Is there a pattern for closed and co-closed $n$-forms on $mathbb{R}^{2n}$?
$begingroup$
Consider $mathbb{R}^{2n}$ with its standard Euclidean Riemannian metric. Let $omega in Omega^n(mathbb{R}^{2n})$ be an $n$-form.
I am trying to understand if there is a succinct way to express the equation
$$ domega=0 , , text{ and }, delta omega=0$$
i.e. $omega$ is closed and co-closed. (Here $delta=pm star d star$ is the adjoint of the $d$.)
For $n=1$, every one-form $omega in Omega^1(mathbb{R}^{2})$ can be written as
$$ omega=fdx+gdy,$$ so
$ domega=(g_x-f_y) dxwedge dy $. Thus, $domega=0 iff f_y =g_x$.
Since $star omega=fdy-gdx$, we have
$delta omega=0 iff dstar omega=0 iff f_x=-g_y$, so
$$ domega=0 , , text{ and }, delta omega=0 iff g+if , , text{ is holomorphic. }$$
Question: Is there some "nice" equivalent formulation of $0= delta omega= d omega$ for middle-dimensional forms in $mathbb{R}^{2n}$? Some sort of "generalized holomorphicity"?
Here is an attempt to write the equations for $n=2$:
Write
$omega=f_{12}dx_1 wedge dx_2 + f_{13}dx_1 wedge dx_3+f_{14}dx_1 wedge dx_4+f_{23}dx_2 wedge dx_3+f_{24}dx_2 wedge dx_4+f_{34}dx_3 wedge dx_4$,
for some $f_{ij}:mathbb{R}^4 to mathbb{R}$.
Then $domega=0$ is equivalent to the following system of $4$ equations:
$$ (f_{12})_3-(f_{13})_2+(f_{23})_1=0$$
$$ (f_{12})_4-(f_{14})_2+(f_{24})_1=0$$
$$ (f_{13})_4-(f_{14})_3+(f_{34})_1=0$$
$$ (f_{23})_4-(f_{24})_3+(f_{34})_2=0.$$
If $star omega = (tilde f_{ij})$, then $tilde f_{ij}=text{sgn}(ijkl)f_{kl}$, so (if am not mistaken) $d(star omega)=0$ is equivalent to
$$ (f_{34})_3+(f_{24})_2+(f_{14})_1=0$$
$$ (f_{34})_4-(f_{23})_2-(f_{13})_1=0$$
$$ -(f_{24})_4-(f_{23})_3+(f_{12})_1=0$$
$$ (f_{14})_4+(f_{13})_3+(f_{12})_2=0.$$
Is there any pattern here?
Any relation to holomorphicity? Or is this connection something special for dimension $2$?
We have here $6$ functions $f_{ij}$ which we can "pair naturally" (by $f_{12} iff f_{34}$ etc), and so get $3$ functions $mathbb{R}^4 cong mathbb{C}^2 to mathbb{C}$, but I am not sure that the holomorphicity of these pairs has any relation to the systems above.
Any ideas about this?
complex-analysis riemannian-geometry differential-forms complex-geometry harmonic-functions
$endgroup$
add a comment |
$begingroup$
Consider $mathbb{R}^{2n}$ with its standard Euclidean Riemannian metric. Let $omega in Omega^n(mathbb{R}^{2n})$ be an $n$-form.
I am trying to understand if there is a succinct way to express the equation
$$ domega=0 , , text{ and }, delta omega=0$$
i.e. $omega$ is closed and co-closed. (Here $delta=pm star d star$ is the adjoint of the $d$.)
For $n=1$, every one-form $omega in Omega^1(mathbb{R}^{2})$ can be written as
$$ omega=fdx+gdy,$$ so
$ domega=(g_x-f_y) dxwedge dy $. Thus, $domega=0 iff f_y =g_x$.
Since $star omega=fdy-gdx$, we have
$delta omega=0 iff dstar omega=0 iff f_x=-g_y$, so
$$ domega=0 , , text{ and }, delta omega=0 iff g+if , , text{ is holomorphic. }$$
Question: Is there some "nice" equivalent formulation of $0= delta omega= d omega$ for middle-dimensional forms in $mathbb{R}^{2n}$? Some sort of "generalized holomorphicity"?
