Why does this 2Pi-Periodic function looks like this?
0
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I am given this function 1 on an interval $[0,pi]$ and am asked to make a sketch of it on an interval $[-pi,pi]$. When plugging it into Maple, I am given a sketch graph like this 2, however, that is incorrect. According to the solutions by my professor, the graph is supposed to look like this 3. I particularly don't understand the left side of the graph, why is it just like the right side?
functions graphing-functions pi
edited Dec 7 '18 at 17:01
neelkanth
2,15121028
asked Dec 7 '18 at 16:58
VelionisVelionis
32
$endgroup$
add a comment |
0
$begingroup$
I am given this function 1 on an interval $[0,pi]$ and am asked to make a sketch of it on an interval $[-pi,pi]$. When plugging it into Maple, I am given a sketch graph like this 2, however, that is incorrect. According to the solutions by my professor, the graph is supposed to look like this 3. I particularly don't understand the left side of the graph, why is it just like the right side?
functions graphing-functions pi
edited Dec 7 '18 at 17:01
neelkanth
2,15121028
asked Dec 7 '18 at 16:58
VelionisVelionis
32
$endgroup$
add a comment |
0
0
0
$begingroup$
I am given this function 1 on an interval $[0,pi]$ and am asked to make a sketch of it on an interval $[-pi,pi]$. When plugging it into Maple, I am given a sketch graph like this 2, however, that is incorrect. According to the solutions by my professor, the graph is supposed to look like this 3. I particularly don't understand the left side of the graph, why is it just like the right side?
functions graphing-functions pi
edited Dec 7 '18 at 17:01
neelkanth
2,15121028
asked Dec 7 '18 at 16:58
VelionisVelionis
32
$endgroup$
I am given this function 1 on an interval $[0,pi]$ and am asked to make a sketch of it on an interval $[-pi,pi]$. When plugging it into Maple, I am given a sketch graph like this 2, however, that is incorrect. According to the solutions by my professor, the graph is supposed to look like this 3. I particularly don't understand the left side of the graph, why is it just like the right side?
functions graphing-functions pi
functions graphing-functions pi
edited Dec 7 '18 at 17:01
neelkanth
2,15121028
asked Dec 7 '18 at 16:58
VelionisVelionis
32
edited Dec 7 '18 at 17:01
neelkanth
2,15121028
asked Dec 7 '18 at 16:58
VelionisVelionis
32
edited Dec 7 '18 at 17:01
neelkanth
2,15121028
edited Dec 7 '18 at 17:01
neelkanth
2,15121028
edited Dec 7 '18 at 17:01
neelkanth
2,15121028
2,15121028
asked Dec 7 '18 at 16:58
VelionisVelionis
32
asked Dec 7 '18 at 16:58
VelionisVelionis
32
asked Dec 7 '18 at 16:58
VelionisVelionis
32
32
add a comment |
add a comment |
1 Answer
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The problem specifies it is an even function. That is, $f(-x) = f(x)$ for all $x$.
answered Dec 7 '18 at 17:00
eyeballfrogeyeballfrog
6,218629
$endgroup$
$begingroup$
Could you please clarify? I still don't quite understand that? Does it mean the function turns into 1+t?
$endgroup$
– Velionis
Dec 7 '18 at 20:06
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@Velionis In the region $-1 < t < 0$, yes.
$endgroup$
– eyeballfrog
Dec 7 '18 at 20:11
$begingroup$
Alright, but this is not given in the equation? what is the entire function then? How could I plot the whole function in Maple then?
$endgroup$
– Velionis
Dec 7 '18 at 21:05
$begingroup$
You are given the function in the interval $[0,pi]$. You are told it is even ($f(-t) = f(t)$) and has period $2pi$ ($f(t + 2pi) = f(t)$). Since every real number $t$ can be expressed as $2pi n pm x$ for some integer $n$ and $x in [0,pi]$, you have enough information to find the value of the function at every real number.
$endgroup$
– eyeballfrog
Dec 7 '18 at 21:20
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
2
$begingroup$
The problem specifies it is an even function. That is, $f(-x) = f(x)$ for all $x$.
answered Dec 7 '18 at 17:00
eyeballfrogeyeballfrog
6,218629
$endgroup$
$begingroup$
Could you please clarify? I still don't quite understand that? Does it mean the function turns into 1+t?
$endgroup$
– Velionis
Dec 7 '18 at 20:06
$begingroup$
@Velionis In the region $-1 < t < 0$, yes.
$endgroup$
– eyeballfrog
Dec 7 '18 at 20:11
$begingroup$
Alright, but this is not given in the equation? what is the entire function then? How could I plot the whole function in Maple then?
$endgroup$
– Velionis
Dec 7 '18 at 21:05
$begingroup$
You are given the function in the interval $[0,pi]$. You are told it is even ($f(-t) = f(t)$) and has period $2pi$ ($f(t + 2pi) = f(t)$). Since every real number $t$ can be expressed as $2pi n pm x$ for some integer $n$ and $x in [0,pi]$, you have enough information to find the value of the function at every real number.
$endgroup$
– eyeballfrog
Dec 7 '18 at 21:20
add a comment |
2
$begingroup$
The problem specifies it is an even function. That is, $f(-x) = f(x)$ for all $x$.
answered Dec 7 '18 at 17:00
eyeballfrogeyeballfrog
6,218629
$endgroup$
$begingroup$
Could you please clarify? I still don't quite understand that? Does it mean the function turns into 1+t?
