Given: Log2=a, Log7=b. Find: Log 56.
0
I don't know how to solve this. Can someone help me? How do I use the information above to help me find Log 56?
logarithms
asked Nov 27 '18 at 1:18
THE CONFUSED PERSON
183
add a comment |
0
I don't know how to solve this. Can someone help me? How do I use the information above to help me find Log 56?
logarithms
asked Nov 27 '18 at 1:18
THE CONFUSED PERSON
183
What is the prime factorization of 56?
– Don Thousand
Nov 27 '18 at 1:21
Simpler exercises: find out $log(2^3)$ and $log(8times 7)$.
– user587192
Nov 27 '18 at 1:21
its 2, and 7 right?
– THE CONFUSED PERSON
Nov 27 '18 at 1:22
I need to solve it in terms of a and b
– THE CONFUSED PERSON
Nov 27 '18 at 1:23
add a comment |
0
0
0
I don't know how to solve this. Can someone help me? How do I use the information above to help me find Log 56?
logarithms
asked Nov 27 '18 at 1:18
THE CONFUSED PERSON
183
I don't know how to solve this. Can someone help me? How do I use the information above to help me find Log 56?
logarithms
logarithms
asked Nov 27 '18 at 1:18
THE CONFUSED PERSON
183
asked Nov 27 '18 at 1:18
THE CONFUSED PERSON
183
asked Nov 27 '18 at 1:18
THE CONFUSED PERSON
183
asked Nov 27 '18 at 1:18
THE CONFUSED PERSON
183
asked Nov 27 '18 at 1:18
THE CONFUSED PERSON
183
183
What is the prime factorization of 56?
– Don Thousand
Nov 27 '18 at 1:21
Simpler exercises: find out $log(2^3)$ and $log(8times 7)$.
– user587192
Nov 27 '18 at 1:21
its 2, and 7 right?
– THE CONFUSED PERSON
Nov 27 '18 at 1:22
I need to solve it in terms of a and b
– THE CONFUSED PERSON
Nov 27 '18 at 1:23
add a comment |
What is the prime factorization of 56?
– Don Thousand
Nov 27 '18 at 1:21
Simpler exercises: find out $log(2^3)$ and $log(8times 7)$.
– user587192
Nov 27 '18 at 1:21
its 2, and 7 right?
– THE CONFUSED PERSON
Nov 27 '18 at 1:22
I need to solve it in terms of a and b
– THE CONFUSED PERSON
Nov 27 '18 at 1:23
What is the prime factorization of 56?
– Don Thousand
Nov 27 '18 at 1:21
What is the prime factorization of 56?
– Don Thousand
Nov 27 '18 at 1:21
Simpler exercises: find out $log(2^3)$ and $log(8times 7)$.
– user587192
Nov 27 '18 at 1:21
Simpler exercises: find out $log(2^3)$ and $log(8times 7)$.
– user587192
Nov 27 '18 at 1:21
its 2, and 7 right?
– THE CONFUSED PERSON
Nov 27 '18 at 1:22
its 2, and 7 right?
– THE CONFUSED PERSON
Nov 27 '18 at 1:22
I need to solve it in terms of a and b
– THE CONFUSED PERSON
Nov 27 '18 at 1:23
I need to solve it in terms of a and b
– THE CONFUSED PERSON
Nov 27 '18 at 1:23
add a comment |
2 Answers
2
active
oldest
votes
3
$log(56) = log(7cdot8) = log(7) + log(8) = log(7) + logleft(2^{3}right) = log(7) + 3log(2) = b + 3a$
edited Nov 27 '18 at 3:46
Andrew Li
4,1431927
answered Nov 27 '18 at 1:25
ZAF
4307
I got the answer correct. I think you made a mistake, because the computer said the answer is 3a+b. Thanks for the help though ZAF.
– THE CONFUSED PERSON
Nov 27 '18 at 1:27
Might I suggest "cdot" ($cdot$) instead of a period to indicate multiplication.
– Doug M
Nov 27 '18 at 1:28
Corrected, thanks!
– ZAF
Nov 27 '18 at 1:30
add a comment |
2
Hint 1: $56= 7cdot 2^3$
Hint 2: $log (xcdot y^z)= log x+ zlog y$
answered Nov 27 '18 at 1:27
MPW
29.8k12056
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
$log(56) = log(7cdot8) = log(7) + log(8) = log(7) + logleft(2^{3}right) = log(7) + 3log(2) = b + 3a$
edited Nov 27 '18 at 3:46
Andrew Li
4,1431927
answered Nov 27 '18 at 1:25
ZAF
4307
I got the answer correct. I think you made a mistake, because the computer said the answer is 3a+b. Thanks for the help though ZAF.
– THE CONFUSED PERSON
Nov 27 '18 at 1:27
Might I suggest "cdot" ($cdot$) instead of a period to indicate multiplication.
– Doug M
Nov 27 '18 at 1:28
Corrected, thanks!
