pgfplots: How to draw a tangent graph below two others?












7















Assumed I want to draw three simple graphs based on the following illustration:



Screenshot of the desired state





How can I plot those three graphs? I've tried to create something like this:



Minimum Working Example (MWE):



documentclass{standalone}
usepackage{pgfplots}

begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {exp(3*x)};
addplot+[no marks, samples=100] {(-exp(3*x)+20)};
end{axis}
end{tikzpicture}
end{document}




Screenshot of the current state:



Screenshot of the current state





Description of the issue:



However, I don't get the point on how to figure out the function of the third graph as well as how to clip the graphs in x and y direction to align them centered in the plot. It is not necessary to be completely precise, the accuracy of my upper template will be fine enough.



How to do that?










share|improve this question




















  • 3





    @close-voter: Please explain in a comment your reason for voting to close!

    – Kurt
    Apr 1 at 20:15











  • I accept the Kurt's comment.

    – Sebastiano
    Apr 1 at 20:39
















7















Assumed I want to draw three simple graphs based on the following illustration:



Screenshot of the desired state





How can I plot those three graphs? I've tried to create something like this:



Minimum Working Example (MWE):



documentclass{standalone}
usepackage{pgfplots}

begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {exp(3*x)};
addplot+[no marks, samples=100] {(-exp(3*x)+20)};
end{axis}
end{tikzpicture}
end{document}




Screenshot of the current state:



Screenshot of the current state





Description of the issue:



However, I don't get the point on how to figure out the function of the third graph as well as how to clip the graphs in x and y direction to align them centered in the plot. It is not necessary to be completely precise, the accuracy of my upper template will be fine enough.



How to do that?










share|improve this question




















  • 3





    @close-voter: Please explain in a comment your reason for voting to close!

    – Kurt
    Apr 1 at 20:15











  • I accept the Kurt's comment.

    – Sebastiano
    Apr 1 at 20:39














7












7








7


2






Assumed I want to draw three simple graphs based on the following illustration:



Screenshot of the desired state





How can I plot those three graphs? I've tried to create something like this:



Minimum Working Example (MWE):



documentclass{standalone}
usepackage{pgfplots}

begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {exp(3*x)};
addplot+[no marks, samples=100] {(-exp(3*x)+20)};
end{axis}
end{tikzpicture}
end{document}




Screenshot of the current state:



Screenshot of the current state





Description of the issue:



However, I don't get the point on how to figure out the function of the third graph as well as how to clip the graphs in x and y direction to align them centered in the plot. It is not necessary to be completely precise, the accuracy of my upper template will be fine enough.



How to do that?










share|improve this question
















Assumed I want to draw three simple graphs based on the following illustration:



Screenshot of the desired state





How can I plot those three graphs? I've tried to create something like this:



Minimum Working Example (MWE):



documentclass{standalone}
usepackage{pgfplots}

begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {exp(3*x)};
addplot+[no marks, samples=100] {(-exp(3*x)+20)};
end{axis}
end{tikzpicture}
end{document}




Screenshot of the current state:



Screenshot of the current state





Description of the issue:



However, I don't get the point on how to figure out the function of the third graph as well as how to clip the graphs in x and y direction to align them centered in the plot. It is not necessary to be completely precise, the accuracy of my upper template will be fine enough.



How to do that?







tikz-pgf pgfplots plot graphs polynomials






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Apr 1 at 20:04







Dave

















asked Apr 1 at 19:34









DaveDave

1,234619




1,234619








  • 3





    @close-voter: Please explain in a comment your reason for voting to close!

    – Kurt
    Apr 1 at 20:15











  • I accept the Kurt's comment.

    – Sebastiano
    Apr 1 at 20:39














  • 3





    @close-voter: Please explain in a comment your reason for voting to close!

    – Kurt
    Apr 1 at 20:15











  • I accept the Kurt's comment.

