EXCEL SUM Rounding












0















Hello to all Super Users!



I would like to ask about one interesting thing I found today related to sum function within rounding in excel. I have the following set of numbers (they are rounded to full decimal places - no other decimal numbers following in each of the numbers):



0.140495867768595,
0.173553719008264,
0.206611570247934,
0.076741440377804,
0.0826446280991736,
0.118063754427391,
0.063754427390791,
0.0814639905548997,
0.0566706021251476,


When I perform a simple sum function in excel result is equal to 1.0000000000000000 but when I put these numbers into calculator result is equal to 0.9999999999999999 (which is correct) -> my question, therefore, is there any way how to set the behavior of Excel to calculate this correctly and why is it calculating it wrong? Thank you all in advance for your suggestions!










share|improve this question





























    0















    Hello to all Super Users!



    I would like to ask about one interesting thing I found today related to sum function within rounding in excel. I have the following set of numbers (they are rounded to full decimal places - no other decimal numbers following in each of the numbers):



    0.140495867768595,
    0.173553719008264,
    0.206611570247934,
    0.076741440377804,
    0.0826446280991736,
    0.118063754427391,
    0.063754427390791,
    0.0814639905548997,
    0.0566706021251476,


    When I perform a simple sum function in excel result is equal to 1.0000000000000000 but when I put these numbers into calculator result is equal to 0.9999999999999999 (which is correct) -> my question, therefore, is there any way how to set the behavior of Excel to calculate this correctly and why is it calculating it wrong? Thank you all in advance for your suggestions!










    share|improve this question



























      0












      0








      0








      Hello to all Super Users!



      I would like to ask about one interesting thing I found today related to sum function within rounding in excel. I have the following set of numbers (they are rounded to full decimal places - no other decimal numbers following in each of the numbers):



      0.140495867768595,
      0.173553719008264,
      0.206611570247934,
      0.076741440377804,
      0.0826446280991736,
      0.118063754427391,
      0.063754427390791,
      0.0814639905548997,
      0.0566706021251476,


      When I perform a simple sum function in excel result is equal to 1.0000000000000000 but when I put these numbers into calculator result is equal to 0.9999999999999999 (which is correct) -> my question, therefore, is there any way how to set the behavior of Excel to calculate this correctly and why is it calculating it wrong? Thank you all in advance for your suggestions!










      share|improve this question
















      Hello to all Super Users!



      I would like to ask about one interesting thing I found today related to sum function within rounding in excel. I have the following set of numbers (they are rounded to full decimal places - no other decimal numbers following in each of the numbers):



      0.140495867768595,
      0.173553719008264,
      0.206611570247934,
      0.076741440377804,
      0.0826446280991736,
      0.118063754427391,
      0.063754427390791,
      0.0814639905548997,
      0.0566706021251476,


      When I perform a simple sum function in excel result is equal to 1.0000000000000000 but when I put these numbers into calculator result is equal to 0.9999999999999999 (which is correct) -> my question, therefore, is there any way how to set the behavior of Excel to calculate this correctly and why is it calculating it wrong? Thank you all in advance for your suggestions!







      microsoft-excel worksheet-function microsoft-excel-2010






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      edited Jan 21 at 19:50









      teylyn

      17.3k22539




      17.3k22539










      asked Jan 21 at 19:35









      AdysAdys

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          3 Answers
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          1














          Excel number values have 15 digits of precision. Everything after the 15th digit will displayed as a 0.



          Microsoft support article



          Workaround: If you want to show more than 16 significant digits, you need to enter the value as text, i.e. start with a single quote, then enter the value.






          share|improve this answer































            0














            Excel stores 15 significant digits of precision. So that fifth value in your list -- 0.0826446280991736, is treated as 0.082644628099174 in the sum. Similarly for the eighth and ninth values in your list.



            See https://www.microsoft.com/en-us/microsoft-365/blog/2008/04/10/understanding-floating-point-precision-aka-why-does-excel-give-me-seemingly-wrong-answers/ for more information about how Excel stores numbers.






            share|improve this answer































              0














              Excel only stores 15 significant digits of precision. Anything over 15 significant digits will be rounded.



              Therefore, the result 0.9999999999999999 is rounded to 1.00000000000000, i.e. 1.



              Input                     Sum (by Excel)           Sum (Actual)
              ----------------------- ---------------------- -----------------------
              0.140495867768595 [15] 0.140495867768595 [15] 0.140495867768595 [15]
              0.173553719008264 [15] 0.314049586776859 [15] 0.314049586776859 [15]
              0.206611570247934 [15] 0.520661157024793 [15] 0.520661157024793 [15]
              0.076741440377804 [14] 0.597402597402597 [15] 0.597402597402597 [15]
              0.0826446280991736 [15] 0.680047225501771 [15] 0.6800472255017706 [16]
              0.118063754427391 [15] 0.798110979929162 [15] 0.7981109799291616 [16]
              0.063754427390791 [14] 0.861865407319953 [15] 0.8618654073199526 [16]
              0.0814639905548997 [15] 0.943329397874852 [15] 0.9433293978748523 [16]
              0.0566706021251476 [15] 1.00000000000000 [15] 0.9999999999999999 [16]
              0.000000000000001 [ 1] 1.00000000000000 [15] 1.0000000000000009 [17] <-- Bonus info

              [ ] = number of significant digits


              Bonus: Even if you add another 0.000000000000001 (15th decimal place), the result will still be 1.



