About distribution of random variables











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I'm understand what is $mathrm P$ ($eta leq x)$ for a random variable, but what is $mathrm P$ ($eta leq xi$) if $xi$ is random variable too? I can't find definition of something like that. How to calculate it, if I know that $eta, xi$ are independent and have the same geometric distribution with the parameter $p$. Will it be some function from $p$?










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    up vote
    2
    down vote

    favorite












    I'm understand what is $mathrm P$ ($eta leq x)$ for a random variable, but what is $mathrm P$ ($eta leq xi$) if $xi$ is random variable too? I can't find definition of something like that. How to calculate it, if I know that $eta, xi$ are independent and have the same geometric distribution with the parameter $p$. Will it be some function from $p$?










    share|cite|improve this question


























      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      I'm understand what is $mathrm P$ ($eta leq x)$ for a random variable, but what is $mathrm P$ ($eta leq xi$) if $xi$ is random variable too? I can't find definition of something like that. How to calculate it, if I know that $eta, xi$ are independent and have the same geometric distribution with the parameter $p$. Will it be some function from $p$?










      share|cite|improve this question















      I'm understand what is $mathrm P$ ($eta leq x)$ for a random variable, but what is $mathrm P$ ($eta leq xi$) if $xi$ is random variable too? I can't find definition of something like that. How to calculate it, if I know that $eta, xi$ are independent and have the same geometric distribution with the parameter $p$. Will it be some function from $p$?







      probability probability-distributions random-variables






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      edited Nov 21 at 15:47

























      asked Nov 21 at 15:37









      anykk

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          1 Answer
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          If $eta$ and $xi$ are both random variables on the same probability space, then also $eta-xi$ is a random variable on that probability space.



          Now observe that $${etaleqxi}={eta-xileq0}$$ so that $$P({etaleqxi})=P({eta-xileq0})$$



          One way to find (mostly not the most convenient one) is finding the distribution of $eta-xi$.



          Also it can be found as $$mathbb E[etaleqxi]=intint[xleq y]dF_{eta,xi}(x,y)tag1$$ where $[xleq y]$ denotes the function $mathbb R^2tomathbb R$ that takes value $1$ if $xleq y$ and takes value $0$ otherwise, and $F_{eta,xi}$ denotes the CDF of random vector $(eta,xi)$.



          If $eta$ and $xi$ are independent then the RHS of $(1)$ becomes:$$int_{-infty}^{infty}int_{-infty}^ydF_{eta}(x)dF_{xi}(y)=int_{-infty}^{infty}F_{eta}(y)dF_{xi}(y)$$






          share|cite|improve this answer























          • Eh, you have helped me twice, thank you. Could you recommend some lectures or books about probability theory and statistics? I'm from Russia and unfamiliar with english literature, but I think, that it'll better then most that I know
            – anykk
            Nov 21 at 15:52












          • Sorry, but I learned prob. and stat. not from books but from scripts that were used at university. So I am not quite familiar with english books on that stuff either, and cannot recommend something.
            – drhab
            Nov 21 at 15:58











          Your Answer





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          1 Answer
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          active

          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          2
          down vote



          accepted










          If $eta$ and $xi$ are both random variables on the same probability space, then also $eta-xi$ is a random variable on that probability space.



          Now observe that $${etaleqxi}={eta-xileq0}$$ so that $$P({etaleqxi})=P({eta-xileq0})$$



          One way to find (mostly not the most convenient one) is finding the distribution of $eta-xi$.



          Also it can be found as $$mathbb E[etaleqxi]=intint[xleq y]dF_{eta,xi}(x,y)tag1$$ where $[xleq y]$ denotes the function $mathbb R^2tomathbb R$ that takes value $1$ if $xleq y$ and takes value $0$ otherwise, and $F_{eta,xi}$ denotes the CDF of random vector $(eta,xi)$.



          If $eta$ and $xi$ are independent then the RHS of $(1)$ becomes:$$int_{-infty}^{infty}int_{-infty}^ydF_{eta}(x)dF_{xi}(y)=int_{-infty}^{infty}F_{eta}(y)dF_{xi}(y)$$






          share|cite|improve this answer























          • Eh, you have helped me twice, thank you. Could you recommend some lectures or books about probability theory and statistics? I'm from Russia and unfamiliar with english literature, but I think, that it'll better then most that I know
            – anykk
            Nov 21 at 15:52












          • Sorry, but I learned prob. and stat. not from books but from scripts that were used at university. So I am not quite familiar with english books on that stuff either, and cannot recommend something.
            – drhab
            Nov 21 at 15:58















          up vote
          2
          down vote



          accepted










          If $eta$ and $xi$ are both random variables on the same probability space, then also $eta-xi$ is a random variable on that probability space.



          Now observe that $${etaleqxi}={eta-xileq0}$$ so that $$P({etaleqxi})=P({eta-xileq0})$$



          One way to find (mostly not the most convenient one) is finding the distribution of $eta-xi$.



