Does higher Oxidation/ reduction potential translate to higher energy storage in battery?
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Some articles refer to the fact that Lithium is preferred metal of choice for batteries because their half cell voltage is high (slightly above 3V)
If that is the case why can't we use other metals like Mn which can have higher oxidation potential (Mn can have +7 oxidation state which translates to higher oxidation potential)?
electrochemistry
asked Mar 31 at 16:16
Karthick SKarthick S
141
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add a comment |
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Some articles refer to the fact that Lithium is preferred metal of choice for batteries because their half cell voltage is high (slightly above 3V)
If that is the case why can't we use other metals like Mn which can have higher oxidation potential (Mn can have +7 oxidation state which translates to higher oxidation potential)?
electrochemistry
asked Mar 31 at 16:16
Karthick SKarthick S
141
New contributor
Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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2
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There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
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– MaxW
Mar 31 at 16:37
add a comment |
$begingroup$
Some articles refer to the fact that Lithium is preferred metal of choice for batteries because their half cell voltage is high (slightly above 3V)
If that is the case why can't we use other metals like Mn which can have higher oxidation potential (Mn can have +7 oxidation state which translates to higher oxidation potential)?
electrochemistry
asked Mar 31 at 16:16
Karthick SKarthick S
141
New contributor
Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Some articles refer to the fact that Lithium is preferred metal of choice for batteries because their half cell voltage is high (slightly above 3V)
If that is the case why can't we use other metals like Mn which can have higher oxidation potential (Mn can have +7 oxidation state which translates to higher oxidation potential)?
electrochemistry
electrochemistry
asked Mar 31 at 16:16
Karthick SKarthick S
141
New contributor
Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Mar 31 at 16:16
Karthick SKarthick S
141
New contributor
Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Mar 31 at 16:16
Karthick SKarthick S
141
New contributor
Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Mar 31 at 16:16
Karthick SKarthick S
141
asked Mar 31 at 16:16
Karthick SKarthick S
141
141
New contributor
Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Karthick S is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
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There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
Mar 31 at 16:37
add a comment |
2
$begingroup$
There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
Mar 31 at 16:37
2
2
$begingroup$
There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
Mar 31 at 16:37
$begingroup$
There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
Mar 31 at 16:37
add a comment |
1 Answer
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Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.
Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.
So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.
answered Mar 31 at 18:29
DrMoishe PippikDrMoishe Pippik
14.5k1231
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$begingroup$
Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.
Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.
So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.
answered Mar 31 at 18:29
DrMoishe PippikDrMoishe Pippik
14.5k1231
$endgroup$
add a comment |
$begingroup$
Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.
Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.
So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.
answered Mar 31 at 18:29
DrMoishe PippikDrMoishe Pippik
14.5k1231
$endgroup$
add a comment |
$begingroup$
Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.
Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.
So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.
answered Mar 31 at 18:29
DrMoishe PippikDrMoishe Pippik
14.5k1231
$endgroup$
Energy storage depends on the electromotive potential (i.e. difference between species in the electromotive series) and on the number of electrons available.
Li, for example, has an oxidation potential of ~3.04 V relative to hydrogen, but Al has one of 1.66 V, so Li has the greater potential. On the other hand, Li has only one freely available outer electron, but Al has three, so Al stores more charge per mol, giving three times the capacity in coulombs on that basis. On the gripping hand, however, Li has a mass of ~7 amu, and Al is ~27 amu, so an aluminum cell carries around the dead weight of unused neutrons and inner electron/protons.
So, depending on the needs, Li batteries weigh relatively little and provide comparatively high potential, aluminum batteries would hold more charge at a bit lower voltage, and even Zn is useful, though deficient compared to those others in volts and coulombs (it also has a bunch of inert neutrons, but there is no charge for them), because it is relatively inexpensive.
answered Mar 31 at 18:29
DrMoishe PippikDrMoishe Pippik
14.5k1231
edited Mar 31 at 23:37
answered Mar 31 at 18:29
DrMoishe PippikDrMoishe Pippik
14.5k1231
answered Mar 31 at 18:29
DrMoishe PippikDrMoishe Pippik
14.5k1231
answered Mar 31 at 18:29
DrMoishe PippikDrMoishe Pippik
14.5k1231
14.5k1231
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add a comment |
Karthick S is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
There is a difference in a high oxidation state and a large EMF. A number of factors are considered in making a battery, not just the EMF of the half cell. A battery can relatively easily have multiple cells to get a higher voltage.
$endgroup$
– MaxW
Mar 31 at 16:37