how to find the primitive of this function? [closed]












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How to find the primitive of this function in the interval $(0,1)$ and $(-1,0)$
$$int frac {sqrt{1-x}}{x^{4/5}} dx=?$$










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closed as off-topic by RRL, Saad, Did, metamorphy, José Carlos Santos Dec 20 '18 at 9:00


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – RRL, Saad, Did, metamorphy, José Carlos Santos

If this question can be reworded to fit the rules in the help center, please edit the question.
















  • $begingroup$
    Is this what you mean?$$displaystyleintfrac{sqrt{1-x}}{x^{4/5}}dx$$
    $endgroup$
    – Shubham Johri
    Dec 20 '18 at 5:06












  • $begingroup$
    What have you tried?
    $endgroup$
    – clathratus
    Dec 20 '18 at 5:12






  • 2




    $begingroup$
    Welcome to the site ! I suppose that the incomplete beta function will appear in the antiderivative.
    $endgroup$
    – Claude Leibovici
    Dec 20 '18 at 5:19


















1












$begingroup$


How to find the primitive of this function in the interval $(0,1)$ and $(-1,0)$
$$int frac {sqrt{1-x}}{x^{4/5}} dx=?$$










share|cite|improve this question











$endgroup$



closed as off-topic by RRL, Saad, Did, metamorphy, José Carlos Santos Dec 20 '18 at 9:00


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – RRL, Saad, Did, metamorphy, José Carlos Santos

If this question can be reworded to fit the rules in the help center, please edit the question.
















  • $begingroup$
    Is this what you mean?$$displaystyleintfrac{sqrt{1-x}}{x^{4/5}}dx$$
    $endgroup$
    – Shubham Johri
    Dec 20 '18 at 5:06












  • $begingroup$
    What have you tried?
    $endgroup$
    – clathratus
    Dec 20 '18 at 5:12






  • 2




    $begingroup$
    Welcome to the site ! I suppose that the incomplete beta function will appear in the antiderivative.
    $endgroup$
    – Claude Leibovici
    Dec 20 '18 at 5:19
















1












1








1


1



$begingroup$


How to find the primitive of this function in the interval $(0,1)$ and $(-1,0)$
$$int frac {sqrt{1-x}}{x^{4/5}} dx=?$$










share|cite|improve this question











$endgroup$




How to find the primitive of this function in the interval $(0,1)$ and $(-1,0)$
$$int frac {sqrt{1-x}}{x^{4/5}} dx=?$$







indefinite-integrals






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 20 '18 at 5:11









clathratus

5,0991439




5,0991439










asked Dec 20 '18 at 4:58









Bijayan RayBijayan Ray

1511213




1511213




closed as off-topic by RRL, Saad, Did, metamorphy, José Carlos Santos Dec 20 '18 at 9:00


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – RRL, Saad, Did, metamorphy, José Carlos Santos

If this question can be reworded to fit the rules in the help center, please edit the question.







closed as off-topic by RRL, Saad, Did, metamorphy, José Carlos Santos Dec 20 '18 at 9:00


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – RRL, Saad, Did, metamorphy, José Carlos Santos

If this question can be reworded to fit the rules in the help center, please edit the question.












  • $begingroup$
    Is this what you mean?$$displaystyleintfrac{sqrt{1-x}}{x^{4/5}}dx$$
    $endgroup$
    – Shubham Johri
    Dec 20 '18 at 5:06












  • $begingroup$
    What have you tried?
    $endgroup$
    – clathratus
    Dec 20 '18 at 5:12






  • 2




    $begingroup$
    Welcome to the site ! I suppose that the incomplete beta function will appear in the antiderivative.
    $endgroup$
    – Claude Leibovici
    Dec 20 '18 at 5:19




















  • $begingroup$
    Is this what you mean?$$displaystyleintfrac{sqrt{1-x}}{x^{4/5}}dx$$
    $endgroup$
    – Shubham Johri
    Dec 20 '18 at 5:06












  • $begingroup$
    What have you tried?
    $endgroup$
    – clathratus
    Dec 20 '18 at 5:12






  • 2




    $begingroup$
    Welcome to the site ! I suppose that the incomplete beta function will appear in the antiderivative.
    $endgroup$
    – Claude Leibovici
    Dec 20 '18 at 5:19


















$begingroup$
Is this what you mean?$$displaystyleintfrac{sqrt{1-x}}{x^{4/5}}dx$$
$endgroup$
– Shubham Johri
Dec 20 '18 at 5:06






$begingroup$
Is this what you mean?$$displaystyleintfrac{sqrt{1-x}}{x^{4/5}}dx$$
$endgroup$
– Shubham Johri
Dec 20 '18 at 5:06














$begingroup$
What have you tried?
$endgroup$
– clathratus
Dec 20 '18 at 5:12




$begingroup$
What have you tried?
$endgroup$
– clathratus
Dec 20 '18 at 5:12




2




2




$begingroup$
Welcome to the site ! I suppose that the incomplete beta function will appear in the antiderivative.
$endgroup$
– Claude Leibovici
Dec 20 '18 at 5:19






$begingroup$
Welcome to the site ! I suppose that the incomplete beta function will appear in the antiderivative.
$endgroup$
– Claude Leibovici
Dec 20 '18 at 5:19












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