Cleaner way to handle double pointer in C++ BST?












3














I have an implementation for my first binary search tree in C++. I was wondering if there was some cleaner way to avoid using the double pointer in the way I have my code setup? Such as on one line I have:



(*node)->left = insert(&((*node)->left),value);


Which seems a bit "messy", but it almost seems necessary for the way I have implemented the BST. Maybe I am possibly missing a way I can change the syntax slightly to achieve the same result? I understand that I can have a double pointer as a parameter for my functions, but I have been told that it is not the standard in C++. I have my code posted below, along with how I am testing it.I am trying to prepare for technical interviews so any feedback is welcome.



#include<stdio.h> 
#include<stdlib.h>
#include<iostream>
struct Node
{
int data;
Node *left, *right;
};

// A utility function to create a new BST node
Node* newNode(int data)
{
Node *temp = new Node();
temp->data = data;
temp->left = NULL;
temp->right = NULL;
return temp;
}

// A utility function to do inorder traversal of BST
void inorder(Node **root)
{
if (*root != NULL)
{
inorder(&((*root)->left));
printf("%d n", (*root)->data);
inorder(&((*root)->right));
}
}

/* A utility function to insert a new node with given key in BST */
Node* insert(Node** node, int value)
{
if(*node==NULL){
return newNode(value);
}
if((*node)->data > value){
(*node)->left = insert(&((*node)->left),value);
}
else if((*node)->data < value){
(*node)->right = insert(&((*node)->right),value);
}
return *node;
}

// Driver Program to test above functions
int main()
{
/* Let us create following BST
50
/
30 70
/ /
20 40 60 80 */
Node *root = NULL;
root = insert(&root, 50);
insert(&root, 30);
insert(&root, 20);
insert(&root, 40);
insert(&root, 70);
insert(&root, 60);
insert(&root, 80);

// print inoder traversal of the BST
inorder(&root);

return 0;
}


EDIT:
By changing " ** " in the parameters of the function to "*&" was able to make code much easier to read, with the same functionality.



#include<stdio.h> 
#include<stdlib.h>
#include<iostream>
struct Node
{
int data;
Node *left, *right;
};

// A utility function to create a new BST node
Node* newNode(int data)
{
Node *temp = new Node();
temp->data = data;
temp->left = NULL;
temp->right = NULL;
return temp;
}

// A utility function to do inorder traversal of BST
void inorder(Node *&root)
{
if (root != NULL)
{
inorder(((root)->left));
printf("%d n", (root)->data);
inorder(((root)->right));
}
}

/* A utility function to insert a new node with given key in BST */
Node* insert(Node*& node, int value)
{
if(node==NULL){
return newNode(value);
}
if((node)->data > value){
node->left = insert(((node)->left),value);
}
else if((node)->data < value){
(node)->right = insert(((node)->right),value);
}
return node;
}

// Driver Program to test above functions
int main()
{
/* following BST
50
/
30 70
/ /
20 40 60 80 */
Node *root = NULL;
root = insert(root, 50);
insert(root, 30);
insert(root, 20);
insert(root, 40);
insert(root, 70);
insert(root, 60);
insert(root, 80);

// print inoder traversal of the BST
inorder(root);

return 0;
}









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    3














    I have an implementation for my first binary search tree in C++. I was wondering if there was some cleaner way to avoid using the double pointer in the way I have my code setup? Such as on one line I have:



    (*node)->left = insert(&((*node)->left),value);


    Which seems a bit "messy", but it almost seems necessary for the way I have implemented the BST. Maybe I am possibly missing a way I can change the syntax slightly to achieve the same result? I understand that I can have a double pointer as a parameter for my functions, but I have been told that it is not the standard in C++. I have my code posted below, along with how I am testing it.I am trying to prepare for technical interviews so any feedback is welcome.



