How to align equations to the left












3















I have this equation on Overleaf that aligns to the right instead of the left. I have followed instructions on other questions found here but it doesn't work.



{setlength{abovedisplayskip}{0pt}%
begin{flalign}
-frac{tau}{2} sum (x_n - mu)^2 -b_0tau -frac{lambda_0tau}{2} (mu - mu_0)^2 \
= -frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau - frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)\
= -frac{tau}{2}(sum x_n^2 + Nmu^2 - 2musum x_n) - b_0tau - frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)
end{flalign}%
}%


enter image description here



How can I align to the left?










share|improve this question


















  • 2





    Please make your given code snippet compilable ...

    – Kurt
    Dec 23 '18 at 17:17
















3















I have this equation on Overleaf that aligns to the right instead of the left. I have followed instructions on other questions found here but it doesn't work.



{setlength{abovedisplayskip}{0pt}%
begin{flalign}
-frac{tau}{2} sum (x_n - mu)^2 -b_0tau -frac{lambda_0tau}{2} (mu - mu_0)^2 \
= -frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau - frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)\
= -frac{tau}{2}(sum x_n^2 + Nmu^2 - 2musum x_n) - b_0tau - frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)
end{flalign}%
}%


enter image description here



How can I align to the left?










share|improve this question


















  • 2





    Please make your given code snippet compilable ...

    – Kurt
    Dec 23 '18 at 17:17














3












3








3


0






I have this equation on Overleaf that aligns to the right instead of the left. I have followed instructions on other questions found here but it doesn't work.



{setlength{abovedisplayskip}{0pt}%
begin{flalign}
-frac{tau}{2} sum (x_n - mu)^2 -b_0tau -frac{lambda_0tau}{2} (mu - mu_0)^2 \
= -frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau - frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)\
= -frac{tau}{2}(sum x_n^2 + Nmu^2 - 2musum x_n) - b_0tau - frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)
end{flalign}%
}%


enter image description here



How can I align to the left?










share|improve this question














I have this equation on Overleaf that aligns to the right instead of the left. I have followed instructions on other questions found here but it doesn't work.



{setlength{abovedisplayskip}{0pt}%
begin{flalign}
-frac{tau}{2} sum (x_n - mu)^2 -b_0tau -frac{lambda_0tau}{2} (mu - mu_0)^2 \
= -frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau - frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)\
= -frac{tau}{2}(sum x_n^2 + Nmu^2 - 2musum x_n) - b_0tau - frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)
end{flalign}%
}%


enter image description here



How can I align to the left?







overleaf






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share|improve this question










asked Dec 23 '18 at 17:15









SahandSahand

1164




1164








  • 2





    Please make your given code snippet compilable ...

    – Kurt
    Dec 23 '18 at 17:17














  • 2





    Please make your given code snippet compilable ...

    – Kurt
    Dec 23 '18 at 17:17








2




2





Please make your given code snippet compilable ...

– Kurt
Dec 23 '18 at 17:17





Please make your given code snippet compilable ...

– Kurt
Dec 23 '18 at 17:17










2 Answers
2






active

oldest

votes


















4














i guess that you are looking for the following:



enter image description here



documentclass{article}
usepackage{mathtools}

begin{document}
begin{equation}
begin{split}
MoveEqLeft
-frac{tau}{2}sum (x_n-mu)^2-b_0tau
-frac{lambda_0tau}{2}(mu-mu_0)^2 \
& = - frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)\
& = -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0))
end{split}
end{equation}
end{document}





share|improve this answer


























  • @Mico, thank you very much. i consider your suggestion.

    – Zarko
    Dec 23 '18 at 17:38











  • Sorry for not being sufficiently clear earlier about where the large parentheses should go. I've taken the liberty of providing an update.

    – Mico
    Dec 23 '18 at 18:20













  • @Mico, thank you very much. i should see, which parenthesis are in pair.

    – Zarko
    Dec 23 '18 at 18:47



















1














documentclass{article}
usepackage{amsmath}
begin{document}

begin{flalign}
-& frac{tau}{2}sum (x_n-mu)^2-b_0tau -frac{lambda_0tau}{2}(mu-mu_0)^2 notag \
&= -frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0) \
&= -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)) notag
end{flalign}

end{document}



enter image description here







share|improve this answer























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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    4














    i guess that you are looking for the following:



    enter image description here



    documentclass{article}
    usepackage{mathtools}

    begin{document}
    begin{equation}
    begin{split}
    MoveEqLeft
    -frac{tau}{2}sum (x_n-mu)^2-b_0tau
    -frac{lambda_0tau}{2}(mu-mu_0)^2 \
    & = - frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
    frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)\
    & = -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
    frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0))
    end{split}
    end{equation}
    end{document}





    share|improve this answer


























    • @Mico, thank you very much. i consider your suggestion.

      – Zarko
      Dec 23 '18 at 17:38











    • Sorry for not being sufficiently clear earlier about where the large parentheses should go. I've taken the liberty of providing an update.

      – Mico
      Dec 23 '18 at 18:20













    • @Mico, thank you very much. i should see, which parenthesis are in pair.