Here is an attempt to write the equations for $n=2$:
Write
$omega=f_{12}dx_1 wedge dx_2 + f_{13}dx_1 wedge dx_3+f_{14}dx_1 wedge dx_4+f_{23}dx_2 wedge dx_3+f_{24}dx_2 wedge dx_4+f_{34}dx_3 wedge dx_4$,
for some $f_{ij}:mathbb{R}^4 to mathbb{R}$.
Then $domega=0$ is equivalent to the following system of $4$ equations:
$$ (f_{12})_3-(f_{13})_2+(f_{23})_1=0$$
$$ (f_{12})_4-(f_{14})_2+(f_{24})_1=0$$
$$ (f_{13})_4-(f_{14})_3+(f_{34})_1=0$$
$$ (f_{23})_4-(f_{24})_3+(f_{34})_2=0.$$
If $star omega = (tilde f_{ij})$, then $tilde f_{ij}=text{sgn}(ijkl)f_{kl}$, so (if am not mistaken) $d(star omega)=0$ is equivalent to
$$ (f_{34})_3+(f_{24})_2+(f_{14})_1=0$$
$$ (f_{34})_4-(f_{23})_2-(f_{13})_1=0$$
$$ -(f_{24})_4-(f_{23})_3+(f_{12})_1=0$$
$$ (f_{14})_4+(f_{13})_3+(f_{12})_2=0.$$
Is there any pattern here?
Any relation to holomorphicity? Or is this connection something special for dimension $2$?
We have here $6$ functions $f_{ij}$ which we can "pair naturally" (by $f_{12} iff f_{34}$ etc), and so get $3$ functions $mathbb{R}^4 cong mathbb{C}^2 to mathbb{C}$, but I am not sure that the holomorphicity of these pairs has any relation to the systems above.
Any ideas about this?
complex-analysis riemannian-geometry differential-forms complex-geometry harmonic-functions
$endgroup$
add a comment |
$begingroup$
Consider $mathbb{R}^{2n}$ with its standard Euclidean Riemannian metric. Let $omega in Omega^n(mathbb{R}^{2n})$ be an $n$-form.
I am trying to understand if there is a succinct way to express the equation
$$ domega=0 , , text{ and }, delta omega=0$$
i.e. $omega$ is closed and co-closed. (Here $delta=pm star d star$ is the adjoint of the $d$.)
For $n=1$, every one-form $omega in Omega^1(mathbb{R}^{2})$ can be written as
$$ omega=fdx+gdy,$$ so
$ domega=(g_x-f_y) dxwedge dy $. Thus, $domega=0 iff f_y =g_x$.
Since $star omega=fdy-gdx$, we have
$delta omega=0 iff dstar omega=0 iff f_x=-g_y$, so
$$ domega=0 , , text{ and }, delta omega=0 iff g+if , , text{ is holomorphic. }$$
Question: Is there some "nice" equivalent formulation of $0= delta omega= d omega$ for middle-dimensional forms in $mathbb{R}^{2n}$? Some sort of "generalized holomorphicity"?
Here is an attempt to write the equations for $n=2$:
Write
$omega=f_{12}dx_1 wedge dx_2 + f_{13}dx_1 wedge dx_3+f_{14}dx_1 wedge dx_4+f_{23}dx_2 wedge dx_3+f_{24}dx_2 wedge dx_4+f_{34}dx_3 wedge dx_4$,
for some $f_{ij}:mathbb{R}^4 to mathbb{R}$.
Then $domega=0$ is equivalent to the following system of $4$ equations:
$$ (f_{12})_3-(f_{13})_2+(f_{23})_1=0$$
$$ (f_{12})_4-(f_{14})_2+(f_{24})_1=0$$
$$ (f_{13})_4-(f_{14})_3+(f_{34})_1=0$$
$$ (f_{23})_4-(f_{24})_3+(f_{34})_2=0.$$
If $star omega = (tilde f_{ij})$, then $tilde f_{ij}=text{sgn}(ijkl)f_{kl}$, so (if am not mistaken) $d(star omega)=0$ is equivalent to
$$ (f_{34})_3+(f_{24})_2+(f_{14})_1=0$$
$$ (f_{34})_4-(f_{23})_2-(f_{13})_1=0$$
$$ -(f_{24})_4-(f_{23})_3+(f_{12})_1=0$$
$$ (f_{14})_4+(f_{13})_3+(f_{12})_2=0.$$
Is there any pattern here?
