How to retain constant velocity when friction increases
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I'm writing a game and I'm trying to calculate how to retain a constant velocity no matter what the friction is. For example if the player has a velocity of 25, a mass of 40, friction is 0.1 (friction is constant) and acceleration can be calculated through: velocity / (mass + 5). Then I want that player to still have a velocity of 25. So what I'm after is some sort of formula using the acceleration in order to cancel out the friction, no matter what the friction is. Thank you for your time!
functions
asked Nov 29 '18 at 16:03
Blue shirtBlue shirt
1
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add a comment |
$begingroup$
I'm writing a game and I'm trying to calculate how to retain a constant velocity no matter what the friction is. For example if the player has a velocity of 25, a mass of 40, friction is 0.1 (friction is constant) and acceleration can be calculated through: velocity / (mass + 5). Then I want that player to still have a velocity of 25. So what I'm after is some sort of formula using the acceleration in order to cancel out the friction, no matter what the friction is. Thank you for your time!
functions
asked Nov 29 '18 at 16:03
Blue shirtBlue shirt
1
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$begingroup$
Can you just set friction to 0?
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– user3482749
Nov 29 '18 at 16:04
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No, it's done s that if someone wants to change the friction the velocity should still remain the same, no matter what. @user3482749
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– Blue shirt
Nov 29 '18 at 16:08
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You're writing the game. Just write some code that sets friction to zero while this is going on, while keeping track of the actual friction in some other variable as it changes, then write the friction back to the variable when this constant-velocity state ends.
$endgroup$
– user3482749
Nov 29 '18 at 16:10
add a comment |
$begingroup$
I'm writing a game and I'm trying to calculate how to retain a constant velocity no matter what the friction is. For example if the player has a velocity of 25, a mass of 40, friction is 0.1 (friction is constant) and acceleration can be calculated through: velocity / (mass + 5). Then I want that player to still have a velocity of 25. So what I'm after is some sort of formula using the acceleration in order to cancel out the friction, no matter what the friction is. Thank you for your time!
functions
asked Nov 29 '18 at 16:03
Blue shirtBlue shirt
1
$endgroup$
I'm writing a game and I'm trying to calculate how to retain a constant velocity no matter what the friction is. For example if the player has a velocity of 25, a mass of 40, friction is 0.1 (friction is constant) and acceleration can be calculated through: velocity / (mass + 5). Then I want that player to still have a velocity of 25. So what I'm after is some sort of formula using the acceleration in order to cancel out the friction, no matter what the friction is. Thank you for your time!
functions
functions
asked Nov 29 '18 at 16:03
Blue shirtBlue shirt
1
asked Nov 29 '18 at 16:03
Blue shirtBlue shirt
1
asked Nov 29 '18 at 16:03
Blue shirtBlue shirt
1
asked Nov 29 '18 at 16:03
Blue shirtBlue shirt
1
asked Nov 29 '18 at 16:03
Blue shirtBlue shirt
1
1
$begingroup$
Can you just set friction to 0?
$endgroup$
– user3482749
Nov 29 '18 at 16:04
$begingroup$
No, it's done s that if someone wants to change the friction the velocity should still remain the same, no matter what. @user3482749
$endgroup$
– Blue shirt
Nov 29 '18 at 16:08
$begingroup$
You're writing the game. Just write some code that sets friction to zero while this is going on, while keeping track of the actual friction in some other variable as it changes, then write the friction back to the variable when this constant-velocity state ends.
$endgroup$
– user3482749
Nov 29 '18 at 16:10
add a comment |
$begingroup$
Can you just set friction to 0?
$endgroup$
– user3482749
Nov 29 '18 at 16:04
$begingroup$
No, it's done s that if someone wants to change the friction the velocity should still remain the same, no matter what. @user3482749
$endgroup$
– Blue shirt
Nov 29 '18 at 16:08
$begingroup$
You're writing the game. Just write some code that sets friction to zero while this is going on, while keeping track of the actual friction in some other variable as it changes, then write the friction back to the variable when this constant-velocity state ends.
$endgroup$
– user3482749
Nov 29 '18 at 16:10
$begingroup$
Can you just set friction to 0?
$endgroup$
– user3482749
Nov 29 '18 at 16:04
$begingroup$
Can you just set friction to 0?
$endgroup$
– user3482749
Nov 29 '18 at 16:04
$begingroup$
No, it's done s that if someone wants to change the friction the velocity should still remain the same, no matter what. @user3482749
$endgroup$
– Blue shirt
Nov 29 '18 at 16:08
$begingroup$
No, it's done s that if someone wants to change the friction the velocity should still remain the same, no matter what. @user3482749
$endgroup$
– Blue shirt
Nov 29 '18 at 16:08
$begingroup$
You're writing the game. Just write some code that sets friction to zero while this is going on, while keeping track of the actual friction in some other variable as it changes, then write the friction back to the variable when this constant-velocity state ends.
$endgroup$
– user3482749
Nov 29 '18 at 16:10
$begingroup$
You're writing the game. Just write some code that sets friction to zero while this is going on, while keeping track of the actual friction in some other variable as it changes, then write the friction back to the variable when this constant-velocity state ends.
