proble with ti nspire cx cas [closed]
$begingroup$
So i enter a some basic algebra on my calculator
24xy/(27x^(-2))÷(36x^2 y^(-2))/(45xy^4)
screenshot of problem
my pronlem is that, this is a wrong answer the correct answer should be $$dfrac{10x^2 y^8}9$$
and I get $dfrac{10x y^8}9$ on the calculator, I also check it by hand and on the computer as you can see on the screenshot my question is why I'm getting that answer on the calculator.
algebra-precalculus
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closed as off-topic by Morgan Rodgers, Lord Shark the Unknown, user10354138, KReiser, Jyrki Lahtonen Dec 2 '18 at 8:40
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is not about mathematics, within the scope defined in the help center." – Morgan Rodgers, Lord Shark the Unknown, user10354138, KReiser, Jyrki Lahtonen
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
$begingroup$
So i enter a some basic algebra on my calculator
24xy/(27x^(-2))÷(36x^2 y^(-2))/(45xy^4)
screenshot of problem
my pronlem is that, this is a wrong answer the correct answer should be $$dfrac{10x^2 y^8}9$$
and I get $dfrac{10x y^8}9$ on the calculator, I also check it by hand and on the computer as you can see on the screenshot my question is why I'm getting that answer on the calculator.
algebra-precalculus
$endgroup$
closed as off-topic by Morgan Rodgers, Lord Shark the Unknown, user10354138, KReiser, Jyrki Lahtonen Dec 2 '18 at 8:40
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is not about mathematics, within the scope defined in the help center." – Morgan Rodgers, Lord Shark the Unknown, user10354138, KReiser, Jyrki Lahtonen
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
$begingroup$
So i enter a some basic algebra on my calculator
24xy/(27x^(-2))÷(36x^2 y^(-2))/(45xy^4)
screenshot of problem
my pronlem is that, this is a wrong answer the correct answer should be $$dfrac{10x^2 y^8}9$$
and I get $dfrac{10x y^8}9$ on the calculator, I also check it by hand and on the computer as you can see on the screenshot my question is why I'm getting that answer on the calculator.
algebra-precalculus
$endgroup$
So i enter a some basic algebra on my calculator
24xy/(27x^(-2))÷(36x^2 y^(-2))/(45xy^4)
screenshot of problem
my pronlem is that, this is a wrong answer the correct answer should be $$dfrac{10x^2 y^8}9$$
and I get $dfrac{10x y^8}9$ on the calculator, I also check it by hand and on the computer as you can see on the screenshot my question is why I'm getting that answer on the calculator.
algebra-precalculus
algebra-precalculus
edited Dec 2 '18 at 7:27
Tianlalu
3,08621038
3,08621038
asked Dec 2 '18 at 0:16
lcrimsonllcrimsonl
1
1
closed as off-topic by Morgan Rodgers, Lord Shark the Unknown, user10354138, KReiser, Jyrki Lahtonen Dec 2 '18 at 8:40
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is not about mathematics, within the scope defined in the help center." – Morgan Rodgers, Lord Shark the Unknown, user10354138, KReiser, Jyrki Lahtonen
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Morgan Rodgers, Lord Shark the Unknown, user10354138, KReiser, Jyrki Lahtonen Dec 2 '18 at 8:40
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is not about mathematics, within the scope defined in the help center." – Morgan Rodgers, Lord Shark the Unknown, user10354138, KReiser, Jyrki Lahtonen
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
add a comment |
1 Answer
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votes
$begingroup$
Parentheses.
"24xy/(27x^(-2) )÷(36x^2 y^(-2))/(45xy^4 )" means
$$ frac{24xy}{frac{27x^{-2}}{frac{36x^2 y^{-2}}{(45xy^4)}}} $$
That is, a sequence of multiplications and divisions occurs in left-to-right order. An easier example:
$12/2/2/3 = 1$
What is shown on your calculator is
$$ frac{frac{24xy}{27x^{-2}}}{frac{36x^2 y^{-2}}{45 xy^4 }} $$
which can be obtained by parenthesizing your original string: "(24xy/(27x^(-2) ))÷((36x^2 y^(-2))/(45xy^4))".