    #include<stdio.h> 
    #include<stdlib.h>
    #include<iostream>
    struct Node
    {
    int data;
    Node *left, *right;
    };

    // A utility function to create a new BST node
    Node* newNode(int data)
    {
    Node *temp = new Node();
    temp->data = data;
    temp->left = NULL;
    temp->right = NULL;
    return temp;
    }

    // A utility function to do inorder traversal of BST
    void inorder(Node **root)
    {
    if (*root != NULL)
    {
    inorder(&((*root)->left));
    printf("%d n", (*root)->data);
    inorder(&((*root)->right));
    }
    }

    /* A utility function to insert a new node with given key in BST */
    Node* insert(Node** node, int value)
    {
    if(*node==NULL){
    return newNode(value);
    }
    if((*node)->data > value){
    (*node)->left = insert(&((*node)->left),value);
    }
    else if((*node)->data < value){
    (*node)->right = insert(&((*node)->right),value);
    }
    return *node;
    }

    // Driver Program to test above functions
    int main()
    {
    /* Let us create following BST
    50
    /
    30 70
    / /
    20 40 60 80 */
    Node *root = NULL;
    root = insert(&root, 50);
    insert(&root, 30);
    insert(&root, 20);
    insert(&root, 40);
    insert(&root, 70);
    insert(&root, 60);
    insert(&root, 80);

    // print inoder traversal of the BST
    inorder(&root);

    return 0;
    }


    EDIT:
    By changing " ** " in the parameters of the function to "*&" was able to make code much easier to read, with the same functionality.



    #include<stdio.h> 
    #include<stdlib.h>
    #include<iostream>
    struct Node
    {
    int data;
    Node *left, *right;
    };

    // A utility function to create a new BST node
    Node* newNode(int data)
    {
    Node *temp = new Node();
    temp->data = data;
    temp->left = NULL;
    temp->right = NULL;
    return temp;
    }

    // A utility function to do inorder traversal of BST
    void inorder(Node *&root)
    {
    if (root != NULL)
    {
    inorder(((root)->left));
    printf("%d n", (root)->data);
    inorder(((root)->right));
    }
    }

    /* A utility function to insert a new node with given key in BST */
    Node* insert(Node*& node, int value)
    {
    if(node==NULL){
    return newNode(value);
    }
    if((node)->data > value){
    node->left = insert(((node)->left),value);
    }
    else if((node)->data < value){
    (node)->right = insert(((node)->right),value);
    }
    return node;
    }

    // Driver Program to test above functions
    int main()
    {
    /* following BST
    50
    /
    30 70
    / /
    20 40 60 80 */
    Node *root = NULL;
    root = insert(root, 50);
    insert(root, 30);
    insert(root, 20);
    insert(root, 40);
    insert(root, 70);
    insert(root, 60);
    insert(root, 80);

    // print inoder traversal of the BST
    inorder(root);

    return 0;
    }









    share|improve this question









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      3












      3








      3







      I have an implementation for my first binary search tree in C++. I was wondering if there was some cleaner way to avoid using the double pointer in the way I have my code setup? Such as on one line I have:



      (*node)->left = insert(&((*node)->left),value);


      Which seems a bit "messy", but it almost seems necessary for the way I have implemented the BST. Maybe I am possibly missing a way I can change the syntax slightly to achieve the same result? I understand that I can have a double pointer as a parameter for my functions, but I have been told that it is not the standard in C++. I have my code posted below, along with how I am testing it.I am trying to prepare for technical interviews so any feedback is welcome.



      #include<stdio.h> 
      #include<stdlib.h>
      #include<iostream>
      struct Node
      {
      int data;
      Node *left, *right;
      };

      // A utility function to create a new BST node
      Node* newNode(int data)
      {
      Node *temp = new Node();
      temp->data = data;
      temp->left = NULL;
      temp->right = NULL;
      return temp;
      }

      // A utility function to do inorder traversal of BST
      void inorder(Node **root)
      {
      if (*root != NULL)
      {
      inorder(&((*root)->left));
      printf("%d n", (*root)->data);
      inorder(&((*root)->right));
      }
      }

