Can 3 dimensional Heisenberg group be represented irreducibly on L^2(S)?












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It is well-known that unitary dual of the 3 dimensional Heisenberg group H represented on $L^2(mathbb{R})$ is given by a nonzero real number $lambdain R^*$(can be interpreted as $1/hbar$). When $lambda=1/hbar=0$, the unirreps are all 1 dimensional. My question is if H can also be represented irreducibly on $L^2(mathbb{S})$ with $mathbb{S}$ denoting the 1 dimensional compact manifold---circle.










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    $begingroup$


    It is well-known that unitary dual of the 3 dimensional Heisenberg group H represented on $L^2(mathbb{R})$ is given by a nonzero real number $lambdain R^*$(can be interpreted as $1/hbar$). When $lambda=1/hbar=0$, the unirreps are all 1 dimensional. My question is if H can also be represented irreducibly on $L^2(mathbb{S})$ with $mathbb{S}$ denoting the 1 dimensional compact manifold---circle.










    share|cite|improve this question











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      0





      $begingroup$


      It is well-known that unitary dual of the 3 dimensional Heisenberg group H represented on $L^2(mathbb{R})$ is given by a nonzero real number $lambdain R^*$(can be interpreted as $1/hbar$). When $lambda=1/hbar=0$, the unirreps are all 1 dimensional. My question is if H can also be represented irreducibly on $L^2(mathbb{S})$ with $mathbb{S}$ denoting the 1 dimensional compact manifold---circle.










      share|cite|improve this question











      $endgroup$




      It is well-known that unitary dual of the 3 dimensional Heisenberg group H represented on $L^2(mathbb{R})$ is given by a nonzero real number $lambdain R^*$(can be interpreted as $1/hbar$). When $lambda=1/hbar=0$, the unirreps are all 1 dimensional. My question is if H can also be represented irreducibly on $L^2(mathbb{S})$ with $mathbb{S}$ denoting the 1 dimensional compact manifold---circle.







      representation-theory locally-compact-groups heisenberg-group






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      share|cite|improve this question













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      edited Dec 20 '18 at 5:40







      user78032

















      asked Dec 20 '18 at 4:27









      user78032user78032

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