    – Sebastiano
    Apr 1 at 20:39








3




3





@close-voter: Please explain in a comment your reason for voting to close!

– Kurt
Apr 1 at 20:15





@close-voter: Please explain in a comment your reason for voting to close!

– Kurt
Apr 1 at 20:15













I accept the Kurt's comment.

– Sebastiano
Apr 1 at 20:39





I accept the Kurt's comment.

– Sebastiano
Apr 1 at 20:39










2 Answers
2






active

oldest

votes


















9














You can use the function f1*f2/(f1+f2) to get something like what you describe. To make the code a bit clearer I defined the functions f1 and f2.



documentclass{standalone}
usepackage{pgfplots}
pgfplotsset{%
compat=1.12,
/pgf/declare function={f1(x)=exp(3*x);},
/pgf/declare function={f2(x)=-exp(3*x)+20;},
}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {f1(x)};
addplot+[no marks, samples=100] {f2(x)};
addplot+[no marks, samples=100] {f1(x)*f2(x)/(f1(x)+f2(x))};
end{axis}
end{tikzpicture}
end{document}


enter image description here



If you want the function to follow more closely you can use sqrt(f1^2*f2^2/(f1^2+f2^2). Then replace the third plot with



addplot+[no marks, samples=100] {sqrt(f1(x)*f1(x)*f2(x)*f2(x)/(f1(x)*f1(x)+f2(x)*f2(x)))};


to get



enter image description here



Slightly more general, one can use the exponent a (does not have to be an integer):



 foreach a in {1,...,5}{
addplot+[no marks, samples=100] {(f1(x)^a*f2(x)^a/(f1(x)^a+f2(x)^a))^(1/a)};
}


enter image description here






share|improve this answer


























  • The lower one looks perfect, thank you very much!!

    – Dave
    Apr 1 at 21:13











  • Your last edit is simply perfect! Thank you so much!

    – Dave
    yesterday



















5














Are you looking for the minimum? (I shifted the plot a bit but you can of course undo the shift.)



documentclass[border=3.14mm,tikz]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {exp(3*x)};
addplot+[no marks, samples=100] {(-exp(3*x)+20)};
addplot+[no marks, samples=6,smooth]
{min(exp(3*x),(-exp(3*x)+20))-pi/2};
end{axis}
end{tikzpicture}
end{document}


enter image description here






share|improve this answer
























  • Thank you very much marmot! The user StefanH has also posted a great approach which looks very smooth - I hope you are not disappointed if I choose his option as an answer?

    – Dave
    Apr 1 at 21:14














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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









9














You can use the function f1*f2/(f1+f2) to get something like what you describe. To make the code a bit clearer I defined the functions f1 and f2.



documentclass{standalone}
usepackage{pgfplots}
pgfplotsset{%
compat=1.12,
/pgf/declare function={f1(x)=exp(3*x);},
/pgf/declare function={f2(x)=-exp(3*x)+20;},
}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {f1(x)};
addplot+[no marks, samples=100] {f2(x)};
addplot+[no marks, samples=100] {f1(x)*f2(x)/(f1(x)+f2(x))};
end{axis}
end{tikzpicture}
end{document}


enter image description here



If you want the function to follow more closely you can use sqrt(f1^2*f2^2/(f1^2+f2^2). Then replace the third plot with



addplot+[no marks, samples=100] {sqrt(f1(x)*f1(x)*f2(x)*f2(x)/(f1(x)*f1(x)+f2(x)*f2(x)))};


to get



enter image description here



Slightly more general, one can use the exponent a (does not have to be an integer):



 foreach a in {1,...,5}{
addplot+[no marks, samples=100] {(f1(x)^a*f2(x)^a/(f1(x)^a+f2(x)^a))^(1/a)};
}


enter image description here






share|improve this answer


























  • The lower one looks perfect, thank you very much!!

    – Dave
    Apr 1 at 21:13











  • Your last edit is simply perfect! Thank you so much!