      /* A utility function to insert a new node with given key in BST */
      Node* insert(Node** node, int value)
      {
      if(*node==NULL){
      return newNode(value);
      }
      if((*node)->data > value){
      (*node)->left = insert(&((*node)->left),value);
      }
      else if((*node)->data < value){
      (*node)->right = insert(&((*node)->right),value);
      }
      return *node;
      }

      // Driver Program to test above functions
      int main()
      {
      /* Let us create following BST
      50
      /
      30 70
      / /
      20 40 60 80 */
      Node *root = NULL;
      root = insert(&root, 50);
      insert(&root, 30);
      insert(&root, 20);
      insert(&root, 40);
      insert(&root, 70);
      insert(&root, 60);
      insert(&root, 80);

      // print inoder traversal of the BST
      inorder(&root);

      return 0;
      }


      EDIT:
      By changing " ** " in the parameters of the function to "*&" was able to make code much easier to read, with the same functionality.



      #include<stdio.h> 
      #include<stdlib.h>
      #include<iostream>
      struct Node
      {
      int data;
      Node *left, *right;
      };

      // A utility function to create a new BST node
      Node* newNode(int data)
      {
      Node *temp = new Node();
      temp->data = data;
      temp->left = NULL;
      temp->right = NULL;
      return temp;
      }

      // A utility function to do inorder traversal of BST
      void inorder(Node *&root)
      {
      if (root != NULL)
      {
      inorder(((root)->left));
      printf("%d n", (root)->data);
      inorder(((root)->right));
      }
      }

      /* A utility function to insert a new node with given key in BST */
      Node* insert(Node*& node, int value)
      {
      if(node==NULL){
      return newNode(value);
      }
      if((node)->data > value){
      node->left = insert(((node)->left),value);
      }
      else if((node)->data < value){
      (node)->right = insert(((node)->right),value);
      }
      return node;
      }

      // Driver Program to test above functions
      int main()
      {
      /* following BST
      50
      /
      30 70
      / /
      20 40 60 80 */
      Node *root = NULL;
      root = insert(root, 50);
      insert(root, 30);
      insert(root, 20);
      insert(root, 40);
      insert(root, 70);
      insert(root, 60);
      insert(root, 80);

      // print inoder traversal of the BST
      inorder(root);

      return 0;
      }









      share|improve this question









      New contributor




      Pulse is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      I have an implementation for my first binary search tree in C++. I was wondering if there was some cleaner way to avoid using the double pointer in the way I have my code setup? Such as on one line I have:



      (*node)->left = insert(&((*node)->left),value);


      Which seems a bit "messy", but it almost seems necessary for the way I have implemented the BST. Maybe I am possibly missing a way I can change the syntax slightly to achieve the same result? I understand that I can have a double pointer as a parameter for my functions, but I have been told that it is not the standard in C++. I have my code posted below, along with how I am testing it.I am trying to prepare for technical interviews so any feedback is welcome.



      #include<stdio.h> 
      #include<stdlib.h>
      #include<iostream>
      struct Node
      {
      int data;
      Node *left, *right;
      };

      // A utility function to create a new BST node
      Node* newNode(int data)
      {
      Node *temp = new Node();
      temp->data = data;
      temp->left = NULL;
      temp->right = NULL;
      return temp;
      }

      // A utility function to do inorder traversal of BST
      void inorder(Node **root)
      {
      if (*root != NULL)
      {
      inorder(&((*root)->left));
      printf("%d n", (*root)->data);
      inorder(&((*root)->right));
      }
      }

      /* A utility function to insert a new node with given key in BST */
      Node* insert(Node** node, int value)
      {
      if(*node==NULL){
      return newNode(value);
      }
      if((*node)->data > value){
      (*node)->left = insert(&((*node)->left),value);
      }
      else if((*node)->data < value){
      (*node)->right = insert(&((*node)->right),value);
      }
      return *node;
      }

      // Driver Program to test above functions
      int main()
      {
      /* Let us create following BST
      50
      /
      30 70
      / /
      20 40 60 80 */
      Node *root = NULL;
      root = insert(&root, 50);
      insert(&root, 30);
      insert(&root, 20);
      insert(&root, 40);
      insert(&root, 70);
      insert(&root, 60);
      insert(&root, 80);

      // print inoder traversal of the BST
      inorder(&root);

      return 0;
      }


      EDIT:
      By changing " ** " in the parameters of the function to "*&" was able to make code much easier to read, with the same functionality.



