Closed form for recursive sequence mod p












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When we have recursive sequences, we often seek to define them in a closed form if possible. Yet sometimes, these recursive sequences don't have closed forms. So my question is, is there any recursively defined sequence which doesn't have a closed form, but does have a closed form mod p? ie, ($a_n$) doesn't have a closed form, but ($a_n(mod p)$) does?










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    $begingroup$
    what does "closed form" mean?
    $endgroup$
    – Siong Thye Goh
    Dec 21 '18 at 4:39










  • $begingroup$
    Closed form means we can write $a_n = $something not in terms of the other $a_i$. Like the closed form for the fibonacci sequence $F_n=frac{(1+sqrt(5))^n-(1-sqrt(5))^n}{2^nsqrt(5)}$. mathworld.wolfram.com/FibonacciNumber.html
    $endgroup$
    – johnrolfe
    Dec 21 '18 at 4:49


















1












$begingroup$


When we have recursive sequences, we often seek to define them in a closed form if possible. Yet sometimes, these recursive sequences don't have closed forms. So my question is, is there any recursively defined sequence which doesn't have a closed form, but does have a closed form mod p? ie, ($a_n$) doesn't have a closed form, but ($a_n(mod p)$) does?










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    what does "closed form" mean?
    $endgroup$
    – Siong Thye Goh
    Dec 21 '18 at 4:39










  • $begingroup$
    Closed form means we can write $a_n = $something not in terms of the other $a_i$. Like the closed form for the fibonacci sequence $F_n=frac{(1+sqrt(5))^n-(1-sqrt(5))^n}{2^nsqrt(5)}$. mathworld.wolfram.com/FibonacciNumber.html
    $endgroup$
    – johnrolfe
    Dec 21 '18 at 4:49
















1












1








1





$begingroup$


When we have recursive sequences, we often seek to define them in a closed form if possible. Yet sometimes, these recursive sequences don't have closed forms. So my question is, is there any recursively defined sequence which doesn't have a closed form, but does have a closed form mod p? ie, ($a_n$) doesn't have a closed form, but ($a_n(mod p)$) does?










share|cite|improve this question









$endgroup$




When we have recursive sequences, we often seek to define them in a closed form if possible. Yet sometimes, these recursive sequences don't have closed forms. So my question is, is there any recursively defined sequence which doesn't have a closed form, but does have a closed form mod p? ie, ($a_n$) doesn't have a closed form, but ($a_n(mod p)$) does?







sequences-and-series






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asked Dec 21 '18 at 3:58









johnrolfejohnrolfe

111




111








  • 1




    $begingroup$
    what does "closed form" mean?
    $endgroup$
    – Siong Thye Goh
    Dec 21 '18 at 4:39










  • $begingroup$
    Closed form means we can write $a_n = $something not in terms of the other $a_i$. Like the closed form for the fibonacci sequence $F_n=frac{(1+sqrt(5))^n-(1-sqrt(5))^n}{2^nsqrt(5)}$. mathworld.wolfram.com/FibonacciNumber.html
    $endgroup$
    – johnrolfe
    Dec 21 '18 at 4:49
















  • 1




    $begingroup$
    what does "closed form" mean?
    $endgroup$
    – Siong Thye Goh
    Dec 21 '18 at 4:39










  • $begingroup$
    Closed form means we can write $a_n = $something not in terms of the other $a_i$. Like the closed form for the fibonacci sequence $F_n=frac{(1+sqrt(5))^n-(1-sqrt(5))^n}{2^nsqrt(5)}$. mathworld.wolfram.com/FibonacciNumber.html
    $endgroup$
    – johnrolfe
    Dec 21 '18 at 4:49










1




1




$begingroup$
what does "closed form" mean?
$endgroup$
– Siong Thye Goh
Dec 21 '18 at 4:39




$begingroup$
what does "closed form" mean?
$endgroup$
– Siong Thye Goh
Dec 21 '18 at 4:39












