Closed form for recursive sequence mod p
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When we have recursive sequences, we often seek to define them in a closed form if possible. Yet sometimes, these recursive sequences don't have closed forms. So my question is, is there any recursively defined sequence which doesn't have a closed form, but does have a closed form mod p? ie, ($a_n$) doesn't have a closed form, but ($a_n(mod p)$) does?
sequences-and-series
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add a comment |
$begingroup$
When we have recursive sequences, we often seek to define them in a closed form if possible. Yet sometimes, these recursive sequences don't have closed forms. So my question is, is there any recursively defined sequence which doesn't have a closed form, but does have a closed form mod p? ie, ($a_n$) doesn't have a closed form, but ($a_n(mod p)$) does?
sequences-and-series
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1
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what does "closed form" mean?
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– Siong Thye Goh
Dec 21 '18 at 4:39
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Closed form means we can write $a_n = $something not in terms of the other $a_i$. Like the closed form for the fibonacci sequence $F_n=frac{(1+sqrt(5))^n-(1-sqrt(5))^n}{2^nsqrt(5)}$. mathworld.wolfram.com/FibonacciNumber.html
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– johnrolfe
Dec 21 '18 at 4:49
add a comment |
$begingroup$
When we have recursive sequences, we often seek to define them in a closed form if possible. Yet sometimes, these recursive sequences don't have closed forms. So my question is, is there any recursively defined sequence which doesn't have a closed form, but does have a closed form mod p? ie, ($a_n$) doesn't have a closed form, but ($a_n(mod p)$) does?
sequences-and-series
$endgroup$
When we have recursive sequences, we often seek to define them in a closed form if possible. Yet sometimes, these recursive sequences don't have closed forms. So my question is, is there any recursively defined sequence which doesn't have a closed form, but does have a closed form mod p? ie, ($a_n$) doesn't have a closed form, but ($a_n(mod p)$) does?
sequences-and-series
sequences-and-series
asked Dec 21 '18 at 3:58
johnrolfejohnrolfe
111
111
1
$begingroup$
what does "closed form" mean?
$endgroup$
– Siong Thye Goh
Dec 21 '18 at 4:39
$begingroup$
Closed form means we can write $a_n = $something not in terms of the other $a_i$. Like the closed form for the fibonacci sequence $F_n=frac{(1+sqrt(5))^n-(1-sqrt(5))^n}{2^nsqrt(5)}$. mathworld.wolfram.com/FibonacciNumber.html
$endgroup$
– johnrolfe
Dec 21 '18 at 4:49
add a comment |
1
$begingroup$
what does "closed form" mean?
$endgroup$
– Siong Thye Goh
Dec 21 '18 at 4:39
$begingroup$
Closed form means we can write $a_n = $something not in terms of the other $a_i$. Like the closed form for the fibonacci sequence $F_n=frac{(1+sqrt(5))^n-(1-sqrt(5))^n}{2^nsqrt(5)}$. mathworld.wolfram.com/FibonacciNumber.html
$endgroup$
– johnrolfe
Dec 21 '18 at 4:49
1
1
$begingroup$
what does "closed form" mean?
$endgroup$
– Siong Thye Goh
Dec 21 '18 at 4:39
$begingroup$
what does "closed form" mean?
$endgroup$
– Siong Thye Goh
Dec 21 '18 at 4:39
$begingroup$
Closed form means we can write $a_n = $something not in terms of the other $a_i$. Like the closed form for the fibonacci sequence $F_n=frac{(1+sqrt(5))^n-(1-sqrt(5))^n}{2^nsqrt(5)}$. mathworld.wolfram.com/FibonacciNumber.html
$endgroup$
– johnrolfe
Dec 21 '18 at 4:49
$begingroup$
Closed form means we can write $a_n = $something not in terms of the other $a_i$. Like the closed form for the fibonacci sequence $F_n=frac{(1+sqrt(5))^n-(1-sqrt(5))^n}{2^nsqrt(5)}$. mathworld.wolfram.com/FibonacciNumber.html
$endgroup$
– johnrolfe
Dec 21 '18 at 4:49
add a comment |
1 Answer
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$begingroup$
It is really much harder than you think to nail down precisely what "closed form" means. Your definition in the comments is really not sufficient: for example, does "$a_n = 1$ if $n$ is prime and $0$ otherwise" count as a closed form?