      #include<stdio.h> 
      #include<stdlib.h>
      #include<iostream>
      struct Node
      {
      int data;
      Node *left, *right;
      };

      // A utility function to create a new BST node
      Node* newNode(int data)
      {
      Node *temp = new Node();
      temp->data = data;
      temp->left = NULL;
      temp->right = NULL;
      return temp;
      }

      // A utility function to do inorder traversal of BST
      void inorder(Node *&root)
      {
      if (root != NULL)
      {
      inorder(((root)->left));
      printf("%d n", (root)->data);
      inorder(((root)->right));
      }
      }

      /* A utility function to insert a new node with given key in BST */
      Node* insert(Node*& node, int value)
      {
      if(node==NULL){
      return newNode(value);
      }
      if((node)->data > value){
      node->left = insert(((node)->left),value);
      }
      else if((node)->data < value){
      (node)->right = insert(((node)->right),value);
      }
      return node;
      }

      // Driver Program to test above functions
      int main()
      {
      /* following BST
      50
      /
      30 70
      / /
      20 40 60 80 */
      Node *root = NULL;
      root = insert(root, 50);
      insert(root, 30);
      insert(root, 20);
      insert(root, 40);
      insert(root, 70);
      insert(root, 60);
      insert(root, 80);

      // print inoder traversal of the BST
      inorder(root);

      return 0;
      }






      c++ algorithm binary-search






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      share|improve this question




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      edited 3 hours ago







      Pulse













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      asked 4 hours ago









      PulsePulse

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      Check out our Code of Conduct.






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      Check out our Code of Conduct.






















          1 Answer
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          4














          If you're trying to learn C++, you should get comfortable with constructors and destructors — they're what C++ is all about!



          struct Node 
          {
          int data;
          Node *left, *right;
          };

          // A utility function to create a new BST node
          Node* newNode(int data)
          {
          Node *temp = new Node();
          temp->data = data;
          temp->left = NULL;
          temp->right = NULL;
          return temp;
          }


          That's C style. C++ style would be:



          struct Node { 
          int data_;
          Node *left_ = nullptr;
          Node *right_ = nullptr;

          explicit Node(int data) : data_(data) {}
          };


          Then when you want a new heap-allocated node, you don't call newNode(42) — you call new Node(42)! Or, a good habit you should get into: call std::make_unique<Node>(42) to get back a smart pointer.



          Notice that I added sigils to your data members (data_ etc) to distinguish them from non-member variables; and I declared no more than one variable per line to reduce reader confusion.





          void inorder(Node *&root) 
          {
          if (root != NULL)
          {
          inorder(((root)->left));
          printf("%d n", (root)->data);
          inorder(((root)->right));
          }
          }


          Several things weird here. First, you have a bunch of unnecessary parentheses. (root) is the same thing as root. Second, you're passing root by non-const reference, even though you don't intend to modify it. Third, very minor nit, you're using C-style NULL instead of nullptr. Fourth, why do you print a space before the newline? Fixed up:



          void inorder(const Node *root)
          {
          if (root != nullptr) {
          inorder(root->left);
          printf("%dn", root->data);
          inorder(root->right);
          }
          }


          Remember to remove the redundant parentheses in places like insert(((node)->right),value). It's much easier to read as insert(node->right, value).






          share|improve this answer





















          • Yeah the unnecessary parentheses came from when I was editing from the previous solution. Also, surprisingly was not aware of putting a constructor / destructor into the struct, thanks for pointing that out to me. Much needed feedback.
            – Pulse
            1 hour ago











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          active

          oldest

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          active

          oldest

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          4














          If you're trying to learn C++, you should get comfortable with constructors and destructors — they're what C++ is all about!



          struct Node 
          {
          int data;
          Node *left, *right;
          };

          // A utility function to create a new BST node
          Node* newNode(int data)
          {
          Node *temp = new Node();
          temp->data = data;
          temp->left = NULL;
          temp->right = NULL;
          return temp;
          }


          That's C style. C++ style would be:



          struct Node { 
          int data_;
          Node *left_ = nullptr;
          Node *right_ = nullptr;

          explicit Node(int data) : data_(data) {}
          };


          Then when you want a new heap-allocated node, you don't call newNode(42) — you call new Node(42)! Or, a good habit you should get into: call std::make_unique<Node>(42) to get back a smart pointer.