$endgroup$
– Velionis
Dec 7 '18 at 20:06
$begingroup$
@Velionis In the region $-1 < t < 0$, yes.
$endgroup$
– eyeballfrog
Dec 7 '18 at 20:11
$begingroup$
Alright, but this is not given in the equation? what is the entire function then? How could I plot the whole function in Maple then?
$endgroup$
– Velionis
Dec 7 '18 at 21:05
$begingroup$
You are given the function in the interval $[0,pi]$. You are told it is even ($f(-t) = f(t)$) and has period $2pi$ ($f(t + 2pi) = f(t)$). Since every real number $t$ can be expressed as $2pi n pm x$ for some integer $n$ and $x in [0,pi]$, you have enough information to find the value of the function at every real number.
$endgroup$
– eyeballfrog
Dec 7 '18 at 21:20
add a comment |
2
2
2
$begingroup$
The problem specifies it is an even function. That is, $f(-x) = f(x)$ for all $x$.
answered Dec 7 '18 at 17:00
eyeballfrogeyeballfrog
6,218629
$endgroup$
The problem specifies it is an even function. That is, $f(-x) = f(x)$ for all $x$.
answered Dec 7 '18 at 17:00
eyeballfrogeyeballfrog
6,218629
edited Dec 7 '18 at 19:59
answered Dec 7 '18 at 17:00
eyeballfrogeyeballfrog
6,218629
answered Dec 7 '18 at 17:00
eyeballfrogeyeballfrog
6,218629
answered Dec 7 '18 at 17:00
eyeballfrogeyeballfrog
6,218629
6,218629
$begingroup$
Could you please clarify? I still don't quite understand that? Does it mean the function turns into 1+t?
$endgroup$
– Velionis
Dec 7 '18 at 20:06
$begingroup$
@Velionis In the region $-1 < t < 0$, yes.
$endgroup$
– eyeballfrog
Dec 7 '18 at 20:11
$begingroup$
Alright, but this is not given in the equation? what is the entire function then? How could I plot the whole function in Maple then?
$endgroup$
– Velionis
Dec 7 '18 at 21:05
$begingroup$
You are given the function in the interval $[0,pi]$. You are told it is even ($f(-t) = f(t)$) and has period $2pi$ ($f(t + 2pi) = f(t)$). Since every real number $t$ can be expressed as $2pi n pm x$ for some integer $n$ and $x in [0,pi]$, you have enough information to find the value of the function at every real number.
$endgroup$
– eyeballfrog
Dec 7 '18 at 21:20
add a comment |
$begingroup$
Could you please clarify? I still don't quite understand that? Does it mean the function turns into 1+t?
$endgroup$
– Velionis
Dec 7 '18 at 20:06
$begingroup$
@Velionis In the region $-1 < t < 0$, yes.
$endgroup$
– eyeballfrog
Dec 7 '18 at 20:11
$begingroup$
Alright, but this is not given in the equation? what is the entire function then? How could I plot the whole function in Maple then?
$endgroup$
– Velionis
Dec 7 '18 at 21:05
$begingroup$
You are given the function in the interval $[0,pi]$. You are told it is even ($f(-t) = f(t)$) and has period $2pi$ ($f(t + 2pi) = f(t)$). Since every real number $t$ can be expressed as $2pi n pm x$ for some integer $n$ and $x in [0,pi]$, you have enough information to find the value of the function at every real number.
$endgroup$
– eyeballfrog
Dec 7 '18 at 21:20
$begingroup$
Could you please clarify? I still don't quite understand that? Does it mean the function turns into 1+t?
$endgroup$
– Velionis
Dec 7 '18 at 20:06
$begingroup$
Could you please clarify? I still don't quite understand that? Does it mean the function turns into 1+t?
$endgroup$
– Velionis
Dec 7 '18 at 20:06
$begingroup$
@Velionis In the region $-1 < t < 0$, yes.
$endgroup$
– eyeballfrog
Dec 7 '18 at 20:11
$begingroup$
@Velionis In the region $-1 < t < 0$, yes.
$endgroup$
– eyeballfrog
Dec 7 '18 at 20:11
$begingroup$
Alright, but this is not given in the equation? what is the entire function then? How could I plot the whole function in Maple then?
$endgroup$
– Velionis
Dec 7 '18 at 21:05
$begingroup$
Alright, but this is not given in the equation? what is the entire function then? How could I plot the whole function in Maple then?
$endgroup$
– Velionis
Dec 7 '18 at 21:05
$begingroup$
You are given the function in the interval $[0,pi]$. You are told it is even ($f(-t) = f(t)$) and has period $2pi$ ($f(t + 2pi) = f(t)$). Since every real number $t$ can be expressed as $2pi n pm x$ for some integer $n$ and $x in [0,pi]$, you have enough information to find the value of the function at every real number.
$endgroup$
– eyeballfrog
Dec 7 '18 at 21:20
$begingroup$
You are given the function in the interval $[0,pi]$. You are told it is even ($f(-t) = f(t)$) and has period $2pi$ ($f(t + 2pi) = f(t)$). Since every real number $t$ can be expressed as $2pi n pm x$ for some integer $n$ and $x in [0,pi]$, you have enough information to find the value of the function at every real number.
$endgroup$
– eyeballfrog
Dec 7 '18 at 21:20
add a comment |
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