The sum of all the numerals from the numbers
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This is math question. Please help to find, what does the sum of all the numerals from the numbers from 100 up to 1000 equal to?
arithmetic
asked Nov 29 '18 at 16:12
Alexandr ChornousAlexandr Chornous
1
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add a comment |
$begingroup$
This is math question. Please help to find, what does the sum of all the numerals from the numbers from 100 up to 1000 equal to?
arithmetic
asked Nov 29 '18 at 16:12
Alexandr ChornousAlexandr Chornous
1
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3
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Hint: $100 + ldots + 1000 = (100 + 1000) + (101 + 999) + ldots + (549+551) + 550$.
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– user3482749
Nov 29 '18 at 16:15
add a comment |
$begingroup$
This is math question. Please help to find, what does the sum of all the numerals from the numbers from 100 up to 1000 equal to?
arithmetic
asked Nov 29 '18 at 16:12
Alexandr ChornousAlexandr Chornous
1
$endgroup$
This is math question. Please help to find, what does the sum of all the numerals from the numbers from 100 up to 1000 equal to?
arithmetic
arithmetic
asked Nov 29 '18 at 16:12
Alexandr ChornousAlexandr Chornous
1
asked Nov 29 '18 at 16:12
Alexandr ChornousAlexandr Chornous
1
asked Nov 29 '18 at 16:12
Alexandr ChornousAlexandr Chornous
1
asked Nov 29 '18 at 16:12
Alexandr ChornousAlexandr Chornous
1
asked Nov 29 '18 at 16:12
Alexandr ChornousAlexandr Chornous
1
1
3
$begingroup$
Hint: $100 + ldots + 1000 = (100 + 1000) + (101 + 999) + ldots + (549+551) + 550$.
$endgroup$
– user3482749
Nov 29 '18 at 16:15
add a comment |
3
$begingroup$
Hint: $100 + ldots + 1000 = (100 + 1000) + (101 + 999) + ldots + (549+551) + 550$.
$endgroup$
– user3482749
Nov 29 '18 at 16:15
3
3
$begingroup$
Hint: $100 + ldots + 1000 = (100 + 1000) + (101 + 999) + ldots + (549+551) + 550$.
$endgroup$
– user3482749
Nov 29 '18 at 16:15
$begingroup$
Hint: $100 + ldots + 1000 = (100 + 1000) + (101 + 999) + ldots + (549+551) + 550$.
$endgroup$
– user3482749
Nov 29 '18 at 16:15
add a comment |
1 Answer
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$begingroup$
You can answer this by using the following formula:
$sum^n_{i=1}i=dfrac{n(n+1)}{2}$
The proof of which can be found here. If we rephrase your question in mathematical terms, using this sum notation, you are asking:
$sum^{1000}_{i=100}i=?$
This is equal to
$sum^{1000}_{i=1}i-sum^{99}_{i=1}i$
So use the formula above with these values to get the answer.
answered Nov 29 '18 at 16:19
MMRMMR
267
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1 Answer
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1 Answer
1
active
oldest
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active
oldest
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active
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votes
$begingroup$
You can answer this by using the following formula:
$sum^n_{i=1}i=dfrac{n(n+1)}{2}$
The proof of which can be found here. If we rephrase your question in mathematical terms, using this sum notation, you are asking:
$sum^{1000}_{i=100}i=?$
This is equal to
$sum^{1000}_{i=1}i-sum^{99}_{i=1}i$
So use the formula above with these values to get the answer.
answered Nov 29 '18 at 16:19
MMRMMR
267
$endgroup$
add a comment |
$begingroup$
You can answer this by using the following formula:
$sum^n_{i=1}i=dfrac{n(n+1)}{2}$
The proof of which can be found here. If we rephrase your question in mathematical terms, using this sum notation, you are asking:
$sum^{1000}_{i=100}i=?$
This is equal to
$sum^{1000}_{i=1}i-sum^{99}_{i=1}i$
So use the formula above with these values to get the answer.
answered Nov 29 '18 at 16:19
MMRMMR
267
$endgroup$
add a comment |
$begingroup$
You can answer this by using the following formula:
$sum^n_{i=1}i=dfrac{n(n+1)}{2}$
The proof of which can be found here. If we rephrase your question in mathematical terms, using this sum notation, you are asking:
$sum^{1000}_{i=100}i=?$
This is equal to
$sum^{1000}_{i=1}i-sum^{99}_{i=1}i$
So use the formula above with these values to get the answer.
answered Nov 29 '18 at 16:19
MMRMMR
267
$endgroup$
You can answer this by using the following formula:
$sum^n_{i=1}i=dfrac{n(n+1)}{2}$
The proof of which can be found here. If we rephrase your question in mathematical terms, using this sum notation, you are asking:
$sum^{1000}_{i=100}i=?$
This is equal to
$sum^{1000}_{i=1}i-sum^{99}_{i=1}i$
So use the formula above with these values to get the answer.
answered Nov 29 '18 at 16:19
MMRMMR
267
edited Nov 29 '18 at 16:33
answered Nov 29 '18 at 16:19
MMRMMR
267
answered Nov 29 '18 at 16:19
MMRMMR
267
answered Nov 29 '18 at 16:19
MMRMMR
267
267
add a comment |
add a comment |
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$begingroup$
Hint: $100 + ldots + 1000 = (100 + 1000) + (101 + 999) + ldots + (549+551) + 550$.
$endgroup$
– user3482749
Nov 29 '18 at 16:15