          Notice that I added sigils to your data members (data_ etc) to distinguish them from non-member variables; and I declared no more than one variable per line to reduce reader confusion.





          void inorder(Node *&root) 
          {
          if (root != NULL)
          {
          inorder(((root)->left));
          printf("%d n", (root)->data);
          inorder(((root)->right));
          }
          }


          Several things weird here. First, you have a bunch of unnecessary parentheses. (root) is the same thing as root. Second, you're passing root by non-const reference, even though you don't intend to modify it. Third, very minor nit, you're using C-style NULL instead of nullptr. Fourth, why do you print a space before the newline? Fixed up:



          void inorder(const Node *root)
          {
          if (root != nullptr) {
          inorder(root->left);
          printf("%dn", root->data);
          inorder(root->right);
          }
          }


          Remember to remove the redundant parentheses in places like insert(((node)->right),value). It's much easier to read as insert(node->right, value).






          share|improve this answer





















          • Yeah the unnecessary parentheses came from when I was editing from the previous solution. Also, surprisingly was not aware of putting a constructor / destructor into the struct, thanks for pointing that out to me. Much needed feedback.
            – Pulse
            1 hour ago
















          4














          If you're trying to learn C++, you should get comfortable with constructors and destructors — they're what C++ is all about!



          struct Node 
          {
          int data;
          Node *left, *right;
          };

          // A utility function to create a new BST node
          Node* newNode(int data)
          {
          Node *temp = new Node();
          temp->data = data;
          temp->left = NULL;
          temp->right = NULL;
          return temp;
          }


          That's C style. C++ style would be:



          struct Node { 
          int data_;
          Node *left_ = nullptr;
          Node *right_ = nullptr;

          explicit Node(int data) : data_(data) {}
          };


          Then when you want a new heap-allocated node, you don't call newNode(42) — you call new Node(42)! Or, a good habit you should get into: call std::make_unique<Node>(42) to get back a smart pointer.



          Notice that I added sigils to your data members (data_ etc) to distinguish them from non-member variables; and I declared no more than one variable per line to reduce reader confusion.





          void inorder(Node *&root) 
          {
          if (root != NULL)
          {
          inorder(((root)->left));
          printf("%d n", (root)->data);
          inorder(((root)->right));
          }
          }


          Several things weird here. First, you have a bunch of unnecessary parentheses. (root) is the same thing as root. Second, you're passing root by non-const reference, even though you don't intend to modify it. Third, very minor nit, you're using C-style NULL instead of nullptr. Fourth, why do you print a space before the newline? Fixed up:



          void inorder(const Node *root)
          {
          if (root != nullptr) {
          inorder(root->left);
          printf("%dn", root->data);
          inorder(root->right);
          }
          }


          Remember to remove the redundant parentheses in places like insert(((node)->right),value). It's much easier to read as insert(node->right, value).






          share|improve this answer





















          • Yeah the unnecessary parentheses came from when I was editing from the previous solution. Also, surprisingly was not aware of putting a constructor / destructor into the struct, thanks for pointing that out to me. Much needed feedback.
            – Pulse
            1 hour ago














          4












          4








          4






          If you're trying to learn C++, you should get comfortable with constructors and destructors — they're what C++ is all about!



          struct Node 
          {
          int data;
          Node *left, *right;
          };

          // A utility function to create a new BST node
          Node* newNode(int data)
          {
          Node *temp = new Node();
          temp->data = data;
          temp->left = NULL;
          temp->right = NULL;
          return temp;
          }


          That's C style. C++ style would be:



          struct Node { 
          int data_;
          Node *left_ = nullptr;
          Node *right_ = nullptr;

          explicit Node(int data) : data_(data) {}
          };


          Then when you want a new heap-allocated node, you don't call newNode(42) — you call new Node(42)! Or, a good habit you should get into: call std::make_unique<Node>(42) to get back a smart pointer.



