Quotient Set of a Quotient Set
$begingroup$
Can anyone help me with this problem?
Given:
$A = {a,b,c}$
$G=I_A cup{(a,b), (b,a),(b,c),(c,b)}$
$H=I_A cup{(b,c), (c,b)}$ (Note: H is a refinement of G)
Then:
$A|G = {G_a, G_b,G_c}$ wherein $G_a = {a,b}, G_b={a,b,c}, G_c={c,b}$
$A|H = {H_a,H_b,H_c}$ wherein $H_a = {a}, H_b={b,c}, H_c={b,c}$
Is $G|H = A|H = {H_a,H_b,H_c}$
?
elementary-set-theory equivalence-relations quotient-group
$endgroup$
add a comment |
$begingroup$
Can anyone help me with this problem?
Given:
$A = {a,b,c}$
$G=I_A cup{(a,b), (b,a),(b,c),(c,b)}$
$H=I_A cup{(b,c), (c,b)}$ (Note: H is a refinement of G)
Then:
$A|G = {G_a, G_b,G_c}$ wherein $G_a = {a,b}, G_b={a,b,c}, G_c={c,b}$
$A|H = {H_a,H_b,H_c}$ wherein $H_a = {a}, H_b={b,c}, H_c={b,c}$
Is $G|H = A|H = {H_a,H_b,H_c}$
?
elementary-set-theory equivalence-relations quotient-group
$endgroup$
add a comment |
$begingroup$
Can anyone help me with this problem?
Given:
$A = {a,b,c}$
$G=I_A cup{(a,b), (b,a),(b,c),(c,b)}$
$H=I_A cup{(b,c), (c,b)}$ (Note: H is a refinement of G)
Then:
$A|G = {G_a, G_b,G_c}$ wherein $G_a = {a,b}, G_b={a,b,c}, G_c={c,b}$
$A|H = {H_a,H_b,H_c}$ wherein $H_a = {a}, H_b={b,c}, H_c={b,c}$
Is $G|H = A|H = {H_a,H_b,H_c}$
?
elementary-set-theory equivalence-relations quotient-group
$endgroup$
Can anyone help me with this problem?
Given:
$A = {a,b,c}$
$G=I_A cup{(a,b), (b,a),(b,c),(c,b)}$
$H=I_A cup{(b,c), (c,b)}$ (Note: H is a refinement of G)
Then:
$A|G = {G_a, G_b,G_c}$ wherein $G_a = {a,b}, G_b={a,b,c}, G_c={c,b}$
$A|H = {H_a,H_b,H_c}$ wherein $H_a = {a}, H_b={b,c}, H_c={b,c}$
Is $G|H = A|H = {H_a,H_b,H_c}$
?
elementary-set-theory equivalence-relations quotient-group
elementary-set-theory equivalence-relations quotient-group
edited Dec 6 '18 at 16:24
Andrés E. Caicedo
65.4k8158248
65.4k8158248
asked Dec 6 '18 at 15:52
LRSLRS
33
33
add a comment |
add a comment |
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