              Reference: https://en.wikipedia.org/wiki/Numeric_precision_in_Microsoft_Excel






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                3 Answers
                3






                active

                oldest

                votes








                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes









                1














                Excel number values have 15 digits of precision. Everything after the 15th digit will displayed as a 0.



                Microsoft support article



                Workaround: If you want to show more than 16 significant digits, you need to enter the value as text, i.e. start with a single quote, then enter the value.






                share|improve this answer




























                  1














                  Excel number values have 15 digits of precision. Everything after the 15th digit will displayed as a 0.



                  Microsoft support article



                  Workaround: If you want to show more than 16 significant digits, you need to enter the value as text, i.e. start with a single quote, then enter the value.






                  share|improve this answer


























                    1












                    1








                    1







                    Excel number values have 15 digits of precision. Everything after the 15th digit will displayed as a 0.



                    Microsoft support article



                    Workaround: If you want to show more than 16 significant digits, you need to enter the value as text, i.e. start with a single quote, then enter the value.






                    share|improve this answer













                    Excel number values have 15 digits of precision. Everything after the 15th digit will displayed as a 0.



                    Microsoft support article



                    Workaround: If you want to show more than 16 significant digits, you need to enter the value as text, i.e. start with a single quote, then enter the value.







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Jan 21 at 19:50









                    teylynteylyn

                    17.3k22539




                    17.3k22539

























                        0














                        Excel stores 15 significant digits of precision. So that fifth value in your list -- 0.0826446280991736, is treated as 0.082644628099174 in the sum. Similarly for the eighth and ninth values in your list.



                        See https://www.microsoft.com/en-us/microsoft-365/blog/2008/04/10/understanding-floating-point-precision-aka-why-does-excel-give-me-seemingly-wrong-answers/ for more information about how Excel stores numbers.






                        share|improve this answer




























                          0














                          Excel stores 15 significant digits of precision. So that fifth value in your list -- 0.0826446280991736, is treated as 0.082644628099174 in the sum. Similarly for the eighth and ninth values in your list.



                          See https://www.microsoft.com/en-us/microsoft-365/blog/2008/04/10/understanding-floating-point-precision-aka-why-does-excel-give-me-seemingly-wrong-answers/ for more information about how Excel stores numbers.






                          share|improve this answer


























                            0












                            0








                            0







                            Excel stores 15 significant digits of precision. So that fifth value in your list -- 0.0826446280991736, is treated as 0.082644628099174 in the sum. Similarly for the eighth and ninth values in your list.



                            See https://www.microsoft.com/en-us/microsoft-365/blog/2008/04/10/understanding-floating-point-precision-aka-why-does-excel-give-me-seemingly-wrong-answers/ for more information about how Excel stores numbers.






                            share|improve this answer













                            Excel stores 15 significant digits of precision. So that fifth value in your list -- 0.0826446280991736, is treated as 0.082644628099174 in the sum. Similarly for the eighth and ninth values in your list.



                            See https://www.microsoft.com/en-us/microsoft-365/blog/2008/04/10/understanding-floating-point-precision-aka-why-does-excel-give-me-seemingly-wrong-answers/ for more information about how Excel stores numbers.







                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Jan 21 at 19:51









                            Doug DedenDoug Deden

                            852213




                            852213























                                0














                                Excel only stores 15 significant digits of precision. Anything over 15 significant digits will be rounded.



                                Therefore, the result 0.9999999999999999 is rounded to 1.00000000000000, i.e. 1.



                                Input                     Sum (by Excel)           Sum (Actual)
                                ----------------------- ---------------------- -----------------------
                                0.140495867768595 [15] 0.140495867768595 [15] 0.140495867768595 [15]
                                0.173553719008264 [15] 0.314049586776859 [15] 0.314049586776859 [15]
                                0.206611570247934 [15] 0.520661157024793 [15] 0.520661157024793 [15]
                                0.076741440377804 [14] 0.597402597402597 [15] 0.597402597402597 [15]
                                0.0826446280991736 [15] 0.680047225501771 [15] 0.6800472255017706 [16]
                                0.118063754427391 [15] 0.798110979929162 [15] 0.7981109799291616 [16]
                                0.063754427390791 [14] 0.861865407319953 [15] 0.8618654073199526 [16]
                                0.0814639905548997 [15] 0.943329397874852 [15] 0.9433293978748523 [16]
                                0.0566706021251476 [15] 1.00000000000000 [15] 0.9999999999999999 [16]
                                0.000000000000001 [ 1] 1.00000000000000 [15] 1.0000000000000009 [17] <-- Bonus info

                                [ ] = number of significant digits


                                Bonus: Even if you add another 0.000000000000001 (15th decimal place), the result will still be 1.



