pgfplots: How to draw a tangent graph below two others?
Assumed I want to draw three simple graphs based on the following illustration:
How can I plot those three graphs? I've tried to create something like this:
Minimum Working Example (MWE):
documentclass{standalone}
usepackage{pgfplots}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {exp(3*x)};
addplot+[no marks, samples=100] {(-exp(3*x)+20)};
end{axis}
end{tikzpicture}
end{document}
Screenshot of the current state:
Description of the issue:
However, I don't get the point on how to figure out the function of the third graph as well as how to clip the graphs in x
and y
direction to align them centered in the plot. It is not necessary to be completely precise, the accuracy of my upper template will be fine enough.
How to do that?
tikz-pgf pgfplots plot graphs polynomials
add a comment |
Assumed I want to draw three simple graphs based on the following illustration:
How can I plot those three graphs? I've tried to create something like this:
Minimum Working Example (MWE):
documentclass{standalone}
usepackage{pgfplots}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {exp(3*x)};
addplot+[no marks, samples=100] {(-exp(3*x)+20)};
end{axis}
end{tikzpicture}
end{document}
Screenshot of the current state:
Description of the issue:
However, I don't get the point on how to figure out the function of the third graph as well as how to clip the graphs in x
and y
direction to align them centered in the plot. It is not necessary to be completely precise, the accuracy of my upper template will be fine enough.
How to do that?
tikz-pgf pgfplots plot graphs polynomials
3
@close-voter: Please explain in a comment your reason for voting to close!
– Kurt
Apr 1 at 20:15
I accept the Kurt's comment.
– Sebastiano
Apr 1 at 20:39
add a comment |
Assumed I want to draw three simple graphs based on the following illustration:
How can I plot those three graphs? I've tried to create something like this:
Minimum Working Example (MWE):
documentclass{standalone}
usepackage{pgfplots}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {exp(3*x)};
addplot+[no marks, samples=100] {(-exp(3*x)+20)};
end{axis}
end{tikzpicture}
end{document}
Screenshot of the current state:
Description of the issue:
However, I don't get the point on how to figure out the function of the third graph as well as how to clip the graphs in x
and y
direction to align them centered in the plot. It is not necessary to be completely precise, the accuracy of my upper template will be fine enough.
How to do that?
tikz-pgf pgfplots plot graphs polynomials
Assumed I want to draw three simple graphs based on the following illustration:
How can I plot those three graphs? I've tried to create something like this:
Minimum Working Example (MWE):
documentclass{standalone}
usepackage{pgfplots}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {exp(3*x)};
addplot+[no marks, samples=100] {(-exp(3*x)+20)};
end{axis}
end{tikzpicture}
end{document}
Screenshot of the current state:
Description of the issue:
However, I don't get the point on how to figure out the function of the third graph as well as how to clip the graphs in x
and y
direction to align them centered in the plot. It is not necessary to be completely precise, the accuracy of my upper template will be fine enough.
How to do that?
tikz-pgf pgfplots plot graphs polynomials
tikz-pgf pgfplots plot graphs polynomials
edited Apr 1 at 20:04
Dave
asked Apr 1 at 19:34
DaveDave
1,234619
1,234619
3
@close-voter: Please explain in a comment your reason for voting to close!
– Kurt
Apr 1 at 20:15
I accept the Kurt's comment.
– Sebastiano
Apr 1 at 20:39
add a comment |
3
@close-voter: Please explain in a comment your reason for voting to close!
– Kurt
Apr 1 at 20:15
I accept the Kurt's comment.
– Sebastiano
Apr 1 at 20:39
3
3
@close-voter: Please explain in a comment your reason for voting to close!
– Kurt
Apr 1 at 20:15
@close-voter: Please explain in a comment your reason for voting to close!
– Kurt
Apr 1 at 20:15
I accept the Kurt's comment.
– Sebastiano
Apr 1 at 20:39
I accept the Kurt's comment.
– Sebastiano
Apr 1 at 20:39
add a comment |
2 Answers
2
active
oldest
votes
You can use the function f1*f2/(f1+f2) to get something like what you describe. To make the code a bit clearer I defined the functions f1
and f2
.
documentclass{standalone}
usepackage{pgfplots}
pgfplotsset{%
compat=1.12,
/pgf/declare function={f1(x)=exp(3*x);},
/pgf/declare function={f2(x)=-exp(3*x)+20;},
}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {f1(x)};
addplot+[no marks, samples=100] {f2(x)};
addplot+[no marks, samples=100] {f1(x)*f2(x)/(f1(x)+f2(x))};
end{axis}
end{tikzpicture}
end{document}
If you want the function to follow more closely you can use sqrt(f1^2*f2^2/(f1^2+f2^2). Then replace the third plot with
addplot+[no marks, samples=100] {sqrt(f1(x)*f1(x)*f2(x)*f2(x)/(f1(x)*f1(x)+f2(x)*f2(x)))};
to get
Slightly more general, one can use the exponent a
(does not have to be an integer):
foreach a in {1,...,5}{
addplot+[no marks, samples=100] {(f1(x)^a*f2(x)^a/(f1(x)^a+f2(x)^a))^(1/a)};
}
The lower one looks perfect, thank you very much!!