Anyway, assuming you're only asking about one prime, the answer is yes for dumb reasons. Consider, for example, the recurrence
$$a_n = p a_{n-1}^3 + 1, a_0 = 1.$$
As far as I know, this doesn't have a closed form in any reasonable sense, but $bmod p$ the recurrence reduces to $a_n = 1$, so this sequence is constant $bmod p$.
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add a comment |
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$begingroup$
It is really much harder than you think to nail down precisely what "closed form" means. Your definition in the comments is really not sufficient: for example, does "$a_n = 1$ if $n$ is prime and $0$ otherwise" count as a closed form?
Anyway, assuming you're only asking about one prime, the answer is yes for dumb reasons. Consider, for example, the recurrence
$$a_n = p a_{n-1}^3 + 1, a_0 = 1.$$
As far as I know, this doesn't have a closed form in any reasonable sense, but $bmod p$ the recurrence reduces to $a_n = 1$, so this sequence is constant $bmod p$.
$endgroup$
add a comment |
$begingroup$
It is really much harder than you think to nail down precisely what "closed form" means. Your definition in the comments is really not sufficient: for example, does "$a_n = 1$ if $n$ is prime and $0$ otherwise" count as a closed form?
Anyway, assuming you're only asking about one prime, the answer is yes for dumb reasons. Consider, for example, the recurrence
$$a_n = p a_{n-1}^3 + 1, a_0 = 1.$$
As far as I know, this doesn't have a closed form in any reasonable sense, but $bmod p$ the recurrence reduces to $a_n = 1$, so this sequence is constant $bmod p$.
$endgroup$
add a comment |
$begingroup$
It is really much harder than you think to nail down precisely what "closed form" means. Your definition in the comments is really not sufficient: for example, does "$a_n = 1$ if $n$ is prime and $0$ otherwise" count as a closed form?
Anyway, assuming you're only asking about one prime, the answer is yes for dumb reasons. Consider, for example, the recurrence
$$a_n = p a_{n-1}^3 + 1, a_0 = 1.$$
As far as I know, this doesn't have a closed form in any reasonable sense, but $bmod p$ the recurrence reduces to $a_n = 1$, so this sequence is constant $bmod p$.
$endgroup$
It is really much harder than you think to nail down precisely what "closed form" means. Your definition in the comments is really not sufficient: for example, does "$a_n = 1$ if $n$ is prime and $0$ otherwise" count as a closed form?
Anyway, assuming you're only asking about one prime, the answer is yes for dumb reasons. Consider, for example, the recurrence
$$a_n = p a_{n-1}^3 + 1, a_0 = 1.$$
As far as I know, this doesn't have a closed form in any reasonable sense, but $bmod p$ the recurrence reduces to $a_n = 1$, so this sequence is constant $bmod p$.
answered Dec 21 '18 at 23:00
Qiaochu YuanQiaochu Yuan
282k32597944
282k32597944
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1
$begingroup$
what does "closed form" mean?
$endgroup$
– Siong Thye Goh
Dec 21 '18 at 4:39
$begingroup$
Closed form means we can write $a_n = $something not in terms of the other $a_i$. Like the closed form for the fibonacci sequence $F_n=frac{(1+sqrt(5))^n-(1-sqrt(5))^n}{2^nsqrt(5)}$. mathworld.wolfram.com/FibonacciNumber.html
$endgroup$
– johnrolfe
Dec 21 '18 at 4:49