          Notice that I added sigils to your data members (data_ etc) to distinguish them from non-member variables; and I declared no more than one variable per line to reduce reader confusion.





          void inorder(Node *&root) 
          {
          if (root != NULL)
          {
          inorder(((root)->left));
          printf("%d n", (root)->data);
          inorder(((root)->right));
          }
          }


          Several things weird here. First, you have a bunch of unnecessary parentheses. (root) is the same thing as root. Second, you're passing root by non-const reference, even though you don't intend to modify it. Third, very minor nit, you're using C-style NULL instead of nullptr. Fourth, why do you print a space before the newline? Fixed up:



          void inorder(const Node *root)
          {
          if (root != nullptr) {
          inorder(root->left);
          printf("%dn", root->data);
          inorder(root->right);
          }
          }


          Remember to remove the redundant parentheses in places like insert(((node)->right),value). It's much easier to read as insert(node->right, value).






          share|improve this answer












          If you're trying to learn C++, you should get comfortable with constructors and destructors — they're what C++ is all about!



          struct Node 
          {
          int data;
          Node *left, *right;
          };

          // A utility function to create a new BST node
          Node* newNode(int data)
          {
          Node *temp = new Node();
          temp->data = data;
          temp->left = NULL;
          temp->right = NULL;
          return temp;
          }


          That's C style. C++ style would be:



          struct Node { 
          int data_;
          Node *left_ = nullptr;
          Node *right_ = nullptr;

          explicit Node(int data) : data_(data) {}
          };


          Then when you want a new heap-allocated node, you don't call newNode(42) — you call new Node(42)! Or, a good habit you should get into: call std::make_unique<Node>(42) to get back a smart pointer.



          Notice that I added sigils to your data members (data_ etc) to distinguish them from non-member variables; and I declared no more than one variable per line to reduce reader confusion.





          void inorder(Node *&root) 
          {
          if (root != NULL)
          {
          inorder(((root)->left));
          printf("%d n", (root)->data);
          inorder(((root)->right));
          }
          }


          Several things weird here. First, you have a bunch of unnecessary parentheses. (root) is the same thing as root. Second, you're passing root by non-const reference, even though you don't intend to modify it. Third, very minor nit, you're using C-style NULL instead of nullptr. Fourth, why do you print a space before the newline? Fixed up:



          void inorder(const Node *root)
          {
          if (root != nullptr) {
          inorder(root->left);
          printf("%dn", root->data);
          inorder(root->right);
          }
          }


          Remember to remove the redundant parentheses in places like insert(((node)->right),value). It's much easier to read as insert(node->right, value).







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 2 hours ago









          QuuxplusoneQuuxplusone

          11.5k11959




          11.5k11959












          • Yeah the unnecessary parentheses came from when I was editing from the previous solution. Also, surprisingly was not aware of putting a constructor / destructor into the struct, thanks for pointing that out to me. Much needed feedback.
            – Pulse
            1 hour ago


















          • Yeah the unnecessary parentheses came from when I was editing from the previous solution. Also, surprisingly was not aware of putting a constructor / destructor into the struct, thanks for pointing that out to me. Much needed feedback.
            – Pulse
            1 hour ago
















          Yeah the unnecessary parentheses came from when I was editing from the previous solution. Also, surprisingly was not aware of putting a constructor / destructor into the struct, thanks for pointing that out to me. Much needed feedback.
          – Pulse
          1 hour ago




          Yeah the unnecessary parentheses came from when I was editing from the previous solution. Also, surprisingly was not aware of putting a constructor / destructor into the struct, thanks for pointing that out to me. Much needed feedback.
          – Pulse
          1 hour ago










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