This should also be a reminder to not be sloppy about the width of the horizontal lines in nested divisions, since that width is the only indication about the grouping, and hence ordering, of the divisions.
$endgroup$
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Parentheses.
"24xy/(27x^(-2) )÷(36x^2 y^(-2))/(45xy^4 )" means
$$ frac{24xy}{frac{27x^{-2}}{frac{36x^2 y^{-2}}{(45xy^4)}}} $$
That is, a sequence of multiplications and divisions occurs in left-to-right order. An easier example:
$12/2/2/3 = 1$
What is shown on your calculator is
$$ frac{frac{24xy}{27x^{-2}}}{frac{36x^2 y^{-2}}{45 xy^4 }} $$
which can be obtained by parenthesizing your original string: "(24xy/(27x^(-2) ))÷((36x^2 y^(-2))/(45xy^4))".
This should also be a reminder to not be sloppy about the width of the horizontal lines in nested divisions, since that width is the only indication about the grouping, and hence ordering, of the divisions.
$endgroup$
add a comment |
$begingroup$
Parentheses.
"24xy/(27x^(-2) )÷(36x^2 y^(-2))/(45xy^4 )" means
$$ frac{24xy}{frac{27x^{-2}}{frac{36x^2 y^{-2}}{(45xy^4)}}} $$
That is, a sequence of multiplications and divisions occurs in left-to-right order. An easier example:
$12/2/2/3 = 1$
What is shown on your calculator is
$$ frac{frac{24xy}{27x^{-2}}}{frac{36x^2 y^{-2}}{45 xy^4 }} $$
which can be obtained by parenthesizing your original string: "(24xy/(27x^(-2) ))÷((36x^2 y^(-2))/(45xy^4))".
This should also be a reminder to not be sloppy about the width of the horizontal lines in nested divisions, since that width is the only indication about the grouping, and hence ordering, of the divisions.
$endgroup$
add a comment |
$begingroup$
Parentheses.
"24xy/(27x^(-2) )÷(36x^2 y^(-2))/(45xy^4 )" means
$$ frac{24xy}{frac{27x^{-2}}{frac{36x^2 y^{-2}}{(45xy^4)}}} $$
That is, a sequence of multiplications and divisions occurs in left-to-right order. An easier example:
$12/2/2/3 = 1$
What is shown on your calculator is
$$ frac{frac{24xy}{27x^{-2}}}{frac{36x^2 y^{-2}}{45 xy^4 }} $$
which can be obtained by parenthesizing your original string: "(24xy/(27x^(-2) ))÷((36x^2 y^(-2))/(45xy^4))".
This should also be a reminder to not be sloppy about the width of the horizontal lines in nested divisions, since that width is the only indication about the grouping, and hence ordering, of the divisions.
$endgroup$
Parentheses.
"24xy/(27x^(-2) )÷(36x^2 y^(-2))/(45xy^4 )" means
$$ frac{24xy}{frac{27x^{-2}}{frac{36x^2 y^{-2}}{(45xy^4)}}} $$
That is, a sequence of multiplications and divisions occurs in left-to-right order. An easier example:
$12/2/2/3 = 1$
What is shown on your calculator is
$$ frac{frac{24xy}{27x^{-2}}}{frac{36x^2 y^{-2}}{45 xy^4 }} $$
which can be obtained by parenthesizing your original string: "(24xy/(27x^(-2) ))÷((36x^2 y^(-2))/(45xy^4))".
This should also be a reminder to not be sloppy about the width of the horizontal lines in nested divisions, since that width is the only indication about the grouping, and hence ordering, of the divisions.
answered Dec 2 '18 at 0:27
Eric TowersEric Towers
32.4k22268
32.4k22268
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