How is it called if “$f(g(x_0), g(x_1), …) = g(f(x_0,x_1,…))$” [closed]












1












$begingroup$


What is the correct mathematic term to be used for the relation between two functions $f$ and $g$ if the following holds:
$$fbig(g(x_0), g(x_1), ...big) = gbig(f(x_0,x_1,...)big)$$
Thanks.






functions







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closed as off-topic by Brahadeesh, Hanul Jeon, Namaste, mrtaurho, Jyrki Lahtonen Dec 22 '18 at 12:49


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Brahadeesh, Hanul Jeon, Namaste, mrtaurho, Jyrki Lahtonen

If this question can be reworded to fit the rules in the help center, please edit the question.












  • 2




    $begingroup$
    Generalized commutativity?
    $endgroup$
    – Wuestenfux
    Dec 22 '18 at 10:15
















1












$begingroup$


What is the correct mathematic term to be used for the relation between two functions $f$ and $g$ if the following holds:
$$fbig(g(x_0), g(x_1), ...big) = gbig(f(x_0,x_1,...)big)$$
Thanks.






functions







share|cite|improve this question











$endgroup$



closed as off-topic by Brahadeesh, Hanul Jeon, Namaste, mrtaurho, Jyrki Lahtonen Dec 22 '18 at 12:49


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Brahadeesh, Hanul Jeon, Namaste, mrtaurho, Jyrki Lahtonen

If this question can be reworded to fit the rules in the help center, please edit the question.












  • 2




    $begingroup$
    Generalized commutativity?
    $endgroup$
    – Wuestenfux
    Dec 22 '18 at 10:15














1












1








1





$begingroup$


What is the correct mathematic term to be used for the relation between two functions $f$ and $g$ if the following holds:
$$fbig(g(x_0), g(x_1), ...big) = gbig(f(x_0,x_1,...)big)$$
Thanks.






functions







share|cite|improve this question











$endgroup$




What is the correct mathematic term to be used for the relation between two functions $f$ and $g$ if the following holds:
$$fbig(g(x_0), g(x_1), ...big) = gbig(f(x_0,x_1,...)big)$$
Thanks.






functions




functions






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share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 22 '18 at 11:57









Namaste

1




1










asked Dec 22 '18 at 10:12









Frank-Rene SchäferFrank-Rene Schäfer

1084




1084




closed as off-topic by Brahadeesh, Hanul Jeon, Namaste, mrtaurho, Jyrki Lahtonen Dec 22 '18 at 12:49


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Brahadeesh, Hanul Jeon, Namaste, mrtaurho, Jyrki Lahtonen

If this question can be reworded to fit the rules in the help center, please edit the question.







closed as off-topic by Brahadeesh, Hanul Jeon, Namaste, mrtaurho, Jyrki Lahtonen Dec 22 '18 at 12:49


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Brahadeesh, Hanul Jeon, Namaste, mrtaurho, Jyrki Lahtonen

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 2




    $begingroup$
    Generalized commutativity?
    $endgroup$
    – Wuestenfux
    Dec 22 '18 at 10:15














  • 2




    $begingroup$
    Generalized commutativity?
    $endgroup$
    – Wuestenfux
    Dec 22 '18 at 10:15








2




2




$begingroup$
Generalized commutativity?
$endgroup$
– Wuestenfux
Dec 22 '18 at 10:15




$begingroup$
Generalized commutativity?
$endgroup$
– Wuestenfux
Dec 22 '18 at 10:15










1 Answer
1






active

oldest

votes


















2












$begingroup$

Assuming that is an identity, this is the same as saying $fcirc g=gcirc f$, which is to say these two functions commute (under function composition, if you like).






share|cite|improve this answer









$endgroup$









  • 1




    $begingroup$
    To be picky, we have $f circ (g times g times cdots) = g circ f$.
    $endgroup$
    – lhf
    Dec 22 '18 at 12:39




















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2












$begingroup$

Assuming that is an identity, this is the same as saying $fcirc g=gcirc f$, which is to say these two functions commute (under function composition, if you like).






share|cite|improve this answer









$endgroup$









  • 1




    $begingroup$
    To be picky, we have $f circ (g times g times cdots) = g circ f$.
    $endgroup$
    – lhf
    Dec 22 '18 at 12:39


















2












$begingroup$

Assuming that is an identity, this is the same as saying $fcirc g=gcirc f$, which is to say these two functions commute (under function composition, if you like).






share|cite|improve this answer









$endgroup$









  • 1




    $begingroup$
    To be picky, we have $f circ (g times g times cdots) = g circ f$.
    $endgroup$
    – lhf
    Dec 22 '18 at 12:39
















2












2








2





$begingroup$

Assuming that is an identity, this is the same as saying $fcirc g=gcirc f$, which is to say these two functions commute (under function composition, if you like).






share|cite|improve this answer









$endgroup$



Assuming that is an identity, this is the same as saying $fcirc g=gcirc f$, which is to say these two functions commute (under function composition, if you like).







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Dec 22 '18 at 11:48









YiFanYiFan

5,3832728




5,3832728








  • 1




    $begingroup$
    To be picky, we have $f circ (g times g times cdots) = g circ f$.
    $endgroup$
    – lhf
    Dec 22 '18 at 12:39
















  • 1




    $begingroup$
    To be picky, we have $f circ (g times g times cdots) = g circ f$.
    $endgroup$
    – lhf
    Dec 22 '18 at 12:39










1




1




$begingroup$
To be picky, we have $f circ (g times g times cdots) = g circ f$.
$endgroup$
– lhf
Dec 22 '18 at 12:39






$begingroup$
To be picky, we have $f circ (g times g times cdots) = g circ f$.
$endgroup$
– lhf
Dec 22 '18 at 12:39





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