– Dave
Apr 1 at 21:13
Your last edit is simply perfect! Thank you so much!
– Dave
yesterday
add a comment |
Are you looking for the minimum? (I shifted the plot a bit but you can of course undo the shift.)
documentclass[border=3.14mm,tikz]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {exp(3*x)};
addplot+[no marks, samples=100] {(-exp(3*x)+20)};
addplot+[no marks, samples=6,smooth]
{min(exp(3*x),(-exp(3*x)+20))-pi/2};
end{axis}
end{tikzpicture}
end{document}
Thank you very much marmot! The user StefanH has also posted a great approach which looks very smooth - I hope you are not disappointed if I choose his option as an answer?
– Dave
Apr 1 at 21:14
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use the function f1*f2/(f1+f2) to get something like what you describe. To make the code a bit clearer I defined the functions f1
and f2
.
documentclass{standalone}
usepackage{pgfplots}
pgfplotsset{%
compat=1.12,
/pgf/declare function={f1(x)=exp(3*x);},
/pgf/declare function={f2(x)=-exp(3*x)+20;},
}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {f1(x)};
addplot+[no marks, samples=100] {f2(x)};
addplot+[no marks, samples=100] {f1(x)*f2(x)/(f1(x)+f2(x))};
end{axis}
end{tikzpicture}
end{document}
If you want the function to follow more closely you can use sqrt(f1^2*f2^2/(f1^2+f2^2). Then replace the third plot with
addplot+[no marks, samples=100] {sqrt(f1(x)*f1(x)*f2(x)*f2(x)/(f1(x)*f1(x)+f2(x)*f2(x)))};
to get
Slightly more general, one can use the exponent a
(does not have to be an integer):
foreach a in {1,...,5}{
addplot+[no marks, samples=100] {(f1(x)^a*f2(x)^a/(f1(x)^a+f2(x)^a))^(1/a)};
}
The lower one looks perfect, thank you very much!!
– Dave
Apr 1 at 21:13
Your last edit is simply perfect! Thank you so much!
– Dave
yesterday
add a comment |
You can use the function f1*f2/(f1+f2) to get something like what you describe. To make the code a bit clearer I defined the functions f1
and f2
.
documentclass{standalone}
usepackage{pgfplots}
pgfplotsset{%
compat=1.12,
/pgf/declare function={f1(x)=exp(3*x);},
/pgf/declare function={f2(x)=-exp(3*x)+20;},
}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {f1(x)};
addplot+[no marks, samples=100] {f2(x)};
addplot+[no marks, samples=100] {f1(x)*f2(x)/(f1(x)+f2(x))};
end{axis}
end{tikzpicture}
end{document}
If you want the function to follow more closely you can use sqrt(f1^2*f2^2/(f1^2+f2^2). Then replace the third plot with
addplot+[no marks, samples=100] {sqrt(f1(x)*f1(x)*f2(x)*f2(x)/(f1(x)*f1(x)+f2(x)*f2(x)))};
to get
Slightly more general, one can use the exponent a
(does not have to be an integer):
foreach a in {1,...,5}{
addplot+[no marks, samples=100] {(f1(x)^a*f2(x)^a/(f1(x)^a+f2(x)^a))^(1/a)};
}
The lower one looks perfect, thank you very much!!
– Dave
Apr 1 at 21:13
Your last edit is simply perfect! Thank you so much!
– Dave
yesterday
add a comment |
You can use the function f1*f2/(f1+f2) to get something like what you describe. To make the code a bit clearer I defined the functions f1
and f2
.
documentclass{standalone}
usepackage{pgfplots}
pgfplotsset{%
compat=1.12,
/pgf/declare function={f1(x)=exp(3*x);},
/pgf/declare function={f2(x)=-exp(3*x)+20;},
}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {f1(x)};
addplot+[no marks, samples=100] {f2(x)};
addplot+[no marks, samples=100] {f1(x)*f2(x)/(f1(x)+f2(x))};
end{axis}
end{tikzpicture}
end{document}
If you want the function to follow more closely you can use sqrt(f1^2*f2^2/(f1^2+f2^2). Then replace the third plot with
addplot+[no marks, samples=100] {sqrt(f1(x)*f1(x)*f2(x)*f2(x)/(f1(x)*f1(x)+f2(x)*f2(x)))};
to get
Slightly more general, one can use the exponent a
(does not have to be an integer):
foreach a in {1,...,5}{
addplot+[no marks, samples=100] {(f1(x)^a*f2(x)^a/(f1(x)^a+f2(x)^a))^(1/a)};
}
You can use the function f1*f2/(f1+f2) to get something like what you describe. To make the code a bit clearer I defined the functions f1
and f2
.
