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How can 260 folders be zipped individually using 7zip with a single command?

The person who originally asked this question voluntarily deleted the post. Since it was an interesting task, I resurrected the question and developed a solution, which is posted below as an answer.

This works for files not sub-folder in a parent folder
http://dropcanvas.com/w7u6a/3

http://dropcanvas.com/w7u6a/3

@echo off

cd /d %~dp0

rem 7z.exe path

set sevenzip=

if "%sevenzip%"=="" if exist "%ProgramFiles(x86)%7-zip7z.exe" set sevenzip=%ProgramFiles(x86)%7-zip7z.exe

if "%sevenzip%"=="" if exist "%ProgramFiles%7-zip7z.exe" set sevenzip=%ProgramFiles%7-zip7z.exe

if "%sevenzip%"=="" echo 7-zip not found&pause&exit

set extension=.mp4

for %%a in (*%extension%) do "%sevenzip%" a "%%~na.7z" "%%a"

pause

[/CODE]

Write it like this and there won't be any problems.

7z a  -t7z "c:usersuserdesktopfolder%%G.7z" c:usersuserdesktopfolder%%G -r

Here is a script to accomplish that (omit the comments "//", which are shown for explanation):

@echo off

for /D %%G IN (*) DO (

    //This is my path to 7-Zip, it could be different for you

cd c:program files7-zip

    //This is the dir of the parent folder in which you want the subfolders to be zipped individually.

7z a  -t7z c:usersuserdesktopfolder%%G.7z c:usersuserdesktopfolder%%G -r )

pause

-t7z is the .7z archive format being used.

To use the script:

The way the script is written is assuming that you have a parent folder with sub directory that you want to zip individually (each sub directory in its own zip archive).

Visual Representation:

----Parent Directory

--------Sub Directory (to be zipped)

--------Sub Directory (to be zipped)

--------Sub Directory (to be zipped)

--------Sub Directory (to be zipped)

--------Sub Directory (to be zipped)

Lers say that the sub directories you want to zip are located in C:UsersFooDocuments. So it would look like:

----C:UsersFooDocuments

--------Foo1

--------Foo2

--------Foo3

--------Foo4

--------Foo5

So in the script i provided, you would edit the line:

7z a  -t7z c:usersuserdesktopfolder%%G.7z c:usersuserdesktopfolder%%G -r )

to say:

7z a  -t7z c:UsersFooDocuments%%G.7z c:UsersFooDocuments%%G -r )

So now we have to set our 7z.exe location so the script can run properly.

NOTE: You do not have to do this if you succeed in setting the Environmental Variable for 7z.exe. For those who succeed, omit the line cd c:program files7-zip. To test if it worked or not, simply open cmd.exe and type in 7z, if you get a list of options and parameters, then it worked and if not, then continue with the cd command.

Find where you installed 7-Zip and copy the directory and add it after the cd. In the example, it will be installed in C:Program Files7-Zip. So the finished script will look like this:

@echo off

for /D %%G IN (*) DO (

cd C:Program Files7-Zip

7z a  -t7z c:UsersFooDocuments%%G.7z c:UsersFooDocuments%%G -r )

pause

now save the script as a .bat file extension, if using notepad you must change Save as Type to All Files (".").

If written correctly, end result should look like this:

NOTE: If you have folders that have spaces, it wont output the entire name, but where the first word before the space. Ex: Foo 1 will be archived as Foo.7z (no bueno). Same thing with more than one folder with the first word as Foo and Foo 1, they both run into the last problem i explained and when Foo is first archived, the archive for Foo 1 will try to overwrite Foo's because they have the same name. If you can find a work around this, Kudos to you!

You may also want to try Tyler's version of my script, of course, his is more "universally compatible" and involves having 7z.exe as an E.V. (Environmental Variable).