In homogeneous ODE
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If the solution to an ode is an exponential of x multiplied by $sin x$ , what “guess” do i use for $y_p$ in order to solve the equation?
I have tried using the guess $e^x(Asin x + Bcos x)$ but i think it comes out wrong
differential-equations
edited Nov 14 at 17:27
Isham
12.7k3929
asked Nov 14 at 17:03
Gabriel Grant
1
add a comment |
up vote
0
down vote
favorite
If the solution to an ode is an exponential of x multiplied by $sin x$ , what “guess” do i use for $y_p$ in order to solve the equation?
I have tried using the guess $e^x(Asin x + Bcos x)$ but i think it comes out wrong
differential-equations
edited Nov 14 at 17:27
Isham
12.7k3929
asked Nov 14 at 17:03
Gabriel Grant
1
2
Can you post the actual ODE?
– Moo
Nov 14 at 17:06
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
If the solution to an ode is an exponential of x multiplied by $sin x$ , what “guess” do i use for $y_p$ in order to solve the equation?
I have tried using the guess $e^x(Asin x + Bcos x)$ but i think it comes out wrong
differential-equations
edited Nov 14 at 17:27
Isham
12.7k3929
asked Nov 14 at 17:03
Gabriel Grant
1
If the solution to an ode is an exponential of x multiplied by $sin x$ , what “guess” do i use for $y_p$ in order to solve the equation?
I have tried using the guess $e^x(Asin x + Bcos x)$ but i think it comes out wrong
differential-equations
differential-equations
edited Nov 14 at 17:27
Isham
12.7k3929
asked Nov 14 at 17:03
Gabriel Grant
1
edited Nov 14 at 17:27
Isham
12.7k3929
asked Nov 14 at 17:03
Gabriel Grant
1
edited Nov 14 at 17:27
Isham
12.7k3929
edited Nov 14 at 17:27
Isham
12.7k3929
edited Nov 14 at 17:27
Isham
12.7k3929
12.7k3929
asked Nov 14 at 17:03
Gabriel Grant
1
asked Nov 14 at 17:03
Gabriel Grant
1
asked Nov 14 at 17:03
Gabriel Grant
1
1
2
Can you post the actual ODE?
– Moo
Nov 14 at 17:06
add a comment |
2
Can you post the actual ODE?
– Moo
Nov 14 at 17:06
2
2
Can you post the actual ODE?
– Moo
Nov 14 at 17:06
Can you post the actual ODE?
– Moo
Nov 14 at 17:06
add a comment |
1 Answer
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down vote
If you have $e^{px}(cos{(kx)})$, you usually want something of the form
$y_p=c_1e^{(m+ik)x}$, with m or k possibly changing signs. Complex exponentials should simplify the math.
answered Nov 14 at 17:19
TurlocTheRed
60819
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
If you have $e^{px}(cos{(kx)})$, you usually want something of the form
$y_p=c_1e^{(m+ik)x}$, with m or k possibly changing signs. Complex exponentials should simplify the math.
answered Nov 14 at 17:19
TurlocTheRed
60819
add a comment |
up vote
0
down vote
If you have $e^{px}(cos{(kx)})$, you usually want something of the form
$y_p=c_1e^{(m+ik)x}$, with m or k possibly changing signs. Complex exponentials should simplify the math.
answered Nov 14 at 17:19
TurlocTheRed
60819
add a comment |
up vote
0
down vote
up vote
0
down vote
If you have $e^{px}(cos{(kx)})$, you usually want something of the form
$y_p=c_1e^{(m+ik)x}$, with m or k possibly changing signs. Complex exponentials should simplify the math.
answered Nov 14 at 17:19
TurlocTheRed
60819
If you have $e^{px}(cos{(kx)})$, you usually want something of the form
$y_p=c_1e^{(m+ik)x}$, with m or k possibly changing signs. Complex exponentials should simplify the math.
answered Nov 14 at 17:19
TurlocTheRed
60819
answered Nov 14 at 17:19
TurlocTheRed
60819
answered Nov 14 at 17:19
TurlocTheRed
60819
answered Nov 14 at 17:19
TurlocTheRed
60819
60819
add a comment |
add a comment |
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Can you post the actual ODE?
– Moo
Nov 14 at 17:06