Do we have $ker (f)_{mathfrak p}simeq ker (g)$?











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Let $A,B$ be commutative rings with identity and $f:Ato B$ a homomorphism of rings. For any prime ideal $mathfrak q$ of $B$, denote $f^{-1}(mathfrak q)$ by $mathfrak p$, then $f$ induces the canonical homomorphism $g: A_{mathfrak p}to B_{mathfrak q}$, do we have $(ker f)_{mathfrak p}simeq ker g$?










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  • By Eric Wofsey's answer, it is not true. math.stackexchange.com/questions/2997819/…
    – Born to be proud
    22 hours ago












  • I wonder if jgon's answer is correct, can anybody help me check it? math.stackexchange.com/questions/2997043/…
    – Born to be proud
    22 hours ago















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Let $A,B$ be commutative rings with identity and $f:Ato B$ a homomorphism of rings. For any prime ideal $mathfrak q$ of $B$, denote $f^{-1}(mathfrak q)$ by $mathfrak p$, then $f$ induces the canonical homomorphism $g: A_{mathfrak p}to B_{mathfrak q}$, do we have $(ker f)_{mathfrak p}simeq ker g$?










share|cite|improve this question






















  • By Eric Wofsey's answer, it is not true. math.stackexchange.com/questions/2997819/…
    – Born to be proud
    22 hours ago












  • I wonder if jgon's answer is correct, can anybody help me check it? math.stackexchange.com/questions/2997043/…
    – Born to be proud
    22 hours ago













up vote
0
down vote

favorite









up vote
0
down vote

favorite











Let $A,B$ be commutative rings with identity and $f:Ato B$ a homomorphism of rings. For any prime ideal $mathfrak q$ of $B$, denote $f^{-1}(mathfrak q)$ by $mathfrak p$, then $f$ induces the canonical homomorphism $g: A_{mathfrak p}to B_{mathfrak q}$, do we have $(ker f)_{mathfrak p}simeq ker g$?










share|cite|improve this question













Let $A,B$ be commutative rings with identity and $f:Ato B$ a homomorphism of rings. For any prime ideal $mathfrak q$ of $B$, denote $f^{-1}(mathfrak q)$ by $mathfrak p$, then $f$ induces the canonical homomorphism $g: A_{mathfrak p}to B_{mathfrak q}$, do we have $(ker f)_{mathfrak p}simeq ker g$?







abstract-algebra ring-theory commutative-algebra






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share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked 23 hours ago









Born to be proud

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735510












  • By Eric Wofsey's answer, it is not true. math.stackexchange.com/questions/2997819/…
    – Born to be proud
    22 hours ago












  • I wonder if jgon's answer is correct, can anybody help me check it? math.stackexchange.com/questions/2997043/…
    – Born to be proud
    22 hours ago


















  • By Eric Wofsey's answer, it is not true. math.stackexchange.com/questions/2997819/…
    – Born to be proud
    22 hours ago












  • I wonder if jgon's answer is correct, can anybody help me check it? math.stackexchange.com/questions/2997043/…
    – Born to be proud
    22 hours ago
















By Eric Wofsey's answer, it is not true. math.stackexchange.com/questions/2997819/…
– Born to be proud
22 hours ago






By Eric Wofsey's answer, it is not true. math.stackexchange.com/questions/2997819/…
– Born to be proud
22 hours ago














I wonder if jgon's answer is correct, can anybody help me check it? math.stackexchange.com/questions/2997043/…
– Born to be proud
22 hours ago




I wonder if jgon's answer is correct, can anybody help me check it? math.stackexchange.com/questions/2997043/…
– Born to be proud
22 hours ago















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