                                Reference: https://en.wikipedia.org/wiki/Numeric_precision_in_Microsoft_Excel






                                share|improve this answer






























                                  0














                                  Excel only stores 15 significant digits of precision. Anything over 15 significant digits will be rounded.



                                  Therefore, the result 0.9999999999999999 is rounded to 1.00000000000000, i.e. 1.



                                  Input                     Sum (by Excel)           Sum (Actual)
                                  ----------------------- ---------------------- -----------------------
                                  0.140495867768595 [15] 0.140495867768595 [15] 0.140495867768595 [15]
                                  0.173553719008264 [15] 0.314049586776859 [15] 0.314049586776859 [15]
                                  0.206611570247934 [15] 0.520661157024793 [15] 0.520661157024793 [15]
                                  0.076741440377804 [14] 0.597402597402597 [15] 0.597402597402597 [15]
                                  0.0826446280991736 [15] 0.680047225501771 [15] 0.6800472255017706 [16]
                                  0.118063754427391 [15] 0.798110979929162 [15] 0.7981109799291616 [16]
                                  0.063754427390791 [14] 0.861865407319953 [15] 0.8618654073199526 [16]
                                  0.0814639905548997 [15] 0.943329397874852 [15] 0.9433293978748523 [16]
                                  0.0566706021251476 [15] 1.00000000000000 [15] 0.9999999999999999 [16]
                                  0.000000000000001 [ 1] 1.00000000000000 [15] 1.0000000000000009 [17] <-- Bonus info

                                  [ ] = number of significant digits


                                  Bonus: Even if you add another 0.000000000000001 (15th decimal place), the result will still be 1.



                                  Reference: https://en.wikipedia.org/wiki/Numeric_precision_in_Microsoft_Excel






                                  share|improve this answer




























                                    0












                                    0








                                    0







                                    Excel only stores 15 significant digits of precision. Anything over 15 significant digits will be rounded.



                                    Therefore, the result 0.9999999999999999 is rounded to 1.00000000000000, i.e. 1.



                                    Input                     Sum (by Excel)           Sum (Actual)
                                    ----------------------- ---------------------- -----------------------
                                    0.140495867768595 [15] 0.140495867768595 [15] 0.140495867768595 [15]
                                    0.173553719008264 [15] 0.314049586776859 [15] 0.314049586776859 [15]
                                    0.206611570247934 [15] 0.520661157024793 [15] 0.520661157024793 [15]
                                    0.076741440377804 [14] 0.597402597402597 [15] 0.597402597402597 [15]
                                    0.0826446280991736 [15] 0.680047225501771 [15] 0.6800472255017706 [16]
                                    0.118063754427391 [15] 0.798110979929162 [15] 0.7981109799291616 [16]
                                    0.063754427390791 [14] 0.861865407319953 [15] 0.8618654073199526 [16]
                                    0.0814639905548997 [15] 0.943329397874852 [15] 0.9433293978748523 [16]
                                    0.0566706021251476 [15] 1.00000000000000 [15] 0.9999999999999999 [16]
                                    0.000000000000001 [ 1] 1.00000000000000 [15] 1.0000000000000009 [17] <-- Bonus info

                                    [ ] = number of significant digits


                                    Bonus: Even if you add another 0.000000000000001 (15th decimal place), the result will still be 1.



                                    Reference: https://en.wikipedia.org/wiki/Numeric_precision_in_Microsoft_Excel






                                    share|improve this answer















                                    Excel only stores 15 significant digits of precision. Anything over 15 significant digits will be rounded.



                                    Therefore, the result 0.9999999999999999 is rounded to 1.00000000000000, i.e. 1.



                                    Input                     Sum (by Excel)           Sum (Actual)
                                    ----------------------- ---------------------- -----------------------
                                    0.140495867768595 [15] 0.140495867768595 [15] 0.140495867768595 [15]
                                    0.173553719008264 [15] 0.314049586776859 [15] 0.314049586776859 [15]
                                    0.206611570247934 [15] 0.520661157024793 [15] 0.520661157024793 [15]
                                    0.076741440377804 [14] 0.597402597402597 [15] 0.597402597402597 [15]
                                    0.0826446280991736 [15] 0.680047225501771 [15] 0.6800472255017706 [16]
                                    0.118063754427391 [15] 0.798110979929162 [15] 0.7981109799291616 [16]
                                    0.063754427390791 [14] 0.861865407319953 [15] 0.8618654073199526 [16]
                                    0.0814639905548997 [15] 0.943329397874852 [15] 0.9433293978748523 [16]
                                    0.0566706021251476 [15] 1.00000000000000 [15] 0.9999999999999999 [16]
                                    0.000000000000001 [ 1] 1.00000000000000 [15] 1.0000000000000009 [17] <-- Bonus info

                                    [ ] = number of significant digits


                                    Bonus: Even if you add another 0.000000000000001 (15th decimal place), the result will still be 1.



                                    Reference: https://en.wikipedia.org/wiki/Numeric_precision_in_Microsoft_Excel







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                                    edited Feb 28 at 6:32

























                                    answered Feb 28 at 4:29









                                    wilsonwilson

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                                    3,68811536






























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