$begingroup$
Closed form means we can write $a_n = $something not in terms of the other $a_i$. Like the closed form for the fibonacci sequence $F_n=frac{(1+sqrt(5))^n-(1-sqrt(5))^n}{2^nsqrt(5)}$. mathworld.wolfram.com/FibonacciNumber.html
$endgroup$
– johnrolfe
Dec 21 '18 at 4:49






$begingroup$
Closed form means we can write $a_n = $something not in terms of the other $a_i$. Like the closed form for the fibonacci sequence $F_n=frac{(1+sqrt(5))^n-(1-sqrt(5))^n}{2^nsqrt(5)}$. mathworld.wolfram.com/FibonacciNumber.html
$endgroup$
– johnrolfe
Dec 21 '18 at 4:49












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$begingroup$

It is really much harder than you think to nail down precisely what "closed form" means. Your definition in the comments is really not sufficient: for example, does "$a_n = 1$ if $n$ is prime and $0$ otherwise" count as a closed form?



Anyway, assuming you're only asking about one prime, the answer is yes for dumb reasons. Consider, for example, the recurrence



$$a_n = p a_{n-1}^3 + 1, a_0 = 1.$$



As far as I know, this doesn't have a closed form in any reasonable sense, but $bmod p$ the recurrence reduces to $a_n = 1$, so this sequence is constant $bmod p$.






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    $begingroup$

    It is really much harder than you think to nail down precisely what "closed form" means. Your definition in the comments is really not sufficient: for example, does "$a_n = 1$ if $n$ is prime and $0$ otherwise" count as a closed form?



    Anyway, assuming you're only asking about one prime, the answer is yes for dumb reasons. Consider, for example, the recurrence



    $$a_n = p a_{n-1}^3 + 1, a_0 = 1.$$



    As far as I know, this doesn't have a closed form in any reasonable sense, but $bmod p$ the recurrence reduces to $a_n = 1$, so this sequence is constant $bmod p$.






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      It is really much harder than you think to nail down precisely what "closed form" means. Your definition in the comments is really not sufficient: for example, does "$a_n = 1$ if $n$ is prime and $0$ otherwise" count as a closed form?



      Anyway, assuming you're only asking about one prime, the answer is yes for dumb reasons. Consider, for example, the recurrence



      $$a_n = p a_{n-1}^3 + 1, a_0 = 1.$$



      As far as I know, this doesn't have a closed form in any reasonable sense, but $bmod p$ the recurrence reduces to $a_n = 1$, so this sequence is constant $bmod p$.






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        It is really much harder than you think to nail down precisely what "closed form" means. Your definition in the comments is really not sufficient: for example, does "$a_n = 1$ if $n$ is prime and $0$ otherwise" count as a closed form?



        Anyway, assuming you're only asking about one prime, the answer is yes for dumb reasons. Consider, for example, the recurrence



        $$a_n = p a_{n-1}^3 + 1, a_0 = 1.$$



        As far as I know, this doesn't have a closed form in any reasonable sense, but $bmod p$ the recurrence reduces to $a_n = 1$, so this sequence is constant $bmod p$.






        share|cite|improve this answer









        $endgroup$



        It is really much harder than you think to nail down precisely what "closed form" means. Your definition in the comments is really not sufficient: for example, does "$a_n = 1$ if $n$ is prime and $0$ otherwise" count as a closed form?



        Anyway, assuming you're only asking about one prime, the answer is yes for dumb reasons. Consider, for example, the recurrence



        $$a_n = p a_{n-1}^3 + 1, a_0 = 1.$$



        As far as I know, this doesn't have a closed form in any reasonable sense, but $bmod p$ the recurrence reduces to $a_n = 1$, so this sequence is constant $bmod p$.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 21 '18 at 23:00









        Qiaochu YuanQiaochu Yuan

        282k32597944




        282k32597944






























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