 0$ if $n$ is even.
– DanielWainfleet
Nov 17 at 10:26
The above answer is more intuitive.
– Tengerye
Nov 20 at 9:02
The above answer is more intuitive.
– Tengerye
Nov 20 at 9:02
add a comment |
1 Answer
1
active
oldest
votes
up vote
2
down vote
accepted
$b$) Using the well known integral
$$
int_{1}^infty frac{sin x}{x}mathrm dx
$$
which converges conditionally, we reflect reflect everything to near $0$ by sending
$$
xto 1/x
$$
and find
$$
int_{1}^inftyfrac{sin x}{x}mathrm dx=
int_0^1frac{sin(1/y)}{y}mathrm dy
$$
For part $a$, you must prove using the definition of the Riemann integral that for a function which is integrable on $[0,1]$, the number
$$
int_0^1 f(x)mathrm dx
$$
is the same as the number
$$
lim_{cto 0^+}int_c^1f(x)mathrm dx
$$
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
$b$) Using the well known integral
$$
int_{1}^infty frac{sin x}{x}mathrm dx
$$
which converges conditionally, we reflect reflect everything to near $0$ by sending
$$
xto 1/x
$$
and find
$$
int_{1}^inftyfrac{sin x}{x}mathrm dx=
int_0^1frac{sin(1/y)}{y}mathrm dy
$$
For part $a$, you must prove using the definition of the Riemann integral that for a function which is integrable on $[0,1]$, the number
$$
int_0^1 f(x)mathrm dx
$$
is the same as the number
$$
lim_{cto 0^+}int_c^1f(x)mathrm dx
$$
add a comment |
up vote
2
down vote
accepted
$b$) Using the well known integral
$$
int_{1}^infty frac{sin x}{x}mathrm dx
$$
which converges conditionally, we reflect reflect everything to near $0$ by sending
$$
xto 1/x
$$
and find
$$
int_{1}^inftyfrac{sin x}{x}mathrm dx=
int_0^1frac{sin(1/y)}{y}mathrm dy
$$
For part $a$, you must prove using the definition of the Riemann integral that for a function which is integrable on $[0,1]$, the number
$$
int_0^1 f(x)mathrm dx
$$
is the same as the number
$$
lim_{cto 0^+}int_c^1f(x)mathrm dx
$$
add a comment |
up vote
2
down vote
accepted
up vote
2
down vote
accepted
$b$) Using the well known integral
$$
int_{1}^infty frac{sin x}{x}mathrm dx
$$
which converges conditionally, we reflect reflect everything to near $0$ by sending
$$
xto 1/x
$$
and find
$$
int_{1}^inftyfrac{sin x}{x}mathrm dx=
int_0^1frac{sin(1/y)}{y}mathrm dy
$$
For part $a$, you must prove using the definition of the Riemann integral that for a function which is integrable on $[0,1]$, the number
$$
int_0^1 f(x)mathrm dx
$$
is the same as the number
$$
lim_{cto 0^+}int_c^1f(x)mathrm dx
$$
$b$) Using the well known integral
$$
int_{1}^infty frac{sin x}{x}mathrm dx
$$
which converges conditionally, we reflect reflect everything to near $0$ by sending
$$
xto 1/x
$$
and find
$$
int_{1}^inftyfrac{sin x}{x}mathrm dx=
int_0^1frac{sin(1/y)}{y}mathrm dy
$$
For part $a$, you must prove using the definition of the Riemann integral that for a function which is integrable on $[0,1]$, the number
$$
int_0^1 f(x)mathrm dx
$$
is the same as the number
$$
lim_{cto 0^+}int_c^1f(x)mathrm dx
$$
answered Nov 17 at 3:50
qbert
21.7k32459
21.7k32459
add a comment |
add a comment |
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For (b) suppose, for $nin Bbb N,$ that $int_{1/(n+1)}^{1/n}f(x)dx=(-1)^n/n .$ Suppose that when $xin [1/(n+1),1/n]$ then $f(x)leq 0$ if $n$ is odd, while $f(x)geq 0$ if $n$ is even.
– DanielWainfleet
Nov 17 at 10:26
The above answer is more intuitive.
– Tengerye
Nov 20 at 9:02