Any relation to holomorphicity? Or is this connection something special for dimension $2$?
We have here $6$ functions $f_{ij}$ which we can "pair naturally" (by $f_{12} iff f_{34}$ etc), and so get $3$ functions $mathbb{R}^4 cong mathbb{C}^2 to mathbb{C}$, but I am not sure that the holomorphicity of these pairs has any relation to the systems above.
Any ideas about this?
complex-analysis riemannian-geometry differential-forms complex-geometry harmonic-functions
$endgroup$
Consider $mathbb{R}^{2n}$ with its standard Euclidean Riemannian metric. Let $omega in Omega^n(mathbb{R}^{2n})$ be an $n$-form.
I am trying to understand if there is a succinct way to express the equation
$$ domega=0 , , text{ and }, delta omega=0$$
i.e. $omega$ is closed and co-closed. (Here $delta=pm star d star$ is the adjoint of the $d$.)
For $n=1$, every one-form $omega in Omega^1(mathbb{R}^{2})$ can be written as
$$ omega=fdx+gdy,$$ so
$ domega=(g_x-f_y) dxwedge dy $. Thus, $domega=0 iff f_y =g_x$.
Since $star omega=fdy-gdx$, we have
$delta omega=0 iff dstar omega=0 iff f_x=-g_y$, so
$$ domega=0 , , text{ and }, delta omega=0 iff g+if , , text{ is holomorphic. }$$
Question: Is there some "nice" equivalent formulation of $0= delta omega= d omega$ for middle-dimensional forms in $mathbb{R}^{2n}$? Some sort of "generalized holomorphicity"?
Here is an attempt to write the equations for $n=2$:
Write
$omega=f_{12}dx_1 wedge dx_2 + f_{13}dx_1 wedge dx_3+f_{14}dx_1 wedge dx_4+f_{23}dx_2 wedge dx_3+f_{24}dx_2 wedge dx_4+f_{34}dx_3 wedge dx_4$,
for some $f_{ij}:mathbb{R}^4 to mathbb{R}$.
Then $domega=0$ is equivalent to the following system of $4$ equations:
$$ (f_{12})_3-(f_{13})_2+(f_{23})_1=0$$
$$ (f_{12})_4-(f_{14})_2+(f_{24})_1=0$$
$$ (f_{13})_4-(f_{14})_3+(f_{34})_1=0$$
$$ (f_{23})_4-(f_{24})_3+(f_{34})_2=0.$$
If $star omega = (tilde f_{ij})$, then $tilde f_{ij}=text{sgn}(ijkl)f_{kl}$, so (if am not mistaken) $d(star omega)=0$ is equivalent to
$$ (f_{34})_3+(f_{24})_2+(f_{14})_1=0$$
$$ (f_{34})_4-(f_{23})_2-(f_{13})_1=0$$
$$ -(f_{24})_4-(f_{23})_3+(f_{12})_1=0$$
$$ (f_{14})_4+(f_{13})_3+(f_{12})_2=0.$$
Is there any pattern here?
Any relation to holomorphicity? Or is this connection something special for dimension $2$?
We have here $6$ functions $f_{ij}$ which we can "pair naturally" (by $f_{12} iff f_{34}$ etc), and so get $3$ functions $mathbb{R}^4 cong mathbb{C}^2 to mathbb{C}$, but I am not sure that the holomorphicity of these pairs has any relation to the systems above.
Any ideas about this?
complex-analysis riemannian-geometry differential-forms complex-geometry harmonic-functions
complex-analysis riemannian-geometry differential-forms complex-geometry harmonic-functions
edited Dec 20 '18 at 12:59
Asaf Shachar
asked Dec 13 '18 at 11:13
Asaf ShacharAsaf Shachar
5,66131141
5,66131141
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