documentclass{standalone}
usepackage{pgfplots}
pgfplotsset{%
compat=1.12,
/pgf/declare function={f1(x)=exp(3*x);},
/pgf/declare function={f2(x)=-exp(3*x)+20;},
}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {f1(x)};
addplot+[no marks, samples=100] {f2(x)};
addplot+[no marks, samples=100] {f1(x)*f2(x)/(f1(x)+f2(x))};
end{axis}
end{tikzpicture}
end{document}
If you want the function to follow more closely you can use sqrt(f1^2*f2^2/(f1^2+f2^2). Then replace the third plot with
addplot+[no marks, samples=100] {sqrt(f1(x)*f1(x)*f2(x)*f2(x)/(f1(x)*f1(x)+f2(x)*f2(x)))};
to get
Slightly more general, one can use the exponent a
(does not have to be an integer):
foreach a in {1,...,5}{
addplot+[no marks, samples=100] {(f1(x)^a*f2(x)^a/(f1(x)^a+f2(x)^a))^(1/a)};
}
edited Apr 2 at 7:05
answered Apr 1 at 20:36
StefanHStefanH
10.9k1920
10.9k1920
The lower one looks perfect, thank you very much!!
– Dave
Apr 1 at 21:13
Your last edit is simply perfect! Thank you so much!
– Dave
yesterday
add a comment |
The lower one looks perfect, thank you very much!!
– Dave
Apr 1 at 21:13
Your last edit is simply perfect! Thank you so much!
– Dave
yesterday
The lower one looks perfect, thank you very much!!
– Dave
Apr 1 at 21:13
The lower one looks perfect, thank you very much!!
– Dave
Apr 1 at 21:13
Your last edit is simply perfect! Thank you so much!
– Dave
yesterday
Your last edit is simply perfect! Thank you so much!
– Dave
yesterday
add a comment |
Are you looking for the minimum? (I shifted the plot a bit but you can of course undo the shift.)
documentclass[border=3.14mm,tikz]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {exp(3*x)};
addplot+[no marks, samples=100] {(-exp(3*x)+20)};
addplot+[no marks, samples=6,smooth]
{min(exp(3*x),(-exp(3*x)+20))-pi/2};
end{axis}
end{tikzpicture}
end{document}
Thank you very much marmot! The user StefanH has also posted a great approach which looks very smooth - I hope you are not disappointed if I choose his option as an answer?
– Dave
Apr 1 at 21:14
add a comment |
Are you looking for the minimum? (I shifted the plot a bit but you can of course undo the shift.)
documentclass[border=3.14mm,tikz]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {exp(3*x)};
addplot+[no marks, samples=100] {(-exp(3*x)+20)};
addplot+[no marks, samples=6,smooth]
{min(exp(3*x),(-exp(3*x)+20))-pi/2};
end{axis}
end{tikzpicture}
end{document}
Thank you very much marmot! The user StefanH has also posted a great approach which looks very smooth - I hope you are not disappointed if I choose his option as an answer?
– Dave
Apr 1 at 21:14
add a comment |
Are you looking for the minimum? (I shifted the plot a bit but you can of course undo the shift.)
documentclass[border=3.14mm,tikz]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {exp(3*x)};
addplot+[no marks, samples=100] {(-exp(3*x)+20)};
addplot+[no marks, samples=6,smooth]
{min(exp(3*x),(-exp(3*x)+20))-pi/2};
end{axis}
end{tikzpicture}
end{document}
Are you looking for the minimum? (I shifted the plot a bit but you can of course undo the shift.)
documentclass[border=3.14mm,tikz]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {exp(3*x)};
addplot+[no marks, samples=100] {(-exp(3*x)+20)};
addplot+[no marks, samples=6,smooth]
{min(exp(3*x),(-exp(3*x)+20))-pi/2};
end{axis}
end{tikzpicture}
end{document}
answered Apr 1 at 20:19
marmotmarmot
116k5147277
116k5147277
Thank you very much marmot! The user StefanH has also posted a great approach which looks very smooth - I hope you are not disappointed if I choose his option as an answer?
– Dave
Apr 1 at 21:14
add a comment |
Thank you very much marmot! The user StefanH has also posted a great approach which looks very smooth - I hope you are not disappointed if I choose his option as an answer?
– Dave
Apr 1 at 21:14
Thank you very much marmot! The user StefanH has also posted a great approach which looks very smooth - I hope you are not disappointed if I choose his option as an answer?
– Dave
Apr 1 at 21:14
Thank you very much marmot! The user StefanH has also posted a great approach which looks very smooth - I hope you are not disappointed if I choose his option as an answer?
– Dave
Apr 1 at 21:14
add a comment |
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3
@close-voter: Please explain in a comment your reason for voting to close!
– Kurt
Apr 1 at 20:15
I accept the Kurt's comment.
– Sebastiano
Apr 1 at 20:39