    – Dave
    yesterday
















9














You can use the function f1*f2/(f1+f2) to get something like what you describe. To make the code a bit clearer I defined the functions f1 and f2.



documentclass{standalone}
usepackage{pgfplots}
pgfplotsset{%
compat=1.12,
/pgf/declare function={f1(x)=exp(3*x);},
/pgf/declare function={f2(x)=-exp(3*x)+20;},
}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {f1(x)};
addplot+[no marks, samples=100] {f2(x)};
addplot+[no marks, samples=100] {f1(x)*f2(x)/(f1(x)+f2(x))};
end{axis}
end{tikzpicture}
end{document}


enter image description here



If you want the function to follow more closely you can use sqrt(f1^2*f2^2/(f1^2+f2^2). Then replace the third plot with



addplot+[no marks, samples=100] {sqrt(f1(x)*f1(x)*f2(x)*f2(x)/(f1(x)*f1(x)+f2(x)*f2(x)))};


to get



enter image description here



Slightly more general, one can use the exponent a (does not have to be an integer):



 foreach a in {1,...,5}{
addplot+[no marks, samples=100] {(f1(x)^a*f2(x)^a/(f1(x)^a+f2(x)^a))^(1/a)};
}


enter image description here






share|improve this answer


























  • The lower one looks perfect, thank you very much!!

    – Dave
    Apr 1 at 21:13











  • Your last edit is simply perfect! Thank you so much!

    – Dave
    yesterday














9












9








9







You can use the function f1*f2/(f1+f2) to get something like what you describe. To make the code a bit clearer I defined the functions f1 and f2.



documentclass{standalone}
usepackage{pgfplots}
pgfplotsset{%
compat=1.12,
/pgf/declare function={f1(x)=exp(3*x);},
/pgf/declare function={f2(x)=-exp(3*x)+20;},
}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {f1(x)};
addplot+[no marks, samples=100] {f2(x)};
addplot+[no marks, samples=100] {f1(x)*f2(x)/(f1(x)+f2(x))};
end{axis}
end{tikzpicture}
end{document}


enter image description here



If you want the function to follow more closely you can use sqrt(f1^2*f2^2/(f1^2+f2^2). Then replace the third plot with



addplot+[no marks, samples=100] {sqrt(f1(x)*f1(x)*f2(x)*f2(x)/(f1(x)*f1(x)+f2(x)*f2(x)))};


to get



enter image description here



Slightly more general, one can use the exponent a (does not have to be an integer):



 foreach a in {1,...,5}{
addplot+[no marks, samples=100] {(f1(x)^a*f2(x)^a/(f1(x)^a+f2(x)^a))^(1/a)};
}


enter image description here






share|improve this answer















You can use the function f1*f2/(f1+f2) to get something like what you describe. To make the code a bit clearer I defined the functions f1 and f2.



documentclass{standalone}
usepackage{pgfplots}
pgfplotsset{%
compat=1.12,
/pgf/declare function={f1(x)=exp(3*x);},
/pgf/declare function={f2(x)=-exp(3*x)+20;},
}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {f1(x)};
addplot+[no marks, samples=100] {f2(x)};
addplot+[no marks, samples=100] {f1(x)*f2(x)/(f1(x)+f2(x))};
end{axis}
end{tikzpicture}
end{document}


enter image description here



If you want the function to follow more closely you can use sqrt(f1^2*f2^2/(f1^2+f2^2). Then replace the third plot with



addplot+[no marks, samples=100] {sqrt(f1(x)*f1(x)*f2(x)*f2(x)/(f1(x)*f1(x)+f2(x)*f2(x)))};


to get



enter image description here



Slightly more general, one can use the exponent a (does not have to be an integer):



 foreach a in {1,...,5}{
addplot+[no marks, samples=100] {(f1(x)^a*f2(x)^a/(f1(x)^a+f2(x)^a))^(1/a)};
}


enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited Apr 2 at 7:05

























answered Apr 1 at 20:36









StefanHStefanH

10.9k1920




10.9k1920













  • The lower one looks perfect, thank you very much!!