$endgroup$
– user3482749
Nov 29 '18 at 16:10
add a comment |
2 Answers
2
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oldest
votes
$begingroup$
If you say acceleration=velocity/(mass+5) there is no consideration of friction there, so it will have no impact. If you want the velocity to be constant you need the acceleration to be zero unless you are using the terms in a nonstandard way. It won't be friction that changes the velocity, it will be your acceleration equation.
answered Nov 29 '18 at 16:14
Ross MillikanRoss Millikan
293k23197371
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add a comment |
$begingroup$
You need to have a force of (µmg) being applied to get zero acceleration, but formula using acceleration doesn't really make sense since you need the acceleration to be zero.
Maybe you want constant acceleration?
answered Nov 29 '18 at 16:18
Kindeep Singh KargilKindeep Singh Kargil
12
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add a comment |
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2 Answers
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active
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2 Answers
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active
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$begingroup$
If you say acceleration=velocity/(mass+5) there is no consideration of friction there, so it will have no impact. If you want the velocity to be constant you need the acceleration to be zero unless you are using the terms in a nonstandard way. It won't be friction that changes the velocity, it will be your acceleration equation.
answered Nov 29 '18 at 16:14
Ross MillikanRoss Millikan
293k23197371
$endgroup$
add a comment |
$begingroup$
If you say acceleration=velocity/(mass+5) there is no consideration of friction there, so it will have no impact. If you want the velocity to be constant you need the acceleration to be zero unless you are using the terms in a nonstandard way. It won't be friction that changes the velocity, it will be your acceleration equation.
answered Nov 29 '18 at 16:14
Ross MillikanRoss Millikan
293k23197371
$endgroup$
add a comment |
$begingroup$
If you say acceleration=velocity/(mass+5) there is no consideration of friction there, so it will have no impact. If you want the velocity to be constant you need the acceleration to be zero unless you are using the terms in a nonstandard way. It won't be friction that changes the velocity, it will be your acceleration equation.
answered Nov 29 '18 at 16:14
Ross MillikanRoss Millikan
293k23197371
$endgroup$
If you say acceleration=velocity/(mass+5) there is no consideration of friction there, so it will have no impact. If you want the velocity to be constant you need the acceleration to be zero unless you are using the terms in a nonstandard way. It won't be friction that changes the velocity, it will be your acceleration equation.
answered Nov 29 '18 at 16:14
Ross MillikanRoss Millikan
293k23197371
answered Nov 29 '18 at 16:14
Ross MillikanRoss Millikan
293k23197371
answered Nov 29 '18 at 16:14
Ross MillikanRoss Millikan
293k23197371
answered Nov 29 '18 at 16:14
Ross MillikanRoss Millikan
293k23197371
293k23197371
add a comment |
add a comment |
$begingroup$
You need to have a force of (µmg) being applied to get zero acceleration, but formula using acceleration doesn't really make sense since you need the acceleration to be zero.
Maybe you want constant acceleration?
answered Nov 29 '18 at 16:18
Kindeep Singh KargilKindeep Singh Kargil
12
$endgroup$
add a comment |
$begingroup$
You need to have a force of (µmg) being applied to get zero acceleration, but formula using acceleration doesn't really make sense since you need the acceleration to be zero.
Maybe you want constant acceleration?
answered Nov 29 '18 at 16:18
Kindeep Singh KargilKindeep Singh Kargil
12
$endgroup$
add a comment |
$begingroup$
You need to have a force of (µmg) being applied to get zero acceleration, but formula using acceleration doesn't really make sense since you need the acceleration to be zero.
Maybe you want constant acceleration?
answered Nov 29 '18 at 16:18
Kindeep Singh KargilKindeep Singh Kargil
12
$endgroup$
You need to have a force of (µmg) being applied to get zero acceleration, but formula using acceleration doesn't really make sense since you need the acceleration to be zero.
Maybe you want constant acceleration?
answered Nov 29 '18 at 16:18
Kindeep Singh KargilKindeep Singh Kargil
12
answered Nov 29 '18 at 16:18
Kindeep Singh KargilKindeep Singh Kargil
12
answered Nov 29 '18 at 16:18
Kindeep Singh KargilKindeep Singh Kargil
12
answered Nov 29 '18 at 16:18
Kindeep Singh KargilKindeep Singh Kargil
12
12
add a comment |
add a comment |
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$begingroup$
Can you just set friction to 0?
$endgroup$
– user3482749
Nov 29 '18 at 16:04
$begingroup$
No, it's done s that if someone wants to change the friction the velocity should still remain the same, no matter what. @user3482749
$endgroup$
– Blue shirt
Nov 29 '18 at 16:08
$begingroup$
You're writing the game. Just write some code that sets friction to zero while this is going on, while keeping track of the actual friction in some other variable as it changes, then write the friction back to the variable when this constant-velocity state ends.
$endgroup$
– user3482749
Nov 29 '18 at 16:10