      – Zarko
      Dec 23 '18 at 18:47
















    4














    i guess that you are looking for the following:



    enter image description here



    documentclass{article}
    usepackage{mathtools}

    begin{document}
    begin{equation}
    begin{split}
    MoveEqLeft
    -frac{tau}{2}sum (x_n-mu)^2-b_0tau
    -frac{lambda_0tau}{2}(mu-mu_0)^2 \
    & = - frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
    frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)\
    & = -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
    frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0))
    end{split}
    end{equation}
    end{document}





    share|improve this answer


























    • @Mico, thank you very much. i consider your suggestion.

      – Zarko
      Dec 23 '18 at 17:38











    • Sorry for not being sufficiently clear earlier about where the large parentheses should go. I've taken the liberty of providing an update.

      – Mico
      Dec 23 '18 at 18:20













    • @Mico, thank you very much. i should see, which parenthesis are in pair.

      – Zarko
      Dec 23 '18 at 18:47














    4












    4








    4







    i guess that you are looking for the following:



    enter image description here



    documentclass{article}
    usepackage{mathtools}

    begin{document}
    begin{equation}
    begin{split}
    MoveEqLeft
    -frac{tau}{2}sum (x_n-mu)^2-b_0tau
    -frac{lambda_0tau}{2}(mu-mu_0)^2 \
    & = - frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
    frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)\
    & = -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
    frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0))
    end{split}
    end{equation}
    end{document}





    share|improve this answer















    i guess that you are looking for the following:



    enter image description here



    documentclass{article}
    usepackage{mathtools}

    begin{document}
    begin{equation}
    begin{split}
    MoveEqLeft
    -frac{tau}{2}sum (x_n-mu)^2-b_0tau
    -frac{lambda_0tau}{2}(mu-mu_0)^2 \
    & = - frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
    frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)\
    & = -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
    frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0))
    end{split}
    end{equation}
    end{document}






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Dec 23 '18 at 18:19









    Mico

    275k30373761




    275k30373761










    answered Dec 23 '18 at 17:30









    ZarkoZarko

    122k865160




    122k865160













    • @Mico, thank you very much. i consider your suggestion.

      – Zarko
      Dec 23 '18 at 17:38











    • Sorry for not being sufficiently clear earlier about where the large parentheses should go. I've taken the liberty of providing an update.

      – Mico
      Dec 23 '18 at 18:20













    • @Mico, thank you very much. i should see, which parenthesis are in pair.

      – Zarko
      Dec 23 '18 at 18:47



















    • @Mico, thank you very much. i consider your suggestion.

      – Zarko
      Dec 23 '18 at 17:38











    • Sorry for not being sufficiently clear earlier about where the large parentheses should go. I've taken the liberty of providing an update.

      – Mico
      Dec 23 '18 at 18:20













    • @Mico, thank you very much. i should see, which parenthesis are in pair.

      – Zarko
      Dec 23 '18 at 18:47

















    @Mico, thank you very much. i consider your suggestion.

    – Zarko
    Dec 23 '18 at 17:38





    @Mico, thank you very much. i consider your suggestion.

    – Zarko
    Dec 23 '18 at 17:38













    Sorry for not being sufficiently clear earlier about where the large parentheses should go. I've taken the liberty of providing an update.

    – Mico
    Dec 23 '18 at 18:20







    Sorry for not being sufficiently clear earlier about where the large parentheses should go. I've taken the liberty of providing an update.

    – Mico
    Dec 23 '18 at 18:20















    @Mico, thank you very much. i should see, which parenthesis are in pair.

    – Zarko
    Dec 23 '18 at 18:47





    @Mico, thank you very much. i should see, which parenthesis are in pair.

    – Zarko
    Dec 23 '18 at 18:47











    1














    documentclass{article}
    usepackage{amsmath}
    begin{document}

    begin{flalign}
    -& frac{tau}{2}sum (x_n-mu)^2-b_0tau -frac{lambda_0tau}{2}(mu-mu_0)^2 notag \
    &= -frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
    frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0) \
    &= -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
    frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)) notag
    end{flalign}

    end{document}



    enter image description here







    share|improve this answer




























      1














      documentclass{article}
      usepackage{amsmath}
      begin{document}

      begin{flalign}
      -& frac{tau}{2}sum (x_n-mu)^2-b_0tau -frac{lambda_0tau}{2}(mu-mu_0)^2 notag \
      &= -frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
      frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0) \
      &= -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
      frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)) notag
      end{flalign}

      end{document}



      enter image description here







      share|improve this answer


























        1












        1








        1







        documentclass{article}
        usepackage{amsmath}
        begin{document}

        begin{flalign}
        -& frac{tau}{2}sum (x_n-mu)^2-b_0tau -frac{lambda_0tau}{2}(mu-mu_0)^2 notag \
        &= -frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
        frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0) \
        &= -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
        frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)) notag
        end{flalign}

        end{document}



        enter image description here







        share|improve this answer













        documentclass{article}
        usepackage{amsmath}
        begin{document}

        begin{flalign}
        -& frac{tau}{2}sum (x_n-mu)^2-b_0tau -frac{lambda_0tau}{2}(mu-mu_0)^2 notag \
        &= -frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
        frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0) \
        &= -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
        frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)) notag
        end{flalign}

        end{document}



        enter image description here








        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Dec 23 '18 at 18:46









        AboAmmarAboAmmar

        33.5k22883




        33.5k22883






























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