– ZAF
Nov 27 '18 at 1:30
add a comment |
3
$log(56) = log(7cdot8) = log(7) + log(8) = log(7) + logleft(2^{3}right) = log(7) + 3log(2) = b + 3a$
edited Nov 27 '18 at 3:46
Andrew Li
4,1431927
answered Nov 27 '18 at 1:25
ZAF
4307
I got the answer correct. I think you made a mistake, because the computer said the answer is 3a+b. Thanks for the help though ZAF.
– THE CONFUSED PERSON
Nov 27 '18 at 1:27
Might I suggest "cdot" ($cdot$) instead of a period to indicate multiplication.
– Doug M
Nov 27 '18 at 1:28
Corrected, thanks!
– ZAF
Nov 27 '18 at 1:30
add a comment |
3
3
3
$log(56) = log(7cdot8) = log(7) + log(8) = log(7) + logleft(2^{3}right) = log(7) + 3log(2) = b + 3a$
edited Nov 27 '18 at 3:46
Andrew Li
4,1431927
answered Nov 27 '18 at 1:25
ZAF
4307
$log(56) = log(7cdot8) = log(7) + log(8) = log(7) + logleft(2^{3}right) = log(7) + 3log(2) = b + 3a$
edited Nov 27 '18 at 3:46
Andrew Li
4,1431927
answered Nov 27 '18 at 1:25
ZAF
4307
edited Nov 27 '18 at 3:46
Andrew Li
4,1431927
edited Nov 27 '18 at 3:46
Andrew Li
4,1431927
edited Nov 27 '18 at 3:46
Andrew Li
4,1431927
4,1431927
answered Nov 27 '18 at 1:25
ZAF
4307
answered Nov 27 '18 at 1:25
ZAF
4307
answered Nov 27 '18 at 1:25
ZAF
4307
4307
I got the answer correct. I think you made a mistake, because the computer said the answer is 3a+b. Thanks for the help though ZAF.
– THE CONFUSED PERSON
Nov 27 '18 at 1:27
Might I suggest "cdot" ($cdot$) instead of a period to indicate multiplication.
– Doug M
Nov 27 '18 at 1:28
Corrected, thanks!
– ZAF
Nov 27 '18 at 1:30
add a comment |
I got the answer correct. I think you made a mistake, because the computer said the answer is 3a+b. Thanks for the help though ZAF.
– THE CONFUSED PERSON
Nov 27 '18 at 1:27
Might I suggest "cdot" ($cdot$) instead of a period to indicate multiplication.
– Doug M
Nov 27 '18 at 1:28
Corrected, thanks!
– ZAF
Nov 27 '18 at 1:30
I got the answer correct. I think you made a mistake, because the computer said the answer is 3a+b. Thanks for the help though ZAF.
– THE CONFUSED PERSON
Nov 27 '18 at 1:27
I got the answer correct. I think you made a mistake, because the computer said the answer is 3a+b. Thanks for the help though ZAF.
– THE CONFUSED PERSON
Nov 27 '18 at 1:27
Might I suggest "cdot" ($cdot$) instead of a period to indicate multiplication.
– Doug M
Nov 27 '18 at 1:28
Might I suggest "cdot" ($cdot$) instead of a period to indicate multiplication.
– Doug M
Nov 27 '18 at 1:28
Corrected, thanks!
– ZAF
Nov 27 '18 at 1:30
Corrected, thanks!
– ZAF
Nov 27 '18 at 1:30
add a comment |
2
Hint 1: $56= 7cdot 2^3$
Hint 2: $log (xcdot y^z)= log x+ zlog y$
answered Nov 27 '18 at 1:27
MPW
29.8k12056
add a comment |
2
Hint 1: $56= 7cdot 2^3$
Hint 2: $log (xcdot y^z)= log x+ zlog y$
answered Nov 27 '18 at 1:27
MPW
29.8k12056
add a comment |
2
2
2
Hint 1: $56= 7cdot 2^3$
Hint 2: $log (xcdot y^z)= log x+ zlog y$
answered Nov 27 '18 at 1:27
MPW
29.8k12056
Hint 1: $56= 7cdot 2^3$
Hint 2: $log (xcdot y^z)= log x+ zlog y$
answered Nov 27 '18 at 1:27
MPW
29.8k12056
answered Nov 27 '18 at 1:27
MPW
29.8k12056
answered Nov 27 '18 at 1:27
MPW
29.8k12056
answered Nov 27 '18 at 1:27
MPW
29.8k12056
29.8k12056
add a comment |
add a comment |
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What is the prime factorization of 56?
– Don Thousand
Nov 27 '18 at 1:21
Simpler exercises: find out $log(2^3)$ and $log(8times 7)$.
– user587192
Nov 27 '18 at 1:21
its 2, and 7 right?
– THE CONFUSED PERSON
Nov 27 '18 at 1:22
I need to solve it in terms of a and b
– THE CONFUSED PERSON
Nov 27 '18 at 1:23