    – Dave
    Apr 1 at 21:13











  • Your last edit is simply perfect! Thank you so much!

    – Dave
    yesterday



















  • The lower one looks perfect, thank you very much!!

    – Dave
    Apr 1 at 21:13











  • Your last edit is simply perfect! Thank you so much!

    – Dave
    yesterday

















The lower one looks perfect, thank you very much!!

– Dave
Apr 1 at 21:13





The lower one looks perfect, thank you very much!!

– Dave
Apr 1 at 21:13













Your last edit is simply perfect! Thank you so much!

– Dave
yesterday





Your last edit is simply perfect! Thank you so much!

– Dave
yesterday











5














Are you looking for the minimum? (I shifted the plot a bit but you can of course undo the shift.)



documentclass[border=3.14mm,tikz]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {exp(3*x)};
addplot+[no marks, samples=100] {(-exp(3*x)+20)};
addplot+[no marks, samples=6,smooth]
{min(exp(3*x),(-exp(3*x)+20))-pi/2};
end{axis}
end{tikzpicture}
end{document}


enter image description here






share|improve this answer
























  • Thank you very much marmot! The user StefanH has also posted a great approach which looks very smooth - I hope you are not disappointed if I choose his option as an answer?

    – Dave
    Apr 1 at 21:14


















5














Are you looking for the minimum? (I shifted the plot a bit but you can of course undo the shift.)



documentclass[border=3.14mm,tikz]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {exp(3*x)};
addplot+[no marks, samples=100] {(-exp(3*x)+20)};
addplot+[no marks, samples=6,smooth]
{min(exp(3*x),(-exp(3*x)+20))-pi/2};
end{axis}
end{tikzpicture}
end{document}


enter image description here






share|improve this answer
























  • Thank you very much marmot! The user StefanH has also posted a great approach which looks very smooth - I hope you are not disappointed if I choose his option as an answer?

    – Dave
    Apr 1 at 21:14
















5












5








5







Are you looking for the minimum? (I shifted the plot a bit but you can of course undo the shift.)



documentclass[border=3.14mm,tikz]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {exp(3*x)};
addplot+[no marks, samples=100] {(-exp(3*x)+20)};
addplot+[no marks, samples=6,smooth]
{min(exp(3*x),(-exp(3*x)+20))-pi/2};
end{axis}
end{tikzpicture}
end{document}


enter image description here






share|improve this answer













Are you looking for the minimum? (I shifted the plot a bit but you can of course undo the shift.)



documentclass[border=3.14mm,tikz]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}
begin{axis}[domain=0:1]
addplot+[no marks, samples=100] {exp(3*x)};
addplot+[no marks, samples=100] {(-exp(3*x)+20)};
addplot+[no marks, samples=6,smooth]
{min(exp(3*x),(-exp(3*x)+20))-pi/2};
end{axis}
end{tikzpicture}
end{document}


enter image description here







share|improve this answer












share|improve this answer



share|improve this answer










answered Apr 1 at 20:19









marmotmarmot

116k5147277




116k5147277













  • Thank you very much marmot! The user StefanH has also posted a great approach which looks very smooth - I hope you are not disappointed if I choose his option as an answer?

    – Dave
    Apr 1 at 21:14





















  • Thank you very much marmot! The user StefanH has also posted a great approach which looks very smooth - I hope you are not disappointed if I choose his option as an answer?

    – Dave
    Apr 1 at 21:14



















Thank you very much marmot! The user StefanH has also posted a great approach which looks very smooth - I hope you are not disappointed if I choose his option as an answer?

– Dave
Apr 1 at 21:14







Thank you very much marmot! The user StefanH has also posted a great approach which looks very smooth - I hope you are not disappointed if I choose his option as an answer?

– Dave
Apr 1 at 21:14




















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