What does “use exponentially distributed inter-arrival times, but make inter-arrival time 25” mean?











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I'm asked to simulate inter-arrival times from exp-distribution and then I'm given that inter-arrival times must be 25, 40, 20, 40. I think these mean "average inter-arrival time", so does that mean that I must take (since the mean of exp-distr. is $lambda^{-1}$) $frac{1}{lambda}=25$ and solve for $lambda$? Then use this for drawing the times?










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  • Do you have any more context?
    – MRobinson
    Nov 21 at 15:54










  • Any chance you could add that (and any other info/attempts) you have to the question?
    – MRobinson
    Nov 21 at 15:57















up vote
0
down vote

favorite












I'm asked to simulate inter-arrival times from exp-distribution and then I'm given that inter-arrival times must be 25, 40, 20, 40. I think these mean "average inter-arrival time", so does that mean that I must take (since the mean of exp-distr. is $lambda^{-1}$) $frac{1}{lambda}=25$ and solve for $lambda$? Then use this for drawing the times?










share|cite|improve this question
























  • Do you have any more context?
    – MRobinson
    Nov 21 at 15:54










  • Any chance you could add that (and any other info/attempts) you have to the question?
    – MRobinson
    Nov 21 at 15:57













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I'm asked to simulate inter-arrival times from exp-distribution and then I'm given that inter-arrival times must be 25, 40, 20, 40. I think these mean "average inter-arrival time", so does that mean that I must take (since the mean of exp-distr. is $lambda^{-1}$) $frac{1}{lambda}=25$ and solve for $lambda$? Then use this for drawing the times?










share|cite|improve this question















I'm asked to simulate inter-arrival times from exp-distribution and then I'm given that inter-arrival times must be 25, 40, 20, 40. I think these mean "average inter-arrival time", so does that mean that I must take (since the mean of exp-distr. is $lambda^{-1}$) $frac{1}{lambda}=25$ and solve for $lambda$? Then use this for drawing the times?







queueing-theory






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share|cite|improve this question













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edited Nov 21 at 15:58

























asked Nov 21 at 15:54









mavavilj

2,69311032




2,69311032












  • Do you have any more context?
    – MRobinson
    Nov 21 at 15:54










  • Any chance you could add that (and any other info/attempts) you have to the question?
    – MRobinson
    Nov 21 at 15:57


















  • Do you have any more context?
    – MRobinson
    Nov 21 at 15:54










  • Any chance you could add that (and any other info/attempts) you have to the question?
    – MRobinson
    Nov 21 at 15:57
















Do you have any more context?
– MRobinson
Nov 21 at 15:54




Do you have any more context?
– MRobinson
Nov 21 at 15:54












Any chance you could add that (and any other info/attempts) you have to the question?
– MRobinson
Nov 21 at 15:57




Any chance you could add that (and any other info/attempts) you have to the question?
– MRobinson
Nov 21 at 15:57















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