          Also it can be found as $$mathbb E[etaleqxi]=intint[xleq y]dF_{eta,xi}(x,y)tag1$$ where $[xleq y]$ denotes the function $mathbb R^2tomathbb R$ that takes value $1$ if $xleq y$ and takes value $0$ otherwise, and $F_{eta,xi}$ denotes the CDF of random vector $(eta,xi)$.



          If $eta$ and $xi$ are independent then the RHS of $(1)$ becomes:$$int_{-infty}^{infty}int_{-infty}^ydF_{eta}(x)dF_{xi}(y)=int_{-infty}^{infty}F_{eta}(y)dF_{xi}(y)$$






          share|cite|improve this answer























          • Eh, you have helped me twice, thank you. Could you recommend some lectures or books about probability theory and statistics? I'm from Russia and unfamiliar with english literature, but I think, that it'll better then most that I know
            – anykk
            Nov 21 at 15:52












          • Sorry, but I learned prob. and stat. not from books but from scripts that were used at university. So I am not quite familiar with english books on that stuff either, and cannot recommend something.
            – drhab
            Nov 21 at 15:58













          up vote
          2
          down vote



          accepted







          up vote
          2
          down vote



          accepted






          If $eta$ and $xi$ are both random variables on the same probability space, then also $eta-xi$ is a random variable on that probability space.



          Now observe that $${etaleqxi}={eta-xileq0}$$ so that $$P({etaleqxi})=P({eta-xileq0})$$



          One way to find (mostly not the most convenient one) is finding the distribution of $eta-xi$.



          Also it can be found as $$mathbb E[etaleqxi]=intint[xleq y]dF_{eta,xi}(x,y)tag1$$ where $[xleq y]$ denotes the function $mathbb R^2tomathbb R$ that takes value $1$ if $xleq y$ and takes value $0$ otherwise, and $F_{eta,xi}$ denotes the CDF of random vector $(eta,xi)$.



          If $eta$ and $xi$ are independent then the RHS of $(1)$ becomes:$$int_{-infty}^{infty}int_{-infty}^ydF_{eta}(x)dF_{xi}(y)=int_{-infty}^{infty}F_{eta}(y)dF_{xi}(y)$$






          share|cite|improve this answer














          If $eta$ and $xi$ are both random variables on the same probability space, then also $eta-xi$ is a random variable on that probability space.



          Now observe that $${etaleqxi}={eta-xileq0}$$ so that $$P({etaleqxi})=P({eta-xileq0})$$



          One way to find (mostly not the most convenient one) is finding the distribution of $eta-xi$.



          Also it can be found as $$mathbb E[etaleqxi]=intint[xleq y]dF_{eta,xi}(x,y)tag1$$ where $[xleq y]$ denotes the function $mathbb R^2tomathbb R$ that takes value $1$ if $xleq y$ and takes value $0$ otherwise, and $F_{eta,xi}$ denotes the CDF of random vector $(eta,xi)$.



          If $eta$ and $xi$ are independent then the RHS of $(1)$ becomes:$$int_{-infty}^{infty}int_{-infty}^ydF_{eta}(x)dF_{xi}(y)=int_{-infty}^{infty}F_{eta}(y)dF_{xi}(y)$$







          share|cite|improve this answer














          share|cite|improve this answer



          share|cite|improve this answer








          edited Nov 21 at 16:01

























          answered Nov 21 at 15:45









          drhab

          96.3k543126




          96.3k543126












          • Eh, you have helped me twice, thank you. Could you recommend some lectures or books about probability theory and statistics? I'm from Russia and unfamiliar with english literature, but I think, that it'll better then most that I know
            – anykk
            Nov 21 at 15:52












          • Sorry, but I learned prob. and stat. not from books but from scripts that were used at university. So I am not quite familiar with english books on that stuff either, and cannot recommend something.
            – drhab
            Nov 21 at 15:58


















          • Eh, you have helped me twice, thank you. Could you recommend some lectures or books about probability theory and statistics? I'm from Russia and unfamiliar with english literature, but I think, that it'll better then most that I know
            – anykk
            Nov 21 at 15:52












          • Sorry, but I learned prob. and stat. not from books but from scripts that were used at university. So I am not quite familiar with english books on that stuff either, and cannot recommend something.
            – drhab
            Nov 21 at 15:58
















          Eh, you have helped me twice, thank you. Could you recommend some lectures or books about probability theory and statistics? I'm from Russia and unfamiliar with english literature, but I think, that it'll better then most that I know
          – anykk
          Nov 21 at 15:52






          Eh, you have helped me twice, thank you. Could you recommend some lectures or books about probability theory and statistics? I'm from Russia and unfamiliar with english literature, but I think, that it'll better then most that I know
          – anykk
          Nov 21 at 15:52














          Sorry, but I learned prob. and stat. not from books but from scripts that were used at university. So I am not quite familiar with english books on that stuff either, and cannot recommend something.
          – drhab
          Nov 21 at 15:58




          Sorry, but I learned prob. and stat. not from books but from scripts that were used at university. So I am not quite familiar with english books on that stuff either, and cannot recommend something.
          – drhab
          Nov 21 at 15:58


















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